L-04-1-01e
Ceiling diffusers
Type DD / DDRQ / DDQ
circular and square
Contents · Application · Safety instructions ·
Realisation · Dimensions
Contents
Application
Application · Safety instructions · Realisation · Dimensions__ 2
The square ceiling diffusers and the circular ceiling
diffusers are suitable for the introduction of supply air or the
removal of extract air in the ceiling. They are available with
circular or square exterior frames. The two designs, flat (type
F) and conical (type K), differ - above all - in their free crosssection. They blow the air flat along the ceiling and therefore
can also be employed for rooms with a low height.
Realisation · Dimensions_______________________________ 3
Realisation · Dimensions · Accessories __________________ 4
Installation___________________________________________ 5
Technical Data ____________________________________ 6–15
Order details________________________________________ 16
Ceiling diffusers are suitable for:
– Installations with constant flow rates
– Installations with variable air volumes (VAV)
Safety instructions
CAUTION!
CAUTION!
Damage to the product due to improper handling.
Check the device for damage and contamination
prior to operation!
Risk of injury from sharp edges and corners, ridges
and thin-walled sheet metal parts!
–
–
Improper handling may lead to considerable material
damage of the product.
– Do not use any acid or abrasive cleaning agents.
– Adhesives from sticky tape may lead to colour
damage.
– Excessive moisture may lead to colour damage
and corrosion.
– Use only cleaning agents, greases and oils that
are expressly specified.
Proceed carefully with all work.
Wear protective gloves, safety shoes and protective
helmet.
WARNING!
Danger from incorrect use. Misuse of the product
may lead to dangerous situations.
The product must not be used:
–
–
–
in areas subject to explosion hazards;
in the open air without sufficient protection against
weather effects;
in atmospheres that may have a damaging and/or
corrosive effect on the product due to scheduled or
unscheduled chemical reactions.
Realisation
Circular with circular exterior frame type DD
Material and colour
Steel, powder-coated according to RAL 9010, matt,
25% brilliance
Damper
Sliding damper
Fixation: by means of a central screw
Type DD F
Aluminium untreated
(possibility of adjustment from below
by means of a concealed lever)
Type DD K
Dimensions
+2
2) Ød + 38 -4
Ød
T1
40
51
1)
1) Sliding damper
2) Recess
ØD
2
Type
ØD
Ød (extérieure)
T1
[mm]
[mm]
[mm]
216
152
24
266
202
26
250
316
252
48
300
366
302
60
400
466
402
84
500
566
502
108
DN
Realisation · Dimensions
150
200
DD
Type
ØD
Ød (external)
T1
[mm]
[mm]
[mm]
150
216
152
24
200
266
202
26
250
316
252
48
300
366
302
60
400
466
402
84
500
566
502
108
ND
DD
Realisation
Fixation possibility: by means of a central screw or inserted
in the ceiling construction.
Damper
Sliding damper:
Aluminium untreated
(possibility of adjustment from below
by means of a concealed lever)
Circular within square exterior ceiling plate type DDRQ
Material and colour
Steel, powder-coated according to RAL 9010, matt,
25% brilliance
Typ
Ød (aussen)
Type
DDRQ K
T1
T2
[mm]
[mm]
[mm]
150
152
24
40
200
202
26
40
252
48
40
302
60
24
402
84
24
502
108
24
A
NW
[mm]
598×
DDRQ
250
300
623×
400
598
623
500
Dimensions
Ød
8
250
300
400
24
40
202
26
252
48
302
60
24
402
84
24
502
108
24
40
40
Ød (external)
T1
T2
[mm]
[mm]
[mm]
150
152
24
40
200
202
26
40
252
48
40
302
60
24
402
84
24
502
108
24
250
300
400
500
Realisation
Square type DDQ
Material and colour
Steel, powder-coated according to RAL 9010, matt,
25% brilliance
Fixation possibility
by means of a central screw
152
A
A
ND
623×
[mm]
623
[mm]
DDRQ
T2
[mm]
598
500
598×
T1
[mm]
T2
200
623×
Type
Ød (extérieure)
150
598×
DDRQ
1) Sliding damper
A
1) [mm]
DN
51
Type
T1
Type DDRQ F
598
623
Damper
Sliding damper
Aluminium untreated
opposed blade damper Frame: Hot galvanized steel
Blades: Aluminium untreated
(possibilities of adjustment from
below by means of a concealed
lever)
3
Realisation · Dimensions · Accessories
Type DDQ F
Type DDQ K
300×200
300
202
49
400×300
400
302
71
500×400
500
402
600×500
a + 28 600
502
115
625
502
115
625×500
5
Type
DDQ
a
DDQ
93 View from below
A
[mm]
300×200
300
202
400×300
400
302
500×400
500
402
600×500
600
502
115
625
502
115
A
a (extérieure)
[mm]
A
T1
[mm]
DN
625×500
Type
a (aussen)
[mm]
49
A
DDQ
A
[mm]
35
Dimensions
T1
[mm]
NW
T1
Typ
71
93
T1
[mm]
ND
A
[mm]
300×200
300
202
49
400×300
400
302
71
500×400
500
402
93
600×500
600
502
115
625×500
625
502
115
a (external)
[mm]
Accessories
M6
50
L = 80
M6
1)
M6
1)
77
50
s =10
Threaded pipe coupling
GRM6 for type DDQ F, DD F and
for type DDQ F, DD F and DDRQ F
F
Ød DDRQ
[mm]
152
202
ForTyp
theDD
installation
/ DDRQ with the plenum
[mm]
80
50
box AKH... and the conical diffuser, C
1) builder‘s supply (p.e. duct)
longer central screws are provided.
