Demand Factor-Diversity Factor-Utilization
Factor-Load Factor
(1) Demand factor
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Demand Factor = Maximum demand of a system / Total connected load on the
system
Demand factor is always less than one.
Example: if a residence having 6000W equipment connected has a maximum demand of
300W,Than demand factor = 6000W / 3300W = 55%.
The lower the demand factor, the less system capacity required to serve the connected
load.
Feeder-circuit conductors should have an ampere sufficient to carry the load; the ampere
of the feeder-circuit need not always be equal to the total of all loads on all branchcircuits connected to it.
Remember that the demand factor permits a feeder-circuit ampere to be less than 100% of
the sum of all branch-circuit loads connected to the feeder.
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Example: One Machine Shop has
Fluorescent fixtures=1 No, 5kw each, Receptacle outlets =1 No, 1500w each.
Lathe=1No, 10 Hp, Air Compressor=1 No, 20 Hp, Fire Pump=1 No, 15 Hp.
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After questioning the customer about the various loads, the information is further
deciphered as follows:
1. The shop lights are on only during the hours of 8 a.m. to 5 p.m.
2. The receptacle outlets are in the office only, and will have computers and other
small loads plugged into them.
3. The lathe is fully loaded for 5 minutes periods. The rest of the time is setup
time. This procedure repeats every 15 minutes.
4. The air compressor supplies air to air tools and cycles off and on about half the
time.
5. The fire pump only runs for 30 minutes when tested which is once a month after
hours.
Calculation:
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Lighting Demand Factor = Demand Interval Factor x Diversity Factor.
= (15 minute run time/ 15 minutes) x 1.0 = 1.0
Lighting Demand Load = 5 kW x 1.0 = 5 kW
Receptacle Outlet Demand Factor = Demand Interval Factor x Diversity Factor
= (15 minute run time / 15 minutes) x 0.1 = 0.1
Receptacle Outlet Demand Load = 15 x 1500 watts x 0.1 = 2.25 kW
Lathe Demand Factor = Demand Interval Factor x Diversity Factor.
= (5 minute run time / 15 minutes) x 1.0 =0 .33
Lathe Demand Load = 10 hp x .746 x .33 = 2.46 kW
Air Compressor Demand Factor = Demand Interval Factor x Diversity Factor.
= (7.5 minute run time / 15 minutes) x 1.0 = 0.5
Air Compressor Demand Load = 20 hp x .746 x .5 = 7.46 kW
Fire Pump Demand Factor = Demand Interval Factor x Diversity Factor.
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= (15 minute run time/ 15 minutes) x 0.0 = 0.0
Fire Pump Demand Load = 15 hp x .746 x 0.0 = 0.0 kW
Summary of Demand Loads :
Equipment
Lighting
Receptacle Outlets
Lathe
Air Compressor
Fire Pump
TOTAL
kW
5
22.5
7.5
15
11.25
61.25 Kw
D.F.
1
.1
.33
0.5
0.0
Demand KW
5
2.25
2.46
7.46
0.0
17.17 Kw
(2) Diversity factor / simultaneity factor (Ks)
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Diversity Factor = Sum of Individual Max. Demand. / Max. Demand on Power
Station.
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Diversity Factor = Installed load. / Running load.
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Diversity factor is usually more than one. (Since the sum of individual max. demands
>Max. Demand)
The load is time dependent as well as being dependent upon equipment characteristics.
The diversity factor recognizes that the whole load does not equal the sum of its parts due
to this time Interdependence (i.e. diverseness).
When the maximum demand of a supply is being assessed it is not sufficient to simply
add together the ratings of all electrical equipment that could be connected to that supply.
If this is done, a figure somewhat higher than the true maximum demand will be
produced. This is because it is unlikely that all the electrical equipment on a supply will
be used simultaneously.
The concept of being able to De-rate a potential maximum load to an actual maximum
demand is known as the application of a diversity factor.
70% diversity means that the device in question operates at its nominal or maximum load
level 70% of the time that it is connected and turned on.
If total installed full load ampere is twice your running load ampere then the diversity
factor is two.
If total installed full load ampere is four times your load a ampere then the diversity
factor is four.
If everything (all electrical equipment) was running at full load at the same time the
diversity factor is equal to One
Greater the diversity factor, lesser is the cost of generation of power.
Diversity factor in a distribution network is the ratio of the sum of the peak demands of
the individual customers to the peak demand of the network.
