Loading Errors Consider again the voltage divider circuit: nd Figure 6.16 in 2 rd and 3 Edition The equivalent resistance of the circuit is given by: R1 R m = + = + R eq R 2 R L R 2 R1 + R m LoadingErrors.docx November 14, 2008 (6.361 , 6.322,3 ) Page 1 The output voltage Eo is related to the input voltage Ei by: 1 Eo = (6.371 , 6.352,3 ) E i 1 + ( R 2/ R1 ) ( R1/ R m + 1) We can define a loading error as the normalized difference between the output voltage with an infinite meter resistance and that with a finite value: ei = Ei ' Eo - Eo Ei Ei (6.381 , 6.37 2,3 ) e - + ( - )( / + 1) = R 1 RT 2 RT R 1 R 1 R m E i RT +( RT / R1 - RT )( R1 / R m + 1) Here is the ideal value and is the actual value. (Notice the correction of the equation in the First Edition of the text). The value of is constant. Let's plot the error as a function of R1/RT for various meter resistances. LoadingErrors.docx November 14, 2008 Page 2 For a meter resistance Rm equal to the total resistance RT, the error is a significant fraction of the signal. To get accurate measurements, we must therefore keep Rm >> RT. When we consider the effects of loading, we must distinguish between measurement of effort variables such as voltage and measurement of flow variables such as current. LoadingErrors.docx November 14, 2008 Page 3 Effort Variable Flow Variable Voltage Current Pressure Flow Temperature Heat Flux Force Velocity We can define the input impedance of the instrument and the output impedance of the system. For the voltage divider circuit, the output impedance is RT and the input impedance of the meter is Rm. For effort variables, the requirement is that the input impedance of the instrument should be much greater than the output impedance of the system. nd Figure 6.17 in 2 rd and 3 Edition LoadingErrors.docx November 14, 2008 Page 4 1 e1 = 11 + Z 1/ Z m E1 (6.39) For flow variables, the input impedance of the instrument should be much less than the output impedance of the system. nd Figure 6.18 in 2 rd and 3 Edition e1 Zm = 2 E1 Z 1 + Z 1 Z m Zm / Z1 = 1+ ( Z m / Z 1 ) I e1 (6.42) If our instrument has more than one component, the same rules are applied to each stage, treating the output of one stage as the input of the next. LoadingErrors.docx November 14, 2008 Page 5 In designing an instrument, we want impedance mismatching. If we wanted to transfer a maximum amount of power, say to the speakers of a sound system, we would want impedance matching. Let us consider an example which is not electrical, the measurement of the temperature of a cup of water using a thermometer. LoadingErrors.docx November 14, 2008 Page 6 An energy balance gives: C t ( T f - T o ) = C w( T i - T f ) where C is the heat capacity, and t refers to the thermometer and w to the water. Here we will define the impedances as: Z 1 = 1/ C w , Z m = 1/ C t The error in the measurement e = (Ti - Tf) can be written: e Z 1/ Z m = T i - T o 1 + Z 1/ Z m 1 = 11 + Z 1/ Z m which is the same as Equation (6.39) LoadingErrors.docx November 14, 2008 Page 7