Radiation by an Accelerated Charge: Scattering by Free and Bound Electrons a Θ Professor David Attwood Univ. California, Berkeley sin2Θ Radiation by an Accelerated Charge: Scattering by Free and Bound Electrons, EE290F, 25 Jan 2007 Title_Lec4_Ch02_F00.ai Maxwell’s Equations Wave Equation ) um u ac r 2) v (in apte h (C Radiation by a single electron (“dipole radiation”) Scattering cross-sections Scattering by a free electron (“Thomson scattering”) Scattering by a single bound electron (“Rayleigh scattering”) Scattering by a multi-electron atom Atomic “scattering factors”, Professor David Attwood Univ. California, Berkeley f0′ and f0′′ (in (C am ha pte ate r3 ria ) l) Refractive index with many atoms present Role of forward scattering Contributions to refractive index by bound electrons Refractive index for soft x-rays and EUV n = 1 – δ + iβ (δ, β << 1) f0′ f0′′ Determining f0′ and f0′′ ; measurements and Kramers-Kronig Total external reflection Reflectivity vs. angle Brewster’s angle Radiation by an Accelerated Charge: Scattering by Free and Bound Electrons, EE290F, 25 Jan 2007 Ch02_Eqs_1.ai Scattering, Refraction, and Reflection Single scatterer, electron or atom, in vacuum. (Chapter 2) Many atoms, each with many electrons, constituting a “material”. (Chapter 3) n = 1– 1– δδ++iβ β n=1 λ λ • How are scattering, refraction, and reflection related? • How do these differ for amorphous and ordered (crystalline) materials? • What is the role of forward scattering? Professor David Attwood Univ. California, Berkeley Radiation by an Accelerated Charge: Scattering by Free and Bound Electrons, EE290F, 25 Jan 2007 Ch02_ScatRefrReflc.ai Maxwell’s Equations and the Wave Equation Maxwell’s equations: (2.1) (2.2) (2.3) (2.4) (2.5) (2.6) The wave equation: (3.1) Professor David Attwood Univ. California, Berkeley Radiation by an Accelerated Charge: Scattering by Free and Bound Electrons, EE290F, 25 Jan 2007 Ch02_Maxwls_WavEqs.ai The Wave Equation From Maxwell’s Equations, take the curl of equation 2.2 ∇× (2.2) and use the vector identity from Appendix D.1, pg. 440, (D.7) to form the Wave Equation (2.7) where (2.8) where J(r,t) is the current density in vacuum and ρ is the charge density: (2.10) J(r,t) = qn(r,t)v(r,t) For transverse waves the Wave Equation reduces to (3.1) Professor David Attwood Univ. California, Berkeley Radiation by an Accelerated Charge: Scattering by Free and Bound Electrons, EE290F, 25 Jan 2007 Ch02_WaveEq.ai Conservation of Charge ρ Vector identity: ∇ (∇ × H) 0 (D.9) (2.9) where the current density is (2.10) Professor David Attwood Univ. California, Berkeley Radiation by an Accelerated Charge: Scattering by Free and Bound Electrons, EE290F, 25 Jan 2007 Ch02_ConsrvChrg.ai Radiated Power and Poynting’s Theorem To obtain Poynting’s Theorem, begin with Maxwell’s Equations and form the difference To obtain Use B = µ0H and D = 0E, and the vector identity ∇ (A × B) = B (∇ × A) – A (∇ × B), Eq. (D.5), to obtain Poynting’s Theorem: (2.27) S Integrating over a volume of interest and using Gauss’ Divergence Theorem one obtains the integral form of Poynting’s Theorem S Professor David Attwood Univ. California, Berkeley Radiation by an Accelerated Charge: Scattering by Free and Bound Electrons, EE290F, 25 Jan 2007 (2.28) Ch02_RadPwrPoyntgs.ai Relationships Among E, H and S for a Plane Wave in Vacuum Among E and H, take to obtain , with B = µ0H in vacuum Write E and H, in terms of Fourier representations E(r, t) = ∫∫Ekω e –i(ωt – k r) kω dωdk (2π)4 and H(r, t) = ∫∫Hkω e –i(ωt – k r) kω dωdk (2π)4 The ∇ and ∂/∂t operates on the fields become algebraic multipliers on the Fourier-Laplace coefficients Ekω and Hkω using the inverse transforms (2.29) and (2.31) with time average (one cycle) Professor David Attwood Univ. California, Berkeley (2.37 & 2.39) Radiation by an Accelerated Charge: Scattering by Free and Bound Electrons, EE290F, 25 Jan 2007 Ch02_RelatnshpsPlWv.ai Radiated Fields Due to a Current J To calculate the radiated fields we want to solve the wave equation for E in terms of J. We introduce Fourier-Laplace