This will be determined by the type of service, i.e., residential, commercial, industrial and
combinations of such.
Example-I: A distribution feeder serves 5 houses, each of which has a peak demand of 5
KW. The feeder peak turns out to be 20 kw. The diversity is then 20/25 or 0.8. This
results from the timing differences between the individual heating/cooling, appliance
usages in the individual customers.
As supply availability decreases, the diversity factor will tend to increase toward 1.00.
This can be demonstrated when restoring service after outages (called “cold starts”) as
the system initial surge can be much greater than the historical peak loads.
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Example-II: A sub-station has three outgoing feeders:
1.
2.
3.
4.
feeder 1 has maximum demand 10 MW at 10:00 am,
feeder 2 has maximum demand 12 MW at 7:00 pm and
feeder 3 has maximum demand 15 MW at 9:00 pm,
While the maximum demand of all three feeders is 33 MW at 8:00 pm.
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Here, the sum of the maximum demand of the individual sub-systems (feeders) is 10 + 12
+ 15 = 37 MW, while the system maximum demand is 33 MW. The diversity factor is
37/33 = 1.12. The diversity factor is usually greater than 1; its value also can be 1 which
indicates the maximum demand of the individual sub-system occurs simultaneously.
Diversity is the relationship between the rated full loads of the equipment downstream of
a connection point, and the rated load of the connection point. To illustrate:
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1. The building at these co-ordinates is fitted with a 100A main supply fuse.
2. The distribution board has 2no. 6A breakers, 1no. 20A breaker and 5no. 32A breakers, a
total, potentially, of 192A.
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Not all these rated loads are turned on at once. If they were, then the 100A supply fuse
would rupture, as it cannot pass 192A. So the diversity factor of the distribution board
can be said to be 192A/100A, or 1.92, or 52%.
Many designers prefer to use unity as the diversity factor in calculations for planning
conservatism because of plant load growth uncertainties. Local experience can justify
using a diversity factor larger than unity, and smaller service entrance conductors and
transformer requirements chosen accordingly.
The diversity factor for all other installations will be different, and would be based upon a
local evaluation of the loads to be applied at different moments in time. Assuming it to be
1.0 may, on some occasions, result in a supply feeder and equipment rating that is rather
larger than the local installation warrants, and an over-investment in cable and equipment
to handle the rated load current. It is better to evaluate the pattern of usage of the loads
and calculate an acceptable diversity factor for each particular case.
In the case of the example given above, achieving a diversity of 1.0 or 100% would
require well over twice the cross-sectional area of copper cable to be installed in a deep
trench underneath a field, the rebuild of a feeder cabinet to larger dimensions, more
substantial overhead supply cables for a distance exceeding 2km northwards and a
different tariff, where one pays rather more for a kWh than at present. The investment
required to achieve 1.0 simply isn’t justifiable in this particular case.
Diversity factor is mostly used for distribution feeder size and transformer as well as to
determine the maximum peak load and diversity factor is always based on knowing the
process. You have to understand what will be on or off at a given time for different
buildings and this will size the feeder. Note for typical buildings diversity factor is
always one. You have to estimate or have a data records to create 24 hours load graph
and you can determine the maximum demand load for node then you can easily
determine the feeder and transformer size.
The diversity factor of a feeder would be the sum of the maximum demands of the
individual consumers divided by the maximum demand of the feeder. In the same
manner, it is possible to compute the diversity factor on a substation, a transmission line
or a whole utility system.
The residential load has the highest diversity factor. Industrial loads have low diversity
factors usually of 1.4, street light practically unity and other loads vary between these
limits.
Diversity Factor in distribution Network
Elements of System
Between individual users
Between transformers
Between feeders
Between substations
From users to transformers
From users to feeder
From users to substation
From users to generating station
Residential
2.00
1.30
1.15
1.10
2.00
2.60
3.00
3.29
Diversity Factors
General
Commercial
Power
1.46
1.45
1.30
1.35
1.15
1.15
1.10
1.10
1.46
1.44
1.90
1.95
2.18
2.24
2.40
2.46
Diversity Factor for distribution switchboards
Number of circuits
Assemblies entirely tested 2 and 3
4 and 5
6 to 9
10 and more
Assemblies partially tested in every case choose
Diversity Factor (ks)
0.9
0.8
0.7
0.6
1
Diversity Factor for according to circuit function (IEC 60439)
Circuits Function
Lighting
Heating and air conditioning
Socket-outlets
Lifts and catering hoist
For the most powerful motor
For the second most powerful motor
For all motors
Diversity Factor for an apartment block
Apartment
2 To 4
5To 19
10To 14
15To 19
20To 24
25To 29
30 To 34
35 To 39
40To 40
50 To Above
Diversity Factor (ks)
1
0.78
0.63
0.53
0.49
0.46
0.44
0.42
0.41
0.40
Diversity Factor (ks)
0.9
0.8
0.7
1
0.75
0.8
Large
Industrial
1.05
1.05
1.10
1.15
1.32
1.45
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Example: 5 storey apartment building with 25 consumers, each having 6 kVA of
installed load.
