Applying Classical Beam Theory to Twisted Cantilever Beams and Comparing to the Results of FEA by Mitchell S. King An Engineering Project Submitted to the Graduate Faculty of Rensselaer Polytechnic Institute in Partial Fulfillment of the Requirements for the degree of MASTER OF ENGINEERING IN MECHANICAL ENGINEERING Approved: _________________________________________ Professor Ernesto Gutierrez-Miravete, Engineering Project Advisor Rensselaer Polytechnic Institute Hartford, Connecticut December, 2012 © Copyright 2012 by Mitchell S. King All Rights Reserved ii CONTENTS LIST OF FIGURES ........................................................................................................... v LIST OF TABLES ........................................................................................................... vii NOMENCLATURE ....................................................................................................... viii GLOSSARY ..................................................................................................................... ix ACKNOWLEDGMENT ................................................................................................... x ABSTRACT ..................................................................................................................... xi 1. Theory .......................................................................................................................... 1 1.1 Coordinate System ............................................................................................. 1 1.2 Twist Parameters ................................................................................................ 4 1.3 Stress, Strain, and Displacement for a Cantilever Beam ................................... 5 1.4 1.5 1.3.1 Stress Equilibrium .................................................................................. 6 1.3.2 Strain-Displacement Relationships ........................................................ 8 1.3.3 Stress-Strain Relationships .................................................................. 10 Generic Cantilever Beam Stress, Strain, and Displacement Solutions ............ 11 1.4.1 Functionally Varying Moment of Inertia ............................................. 13 1.4.2 Discontinuous Shear Stress Solution for a Rectangular Beam ............ 18 1.4.3 General Stress Distribution for a Twisted Cantilever Beam ................ 21 1.4.4 General Strain Distribution for a Twisted Cantilever Beam ................ 22 1.4.5 General Vertical Displacement of a Twisted Cantilever Beam ........... 23 Specific Theoretical Solution ........................................................................... 32 2. Finite Element Analysis (FEA) Model ...................................................................... 38 2.1 Methodology .................................................................................................... 38 2.2 Analytical Results ............................................................................................ 41 2.2.1 Tensile Stress and Strain Values (x-Direction) .................................... 43 2.2.2 Shear Stress and Strain Values (xy-Direction) ..................................... 47 2.2.3 Vertical Displacement (y-Direction) .................................................... 51 iii 3. Comparison of Beam Theory Formulation Results to FEA Results.......................... 54 3.1 Displacement Values ........................................................................................ 54 3.2 Maximum Tensile Stress Values ...................................................................... 57 3.3 Maximum Shear Stress Values ........................................................................ 58 4. Summary and Conclusion .......................................................................................... 60 5. Appendix A – Theoretical Results at Selected x Values ........................................... 62 6. Appendix B – FEA Results at Selected x Values ...................................................... 67 7. Appendix C – ABAQUS Input File (.inp) ................................................................. 72 8. References................................................................................................................ 100 iv LIST OF FIGURES Figure 1 - Example of a Twisted Cantilever Beam ........................................................... 1 Figure 2 – 90° Twisted Cantilever Beam in the xy-Plane.................................................. 2 Figure 3 – 90° Twisted Cantilever Beam in the yz-Plane .................................................. 3 Figure 4 - xyz Axes vs. ABC Axes .................................................................................... 4 Figure 5 – Arbitrary Beam Cross-Section Subjected to Bending Moment Mz(x) ............. 6 Figure 6 - Rotation of Axes and Moment of Inertia ........................................................ 13 Figure 7 - Moment of Inertia Variation within the Twisted Region of a Rectangular Beam ................................................................................................................................ 17 Figure 8 - Point of Discontinuity in Shear Stress ............................................................ 19 Figure 9 - Width and Thickness Parameters of the Solution ........................................... 32 Figure 10 - Load and Length Parameters of the Solution ................................................ 32 Figure 11 - Midplane Shell of the ABAQUS FEA Model .............................................. 38 Figure 12 - Meshed View of the ABAQUS FEA Model................................................. 39 Figure 13 - Load and Boundary Conditions of the ABAQUS FEA Model..................... 40 Figure 14 - FEA Shell Model, Variation of Principal Axes ............................................ 42 Figure 15 - FEA Tensile Stress at the Shell’s Midplane ................................................. 44 Figure 16 - FEA Tensile Stress at the Shell's Positive Face ............................................ 45 Figure 17 - FEA Indicates an Additional Compressive Stress Peak in Twisted Region, Shell’s Positive Face ........................................................................................................ 45 Figure 18 - FEA Tensile Stress at the Shell's Negative Face .......................................... 46 Figure 19 - FEA Indicates an Additional Tensile Stress Peak in Twisted Region, Shell’s Negative Face .................................................................................................................. 46 Figure 20 - FEA Shear Stress Distribution at the Shell's Midplane ................................ 47 Figure 21 - FEA Shear Stress Concentration at Shell's Midplane ................................... 48 Figure 22 - FEA Shear Stress Distribution on Shell’s Positive Face .............................. 49 Figure 23 - FEA Shear Stress Distribution on Shell’s Negative Face ............................. 50 Figure 24 - FEA Displacement Results, Isometric View ................................................ 51 Figure 25 - FEA Displacement Results, xy-Plane ........................................................... 51 Figure 26 - FEA Displacement Results, yz-Plane ............................................................ 52 Figure 27 - FEA Indicates Residual Stiffness and Non-planar Cross-Section at x = x4 .. 53 v Figure 28 - Theory vs. FEA, Vertical Displacement ....................................................... 