Coulomb Damping Today’s Objectives: Students will be able to: 6 b) Identify system parameters when it has Coulomb damping 4 2 Displacement a) Understand the difference between Coulomb and viscous damping 0 -2 -4 -6 Trivia of the day Vibrations Rose-Hulman Institute of Technology Mechanical Engineering SDOF concept map Vibrations Rose-Hulman Institute of Technology Mechanical Engineering Coulomb Damping (dry friction) – EOM Damping Force: Fd=µkN (independent of velocity) (SEP) x k m FBD a) Motion to the right (SEP) µk, µs b) Motion to the left (SEP) x mg x mg kx kx Fd Fd N N Find EOM using conservation of linear momentum rate (Newton’s 2nd Law) in the x-direction ↓ r dPsys dt r = ∑F → m&x& = − kx − Fd sgn (x& ) 123 sign of x& Vibrations Rose-Hulman Institute of Technology Mechanical Engineering Coulomb Damping (dry friction) – EOM We can write this as two EOM (one for each direction) m&x& + kx = − Fd m&x& + kx = Fd x& > 0 (moving right) x& > 0 (moving left) (1) x& > 0 (moving right) (3) x& > 0 (moving left) (4) (2) Or in standard from &x& +x=− &x& +x= ω 2 n ωn2 Fd k Fd k where ωn = k m Vibrations Rose-Hulman Institute of Technology Mechanical Engineering Coulomb Damping (dry friction) – Solution We can solve Eqns. 3 and 4 F xR (t ) = A1cosωn t + A2sinωn t − d k F xR (t ) = A3cosωn t + A4sinωn t + d k Assume IC’s x(0 ) = x0 ⎫⎪ ⎬ starts moving to the left x& (0 ) = 0 ⎪⎭ (moving right) (5) (moving left) (6) Procedure (see book for details) 1. 2. 3. 4. 5. Eq. 1 and 2 are valid for only ½ a cycle Solve Eq. 6 for A3 and A4 using IC’s Endpoint of this ½ cycle becomes the IC for the “moving right” phase governed by Eq. 5 Solve Eq. 5 for A1 and A2. Endpoint of this ½ cycle is IC for next ½ cycle Go to step 2 Vibrations Rose-Hulman Institute of Technology Mechanical Engineering Coulomb damping – Free response Observations 6 x0 4 x0 − 4 Fd k Offset Displacement 2 0 -2 -4 -6 2F x0 − d k 2π ωn Vibrations Rose-Hulman Institute of Technology Mechanical Engineering Hysteretic Damping (structural or solid damping) • Experimental results indicate that for most structural materials such as steel or aluminum the energy loss is: – Independent of the frequency – Proportional to the amplitude squared • Notes: – Rarely is only one form of damping present – A semilog plot can provide an indication of the damping present Vibrations Rose-Hulman Institute of Technology Mechanical Engineering Damping records of automobile motion (Figures taken from An Introduction to Mechanical Vibrations by Steidel) Well function shock absorber Shock absorber action is poor and damping is primarily structural Vibrations Rose-Hulman Institute of Technology Mechanical Engineering Damping records of automobile motion (Figures taken from An Introduction to Mechanical Vibrations by Steidel) Dry friction or rubbing structural parts is apparent Shock absorbers are ineffective. A loose fitting plunger makes the damping different in each direction Vibrations Rose-Hulman Institute of Technology Mechanical Engineering We will use Simulink Vibrations Rose-Hulman Institute of Technology Mechanical Engineering Generic Simulink Model for SDOF System Vibrations Rose-Hulman Institute of Technology Mechanical Engineering One way to get the envelope is to use the Hilbert Transform Vibrations Rose-Hulman Institute of Technology Mechanical Engineering