The total installed load for the building is: 36 + 24 + 30 + 36 + 24 = 150 kVA
The apparent-power supply required for the building is: 150 x 0.46 = 69 kVA
It is a matter of common experience that the simultaneous operation of all installed loads
of a given installation never occurs in practice, i.e. there is always some degree of
diversity and this fact is taken into account for estimating purposes by the use of a
simultaneity factor / Diversity Factor (ks).
The Diversity factor ks is applied to each group of loads (e.g. being supplied from a
distribution or sub-distribution board). The determination of these factors is the
responsibility of the designer, since it requires a detailed knowledge of the installation
and the conditions in which the individual circuits are to be exploited. For this reason, it
is not possible to give precise values for general application.
Designing Size of Electrical Switchgear by use of Demand Factor and Diversity Factor:
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Diversity factors are used by utilities for distribution transformer sizing and load
predictions.
Demand factors are more conservative and are used by NEC for service and feeder
sizing.
Demand factors and diversity factors are used in design.
For example, the sum of the connected loads supplied by a feeder is multiplied by the
demand factor to determine the load for which the feeder must be sized. This load is
termed the maximum demand of the feeder. The sum of the maximum demand loads for a
number of sub feeders divided by the diversity factor for the sub feeders will give the
maximum demand load to be supplied by the feeder from which the sub feeders are
derived.
Example-1: Suppose We have four individual feeder-circuits with connected loads of
250 kVA, 200 kVA, 150 kVA and 400 kVA and demand factors of 90%, 80%, 75% and
85% respectively.Use a diversity factor of 1.5.
Calculating demand for feeder-circuits
o 250 kVA x 90% = 225 kVA
o 200 kVA x 80% = 160 kVA
o 150 kVA x 75% = 112.5 kVA
o 400 kVA x 85% = 340 kVA
o 837.5 kVA
o The sum of the individual demands is equal to 837.5 kVA.
o If the main feeder-circuit were sized at unity diversity: kVA = 837.5 kVA ÷ 1.00
= 837.5 kVA.
o The main feeder-circuit would have to be supplied by an 850 kVA transformer.
o However, using the diversity factor of 1.5, the kVA = 837.5 kVA ÷ 1.5 = 558
kVA for the main feeder.
o For diversity factor of 1.5, a 600 kVA transformer could be used.
o Example-2: A conveyor belt made up of six sections, each driven by a 2 kW
motor. As material is transported along this belt, it is first carried by section 1, and
then each section in succession until the final section is reached. In this simple
example only one section of conveyor is carrying material at any point in time.
Therefore five motors are only handling no-load mechanical losses (say .1 kW)
keeping the belts moving whilst one motor is handling the load (say 1 kW). The
demand presented by each motor when it is carrying its load is 1 kW, the sum of
the demand loads is 6 kW but the maximum load presented by the system at any
time is only 1.5 kW.
Diversity factor =Sum of Individual Max. Demand / Max. Demand = 6 Kw / 1.5
Kw =4.
o Demand Factor = Maximum demand / Total connected load = 1.5 Kw / 12 Kw =
0.125.
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(3) Load factor
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Load Factor = Average load. /Maximum load during a given period.
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It can be calculated for a single day, for a month or for a year.
Its value is always less than one. Because maximum demand is always more than avg.
demand.
It is used for determining the overall cost per unit generated. Higher the load factor,
lesser will be the cost per unit.
Load Factor = Load that a piece of equipment actually draws / Load it could draw (full
load).
Example: Motor of 20 hp drives a constant 15 hp load whenever it is on.
The motor load factor is then 15/20 = 75%.