54 Figure 29 - Theoretical Displacement Results vs. Beams of Constant Cross-Sectional Orientation ....................................................................................................................... 56 Figure 30 - Theory vs. FEA, Maximum Tensile Stress ................................................... 57 Figure 31 - Theory vs. FEA, Maximum Shear Stress...................................................... 58 vi LIST OF TABLES Table 1 - Summary of FEA Input Parameters ................................................................. 40 vii NOMENCLATURE For the following symbols, i ≠ j. Units are in parenthesis. E - Modulus of Elasticity (psi) ε - Strain Tensor (in/in) εii - Extensional Strain (in/in) εij - Tensor Shear Strain (in/in) F - Force Applied to the Free End of the Cantilever Beam (lbs) G - Shear Modulus (psi) γ - Engineering Shear Strain (in/in) Iii - Moment of Inertia (in4) Iij - Product of Inertia (in4) κ - Curvature (in-1) L - Length (in) M - Moment (in-lb) ν - Poisson’s Ratio (dimensionless) σ - Stress Tensor (psi) σii - Tensile Stress (psi) t - Thickness of the Rectangular Cross-Section, Less than its Width, w (in) τij - Shear Stress (psi) ϴ - Angular Measurement Between the B and Y-Axes or the C and Z-Axes (radians or degrees) u - Longitudinal Displacement (in) v - Vertical Displacement (in) w - Transverse Displacement, Only Applicable to Section 1.3.2 (in) w - Width of the Rectangular Cross-Section, Greater than its Thickness, t (in) viii GLOSSARY ABAQUS A software application used for both the modeling and analysis of - mechanical components and assemblies (pre-processing) and visualizing the finite element analysis results (post-processing). A projecting beam that is supported at one end and carries a load at the other end or along its length. A coordinate system comprised of three mutually orthogonal axes to represent three-dimensional space. Cantilever Beam - Cartesian Coordinate System - Deflection - A movement of a structural member resultant of an applied force. Displacement - See ‘deflection’. Equilibrium - A state in which opposing forces or influences are balanced. FEA - An acronym for Finite Element Analysis. Final Orientation - The cross-sectional orientation of the beam in the region beyond L2. Global Axes - of the beam and whose origin is at the fixed end of the beam. Hooke's Law Initial Orientation - related to the applied stress within the elastic limit of the solid. - The cross-sectional orientation of the beam from its origin to L1. Isotropic - Having uniform physical properties in each direction. Local Axes - of the beam’s cross-section and whose origin varies to satisfy this The coordinate system that remains constant throughout the length A law stating that the strain in a solid is proportional and linearly- The coordinate system that remains perpendicular to the perimeter perpendicularity. Computes an approximation to a definite integral, made by finding the area of a collection of rectangles whose heights are determined by the values of the function. The proportionality constant relating a solid’s extensional strain value(s) to its longitudinal stress value(s) within the elastic region. A measurement that quantifies a beam’s ability to resist bending about a particular axis. The point in three-dimensional space where all three Cartesian axes are coincidient, e.g. x = y = z = 0. Midpoint Rule - Modulus of Elasticity - Moment of Inertia - Origin - Poisson's Ratio - The negative ratio of transverse strain to axial strain. Product of Inertia - deformation about a particular axis. Shear Modulus - to its shear stress value(s) within the elastic region. Strain - material body in which the forces are being applied. - A measure of the internal forces acting within a deformable body. Stress Twisted Cantilever Beam Varying Orientation A measurement that quantifies a beam’s ability to resist shear The proportionality constant relating a solid’s shear strain value(s) The ratio of total deformation to the initial dimension of the A cantilever beam whose cross-section remains constant, but is - rotating about its centroid along the beam’s length. - The cross-sectional orientation of the beam in the region of L1 to L2. ix ACKNOWLEDGMENT I would like to thank my fiancé, Jessica Rowe, for her unwavering support, encouragement, and affection during my graduate studies. x ABSTRACT Twisted cantilever beams are defined here as beams whose rectangular cross-sectional orientation changes along the beam’s length with respect to global axes. These beams have a twisted or spiral-type geometric feature somewhere along their length. This project will formulate solutions for twisted cantilever beams in static bending using classical beam theory, compare the results to numerical solutions, and discuss inconsistencies. xi 1. Theory 1.1 Coordinate System The analytical case of interest is a rectangular cantilever beam in static bending with an abrupt, 90° twist, like that shown in Figure 1. The beam is rigidly affixed at one end, preventing any displacements or rotations at that end. The geometric center of the beam at the affixed end will be defined as the ‘origin’ or the point at which all coordinates (x,y,z) are equal to zero. Cartesian coordinates will be used in these solutions because traditional cantilever beams in bending have documented analytical solutions in Cartesian coordinates as well. Note that the placement of the axes shown in Figure 1 does not place the vertex at the analytical origin. Figure 1 - Example of a Twisted Cantilever Beam Moving away from the rigid attachment at (0,0,0), parallel to the length of the beam will be defined as: ‘moving in the x-direction’, defining the x-axis. The direction of the y-axis is orthogonal to the x-axis and is chosen to be parallel to one side of the beam’s cross-section at the origin. The z-axis is orthogonal to both the x and y-axes. These three axes whose origin occurs at the beam’s geometric center, at the fixed end, are defined as the ‘global axes’. 1 Moving down the beam’s length, away from the rigid attachment, in the x-direction, the beam initially has a homogeneous moment of inertia and its ‘initial orientation’. At some distance, denoted by L1, the beam’s cross-section begins to rotate about its x-axis, but its moment of inertia remains continuous, where it can be described as having a ‘varying orientation’. The beam’s cross-section continues to rotate until it reaches another distance, denoted by L2, where the rotation stops but again, the moment of inertia remains continuous. Beyond L2, the beam’s ‘final orientation’ continues until it reaches its free end, whose distance from the origin is denoted by the length L3. For the case of a 90° twist, the final orientation is rotated 90° from the initial orientation. See Figure 2 and Figure 3. Y O F X L1 L12 L3 Figure 2 – 90° Twisted Cantilever Beam in the xy-Plane 2 Y Z Figure 3 – 90° Twisted Cantilever Beam in the yz-Plane Because the cross-sectional orientation of the beam is varying along its length between L1 and L2, another set of axes are defined in order more easily express twist parameters and cross-sectional orientations. These ‘local axes’ are also Cartesian, but are denoted (A,B,C) instead of (x,y,z). The origin of the local axes is not necessarily at the same location as that of the global axes, but can be anywhere along the beam’s length, provided that the A-axis remains collinear with the x-axis. At the beam’s fixed end, at its geometric center, the A-axis is collinear with the x-axis, the B-axis is collinear with the y-axis, and the C-axis is collinear with the z-axis. Once the beam’s cross-section begins to rotate (at L1) the B and C-axes develop an angular measurement greater than zero between their global counterparts (y and z, respectively). The A-axis and x-axis will always remain collinear, and either can be used interchangeably. See Figure 4. 