Central screw with plastic plug
Typ
TypeDDQ
DD / DDRQ
Type DDQ
4
a
Ød
C
C
a
C
[mm]
[mm]
C
s =10
Threaded pipe coupling GRM6
for type DDQ K, DD K and DDRQ K
252
302
402
502
1)
builder‘s
supply
(p.e.
duct)
37
25
0
-22
202
202
32 50
302
252
10
37
[mm]
202
302
402
502
[mm]
32
10
-12
-34
152
[mm] [mm] 80
302
402
25 -12
402
0
502
502
-34-22
Installation
Circular with square exterior ceiling plate type DDRQ
with plenum box
Type DDRQ K
Inserted in ceiling profile from above.
Type DDRQ K
Pressed onto ceiling profile from below.
A
B
1)
1)
1) Grid dimension
Type DDRQ F
Inserted in ceiling profile from above.
NW
Rastermass
[mm]
598×...
600×600
623×...
625×625
1)
1)
1) Grid dimension
DN
Type
Dim. de la trame
A
8
~5,5
[mm]
598×...
600×600
DDRQ
623×...
625×625
Type
ND
Grid dimension
[mm]
DDRQ
B
598×...
600×600
623×...
625×625
Caisson
B de raccordement
Détails voir prospectus
L-04-1-31f (TROX HESCO) ou 2/16.4/… (TROX)
8
A
DDRQ
Anschlusskasten
Details siehe Prospekt
L-04-1-31d (TROX HESCO) oder 2/16.4/… (TROX)
~4
Typ
Type DDRQ F
Pressed onto ceiling profile from below.
Plenum box
Details see prospect
L-04-1-31e (TROX HESCO) or 2/16.4/… (TROX)
5
Technical Data
Technical documentation
1. Our data are based on a maximum difference in
temperature ∆t of -10 K between room air and supply air
temperature. The expected room air velocities are still
within the comfort range. Columns located within the
stream of air are to be protected by blocking the
corresponding sector in the diffuser.
2. In the case of systems supplying hot air, it is advisable
to locate the ceiling diffusers only up to a maximum room
height RH of 3.2 m.
Definitions
6
A
m²
Nominal area of diffuser
Aeff
m²
Effective free area
A0
m²
Nominal reference area
Ød
mm
The diffuser size for circular ceiling diffuser
a
mm
The diffuser size for square ceiling diffuser
b
mm
Width of jet for square ceiling diffuser
D
m
Distance between two ceiling diffusers
f
Hz
Octave-centre-frequencies
h0K
m
Thickness of jet (from ceiling) with isothermal air jet
h10K
m
Thickness of jet (from ceiling) with cold air stream ∆t =10 K(-)
L
m
Distance (by a final velocity of 0.5 m/s in the throw axis)
Lw
dB(A)
Sound power level
LwA0
dB(A)
Sound power level in relation to the nominal reference area Ao
∆Lw
dB
Correction "sound power level" [dB(A)] as a function of the diffuser size
∆ps
Pa
Static pressure drop
rØF
-
Ratio A"/A with circular, flat ceiling diffuser = abt. 0.33 = abt. 33%
rØK
-
Ratio A"/A with circular, conical ceiling diffuser = abt. 0.73 = abt. 73%
r F
-
Ratio A"/A with square, flat ceiling diffuser = env. 0.32 = env. 32%
r K
-
Ratio A"/A with square, conical ceiling diffuser = env. 0.575 = env. 57,5%
RH
m
Room height
veff
m/s
Effective blow-out velocity
‡
m³/h
Air flow rate
Technical Data
Minimum distances
L0.5
D
D/2
1.8 m
RH
h10K = 0.267 × L0.5
h0K = 0.133 × L0.5
0.5 m/s
D
D
D × 1.414
Minimum distances by type DD and DDRQ
D
D × 1.414
b~0.5 × L
D
D
7
70
×
0.
D
D
Minimum distances by type DDQ
D
7
Technical Data
Selection diagram – supply air
Type DD F 5
Type DDRQ F 5
Min. distance D
as a function of room height RH
[m]
0
0
70
0
80
9
00 00
10
00
12
00
16
202
252
302
402
502
∆Lw
-3
-2
-1
0
+1
+2
[dB]
1.5
14
12
[m/s]
502
[dB(A)]
[mm]
58
54
66
64
60
[dB(A)]
[dB]
[dB(A)]
402
+1
+2
62
60
56
.5
54
53
49
65
63
58
56
52
46
0
10
9
8
7
6
42
-1
50
47
45
39
36
33
30
26
42
-2
48
45
42
-3
302
252
34
202
35
152
38
3
∆Lw
3.5
[Pa]
30
28
25
24
22
22
0
20
<2 <
0
Ød
<2
[Pa]
1)
5
4.5
4
2
1.8
1.6
1.4
1
2.5
Correction 'niveau de puissance acoustique'
en fonction de la dimensiondu diffuseur
1.2
Sound power level Lw, type F 5 100%, Ød = 302 mm
∆ps = 2.45 × ∆ps0
avec F 5 - 50% ouvert
Sound power level Lw, type F 5 1) 50%, Ød = 302 mm
∆ps0 = perte de charge statique sans clapet de réglage
[mm]
00
152
20
[Pa]
502
Sound
power
level
Lw, type∆p
F 0s 1) =
Ød 1.32
= 302 ×
mm∆p
avec F 5
- 100%
ouvert
s0
60
0
0
Ød
2
302