transform methods, to algebrize the and ∂/∂t operators, then integrate in k, ω-space. We start with the transverse wave equation: 2 ∂ – c22E(r, t) = – 1 ∂ J (r, t) ∂t2 o ∂t T In a plane wave representation E(r, t) = ∫∫Ekω e –i(ωt – k r) kω where the amplitudes are so that Ekω = ∫∫E(r, t)ei(ωt – k r,t ∂/∂t → –iω and r) dωdk (2π)4 dr dt (2.12a) (2.12b) → ik In k, ω-space, the algebrized form of the wave equation becomes (ω2 – k2c2) Professor David Attwood Univ. California, Berkeley Radiation by an Accelerated Charge: Scattering by Free and Bound Electrons, EE290F, 25 Jan 2007 Ch02_RadiatedFlds.ai Natural Modes of Oscillation (ω2 – k2c2) The electromagnetic waves that naturally propagate in this medium (vacuum) correspond to finite fields Ekω in the absence of a source, i.e., when JTkω = 0. In this case (ω2 – k2c2) Ekω = 0 =0 with solutions ω = ±kc , or fλ = c (where k = 2π/λ and ω = 2πf) Returning now to the case of interest with a finite source (2.18) which has an inverse transform (2.19) a Green’s function-like solution for E in the presence of a source term J in a frequency-wavenumber (energy-momentum) space. To perform the integrations we need a specific source function JTkω. Professor David Attwood Univ. California, Berkeley Radiation by an Accelerated Charge: Scattering by Free and Bound Electrons, EE290F, 25 Jan 2007 Ch02_NaturModeOscil.ai Current Density J Associated with an Accelerated Electron For an oscillating point charge (size << λ), e.g., a single electron δ(r) δ(x) δ(y) δ(z) (2.20) To calculate the radiated field, as in eq.(2.19), we need an expression for JTkω. Using the same Fourier-Laplace representation (2.13b) for the point source with transverse component (2.21) where VT is the component of V perpendicular to the wave’s propagation direction k0 (a unit vector). Professor David Attwood Univ. California, Berkeley Radiation by an Accelerated Charge: Scattering by Free and Bound Electrons, EE290F, 25 Jan 2007 Ch02_CurrntDensty.ai Electric Field Radiated by an Accelerated Charge Previously we determined that (2.19) Where now for an accelerated electron (2.21) Then (2.22) The k-integration can be performed in the complex k-plane using the Cauchy integral formula. The integrand is seen to have two poles, at k = ±ω/c, representing incoming and outgoing waves. The integration path can be closed in the upper half plane with a semi-circle of infinite radius, which makes no contribution to the integral. The closed path then encloses a single pole, slightly displaced from the real axis, and the k-integral is readily evaluated. Details of the integration are given in Appendix E. The result of the k-integration is r + ik e →0 for large r ki Pole at k = ω/c kr Pole at k = –ω/c (2.24) (2.25) or Professor David Attwood Univ. California, Berkeley Radiation by an Accelerated Charge: Scattering by Free and Bound Electrons, EE290F, 25 Jan 2007 Ch02_ElectrcFld.ai Power Radiated by an Accelerated Point Charge Combining (2.25) (2.31) and one obtains the instantaneous power per unit area radiated by an accelerated electron (2.32) k0, propagation direction a For an angle Θ between the direction of acceleration, a, and the observation direction, k0, the instantaneous power per unit area is t 0′ k0 Θ (2.33) t 0′′ Noting that S = (dP/dA)k0 and dA = r2 dΩ, one obtains the power per unit solid angle (a) (2.34) (b) a Θ a sin 2 Θ k0 the well known “donut-shaped” radiation pattern characteristic of a radiator whose size is much smaller than the wavelength (“dipole radiation”). Professor David Attwood Univ. California, Berkeley Radiation by an Accelerated Charge: Scattering by Free and Bound Electrons, EE290F, 25 Jan 2007 Ch02_PowrRadiatd.ai Total Power Radiated by an Accelerated Point Charge The total power radiated, P, is determined by integrating S over the area of a distant sphere: (2.35) where for 0 ≤ Θ ≤ π and 0 ≤ φ ≤ 2π we have dΩ = sin Θ dΘ dφ, thus Thus the instantaneous power radiated to all angles by an oscillating electron of acceleration a is (2.36) For sinusoidal motion, averaging over a full cycle, sin2ωt or