3 Y Y [ x and A-axes both coming out of the page. ] B B Z ϴ Z C C Figure 4 - xyz Axes vs. ABC Axes It is important to describe and define the parameters within the beam’s varying orientation (L1 ≤ x ≤ L2), because these parameters will contribute to the analytical solutions that are eventually formulated. The difference between the cross-sections at x = L1 and L1 ≤ x ≤ L2 can be quantified by the angular difference, ϴ, between the y and B-axes or the z and C-axes. The rate of twist can then be defined as the change in angle, ϴ, over the change in length between L1 and L2, or . 1.2 Twist Parameters For the problem to be solved, the cross-sectional orientation can be described as: [1] [2] [3] Let ϴ(x) be a linear function of x, so that the rate of twist from L1 to L2 is a constant value. Then, by the equalities given by equations [1] through [3]: 4 Substituting the boundary conditions in the expression for ϴ yields: Solving for the constants M and N, and subtracting these equalities gives: The function ϴ(x) can then be written as: [4] So, the rate of twist is: [5] Rewriting equation [1] through [3] with equation [4]: [6] [7] [8] Together, equations [6] through [8] fully describe the beam’s twist parameters and can be derived using the values L1 and L2. 1.3 Stress, Strain, and Displacement for a Cantilever Beam Because the cantilever beam of interest has a functionally varying cross-sectional orientation along its length, the stress distribution throughout the beam must be solved for a generic case first so that the twist parameters developed in section 1.2 can be 5 applied. Let a beam of arbitrary cross-section be subjected to a bending moment, Mz(x), about the z-axis, which is a function of longitudinal (x) position only. The origin of the cross section is at the beam’s centroid, and the y and z-axes are the principal axes. See Figure 5. [ X and A-axes both coming out of the page. ] Y Arbitrary Cross-Section Z Mz(x) Figure 5 – Arbitrary Beam Cross-Section Subjected to Bending Moment Mz(x) 1.3.1 Stress Equilibrium As a result of the applied load, F, and subsequent moment, Mz(x), the beam experiences displacements, strains, and a state of stress. Each can be represented by a tensor at each point throughout its volume. The generic stress tensor, [σ], is given by: [9] In order to satisfy equilibrium, the stress tensor must be symmetric such that: 6 Because stresses can be related to displacements (as will be shown in following discussion), and because the displaced shape of an end-loaded cantilever beam is similar to that of a beam in pure bending, it is reasonable to assume that the cantilever beam has a stress tensor similar to that of a beam in pure bending. Beginning with the bending moment, Mz(x): [10] [11] [12] That is, the normal stresses, σii, and the x-z and y-z shear stresses, τxz and τyz, are identical to those for a beam in pure bending, but no specific assumptions are made about the other shear stress, τxy, only that it is some function of x, y, and z. The equations of 3-D stress equilibrium with no body forces are now noted to augment the discussion and simplify the equations above: [13] [14] [15] Based on equations [10] through [12], equations [13] and [14] reduce to: [16] [17] 7 Equations [16] and [17] make up the 3-D stress equilibrium equations for a cantilever beam experiencing plane stress. Upon inspection, one can see that equation [17] is only satisfied if τxy is constant in the x-domain. Rewriting equations [10] and [11] for clarity, equation [12] can be simplified to: [18] [19] [20] 1.3.2 Strain-Displacement Relationships As mentioned, the beam also experiences a state of strain. The generic stress tensor, [ε], is given by: [21] where εii are normal strains and εij are shear strains. The strain tensor is symmetric, such that: 8 For small deflections (where sin α ≈ α), the following expressions relate strain to displacement: [22] [23] [24] [25] [26] [27] Engineering shear strain is related to tensor shear strain by: Rewriting equations [22] through [27], the components of the strain tensor, [ε], are: [28] [29] [30] [31] [32] [33] 9 1.3.3 Stress-Strain Relationships For an isotropic, linear-elastic material (obeying Hooke’s Law), the stress-strain relationships are as follows: [34] [35] where E is the modulus of elasticity and G is the shear modulus. The two modulii are related through Poisson’s Ratio, ν, by the following: [36] For each component of the strain tensor, the relationships are: [37] [38] [39] [40] [41] [42] 10 1.4 Generic Cantilever Beam Stress, Strain, and Displacement Solutions Equation [18] indicates that the normal stress in the x-direction is dependent on the bending moment, Mz(x), which is a function of x. This bending moment is simply the force, F, multiplied by the distance from the origin, and can be written as: [43] So, the normal stress in the x-direction is: [44] Substituting equation [44] in the x-direction stress equilibrium equation ([16]) gives: [45] Integrating equation [45]: P is a constant of integration and can be determined on the basis that in order to satisfy boundary equilibrium around the perimeter of the beam, the shear force must be equal to zero at these points. The total stress distribution is now repeated for clarity: [46] [47] [48] 11 The strains at each point can be found directly from the resultant stresses, by inserting equations [46] through [48] into equations [37] through [42]. Inserting equation [46] and [47] into the stress-strain relationships (equation [37]), and that into the straindisplacement relationship (equation [22]) leads to a noteworthy: [49] Equation [49] can be integrated in x to solve for the longitudinal displacement of the beam, once the function of Izz is known. For small strains and displacements in the elastic range, and assuming that plane sections remain plane, the curvature of the beam’s neutral surface can be expressed in the following form: where κ is the curvature. Inserting equation [43] gives: [50] Equation [50] is a second-order linear differential equation, and is the governing equation for the elastic curve. The product EI is the flexural rigidity of the beam. Because the moment of inertia, Izz, varies with respect to x, it must be first formulated in order to integrate equation [50] and solve for the vertical displacement. Up to this point, each parameter of the stress, strain, and displacement components is known except the moment of inertia about the neutral axis, Izz, and the constant of integration, P, for the shear term. This moment of inertia and P are derived in the following discussion. 12 1.4.1 Functionally Varying Moment of Inertia Consider the plane area shown in Figure 6 below. The moments and product of inertia with respect to the local BC-axes are: [51] [52] [53] The same forms of expressions exist for the global coordinate system, in xyzcoordinates. [ x and A-axes both coming out of the page. ] Y Arbitrary B Cross-Section ϴ CdA dA z y BdA Z C Figure 6 - Rotation of Axes and Moment of Inertia The moments and product of inertia in the BC-plane are constant values, equal to those of the yz-plane at the origin. However, as the angular measurement θ increases, the moments and product of inertia in the yz-plane change. To obtain these quantities, the coordinates of the differential element dA are expressed in terms of the yz-coordinates as follows: 13 [54] [55] Substituting these values in equations [51] through [53] gives: Using the following trigonometric identities, the form of IYY, IZZ, and IYZ can be simplified. 