[m]
0
6 7 8 9 10
5
50
4
40
80
90
Static pressure ∆ps (Type 0) [Pa]
3
2
Air flow rate ‡ [m³/h]
[Pa]
3
Ød [mm]
15
6 7 8 9 10
5
0
330
300
250
22
0
15
0
12
93
72
51
252
402
Correction 'pertes de charge'
Blow out velocity veff
15
4
∆ps0 = statische Druckdifferenz ohne Drosselelement
6 7 8 9 10
5
Korrektur 'Schallleistung' in Abhängigkeit der Durchlassgrösse
5
2.45 × ∆ps0
6
=
202
15
9
∆ps
mit F 5 - 50% offen
1.32 × ∆ps0
7 8 9 10
13
=
6
15
18
∆ps
mit F 5 - 100% offen
36
29 24
152
Korrektur 'Druckabfall'
5
4
1.5
1
7 8 9 10
0
0.5
6
4
3
2
5
4
3
2
1.5
1
3.76 - 4.50
Distance to a final velocity of 0.5 m/s = L0.5
1.5
1
3.21 - 3.75
eff. free cross section: ~33%
3
2
15
35
1.5
2.81 - 3.20
4
7 8 9 10
0
L0.5
3
2
6
5
4
30
1.5
2.51 - 2.80
3
2
25
1.5
2.25 - 2.50
18
200
0
�ps
0
[m]
0
16
0
Room
height RH
14
Ød
0
flat
Type DDRQ F 0
12
Type DD F 0
10
1) Data applicable for: supply air straight introduced, flat double ceiling; F 0 = flat without damper; F5 = flat with sliding damper
Corrections
Correction 'sound power level' as a function of the diffuser size
Correction 'pressure drop'
with F 5 - 100% open
∆ps
=
1.32 × ∆ps0
[Pa]
Ød
152
202
252
302
402
502
[mm]
with F 5 - 50% open
∆ps
=
2.45 × ∆ps0
[Pa]
∆Lw
-3
-2
-1
0
+1
+2
[dB]
∆ps0 = static pressure drop without damper
Example
givenType
RH =
D =
‡ =
8
DD F 5 (with sliding damper 100% open)
3.0 m
2.4 m
250 m³/h
SolutionØd
= 302 mm
veff = 3.0 m/s
∆ps= 13 × 1.32 = 17 Pa
Lw = 39 dB(A)
L0.5= 1.1 m
Technical Data
Selection diagram – supply air
Type DD K 0
Type DDRQ K 0
conical
Type DD K 5
Type DDRQ K 5
Room
height RH
[m]
[m]
12
0
40
450
0
50
0
10
60
0
70
0
10 9 80
20 18 16 14 12
00 00 0
00 00 00 00 00
202
252
302
402
502
�Lw
-3
-2
-1
0
+1
+2
[mm]
[dB]
40
302
00
152
25
Ød
3
3
00 500 000
Static pressure �ps (Type 0) [Pa]
[Pa]
Air flow rate ‡ [m³/h]
Ød [mm]
60
50
16
23
�ps0 = statische Druckdifferenz ohne Drosselelement
252
11
9
7
2.45 × �ps0
4
=
[m]
Korrektur 'Schallleistung' in Abhängigkeit der Durchlassgrösse
0.
�ps
[Pa]
6
mit K 5 - 50% offen
0.
1.32 × �ps0 202
5 2 2
0
1. 1. 1. 1.
=
5
�ps
6 7 8 9 10
5
4
15
2.
mit K 5 - 100% offen
5
6
3.
152
Korrektur 'Druckabfall'
3
2
38
30
0
1.5
15
6 7 8 910
0
1
0.5
5
4
35
Distance to a final velocity of 0.5 m/s = L0.5
3
2
1.5
15
6 7 8 9 10
5
0
1
3.76 - 4.50
15
6 7 8 9 10
30
eff. free cross section: ~73%
4
15
6 7 8 9 10
5
4
3
2
1.5
3.21 - 3.75
3
2
1.5
2.81 - 3.20
5
4
25
L
3
2
0
18
0
20
0
1.5
2.51 - 2.80
6 7 8 9 10
5
4
16
2.25 - 2.50
3
2
0
1.5
0
�ps
Min. distance D
as a function of room height RH
14
Ød
402
6
11
10
9
8
7
[dB(A)]
[dB]
[dB(A)]
502
+2
69
67
65
62
58
53
47
42
38
34
30
[dB(A)]
[mm]
67
63
+1
[m/s]
44
40
0
58
55
52
48
44
35
33
30
38
-1
402
27
20
-2
302
24
34
32
28
25
-3
252
5
4.5
4
4.5
3
202
20
0
�Lw
152
<2
[Pa]
0
<20
<2
0
<2
0
<2
0
<2
0
Ød
<2
Sound power level Lw, type K 5 100%, Ød = 302 mm
�ps = 2.45 × �ps0
avec K 5 - 50% ouvert
Sound power level Lw, type K 5 1) 50%, Ød = 302 mm
�ps0 = perte de charge statique sans clapet de réglage
[Pa]
1)
2.5
1
Sound
level
Lw, type�p
K s0 1) =Ød 1.32
= 302 ×mm
�ps0
avec K power
5 - 100%
ouvert
2
1.8
1.5
1.4
Correction 'niveau de puissance acoustique'
en fonction de la dimensiondu diffuseur
502
1.2
Correction 'pertes de charge'
Blow out velocity veff
1) Data applicable for: supply air straight introduced, flat double ceiling; K 0 = conical without damper; K 5 = conical with sliding damper
Corrections
Correction 'sound power level' as a function of the diffuser size
Correction 'pressure drop'
with K 5 - 100% open
�ps
=
1.32 × �ps0
[Pa]
Ød
152
202
252
302
402
502
[mm]
with K 5 - 50% open
�ps
=
2.45 × �ps0
[Pa]
�Lw
-3
-2
-1
0
+1
+2
[dB]
�ps0 = static pressure drop without damper
Example
givenType DD K 0 (with sliding damper 100% open)
RH = 2.3 m
D = 2.2 m
‡ = 160 m³/h
SolutionØd = 152 mm
veff = 3.0 m/s
∆ps= 4 Pa
Lw = 24 - 3 = 21 dB(A)
L0.5= 0.85 m
9
Technical Data
Selection diagram – supply air
Type DDQ F 0
flat
