Application of momentum equation Hydraulic jump K141 HYAE Application of momentum eq. 1 Hydraulic jump - transition from supercritical to subcritical flow type of h.j. is given by Fr of supercritical flow presumptions:: •small longitudinal slope of channel G of water can be neglected •small length of h.j. Zt can be neglected •in both profiles (1 and 2) – hydrostatic pressure distribution F F ρQ v from momentum equation: 1 2 2 v1 F1 ρgz1S1 F2 ρgz2S 2 v1 Q Q , v2 S1 S2 K141 HYAE Zh.j. a2v22 2g EL 1 a1v1 2g 2 y1 2 z2 v1 z1 Application of momentum eq. v2 y2 2 Q Q ρgz S ρgz S ρQ 1 1 2 2 S2 S1 1 g Q2 Q2 z1S1 z 2S 2 gS1 gS2 Q2 Function of h. j.: zS y , where S f y , z f y gS y1 y 2 , where y1 and y2 ... conjugate depths of h. j.. y 0 y , y y y yk y min It can be proved that for shape of function of h. j. y a1v 2g 2 1 EL 1 Zh.j. 2 a2v22 2g y2 y1 (y) y2 Zh.j. yk Ed(y) y1 min K141 HYAE Application of momentum eq. Edmin ,Ed 3 Force effects of stream and jet K141 HYAE Application of momentum eq. 4 PRINCIPLE OF SOLUTION Change of direction or change of flow velocity application of momentum equation force effects of stream – jet on walls and pipeline fittings, on rotating (blades) of turbines and pumps, on surfaces of flowed-round solid bodies transition between supercritical and subcritical flow application for dimensioning and shape optimalization of flowed-round elements, for determination of hydraulic resistances and for calculation of capacity of hydrodynamic machines, stilling pool resolution K141 HYAE Application of momentum eq. 5 FORCE EFFECT OF STREAM ON PIPELINE (BEND, KNEEPIPE, CURVED CANAL) F1 F2 G FA Qv 2 v1 F1 – pressure force in entrance profile (F1 = p1S1) F2 – pressure force in exit profile (F2 = p2S2) G – weight of liquid Q1v1 – discharge force in entrance profile Q2v2 – discharge force in exit profile FA – force of pipe wall acting on liquid FR – reaction, force effect of liquid FR FA F1 F2 G ρQv1 v 2 K141 HYAE Application of momentum eq. 6 • vector equation - in components appropriate coordinate system • large pressures and small dimensions of pipe (canal), horizontal arrangement neglect G Horizontal arrangement of curved element: FRx F1 cos a F2 cos Qv1 cos a v 2 cos FRy F1 sin a F2 sin Qv1 sin a v 2 sin 2 2 FR FRx FRy , tg K141 HYAE Application of momentum eq. FRy FRx 7 Division and connection of flow (axis in horizontal plane) FR F1 F2 F3 F4 ρQ1v1 ρQ2v 2 ρQ3 v 3 ρQ4 v 4 FRx F1 cos a1 F2 cos a2 F3 cos a3 F4 cos a 4 Qv1 cos a1 Qv 2 cos a2 Qv 3 cos a3 Qv 4 cos a 4 FRy F1 sin a1 F2 sin a 2 F3 sin a3 F4 sin a 4 Qv1 sin a1 Qv 2 sin a 2 Qv 3 sin a3 Qv 4 sin a 4 F1 p1 S1 F2 p2 S2 F3 p3 S3 F4 p 4 S 4 FR FRx 2 FRy 2 tg K141 HYAE Application of momentum eq. FRy FRx 8 HYDRODYNAMIC FORCE ON SLIDE GATE αv 02 αv c2 h yc Z 2g 2g Q μvba 2gE y c y c εa FR F1 F2 Qv1 v 2 v1 v 0, v 2 vc 2 h F1 g b 2 yc 2 F2 g b 2 sections with paralel flow K141 HYAE 1 2 FR g b h yc 2 Qv 0 v c 2 Application of momentum eq. 9 FORCE EFFECT OF FREE JET ON SURFACES (BODIES) assumptions: axially symmetric flow round a surface (body) p1 = p2 (generally), G 0 FR Q1v1 Q2 v 2 , practically v1 v2 FR Qv1 Qv1 cos Qv11 cos losses by eddies at strike and by friction along surface change of v correction coefficient 1 FR Qv11 cos K141 HYAE Application of momentum eq. 10 In case of = 90° and sufficient dimension of surface (plate): D 4 till 6 D0 , l 2D0 cos 0 FR Qv 1 ( 0,95) v1 2 2 pmax For semi-spherical blade ( = 180° ) cos = -1 FR 2Qv1 K141 HYAE maximum FR 0,94 Application of momentum eq. 11 Note: for surface (body) moving with velocity u relative velocity: v1 – u relative discharge: Q = S1(v1 – u) for system of blades (canals) rotating with peripheral velocity u relative velocity: v1 - u discharge: Q = S1v1 K141 HYAE Application of momentum eq. 12 Pelton-turbine wheel Historical water wheels Installation of Pelton turbine with more injection nozzles K141 HYAE Application of momentum eq. 13