14 These are complicated expressions in their most reduced form, unlike the simple and familiar (for example). However, if the general expressions for moments and product of inertia in the local coordinate system (equations [51], [52], and [53]) are substituted in the above integrals, they take on a more practical form. [56] [57] [58] IYY, IZZ, and IYZ are the moments and product of inertia in the global coordinate system at any point along the x-axis, and IBB, ICC, and IBC are the moments and product of inertia in the local coordinate system. With the moments and products of inertia defined as such, the reader is referred back to Figure 2 to be reminded of the cross-sectional orientation at the origin. Specifically, for this problem, the local moments and product of inertia are the same as those of a rectangular cross-section in bending, where ICC is the “strong axis” of bending and IBB is the “weak axis” of bending at the origin. The limits of integration are defined by the beam’s perimeter. Thus: 15 [59] [60] [61] where w is the width of the beam, and t is the thickness. For any symmetric cross-section whose centroid is at the origin, IBC will be zero, so any terms containing the beam’s local product of inertia will drop out of equations [56], [57], and [58]. Substituting equations [59] through [61] into these equations gives: By substituting in the relationship between ϴ and x (see equations [6], [7], and [8]), these equations yield the full form of the functionally varying moments of inertia. [62] 16 [63] [64] Taking (for example) values of t =0.25” and w = 1.00”, the moments and product of inertia change in the twisted region of the beam as shown in Figure 7 below: Figure 7 - Moment of Inertia Variation within the Twisted Region of a Rectangular Beam 17 1.4.2 Discontinuous Shear Stress Solution for a Rectangular Beam The stress distributions will be solved to eventually formulate the strain and displacement solutions. However, the shear stress, τxy, still has an undefined constant, P, which must be found to fully formulate the stress in the beam. As stated in section 1.4.1, P is a constant of integration that can be determined on the basis that in order to satisfy boundary equilibrium around the perimeter of the beam, the shear force must be equal to zero at these points. But because the beam’s cross-section is rotating, this constant is also related to the twist parameters for L1 ≤ x ≤ L2. For the beam’s initial orientation: Substituting this value into equation [48] gives: [65] For the beam’s final orientation: Substituting this value into equation [48] gives: [66] 18 For the beam’s varying orientation, the y-coordinate of the beam’s outermost fiber is constantly changing. This coordinate is needed to solve the shear stress distribution in this region. The perimeter of the beam can be represented by four straight lines whose orientation varies with the x-position, or ϴ. Because the perimeter edges intersect one another at right angles, however, the function of the outermost y-coordinate will not be a continuous function. The function changes when the y-axis coincides with the corner of the beam’s cross-section. For any rectangular beam, this occurs at an angle of . See Figure 8. Y ϴ = arctan (t/w) w Z t Figure 8 - Point of Discontinuity in Shear Stress For the varying orientation, where 0 ≤ ϴ ≤ arctan (t/w), the y-coordinate of the outermost fiber of the beam’s cross-section is: 19 Substituting this value into equation [48] and using the relationship between ϴ and x (equation [7]) gives: [67] Similarly, for the varying orientation, where arctan (t/w) ≤ ϴ ≤ π/2, the y-coordinate of the outermost fiber of the beam’s cross-section is: Substituting this value into equation [48] and using the relationship between ϴ and x (equation [7]) gives: [68] 20 1.4.3 General Stress Distribution for a Twisted Cantilever Beam Consolidating equations [6], [7], [8], [46], and [65] through [68]: Any [69] Orientation: Any [70] Orientation: Initial [71] Orientation: Varying [72] Orientation: Varying [73] Orientation: Final [74] Orientation: 21 1.4.4 General Strain Distribution for a Twisted Cantilever Beam Inserting equations [69] through [74] into the stress-strain relationships given by equations [37] through [42]: Any [75] Orientation: Any [76] Orientation: Any [77] Orientation: Initial [78] Orientation: Varying [79] Orientation: Varying [80] Orientation: Final [81] Orientation: 22 1.4.5 General Vertical Displacement of a Twisted Cantilever Beam Now that the moment of inertia, Izz, has been derived, equation [50] can be integrated to obtain the y-displacement function. However, because Izz is dependent upon the longitudinal position, x, the vertical displacement function must be dissected into three conditional equations, depending on the magnitude of x. The first solution presented will be for the case of . Because this x-location is within the initial orientation and the moment of inertia is constant in this region, equation [50] is integrated twice in x, as would be done for a normal cantilever beam with constant crosssection: where C1 is a constant of integration. Integrating again in x gives: The constants of integration, C1 and C2 can be determined by applying the boundary conditions of the beam. At the fixed end, beam are equal to 0. Therefore, , the displacement and the slope of the . So, for the region of : [82] The displacement function for x values in the varying orientation becomes more complicated, however. For values of x where , the moment of inertia cannot be considered constant and excluded from the integrals, as was done above. Inserting the equality for Izz into equation [50], for values of x where once with respect to x gives: 23 , and integrating The second term of the y-displacement slope solution (above) indicates an inherent flaw in the application of classical beam theory to this problem. Even a simplified version of the function does not stay within the real domain; the varying moment of inertia function’s presence in the denominator complicates the solution beyond any reasonable point. Because the solution is beyond the scope of this document, a piecewise approximation is instead presented using the midpoint rule. If the second term above is broken into many separate intervals, the integral can be carried out by approximating the value of x for each separate interval. That is, the distance from L1 to L2 will be divided by N number of divisions, and the average longitudinal value between each point will be used in place of x. The midpoint rule is defined as: The midpoint of each interval is equal to the variable xn, where N is the number of predefined intervals chosen: Because the midpoint rule is only needed for values of x where , the value of a is already known and equal to L1. Likewise, the value of b will be set to x. Therefore, the second term of the exact y-displacement slope solution can be approximated as: 24 In this form, the first term of the exact solution can be solved directly, and the second term can be approximated. Of course, as , the function will converge to the exact solution, but in this form it is much “easier” to deal with. Thus, the slope of the beam, , for can be written as: The constant of integration, C3, can be determined by applying the boundary condition provided by equation [82]: at , 25 Rewriting the expression for the slope of the beam in the region of : To solve for the displacements, the equality above must again be integrated in x. However, the second term again creates problems and yields solutions of non-real numbers. Thus, the midpoint rule must be applied a second time. Let the second term above be defined as an arbitrary function of x, β(x), so that: Integrating the second term using the midpoint rule gives: 26 There have certainly been more elegant expressions derived in engineering. Writing the total solution for y-displacement when gives: The constant of integration, C4, can be found by using equation [82] at 27 : The y-displacement solution for becomes: [83] Finally, the displacement solution for values of x where can be formulated using the same process as the other intervals. Because this x-location is within the final orientation and the moment of inertia is constant in this region, equation [50] is integrated twice in x, as was done to derive equations [82] and [83], only the contribution to the displacement from the varying orientation is given the limits of L1 and L2. 