Type DDQ F 6
Room
height RH
[m]
[m]
Distance to a final velocity of 0.5 m/s = L0.5
3
0.8
3
2
1.5
5
4
1.5
1
100
0.5 0.6
4
7 8 9 10
6
7 8 9 10
5
6
15
7 8 9 10
2.5 3
2
15
6 7 8 9 10
5
4
[m]
0
120
140
Korrektur 'Schallleistung' in Abhängigkeit der Durchlassgrösse
mit F 6 - 100% offen
�ps
=
1.10 × �ps0
[Pa]
a
mit F 6 - 50% offen
�ps
=
1.50 × �ps0
[Pa]
�Lw
202×202
302×302
402×402
502×502
-1
0
+1
+2
[mm]
[dB]
�ps0 = statische Druckdifferenz ohne Drosselelement
Correction 'pertes de charge'
250
0
302×302
200 180 160
0
0
0
Static pressure �ps (Type 0) [Pa]
Korrektur 'Druckabfall'
a [mm]
202×202
Air flow rate ‡ [m³/h]
0
0
12
90
68
45
3
30
24
16
12
7
800
100 900
0
1
3.76 - 4.50
6
15
600
700
eff. free cross section: ~32%
7 8 910
6
5
4
2
1.5
3.21 - 3.75
3
2
15
500
1.5
2.81 - 3.20
5
4
7 8 9 10
400
450
L
3
2
6
350
1.5
2.51 - 2.80
5
4
300
2.25 - 2.50
3
2
250
1.5
180
180
�ps
Min. distance D
as a function of room height RH
140
160
a
120
402×402
6
10
9
8
7
5
4.5
4
3.5
3
2.5
+1
+2
[m/s]
[mm]
[dB(A)]
54
502×502
52
48
46
44
41
33
402×402
37
55
53
49
47
45
42
35
39
57
55
51
49
47
44
41
37
32
30
27
23
<20
1) 50%,
F 6clapet
a = 302×302 mm
power
level statique
Lw, type
�Sound
ps0 = perte
de charge
sans
de réglage
0
30
27
24
21
<20
-1
302×302
28
25
22
<20
�Lw
202×202
<20
Sound
power
level
Lw, type �p
F 6 1) =
100%,
302×302 mm
1.50 a× = �p
avec F 6
- 50%
ouvert
[Pa]
s
s0
2
1.8
1.6
1.4
a
1
[Pa]
1.2
× �psmm
avec F 6
- 100%
ouvert
0
Sound
power
level
Lw, type �p
F 0s 1) = a1.10
= 302×302
0.6
Blow out velocity veff
0.8
Correction 'niveau de puissance acoustique'
en fonction de la dimensiondu diffuseur
502×502×600
502×502×625
[dB(A)]
[dB]
[dB(A)]
1) Data applicable for: supply air straight introduced, flat double ceiling; F 0 = flat without damper; F 6= flat with sliding damper
Corrections
Correction 'sound power level' as a function of the diffuser size
Correction 'pressure drop'
with F 6 - 100% open
�ps
=
1.10 × �ps0
[Pa]
a
with F 6 - 50% open
�ps
=
1.50 × �ps0
[Pa]
�Lw
202×202
302×302
402×402
502×502
[mm]
-1
0
+1
+2
[dB]
�ps0 = static pressure drop without damper
Example
givenTypeDDQ F 6 (with opposed blade damper
100% open)
RH = 3.0 m
D = 5.0 m
‡ = 560 m³/h
10
Solution
a = 402×402 mm
veff = 3.0 m/s
∆ps = 16 × 1.1 = 18 Pa
Lw = 39 + 1 = 40 dB(A)
L0.5= 2.2 m
Technical Data
Selection diagram – supply air
Room
height RH
[m]
�ps
Min. distance D
as a function of room height RH
[m]
2.25 - 2.50
L
eff. free cross section: ~57.5%
1
1.5
0.5 0.6
0.8
3.76 - 4.50
5
6 7 8 910
4
1
5
4
15
250
15
6 7 8 910
2 2.5 3
1.5
15
6 7 8 9 10
5
140
160
180
200
Distance to a final velocity of 0.5 m/s = L0.5
7 8 9 10
3
2
15
5 6
4
3
2
1.5
3.21 - 3.75
6 7 8 9 10
4
3
2
1.5
2.81 - 3.20
5
4
3
2
1.5
2.51 - 2.80
3
2
1.5
[m]
6 7 8 9 10
5
4
15
�ps
=
5.60 × �ps0
160
0
140
0
mit K 6 - 50% offen
1.15 ×302×302
�ps0
200 180
0
0
=
[Pa]
a
[Pa]
�Lw
202×202
302×302
402×402
502×502
-1
0
+1
+2
[dB]
300
0
�ps0 = statische Druckdifferenz ohne Drosselelement 402×402
502×502×600
502×502×625
7
6
5
4.5
4
[m/s]
37
38
36
34
[dB(A)]
[dB]
[dB(A)]
502×502
30
52
50
47
+2
44
40
36
[dB(A)]
[mm]
34
32
28
23
27
+1
31
28
25
23
0
21
<2
0
25
402×402
0
<2
0
<2
0
<2
0
<2
0
0
<2
<2
-1
302×302
21
0
202×202
3.5
3
0
<2
0
<2
0
<2
0
<2
0
<2
<2
�Lw
2.5
2
1.8
1.6
1.4
1
a
1.2
Sound power level Lw, type K 0 1)
a = 302×302 mm
�ps = 1.15 × �ps0
avec K 6 - 100% ouvert
[Pa]
Sound power level Lw, type K 6 1) 100%, a = 302×302 mm
�ps = 5.60 × �ps0
avec K 6 - 50% ouvert
[Pa]
Sound power level Lw, type K 6 1) 50%, a = 302×302 mm
�1)ps0 = perte de charge statique sans clapet de réglage
0.8
Correction 'niveau de puissance acoustique'
en fonction de la dimensiondu diffuseur
0.6
Correction 'pertes de charge'
Blow out velocity veff
[mm]
0
�ps
Korrektur 'Schallleistung' in Abhängigkeit der Durchlassgrösse
250
mit K 6 - 100% offen
a [mm]
Korrektur 'Druckabfall'
Static pressure �ps (Type 0) [Pa]
202×202
Air flow rate ‡ [m³/h]
28
20
5
11.