cos2ωt, introduces a factor of 1/2 1 2 The same factor 1/2 appears in the expressions for S (eq. 2.33) and dP/dΩ (eq.2.34) for sinusoidal motion averaged over one or many cycles. Professor David Attwood Univ. California, Berkeley Radiation by an Accelerated Charge: Scattering by Free and Bound Electrons, EE290F, 25 Jan 2007 Ch02_TotalPwrRad.ai Scattering Cross-Sections Measures the ability of an object to remove particles or photons from a directed beam and send them into new directions Diminished by both scattering and absorption λ S σ Pscattered (power) area = (power/area) • Isotropic or anisotropic? • Energy or wavelength dependent? Professor David Attwood Univ. California, Berkeley Radiation by an Accelerated Charge: Scattering by Free and Bound Electrons, EE290F, 25 Jan 2007 Ch02_ScattCrSecs.ai Scattering by a Free Electron Define the cross-section as the average power radiated to all angles, divided by the average incident power per unit area (2.38) For an incident electromagnetic wave of electric field Ei(r,t) (2.39) For a free electron the incident field causes an oscillatory motion described by Newton’s second equation of motion, F = ma, where F is the Lorentz force on the electron small (2.40) Thus the instantaneous acceleration is (2.42) Professor David Attwood Univ. California, Berkeley Radiation by an Accelerated Charge: Scattering by Free and Bound Electrons, EE290F, 25 Jan 2007 Ch02_ScattFreElctrn1.ai Scattering by a Free Electron (continued) The average power scattered by an oscillating electron is The scattering cross-section is Introducing the “classical electron radius” (2.44) One obtains the scttering cross-section for a single free electron (2.45) which we observe is independent of wavelength. This is referred to as the Thomson cross-section (for a free electron), after J.J. Thomson. Numerically re = 2.82 10–13 cm and σe = 6.65 10–25 cm2. The differential Thomson scattering cross-section is (2.47) Professor David Attwood Univ. California, Berkeley Radiation by an Accelerated Charge: Scattering by Free and Bound Electrons, EE290F, 25 Jan 2007 Ch02_ScattFreElctrn2.ai Scattering by a Bound Electron For an electromagnetic wave incident upon a bound electron of resonant frequency ωs, the force equation can be written semi-classically as (2.48) with an acceleration term (ma), a damping term, a restoring force term, and the Lorentz force exerted by the fields. For an incident electric field the harmonic motion will be driven at the same frequency, ω, so that (2.49) (2.50) Following the same procedures used earlier, one obtains the scattering cross-section for a bound electron of resonant frequency, ωs (2.51) Professor David Attwood Univ. California, Berkeley Radiation by an Accelerated Charge: Scattering by Free and Bound Electrons, EE290F, 25 Jan 2007 Ch02_ScattBndElctrn.ai Semi-Classical Scattering Cross-Section for a Bound Electron (2.51) σ = σT(ωs/γ)2 Scattering cross-section, σ(ω)/σT 100 90 80 70 60 Lorentzian line shape of half width γ/2 50 2 1 0 Note that below the resonance, for ω2 << ωs2 (γ/ωs) = 10–1 (ω/ωs)4 0.5 σ = σT 1.0 1.5 2.0 Frequency ω/ωs 2.5 3.0 (2.52) This is the Rayleigh scattering cross-section (1899) for a bound electron, with ω/ωs << 1, which displays a very strong λ–4 wavelength dependence. Professor David Attwood Univ. California, Berkeley Radiation by an Accelerated Charge: Scattering by Free and Bound Electrons, EE290F, 25 Jan 2007 Ch02_SemiClassScatt.ai The sky appears blue because of the strong wave length dependence of scattering by bound electrons. Sun 4 σR ~ – σT λs λ More blue than green or red Atmosphere (O2, N2, . . .) λS ~ – 150 nm Setting sun Earthly observer • • • • • UV resonances in O2 and N2, at 8.6 and 8.2 eV Red (1.8 eV, 700 nm), green (2.3 eV, 530 nm), and blue light (3.3 eV, 380 nm) Density fluctuations essential Long path at sunset, color of clouds Photon energy and wavelength effects. Volcanic eruptions Professor David Attwood Univ. California, Berkeley Radiation by an Accelerated Charge: Scattering by Free and Bound Electrons, EE290F, 25 Jan 2007 Ch02_F09VG.ai