28 The constant of integration, C5, can be determined by recalling the function derived for the beam’s slope between , and inserting 29 : The slope of the beam for can then be written as: Notice that in this region only one term of the beam’s slope is dependent on x. This simplifies things much more than before when deriving the beam’s deflection in the varying orientation. That is, all integrals henceforth can be computed directly, and no more approximations are needed. To solve for the y-displacement, the equality above is integrated in x to give: 30 The final constant of integration can be determined by the boundary condition: at . Therefore, (from equation [83]). [84] Equations [83] and [84] are very complicated and tedious to carry out in real applications. A less cumbersome method is to use the equation of the beam’s slope, , and integrate the numerical value(s) over x, rather than carrying through to a closed-form solution. This method will be used to obtain values in section 1.5 and in Appendix A. 31 1.5 Specific Theoretical Solution Advancing from the generic case, the specifics of the problem are now defined and solved. Figure 9 shows the beam’s cross-section at two distinct points and assigns its width (w) and thickness (t). Let these values be 1.0” and 0.25”, respectively. Figure 10 is a repetition of Figure 2, but assigns values to the applied force, F, and lengths L1, L2, and L3. Y Z Y w Z t w [Final Orientation] Y O t w = 1.0” [Initial Orientation] t = 0.25” Figure 9 - Width and Thickness Parameters of the Solution 10 lbs X 3” 1 4.5” 7.5” Figure 10 - Load and Length Parameters of the Solution Let the material properties of the beam be those of mild steel (ms): 32 For comparison to numerical results, the stress, strain, and displacement values at five distinct values of x will be found. These five x-locations are as follows: corresponds to the start of the twist, its twist feature, corresponds to the midpoint of the beam and corresponds to the end of the twist, and corresponds to the end of the beam. In addition, at each x value the stress, strain, and vertical displacement values will be formulated for three values of y, corresponding to the positive/negative outermost beam fiber y value, and at , the neutral axis. The following solution is that of . The analytical results for all other points can be found in Appendix A. In the beam’s local coordinates, the moments and products of inertia are: For and the moment of inertia, IZZ, is: (See equation [55]). Therefore, the stress distribution for and 33 is: In tensor form: The strains at and can be found by inserting these values into the stress-strain relationships, given by equations [37] through [42]: The vertical displacement at this point is found using the slope equation that, when integrated in x, gives equation [83]. Because the value of x = 3.75” lies in the region of . For the following solution, let N = 5. 34 To extract a vertical displacement from the beam’s slope at this point, is simply integrated again in x with the appropriate limits: The constant of integration, C7, is determined by the boundary condition provided by the beam’s vertical displacement in its initial orientation. At (from equation [82]), 35 The very outer-most beam fiber that lies on the y-axis is derived in section 1.4.2, and is given by the equality: Since For at , the outer-most beam fiber on the y-axis is: and the stress distribution is: In tensor form: The strains at and can be found by inserting these values into the stress-strain relationships, given by equations [37] through [42]: The vertical displacement at this point does not depend on y, so it is the same as previously calculated. 36 For and the stress distribution is: In tensor form: The strains at and can be found by inserting these values into the stress-strain relationships, given by equations [37] through [42]: The vertical displacement at this point does not depend on y, so it is the same as previously calculated. 37 2. Finite Element Analysis (FEA) Model 2.1 Methodology To compare and validate the theoretical results, the finite element analysis (FEA) software ABAQUS was used. ABAQUS is a powerful software application used for both the modeling and analysis of mechanical components and assemblies (preprocessing) and visualizing the finite element analysis results (post-processing). ABAQUS offers a variety of different modeling approaches for the formulation of a cantilever beam problem. The user has the option of using 3D-continuum parts, shell assemblies, axisymmetric models, planar parts, and many other choices. For this particular problem, a shell assembly was created and meshed to generate S4R elements (4-sided shell elements using reduced integration methods). This option was chosen because it most closely matches the theoretical results of a traditional cantilever beam, without a twist feature. First, the midplane shell geometry was created by extruding line-connectors to specific datum planes. These datum planes represent the x-values chosen for examination of the theoretical solutions. See Table 1 for the values of x that represent these datum planes. The figure below shows the shell geometry created in ABAQUS to create an FEA model of the twisted cantilever beam. Figure 11 - Midplane Shell of the ABAQUS FEA Model 38 After the geometry was defined, the element was assigned a shell thickness (t = 0.25”) and material properties (E = 30x106 psi, ν = 0.3) identical to those of the theoretical solution in Section 1.5. The shell geometry was then meshed to form S4R elements, with an approximate global seed size of 0.1”. The seed size of the model determines the coarseness of the mesh. ABAQUS generally selects an appropriate seed size based on the number of elements it is able to process; with the student version of ABAQUS (used herein), the number of elements is limited to 1,000. It is possible to extrude the twisted region of the cantilever beam as one element, however, Figure 11 above shows that it was created with two separate elements. This was done to force the meshing to generate element points at the x = 3.75” point. This is useful in that point results at the middle of the twist feature can later be extracted, instead of using points nearby and approximating. Figure 12, below, shows the meshed model of the twisted cantilever beam. Figure 12 - Meshed View of the ABAQUS FEA Model Finally, the root of the beam was fixed by creating an initial job step and setting all displacement and rotations at x = 0” equal to zero (shown as orange cones in Figure 13). A second job step was created to define the end-load on the beam. To avoid point effects, a transverse shear, line-load on the far edge was used (shown as red arrows in 39 the negative y direction in Figure 13). This model was submitted for analysis and completed successfully. Figure 13 - Load and Boundary Conditions of the ABAQUS FEA Model Table 1 - Summary of FEA Input Parameters Variable Value L1 3” L2 4.5” L3 7.5” w 1.00” t 0.25” E 30 x 106 psi ν 0.3 F -10 lbs 40 2.2 Analytical Results Explicit numerical results for x values corresponding to those analyzed in Section 1.5 and Appendix A can be found in Appendix B. The model used for analysis is a shell model whose thickness or normal direction defines the z-axis, therefore shear stresses cannot be directly extracted from ABAQUS in the traditional manner. As shown in Figure 14 below, the model’s 2 and 3 axes (corresponding to the B and C-axes) evolve over the length of the beam. Thus, the numerical results provided by ABAQUS correspond to the stress states in the ABC-coordinate system (see Figure 4). A direct comparison can be made to any x-direction values, but to compare shearing components or any direction other than x, the values must be properly transformed into the global coordinate system (xyz). To apply this transformation of results, the user must specify a field output transformation option corresponding to the global axes (under ResultsOptionsTransformation). 41 Figure 14 - FEA Shell Model, Variation of Principal Axes 42 NOTE: The following graphical representations extracted from ABAQUS give stress, strain, and displacement values in index notation. Therefore, 2.2.1 Tensile Stress and Strain Values (x-Direction) The midplane of the FEA model shows tensile stress values (σxx) peaking at the fixed end of the beam, as is the case for a traditional cantilever beam. It does not indicate any specific stress-increasing effect induced by the twist feature. See Figure 15 for a view of the tensile stress results at the midplane. At the shell model’s positive face, however, ABAQUS shows a severe increase in compressive stress as the beam approaches its final orientation. At the model’s negative face, the same region indicates a severe increase in tensile stress. See Figure 16 and Figure 17 for the tensile stresses at the positive face of the shell model and Figure 18 and Figure 19 for the tensile stresses at the negative face of the shell model. Because the relationship between stress and strain is linear (see equations [34] and [35]) the graphical results of only stress are given. The strain distributions predicted by ABAQUS are similar to their corresponding stress distributions, shown below. 43 Figure 15 - FEA Tensile Stress at the Shell’s Midplane 44 Figure 16 - FEA Tensile Stress at the Shell's Positive Face Area of compressive stress peak Figure 17 - FEA Indicates an Additional Compressive Stress Peak in Twisted Region, Shell’s Positive Face 45 Figure 18 - FEA Tensile Stress at the Shell's Negative Face Area of tensile stress peak Figure 19 - FEA Indicates an Additional Tensile Stress Peak in Twisted Region, Shell’s Negative Face 46 2.2.2 Shear Stress and Strain Values (xy-Direction) Figure 20 shows the shear stress distribution of the shell’s midplane. Notice that the initial orientation shows a parabolic distribution, as is the case of classical beam theory. However, Figure 20 also shows that the shear stress has a negative shear stress concentration at the origin, near the top and bottom fibers (the blue corners). This may be attributed to point effects and discontinuity extrapolations generated by the numerical integration routine of ABAQUS. Notice that just adjacent to these points, the shear stress is positive, and more close to a zero value. Figure 20 - FEA Shear Stress Distribution at the Shell's Midplane Figure 20 and Figure 21 also show that at the beam’s midpoint, in the middle of its twist feature, there is a negative shear stress concentration. Again, note that there is a linear relationship between stress and strain. Thus, only the distributions for stress are shown. 47 Negative Shear Stress Concentration Figure 21 - FEA Shear Stress Concentration at Shell's Midplane The results of the positive and negative faces of the shell model indicate severe shear stress concentrations after the twist midpoint and before the beam’s final orientation begins. Most notably, there is a large increase in positive shear in the xy-plane. This rebounds the color spectrum of the post-processor, and results in the rest of the beam appearing as a constant shear value. This is not the case, however. The shear stress still follows a parabolic distribution over the height of the beam, up to the twisted region. See Figure 22 and Figure 23 for the shear stress distributions on the positive and negative faces of the shell model. 48 Shear Stress Concentrations Figure 22 - FEA Shear Stress Distribution on Shell’s Positive Face 49 Shear Stress Concentrations Figure 23 - FEA Shear Stress Distribution on Shell’s Negative Face 50 2.2.3 Vertical Displacement (y-Direction) Figure 24 through Figure 26 below show the twisted cantilever beam’s displacement distribution. Note that in Figure 26, there is a positive z displacement at the end of the beam. This feature indicates shear coupling within the layers of the shell, which is not addressed by classical beam theory. Figure 24 - FEA Displacement Results, Isometric View Figure 25 - FEA Displacement Results, xy-Plane 51 Δz Figure 26 - FEA Displacement Results, yz-Plane When viewing the rotational displacements about the x-axis, an interesting point arises: the twist feature seems to have imposed a structural anomaly in the beam at the end of its twist, at x = x4. The displacements across the beam’s width at the end of the twist (z-direction) follow a parabolic distribution. Classical beam theory suggests that vertical displacements are independent of this direction. Looking at regions far from this point (x4), the rotations about the x-axis disappear, corresponding to traditional theory. At 52 x = x4, however, the outer edges of the beam have a higher ‘residual stiffness’ than the centerline, and experience smaller displacements. See Figure 27. x4 = 4.5” Figure 27 - FEA Indicates Residual Stiffness and Non-planar Cross-Section at x = x4 53 3. Comparison of Beam Theory Formulation Results to FEA Results 3.1 Displacement Values The vertical displacement functions derived in section 1.4.5 show the closest correlation to FEA results. Equation [82] matches the displacements calculated by ABAQUS almost exactly. Equation [83] does a reasonable job up to the end of the twist but beyond this (Equation [84]), predicts a slightly stiffer beam. Figure 28 shows the displacements of the beam as calculated in this document and by FEA. Notice that each method plots a smooth, cubic displacement function along the beam’s length. Figure 28 - Theory vs. FEA, Vertical Displacement 54 Overall, it is shown that for vertical displacements, classical beam theory can be applied to cantilever beams with functionally varying moments of inertia to obtain reasonable results. The percent difference of the beam’s vertical deflection at the end of the beam (x = 7.5”) using beam theory is only 4.5% different than the value predicted by FEA. Classical beam theory (as applied in the derivation of theoretical values within), however, does not account for out-of-plane displacements that may occur, as these are resultant of shear-coupling and non-planar cross-sectional deformations. shows that FEA results predict out-of-plane displacements. Figure 26 Abiding by the key assumptions of traditional beam mechanics (see section 1.3.1) forces one to discount out-of-plane effects. In the case of a twisted cantilever beam, this may disregard key aspects of the beam’s internal mechanics. Beam theory does not leave room for out-ofplane displacements but does predict fairly accurate in-plane displacements when compared to the results of FEA. When compared to the analytical solutions for similar rectangular beams with constant cross-sections (see Figure 29), the vertical displacement curve of this particular twisted cantilever beam seems to relate more closely to the beam experiencing strong-axis bending, though this correlation will be a function of the length and twist parameters. If the twist was closer to the fixed end of the beam (near x = 0”), the displacement curve of the twisted cantilever beam would be expected to more closely follow that of the constant cross-section beam in weak-axis bending. Conversely, the closer the twist is to the applied load (near x = L3), the more closely the displacement curve would follow that of the constant cross-section beam in strong-axis bending. 