9.5
7
5
3.8
2.8
1.6
120
0
800
900
100
0
a
600
700
Type DDQ K 6
400
450
500
conical
350
Type DDQ K 0
300
Data applicable for: supply air straight introduced, flat double ceiling; K 0 = conical without damper; K 6= conical with sliding damper
Corrections
Correction 'sound power level' as a function of the diffuser size
Correction 'pressure drop'
with K 6 - 100% open
�ps
=
1.15
× �ps0
[Pa]
a
with K 6 - 50% open
�ps
=
5.60
× �ps0
[Pa]
�Lw
202×202
302×302
402×402
502×502
[mm]
-1
0
+1
+2
[dB]
�ps0 = static pressure drop without damper
Example
given
Type
DDQ K 6 (with opposed blade damper
100% open)
RH = 3.0 m
D = 5.8 m
‡ = 560 m³/h
a = 302×302 mm
veff = 3.0 m/s
∆ps = 3.8 × 1.15 = 5 Pa
Lw = 27 dB(A)
L0.5= 2.7 m
Solution
11
conique
DDQ
DDRQ
100, 75 und 50%
100,offen
75, 50 et
[dB]
DD
K 0K 0
DDQ
DDRQ
DDQ KK60
+4
+1
+6
-1
-2
-3
-5
-5
+2
-6
+4
-4
0
-7
-5
-3
-5
-7
-8
-13
< (-22)
< (-20)
125
125
250
500
500
1k
1k
2k
2k
4k
4k
8k
8k
0
-2
+2
+1
-3
0
-7
-6
-14
-12
< -20
(-20) << (-20)
(-22)
-2
+4
+4
+6
-2
-7
-5
-9
-12
(-20)
< -11
(-20) << (-20)
+1
-1
-3
-5
-4
-7
-3
-7
-13
< (-20)
+2
+4
0
-5
-5
-8
< (-22)
125
250
500
2k
4k
8k
DDQ F 0
DDQ F 6
0
+2
-3
-7
-14
< (-20) < (-20)
DDQ K 0
DDQ K 6
+4
+6
-2
-5
-12
< (-20) < (-20)
DD K 6
-6
-4
-7
-3
-7
DD K 5
DDRQ K 5
25% ouvert
25% offen
DD K 6
±4 [dB]
Tolérances des corrections d'octave:
±4 [dB]
Toleranzen der Oktav-Korrekturen:
Technical Data
< -12
(-11) << (-20)
(-18) << (-20)
(-22)
Correction table for the octave centre frequencies
Type
Type
Position du clapet
Damper
position
de réglage
flat
plat
DD
100,7575,
5050%
et
100,
and
25%
ouvert
open
f
Type
Type
DD F 0
DDRQ F 0
DDQ F 0
DDQ
DD
F 5F 6
DDRQ F 5
conique
DD F 5
DDQ KF05
DDRQ
DDQ K 6
DDQ
100,conical
75 et 50%
DD
K0
ouvert
DDRQ K 0
25% ouvert
DD K 6
DDRQ
DD K 5
100, 75, 50 and
DDRQ K 5
25% open
±4 [dB]
Tolérances des corrections
d'octave:
25% open
Tolerances of the octave corrections:
Type
Damper position
-6
[Hz]
[dB]
[dB]
< (-11) < (-18) < (-22)
±4 [dB]
f
Type
1k
[Hz]
flat
100, 75, 50 and
25% open
conical
DDQ
100, 75 and 50%
open
25% open
Tolerances of the octave corrections:
-13
[dB]
< (-20)
±4 [dB]
Example
Given
Example from page 8, (DD F 5, 100% open, instead of
Ød = 302 mm Ød = 402 mm mm is selected)
Solution
Sought
Level of the octave centre frequencies
Step 1:
Make size correction, i.e.:
Lw = Lw Ød 302 mm = 39 db(A)
correction for Ød 402 mm = +1
Lw = 39 + 1 = 40 dB(A)
Step 2:
Calculate level of the octave centre frequencies
f
125
250
500
1k
2k
4k
8k
[Hz]
40
40
40
40
40
40
40
[dB(A)]
�LA
-2
+1
0
-6
-12
-20
< (-22)
[dB]
LwOkt
38
41
40
34
28
20
< 18
[dB]
LwA
12
Ød = 402 mm
DD
DDRQ
152
AKH08 ZL-Ø160
0.97
2.7
1.12
2.7
202
AKH09 ZL-Ø160
1.00
2.8
1.50
3.6
252
AKH01 ZL-Ø160
1.09
3.1
2.01
5.1
302
AKH02 ZL-Ø200
1.09
3.1
1.89
4.6
402
AKH03 ZL-Ø200
1.21
4.4
2.63
8.4
502
AKH04 ZL-Ø250
1.27
4.2
2.52
7.3
DD / DDRQ
1. Supply air with plenum box
AnschlussPlenum box
kasten
Typ
Type
DD
DD
DDRQ
DDRQ
ØdØd
Typ
Type
Technical Data
flach
DD / DDRQ
flat
F0
DD K / DDRQ K
konisch
DD K / DDRQ K
F 5 – 100%
fLww
�L
f�pf�p
�Lw
s
conical
f�p
fL s
w
K0
F 5 – 50%
�Lw
K 5 – 100%
K 5 – 50%
f�ps
�Lw
f�ps
�Lw
f�ps
�Lw
f�ps
f�p
152
152
AKH08
AL-Ø160 0.97
AKH08
ZL-Ø160
–5
1.10
–7
2.7
1.12
1.60
– 7 2.71.80
+9
6.00
–5
11.00
–8
29.00
202
202
AKH09
AL-Ø160 1.00
–3
AKH09
ZL-Ø160
1.40
2.8 – 5
1.85
1.50
– 5 3.62.10
+ 10
6.10
–4
11.20
–6
29.40
252
252
AKH01
ZL-Ø160
AKH01
AL-Ø160 1.09
+3
1.70
3.1 – 2
2.13
2.01
– 2 5.12.40
+ 11
6.10
–3
11.45
0
29.60
302
302
AKH02
ZL-Ø200
AKH02
AL-Ø200 1.09
+7
3.1
2.20
0
1.89
2.45
– 1 4.62.80
+ 12
6.15
–3
11.60 + 3
33.60
402
402
AKH03
ZL-Ø200
AKH03
AL-Ø200 1.21
+9
4.4
3.30
0
2.63
3.45
+ 4 8.44.55
+ 21 17.75
+8
22.00 + 8
40.40
502
AKH04 ZL-Ø250
2.52
7.3
+ 22 17.50
+ 10 19.50 + 10 40.40
502
AKH04 AL-Ø250
1.27
+8
4.2
2.10
–1
2.40
+1
2.95
Note: With DDRQ and DDRQ K a plenum box up to size AKH04 can be selected.