Load factor is term that does not appear on your utility bill, but does affect electricity
costs. Load factor indicates how efficiently the customer is using peak demand.
Load Factor = ( energy (kWh per month) ) / ( peak demand (kW) x hours/month )
A high load factor means power usage is relatively constant. Low load factor shows that
occasionally a high demand is set. To service that peak, capacity is sitting idle for long
periods, thereby imposing higher costs on the system. Electrical rates are designed so that
customers with high load factor are charged less overall per kWh.
For Example
Customer A – High Load Factor
82% load factor = (3000 kWh per month x 100%) / 5 kW x 730 hours/month.
Customer B – Low Load Factor
41% load factor = (3000 kWh per month x 100%) / 10kW x 730 hours/month.
To encourage the efficient use of installed capacity, electricity rates are structured so the
price per kWh above a certain load factor is lower. The actual structure of the price
blocks varies by rate.
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(4) Utilization factor (Ku)
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In normal operating conditions the power consumption of a load is sometimes less than
that indicated as its nominal power rating, a fairly common occurrence that justifies the
application of an utilization factor (ku) in the estimation of realistic values.
Utilization Factor = The time that a equipment is in use./ The total time that it could
be in use.
Example: The motor may only be used for eight hours a day, 50 weeks a year. The hours
of operation would then be 2000 hours, and the motor Utilization factor for a base of
8760 hours per year would be 2000/8760 = 22.83%. With a base of 2000 hours per year,
the motor Utilization factor would be 100%. The bottom line is that the use factor is
applied to get the correct number of hours that the motor is in use.
This factor must be applied to each individual load, with particular attention to electric
motors, which are very rarely operated at full load. In an industrial installation this factor
may be estimated on an average at 0.75 for motors.
For incandescent-lighting loads, the factor always equals 1.
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For socket-outlet circuits, the factors depend entirely on the type of appliances being
supplied from the sockets concerned.
Maximum demand
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Maximum demand (often referred to as MD) is the largest current normally carried by
circuits, switches and protective devices. It does not include the levels of current flowing
under overload or short circuit conditions.
Assessment of maximum demand is sometimes straightforward. For example, the
maximum demand of a 240 V single-phase 8 kW shower heater can be calculated by
dividing the power (8 kW) by the voltage (240 V) to give a current of 33.3 A. This
calculation assumes a power factor of unity, which is a reasonable assumption for such a
purely resistive load.
There are times, however, when assessment of maximum demand is less obvious. For
example, if a ring circuit feeds fifteen 13 A sockets, the maximum demand clearly should
not be 15 x 13 = 195 A, if only because the circuit protection will not be rated at more
than 32 A. Some 13 A sockets may feed table lamps with 60 W lamps fitted, whilst
others may feed 3 kW washing machines; others again may not be loaded at all.
Lighting circuits pose a special problem when determining MD. Each lamp-holder must
be assumed to carry the current required by the connected load, subject to a minimum
loading of 100 W per lamp holder (a demand of 0.42 A per lamp holder at 240 V).
Discharge lamps are particularly difficult to assess, and current cannot be calculated
simply by dividing lamp power by supply voltage. The reasons for this are:
1. Control gear losses result in additional current,
2. the power factor is usually less than unity so current is greater, and
3. Chokes and other control gear usually distort the waveform of the current so that it
contains harmonics which are additional to the fundamental supply current.
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So long as the power factor of a discharge lighting circuit is not less than 0.85, the current
demand for the circuit can be calculated from:
current (A) = (lamp power (W) x 1.8) / supply voltage (V)
For example, the steady state current demand of a 240 V circuit supplying ten 65 W
fluorescent lamps would be: I = 10X65X1.8A / 240 = 4.88A
Switches for circuits feeding discharge lamps must be rated at twice the current they are
required to carry, unless they have been specially constructed to withstand the severe
arcing resulting from the switching of such inductive and capacitive loads.