55 Figure 29 - Theoretical Displacement Results vs. Beams of Constant Cross-Sectional Orientation 56 3.2 Maximum Tensile Stress Values The theoretical values of tensile stress (σxx) match the numerical results very well outside of the beam’s twisted region. Within the twisted region, however, the ABAQUS model generally predicts much higher values, and does not indicate maximum or minimums at exactly the same value of x. The FEA model also does not follow the smooth curve based on trigonometric modifications of the moment of inertia in this region. At each tensile stress’ maximum point, the theoretical value is 9% less than that of the numerical solution. See Figure 30 for the maximum tensile stresses predicted by theoretical methods and by numerical methods. The theoretical method, as presented herein, should not be used to calculate maximum tensile stress within the varying-orientation region of a twisted cantilever beam. Figure 30 - Theory vs. FEA, Maximum Tensile Stress 57 3.3 Maximum Shear Stress Values Again, beyond the twisted region, the theoretical stress values closely match the numerical values. However, for the shear stress (τxy), the FEA results vary greatly from the theoretical results in the twisted region. Both methods allude to a maximum or minimum at the twist’s midpoint (x = 3.75”), but the theoretical results appear to have an inverted shape compared to those of the FEA shell model. See Figure 31. Figure 31 - Theory vs. FEA, Maximum Shear Stress The FEA model shows the shear stress peaking at the midpoint of the twist, but this effect is not predicted by the application of classical beam theory. A possible explanation is that, contrary to classical beam theory, plane sections are not remaining plane under deformation (as shown by Figure 27). This effect would cause the shear deformations to have a much greater impact on the distribution of flexural stresses 58 within the beam than calculated with traditional methods. Figure 31 shows the severity of error in using traditional beam theory to calculate shear stresses within the beam’s twisted region. For the application of failure criterion (such as von Mises, Tresca, maximum stress, etc), the shear stress equations developed by this document would not accurately demonstrate maximum shear stress values, and could lead to errors. However, both theoretical and FEA models indicate a peak of sorts at the twist’s midpoint. To mitigate gross errors and propagate conservatism, a scalar factor could be applied to the constant shear stress values of the initial or final orientations formulated by traditional methods to estimate the maximum shear stress at the midpoint of the twist. In this particular problem, the scalar factor is approximately 8/3. Additional case studies of beam geometries should be performed to confirm the validity of this value and method. Refining the tensile and shear stress equations could be possible by using the methodology of Timoshenko, where plane sections do not necessarily remain plane, as demonstrated in Chapter 12 of Reference [d]. 59 4. Summary and Conclusion Based on comparison of theoretical results to FEA results, application of classical beam theory to twisted cantilever beams of rectangular cross-section is only useful in calculating vertical displacement values, derived from the curvature of the beam at its neutral surface. This approach is the beginning of the direct method. The vertical displacement function developed correlates very well with FEA results. The theoretical curve follows a smooth, negative-cubic shape along its length as would be expected with a cantilever beam. However, classical beam theory does not leave room for deformation coupling, non-planar cross-sections, and gives no method of solving for the out-of-plane displacements that FEA predicts. When the indirect method is used to calculate stresses and strains in the twisted region of the cantilever beam, the results of this document demonstrate that classical beam theory is not applicable. If the exact stress distribution was needed within the twisted region, using the indirect method and classical beam theory would not predict reliable values. The margin of error within the twisted region is too great to be safely applied to real applications of twisted cantilever beams. A possible explanation for the stress calculation error is that cross-sections of the beam that begin plane are not remaining plane under load and subsequent displacement, which is a critical assumption of classical beam theory. A non-planar section becomes evident by studying the FEA rotational and displacement results at the end of the twist, presented in Figure 27. Because the beam’s cross-section is being distorted as a result of the applied load, a key stipulation of beam theory is obviously not being satisfied. The theoretical stress and strain functions derived by this document are not recommended for detailed analyses. However, based on the applied load and beam geometry, the results presented herein suggest that the method of calculating vertical displacement gives reasonable results. These displacement results could be applied to the strain-displacement equations (section 1.3.2), and then to the stress-strain equations (section 1.3.3) to approximate stress and strain values within the beam’s twisted region. 60 Note that although the vertical displacement functions derived are very close to FEA results, full application of the direct method to find stresses and strains will still be an approximation. Under an applied load, FEA shows that the beam experiences out-ofplane displacement. This z-displacement will contribute to the stress and strain distribution throughout the beam, though its magnitude is much less than the vertical displacements’. Therefore, applying the direct method to calculate stresses will not yield exact results, but could be used to estimate stress and strain values within the beam’s twisted region. 