DD / DDRQ
DD K / DDRQ K
Example
Solution from diagram page 9conique
Given
plat
Caisson de
a) L = 20 dB(A)
– Supply air
F0
K0
F 5 – 100%w F 5 – 50%
K 5 – 100% K 5 – 50%
raccordement
correction for AKH04 ZL: fLw = 2.52
– DDRQ K 0 / 623x500 with
AKH04 ZL..., 1 x Ø 248 mm
20wx 2.52
– vType
f�ps= 50
�LdB(A)
f�ps �Lw f�ps �Lw f�ps
�Lw f�ps �Lw f�psLw =�L
Type
w
eff = 2.5 m/s Ød
Sought
a) Lw
b) ∆p
s
DD
DDRQ
152
AKH08 AL-Ø160
–5
1.10
–7
= ? 202
=?
252
AKH09 AL-Ø160
–3
1.40
–5
AKH01 AL-Ø160
+3
1.70
–2
302
AKH02 AL-Ø200
+7
2.20
0
2.45
–1
2.80
+ 12
6.15
–3
11.60 + 3
33.60
402
AKH03 AL-Ø200
+9
3.30
0
3.45
+4
4.55
+ 21 17.75
+8
22.00 + 8
40.40
502
AKH04 AL-Ø250
+8
2.10
–1
2.40
+1
2.95
+ 22 17.50
+ 10 19.50 + 10 40.40
1.60
7 Pa
1.80
+ 9 6.00
– 5 11.00
b)
∆ps =– 2.5
correction
for AKH04
f∆ps = –7.3
1.85
– 5 2.10
+ 10ZL:6.10
4 11.20
∆ps = 2.5 × 7.3 = 18 Pa
2.13
– 2 2.40 + 11 6.10
– 3 11.45
–8
29.00
–6
29.40
0
29.60
2. Extract air with plenum box
DD / DDRQ
Ød
DD
DDRQ
Type
conical
flat
Plenum box
Type
DD K / DDRQ K
F0
F 5 – 100%
F 5 – 50%
K0
K 5 – 100%
K 5 – 50%
�Lw
f�ps
�Lw
f�ps
�Lw
f�ps
�Lw
f�ps
�Lw
f�ps
�Lw
f�ps
152
AKH08 AL-Ø160
–5
1.10
–7
1.60
–7
1.80
+9
6.00
–5
11.00
–8
29.00
202
AKH09 AL-Ø160
–3
1.40
–5
1.85
–5
2.10
+ 10
6.10
–4
11.20
–6
29.40
252
AKH01 AL-Ø160
+3
1.70
–2
2.13
–2
2.40
+ 11
6.10
–3
11.45
0
29.60
302
AKH02 AL-Ø200
+7
2.20
0
2.45
–1
2.80
+ 12
6.15
–3
11.60 + 3
33.60
402
AKH03 AL-Ø200
+9
3.30
0
3.45
+4
4.55
+ 21 17.75
+8
22.00 + 8
40.40
502
AKH04 AL-Ø250
+8
2.10
–1
2.40
+1
2.95
+ 22 17.50
+ 10 19.50 + 10 40.40
Note: With DDRQ and DDRQ K a plenum box up to size AKH04 can be selected.
Example
Given
– Extract air
– DDRQ K 5 / 598x200 (with sliding damper 100% open)
with AKH09 AL, 1 x Ø 160 mm
– veff = 3.0 m/s
Sought
a) Lw
b) ∆ps
=?
=?