(5) Coincidence factor
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The coincidence factor =Max. demand of a system / sum of the individual maximum
demands
The coincidence factor is the reciprocal of the diversity factor
Demand Factor & Load Factor according to Type of Industries
Type of Industry
Arc Furnace
Induction Furnace
Steel Rolling mills
Demand
Factor
0.55
0.90
0.80
Load
Factor
0.80
0.80
0.25
Utilization Factor
(DF x LF)
0.44
0.72
0.20
Mechanical/ Electrical
a) Single Shift
b) Double Shift
Cycle Industry
Wire products
Auto Parts
Forgings
Cold Storage
a) Working Season
b) Non-Working Season
Rice Sheller’s
a) Working Season
b) Non-Working Season
Ice Candy Units
a) Working Season
b) Non-Working Season
Ice Factories
a) Working Season
b) Non-Working Season
Cotton Ginning
a) Working Season
b) Non-Working Season
Spinning Mills
Textile Industry
Dyeing and Printing
Ghee Mills
Oil Mills
Solvent Extraction Mills
Plastic
Soap
Rubber (Foot Wear)
Distilleries
Chemical Industry
Gas Plant Industry
Pain and Colour Factory
Sugar
Paper
Flour Mills(Single Shift)
Atta Chakies
Milk Plants
Printing Presses
Repair Workshops
Bottling Plants
Radio Stations
Telephone exchange
Public Water Works
Medical Colleges
0.45
0.45
0.40
0.35
0.40
0.50
0.25
0.50
0.40
0.40
0.50
0.35
0.11
0.22
0.16
0.14
0.20
0.17
0.60
0.25
0.65
0.15
0.39
0.04
0.70
0.05
0.80
0.30
0.56
0.01
0.50
0.50
0.65
0.10
0.32
0.05
0.80
0.80
0.65
0.10
0.52
0.08
0.70
0.10
0.60
0.50
0.40
0.50
0.70
0.45
0.60
0.50
0.45
0.35
0.40
0.70
0.50
0.30
0.50
0.80
0.50
0.40
0.35
0.40
0.40
0.55
0.50
0.75
0.60
0.25
0.10
0.80
0.80
0.50
0.50
0.50
0.50
0.25
0.25
0.35
0.50
0.50
0.50
0.40
0.45
0.80
0.25
0.25
0.80
0.30
0.25
0.35
.0.45
0.90
0.40
0.25
0.17
0.01
0.48
0.40
0.20
0.25
0.35
0.22
0.11
0.12
0.16
0.17
0.20
0.35
0.20
0.13
0.40
0.20
0.12
0.32
0.10
0.10
0.14
0.25
0.45
0.30
0.15
Hospitals
Nursing Homes
Colleges and Schools
Hotels and Restaurants
Marriage Palaces
0.25
0.50
0.50
0.75
1.00
0.90
0.50
0.20
0.40
0.25
0.22
0.25
0.10
0.30
0.25
Demand Factor & Load Factor according to Type of Buildings:
dual Facilities
Communications – buildings
Telephone exchange building
Air passenger terminal building
Aircraft fire and rescue station
Aircraft line operations building
Academic instruction building
Applied instruction building
Chemistry and Toxicology Laboratory
Materials Laboratory
Physics Laboratory
Electrical and electronics systems
laboratory
Cold storage warehouse
General warehouse
Controlled humidity warehouse
Hazardous/flammable storehouse
Disposal, salvage, scrap building
Hospital
Laboratory
Dental Clinic
Medical Clinic
Administrative Office
Single-family residential housing
Detached garages
Apartments
Fire station
Police station
Bakery
Laundry/dry cleaning plant
K-6 schools
7-12 schools
Churches
Post Office
Retail store
Bank
Supermarket
Restaurant
Demand
Factor
60-65
55-70
65-80
25-35
65-80
40-60
35-65
70-80
Load Factor
70-75
20-25
28-32
13-17
24-28
22-26
24-28
22-28
30-35
70-80
20-30
27-32
22-28
3-7
70-75
75-80
60-65
75-80
35-40
38-42
32-37
35-40
45-50
50-65
60-70
40-50
35-40
25-35
48-53
30-35
30-35
75-80
65-70
65-70
75-80
65-70
75-80
55-60
45-75
20-25
23-28
33-38
20-25
25-20
45-50
20-25
18-23
20-23
20-35
10-15
2-4
38-42
13-17
20-25
45-60
20-25
10-15
12-17
5-25
20-25
25-32
20-25
25-30
15-25
Auto repair shop
Hobby shop, art/crafts
Bowling alley
Gymnasium
Skating rink
Indoor swimming pool
Theater
Library
Golf clubhouse
Museum
40-60
30-40
70-75
70-75
70-75
55-60
45-55
75-80
75-80
75-80
15-20
25-30
10-15
20-45
10-15
25-50
8-13
30-35
15-20
30-35