Solution from diagram page 9
a) Lw = 44 dB(A)
correction for AKH09 AL: ∆Lw = -4
Lw = 44 – 4 = 40 dB(A)
b) ∆ps = 3.6 Pa
correction for AKH09 AL: f∆ps = 11.2
∆ps = 3.6 × 11.2 = 40 Pa
13
Technical Data
F0
Type
conique
plat
F 5 – 100%
Ød
�Lw
f�ps
�Lw
f�ps
�Lw
152
-14
1.10
-10
2.00
-7
2.25
-5
2.85
+2
3. Extract air without plenum box
Correction table for circular ceiling diffusers
202
-12
1.15
-8
DD
252 exterior
-5frames
1.20Type -5
Circular with circular
DD
K0
F 5 – 50%
K 5 – 100%
K 5 – 50%
f�ps
�Lw f�ps
�Lw
f�ps �Lw f�ps
Extract
air (only
diffusers with
and without
damper)
7.50
-11
3.30
-8
3.80
-7
8.10
8.10
-9
3.55
-6
4.05
-5
8.40
Basis:
Diagram
values
of
DD-dimensions
(supply
air)
2.55
-3.5
8.95
-4
3.85 -3.5
4.35
-3
8.95
a) Sound power level
LwA AL = LwA ZL + ∆Lw
Circular within square
DDRQ -2 b)9.70
302 exterior
+1 ceiling
1.25plate-3Type2.85
+1
4.25
Static pressure
drop: -2∆psAL 5.00
= ∆psZL ×-1f∆ps 9.50
DDRQ
402
+6
1.35
-1
3.1
0
10.55
+6
5.00
0
5.30
+1
10.35
502
+7
1.60
+1
10.40
+7
6.15
+1
6.65
+2
10.35
Extract air
conical
flat
Type
Typ
DD
DDRQ
DDQ
Ød
152
a
202
202
252
302
302
402
402
502
502
F0
F 5 – 100%
�L
f�ps
w
Anschlusskasten
-14
1.10
�Lflach
w f�ps
�Lw
-10
-7
7.50
-11
f�p
fLw
-5
8.10
-9
2.8
1.71
-3.5
8.95
-4
3.1
2.17
-2
9.70
+1
3.6
2.95
0
10.55
+6
3.8
2.93
+2
10.40
+7
Typ
-12
1.15
AKH09 ZL-Ø160
-5
1.20
AKH02 ZL-Ø200
+1
1.25
AKH03 ZL-Ø200
+6
1.35
AKH04 ZL-Ø250
+7
1.60
-8
-5
-3
-1
+1
2.00
fLw
2.25
1.05
2.55
1.11
2.85
1.24
3.1
1.34
2.85
Example
Given
– Extract air
– DD F 5 / 300 (with sliding damper
Caisson50%
de open)plat
– veff = 2.0 m/s
raccordement
a
fLw
Type
Type
Sought
AKH09 ZL-Ø160
1.05
202
a)Lw = ?
b) ∆ps = ?
AKH02 ZL-Ø200
1.11
302
DDQ
K0
F 5 – 50%
f�ps konisch
�Lw f�ps
3.30
3.55
3.85
4.25
5.00
6.15
K 5 – 100%
K 5 – 50%
�Lw
f�ps
�Lw
-8
3.80
-7
8.10
4.05
-5
8.40
4.35
-3
8.95
5.00
-1
9.50
5.30
+1
10.35
6.65
+2
10.35
f�p
-6
3.9
-3.5
5.3
-2
7.4
0
7.2
+1
Solution from diagram page 8
a) Lw = 36 dB(A)
correction
for AKH... AL: ∆Lw = -2
conique
Lw = 36 – 2 = 34 dB(A)
f�p
fL
f�p
b) ∆ps = 6wPa
2.8 correction
1.71 for AKH...
3.9AL: f∆ps = 9.70
∆ps = 6 × 9.70 = 58 Pa
3.1
2.17
5.3
402
AKH03 ZL-Ø200
1.24
3.6
2.95
7.4
502
AKH04 ZL-Ø250
1.34
3.8
2.93
7.2
1. Supply air with plenum box
Plenum box
a
Type
DDQ
Type
flat
conical
fLw
f�p
fLw
f�p
202
AKH09 ZL-Ø160
1.05
2.8
1.71
3.9
302
AKH02 ZL-Ø200
1.11
3.1
2.17
5.3
402
AKH03 ZL-Ø200
1.24
3.6
2.95
7.4
502
AKH04 ZL-Ø250
1.34
3.8
2.93
7.2
Example
Given
– Supply air
– DDQ F 0 / 300×200 with AKH09 ZL..., 1 x Ø 160 mm
–veff = 3.5 m/s
Solution from diagram page 10
a) Lw = 41 dB(A)
correction for AKH09 ZL: fLw = 1.05
Lw = 41 x 1.05 = 43 dB(A)
Sought
?
a)Lw=
b) ∆ps =?
b) ∆ps = 24 Pa
correction for AKH09 ZL: f∆ps = 2.8
∆ps = 24 x 2.8 = 67 Pa
14
f�ps
raccordement
DDQ
f�ps
�Lw
f�ps
�Lw
f�ps
�Lw
f�ps
– 18
0.90
+3
3.80
+2
3.80
– 10
5.90
1.30
–8
1.43
+4
3.80
+3
3.80
–9
5.60
–3
2.55
–6
0.78
+ 21
23.0
+ 12
26.0
+ 17
54.0
–2
1.75
–5
1.95
+ 23
22.0
+ 15
32.0
+ 20
54.0
Type
�Lw
f�ps
�Lw
f�ps
202
AKH09 AL-Ø160
– 17
0.85
– 17
0.85
302
AKH02 AL-Ø200
–6
1.35
–6
402
AKH03 AL-Ø200
–3
2.60
502
AKH04 AL-Ø250
–2
1.85
a
Type
�Lw
Technical Data
2. Extract air with plenum box
flat
Plenum box
Sought
a)Lw
b) ∆ps
f�ps
�Lw
f�ps
�Lw
f�ps
– 18
0.90
+3
3.80
+2
3.80
– 10
5.90
1.30
–8
1.43
+4
3.80
+3
3.80
–9
5.60
–3
2.55
–6
0.78
+ 21
23.0
+ 12
26.0
+ 17
54.0
–2
1.75
–5
1.95
+ 23
22.0
+ 15
32.0
+ 20
54.0
�Lw
f�ps
202
AKH09 AL-Ø160
– 17
0.85
– 17
0.85
302
AKH02 AL-Ø200
–6
1.35
–6
402
AKH03 AL-Ø200
–3
2.60
502
AKH04 AL-Ø250
–2
1.85
< (-10) 0.85
< (-10) 0.85
K 6 – 50%
�Lw
f�ps
202
=?
=302
?
K 6 – 100%
f�ps
�Lw
Example
flach
Given
– Extract air
– DDQ K 0 / 300×200 with AKH04
mm
F 0AL..., 1 xF Ø
6 160
– 100%
–veff = 3.0 m/s
f�ps �Lw
Typ
�Lw
f�ps
a
K0
F 6 – 50%
F 6 – 100%
Type
a
Type
DDQ
F0
conical
�Lw
konisch
Solution from diagram
page 11
a) Lw = 25 dB(A)
F 6 –50%
for0AKH09 AL:
correction K
K 6 ∆L
– 100%
w = +3 K 6 – 50%
Lw = 25 + 3 = 28 dB(A)
f�ps �Lw
�Lw
f�ps �Lw
f�ps
f�ps �Lw
Pa 1.50
∆ps =<3.8
< (-10) b) 0.90
(-10)
-3
1.45
-9
correction for AKH09 AL: f∆ps = 3.8
-8 1.13
(-10)
1.60
-8
∆ps =<3.8
x 3.81.70
= 15 Pa-2
1.95
-5
1.05
-5
1.0
-2
1.30
-5
1.20
-6
1.28 < (-10)
1.90
0
1.85
-6
3.65
502 plenum
-1 box
1.30
3. Extract air without
-4
1.20
-5
1.28 < (-10)
1.90
+4
1.85
0
3.65
DDQ
402
2.80
Correction table for square ceiling diffusers
plat
Square Type DDQ
F0
a
Type
202
�Lw
F 6 – 100%
f�ps
< (-10) 0.85
�Lw
f�ps
< (-10) 0.85
-5
1.05
-5
1.0
302
Extract air (only diffusers with and without dampers)
402
-2
1.30
-5
1.20
DDQ
502
-1
1.30
-4
1.20
conique
Base:
F 6 –Diagram
50%
K 6 air)
– 50%
K of
0 DDQ - K
6 – 100% (supply
values
dimensions
LwA AL = LwA ZL + ∆Lw
a) Sound power level
�Lw
f�ps �Lw
�Lw
f�ps �Lw
f�ps
b) Static
pressure drop:
∆psAL =f�p
∆pssZL × f∆ps
< (-10) 0.90 < (-10) 1.50
-3
1.45
-9
1.95
-8
1.13 < (-10)
1.70
-2
1.60
-8
2.80
-6
1.28 < (-10)
1.90
0
1.85
-6
3.65
-5
1.28 < (-10)
1.90
+4
1.85
0
3.65
Extract air without plenum box
conical
flat
F0
a
Type
202
DDQ
�Lw
F 6 – 100%
f�ps
< (-10) 0.85
�Lw
f�ps
< (-10) 0.85
�Lw
f�ps
K 6 – 100%
K 6 – 50%
f�ps
�Lw
f�ps
�Lw
f�ps
K0
�Lw
< (-10)
0.90 < (-10)
1.50
-3
1.45
-9
1.95
302
-5
1.05
-5
1.0
-8
1.13 < (-10)
1.70
-2
1.60
-8
2.80
402
-2
1.30
-5
1.20
-6
1.28 < (-10)
1.90
0
1.85
-6
3.65
502
-1
1.30
-4
1.20
-5
1.28 < (-10)
1.90
+4
1.85
0
3.65
Example
Given
– Extract air
– DDQ K 6 / 400×300 (with opposed blade damper
100% open)
–veff = 3 m/s
Sought
a)Lw = b) ∆ps =
F 6 – 50%
?
?
Solution from diagram page 11
a) Lw = 27 dB(A)
correction for AKH... AL: ∆Lw = -2
Lw = 27 – 2 = 25 dB(A)
b) ∆ps = 3.8 Pa
correction for AKH... AL: f∆ps = 1.60
∆ps = 3.8 x 1.60 = 6 Pa
15
Order details
Order codes
No details for standard products
DDQ
F
6
/
... × ...
/
0
/
0
/
P1
/
RAL 9006
RAL 9006 matt,
25% brilliance
Type
Ceiling diffuser
DD
=circular
DDRQ = circular/square
DDQ =square
Nominal dimension
= diameter for Type DD
....
...×... = external dimension ×
nominal dim. for
Type DDRQ + DDQ
F =flat
K=conical
0 =without damper
5 =with sliding damper
(DD + DDRQ)
6 =with opposed blade damper (DDQ)
0 = powder coated according to
RAL 9010 mat, 25% brilliance
(standard)
P1 = powder coated according to
RAL .... (other RAL colours and
brilliance on request)
Order examples
15 off
DDQ F 0 / 500×400 / P1 / RAL 9006
20 off
DDQ K 6 / 600x500
15 off
DD F 5 / 500 / P1 / RAL 9006
20 off
DDRQ K 5 / 623×400
Type DD / DDRQ
Circular ceiling diffusers with or without square exterior
frames for installation flush with the ceiling and uniform,
circular air circulation. Comprising conical circular blades
and flat exterior frames flush with the ceiling. Flat or conical
design. With or without sliding damper for air volume control.
Fixation by means of central screw.
Type DDQ
Square ceiling diffusers, blowing on all four sides, suitable for
the horizontal introduction of air (or the removal of extract air).
Flat or conical design.
Comprising a front frame with plastic foam sealing and
suitably-formed air-guidance blades. With or without
opposed volume control (opposed blade damper). Fixation by
means of central screw.
Plenum box for type DD / DDRQ and DDQ
(see prospect L-04-1-31e)
A standard plenum box of galvanised steel, with integrated
cross bar for the M6 central screw, for quick and simple
installation of the ceiling panel air diffuser. A connection with
volume control for connecting a spiral tube or hose is included; the inlet box also contains an air distributor element.
16
Material
Diffuser
Steel, powder-coated according to RAL 9010, matt,
25% brilliance
Damper
Sliding damper
Aluminium untreated
Opposed blade damper
Frame: Hot galvanized steel
Blades: Aluminium untreated
Plenum box
– Galvanised steel plate
– Please note: deliveries with AKH ZL MO and
AK1 ZL MO are without opposed blade damper.
Option
– Other RAL-colours
We reserve the right to make design and shade of colour changes (07/2015)
Text for tendering purposes