61 5. Appendix A – Theoretical Results at Selected x Values x1 x = 0”, y = 0” Tensile Stress, σxx (Equation [69]) 0 psi Shear Stress, τxy (Equation [71]) -60 psi Longitudinal Strain, εxx (Equation [75]) 0 in/in Shear Strain, εxy (Equation [78]) -2.600 x 10-6 in/in Vertical Displacement, v (Equation [82]) 0.000 in x = 0”, y = 0.5” Tensile Stress, σxx (Equation [69]) 1,800 psi Shear Stress, τxy (Equation [71]) 0 psi Longitudinal Strain, εxx (Equation [75]) 6.000 x 10-5 in/in Shear Strain, εxy (Equation [78]) 0 in/in Vertical Displacement, v (Equation [82]) 0.000 in x = 0”, y = -0.5” Tensile Stress, σxx (Equation [69]) -1,800 psi Shear Stress, τxy (Equation [71]) 0 psi Longitudinal Strain, εxx (Equation [75]) -6.000 x 10-5 in/in Shear Strain, εxy (Equation [78]) 0 in/in Vertical Displacement, v (Equation [82]) 0.000 in 62 x2 x = 3.00”, y = 0” Tensile Stress, σxx (Equation [69]) 0 psi Shear Stress, τxy (Equation [71]) -60 psi Longitudinal Strain, εxx (Equation [75]) 0 in/in Shear Strain, εxy (Equation [78]) -2.600 x 10-6 in/in Vertical Displacement, v (Equation [82]) -4.680 x 10-4 in x = 3.00”, y = 0.5” Tensile Stress, σxx (Equation [69]) 1,080 psi Shear Stress, τxy (Equation [71]) 0 psi Longitudinal Strain, εxx (Equation [75]) 3.600 x 10-5 in/in Shear Strain, εxy (Equation [78]) 0 in/in Vertical Displacement, v (Equation [82]) -4.680 x 10-4 in x = 3.00”, y = -0.5” Tensile Stress, σxx (Equation [69]) -1,080 psi Shear Stress, τxy (Equation [71]) 0 psi Longitudinal Strain, εxx (Equation [75]) -3.600 x 10-5 in/in Shear Strain, εxy (Equation [78]) 0 in/in Vertical Displacement, v (Equation [82]) -4.680 x 10-4 in 63 x3 x = 3.75”, y = 0” Tensile Stress, σxx (Equation [69]) 0 psi Shear Stress, τxy (Equation [73]) -14.12 psi Longitudinal Strain, εxx (Equation [75]) 0 in/in Shear Strain, εxy (Equation [80]) -6.118 x 10-7 in/in Vertical Displacement, v (Equation [83]) -7.297x 10-4 in x = 3.75”, y = = 0.1768” Tensile Stress, σxx (Equation [69]) 599.0 psi Shear Stress, τxy (Equation [73]) 0 psi Longitudinal Strain, εxx (Equation [75]) 1.997 x 10-5 in/in Shear Strain, εxy (Equation [80]) 0 in/in Vertical Displacement, v (Equation [83]) -7.297x 10-4 in x = 3.75”, y = - = -0.1768” Tensile Stress, σxx (Equation [69]) -599.0 psi Shear Stress, τxy (Equation [73]) 0 psi Longitudinal Strain, εxx (Equation [75]) -1.997 x 10-5 in/in Shear Strain, εxy (Equation [80]) 0 in/in Vertical Displacement, v (Equation [83]) -7.297x 10-4 in 64 x4 x = 4.50”, y = 0” Tensile Stress, σxx (Equation [69]) 0 psi Shear Stress, τxy (Equation [74]) -60 psi Longitudinal Strain, εxx (Equation [75]) 0 in/in Shear Strain, εxy (Equation [81]) -2.600 x 10-6 in/in Vertical Displacement, v (Equation [84]) -1.382 x 10-3 in x = 4.50”, y = 0.125” Tensile Stress, σxx (Equation [69]) 2,880 psi Shear Stress, τxy (Equation [74]) 0 psi Longitudinal Strain, εxx (Equation [75]) 9.600 x 10-5 in/in Shear Strain, εxy (Equation [81]) 0 in/in Vertical Displacement, v (Equation [84]) -1.382 x 10-3 in x = 4.50”, y = -0.125” Tensile Stress, σxx (Equation [69]) -2,880 psi Shear Stress, τxy (Equation [74]) 0 psi Longitudinal Strain, εxx (Equation [75]) -9.600 x 10-5 in/in Shear Strain, εxy (Equation [81]) 0 in/in Vertical Displacement, v (Equation [84]) -1.382 x 10-3 in 65 x5 x = 7.50”, y = 0” Tensile Stress, σxx (Equation [69]) 0 psi Shear Stress, τxy (Equation [74]) -60 psi Longitudinal Strain, εxx (Equation [75]) 0 in/in Shear Strain, εxy (Equation [81]) -2.600 x 10-6 in/in Vertical Displacement, v (Equation [84]) -6.665 x 10-3 in x = 7.50”, y = 0.125” Tensile Stress, σxx (Equation [69]) 0 psi Shear Stress, τxy (Equation [74]) 0 psi Longitudinal Strain, εxx (Equation [75]) 0 in/in Shear Strain, εxy (Equation [81]) 0 in/in Vertical Displacement, v (Equation [84]) -6.665 x 10-3 in x = 7.50”, y = -0.125” Tensile Stress, σxx (Equation [69]) 0 psi Shear Stress, τxy (Equation [74]) 0 psi Longitudinal Strain, εxx (Equation [75]) 0 in/in Shear Strain, εxy (Equation [81]) 0 in/in Vertical Displacement, v (Equation [84]) -6.665 x 10-3 in 66 6. Appendix B – FEA Results at Selected x Values x1 x = 0”, y = 0” Tensile Stress, σxx -3.691 psi Shear Stress, τxy -62.26 psi Longitudinal Strain, εxx -1.096 x 10-11 in/in Shear Strain, εxy -3.676 x 10-6 in/in Vertical Displacement, v 0.000 in x = 0”, y = 0.5” Tensile Stress, σxx 1,717 psi Shear Stress, τxy -150.7 psi Longitudinal Strain, εxx 5.527 x 10-5 in/in Shear Strain, εxy -1.306 x 10-5 in/in Vertical Displacement, v 0.000 in x = 0”, y = -0.5” Tensile Stress, σxx -1,719 psi Shear Stress, τxy -150.0 psi Longitudinal Strain, εxx -5.533 x 10-5 in/in Shear Strain, εxy -1.300 x 10-5 in/in Vertical Displacement, v 0.000 in 67 x2 x = 3.00”, y = 0” Tensile Stress, σxx -204.8 psi Shear Stress, τxy -51.12 psi Longitudinal Strain, εxx -7.470 x 10-8in/in Shear Strain, εxy -4.460 x 10-6 in/in Vertical Displacement, v -4.812 x 10-6 in x = 3.00”, y = 0.5” Tensile Stress, σxx 818.1 psi Shear Stress, τxy 35.16 psi Longitudinal Strain, εxx 3.225 x 10-5 in/in Shear Strain, εxy -1.502 x 10-6 in/in Vertical Displacement, v -4.840 x 10-6 in x = 3.00”, y = -0.5” Tensile Stress, σxx -850.3 psi Shear Stress, τxy -68.46 psi Longitudinal Strain, εxx -3.230 x 10-5 in/in Shear Strain, εxy -1.453 x 10-6 in/in Vertical Displacement, v -4.840 x 10-6 in 68 x3 x = 3.75”, y = 0” Tensile Stress, σxx -9.876 psi Shear Stress, τxy -162.9 psi Longitudinal Strain, εxx -5.360 x 10-7 in/in Shear Strain, εxy -1.411 x 10-5 in/in Vertical Displacement, v -7.589 x 10-4 in x = 3.75”, y = = 0.1768” Tensile Stress, σxx 2,719 psi Shear Stress, τxy -852.9 psi Longitudinal Strain, εxx 8.139 x 10-5 in/in Shear Strain, εxy -7.471 x 10-5 in/in Vertical Displacement, v -7.561 x 10-4 in x = 3.75”, y = - = -0.1768” Tensile Stress, σxx -2,576 psi Shear Stress, τxy -844.8 psi Longitudinal Strain, εxx -8.267 x 10-5 in/in Shear Strain, εxy -8.848 x 10-5 in/in Vertical Displacement, v -7.560 x 10-4 in 69 x4 x = 4.50”, y = 0” Tensile Stress, σxx -0.7396 psi Shear Stress, τxy -66.70 psi Longitudinal Strain, εxx -2.047 x 10-8 in/in Shear Strain, εxy -5.780 x 10-6 in/in Vertical Displacement, v -1.352 x 10-3 in x = 4.50”, y = 0.125” Tensile Stress, σxx 2,929 psi Shear Stress, τxy -70.85 psi Longitudinal Strain, εxx 9.758 x 10-5 in/in Shear Strain, εxy -6.052 x 10-6 in/in Vertical Displacement, v -1.352 x 10-3 in x = 4.50”, y = -0.125” Tensile Stress, σxx -2,930 psi Shear Stress, τxy -62.54 psi Longitudinal Strain, εxx -9.762 x 10-5 in/in Shear Strain, εxy -5.509 x 10-6 in/in Vertical Displacement, v -1.352 x 10-3 in 70 x5 x = 7.50”, y = 0” Tensile Stress, σxx 8.282 x 10-6 psi Shear Stress, τxy -58.87 psi Longitudinal Strain, εxx -5.136 x 10-6 in/in Shear Strain, εxy x 10-6 in/in Vertical Displacement, v -6.986 x 10-3 in x = 7.50”, y = 0.125” Tensile Stress, σxx 47.86 psi Shear Stress, τxy 0.3965 psi Longitudinal Strain, εxx 2.559 x 10-6 in/in Shear Strain, εxy 3.436 x 10-8 in/in Vertical Displacement, v -6.986 x 10-3 in x = 7.50”, y = -0.125” Tensile Stress, σxx -47.86 psi Shear Stress, τxy -0.3965 psi Longitudinal Strain, εxx -2.559 x 10-6 in/in Shear Strain, εxy -3.436 x 10-8 in/in Vertical Displacement, v -6.986 x 10-3 in 71 7. Appendix C – ABAQUS Input File (.inp) *Heading ProjectLoad ** Job name: TFBshell Model name: TFBshell *Preprint, echo=YES, model=YES, history=NO, contact=NO ** ** PARTS ** *Part, name=TFBshell *Node 1, 0.5, 0., 7.5 2, -0.5, 0., 7.5 3, -0.5, 0., 4.5 4, 0., 0., 4.5 5, 0.5, 0., 4.5 6, -0.353553385, 0.353553385, 3.75 7, 0.353553385, -0.353553385, 3.75 8, 0., 0.5, 3. 9, 0., 0., 3. 10, 0., -0.5, 3. 11, 0., 0.5, 0. 12, 0., -0.5, 0. 13, 0.400000006, 0., 7.5 14, 0.300000012, 0., 7.5 15, 0.200000003, 0., 7.5 16, 0.100000001, 0., 7.5 17, 0., 0., 7.5 18, -0.100000001, 0., 7.5 19, -0.200000003, 0., 7.5 20, -0.300000012, 0., 7.5 21, -0.400000006, 0., 7.5 22, -0.5, 0., 7.4000001 23, -0.5, 0., 7.30000019 24, -0.5, 0., 7.19999981 25, -0.5, 0., 7.0999999 26, -0.5, 0., 7. 27, -0.5, 0., 6.9000001 28, -0.5, 0., 6.80000019 29, -0.5, 0., 6.69999981 30, -0.5, 0., 6.5999999 31, -0.5, 0., 6.5 32, -0.5, 0., 6.4000001 33, -0.5, 0., 6.30000019 34, -0.5, 0., 6.19999981 35, -0.5, 0., 6.0999999 36, -0.5, 0., 6. 37, -0.5, 0., 5.9000001 38, -0.5, 0., 5.80000019 39, -0.5, 0., 5.69999981 40, -0.5, 0., 5.5999999 41, -0.5, 0., 5.5 42, -0.5, 0., 5.4000001 43, -0.5, 0., 5.30000019 44, -0.5, 0., 5.19999981 45, -0.5, 0., 5.0999999 46, -0.5, 0., 5. 47, -0.5, 0., 4.9000001 48, -0.5, 0., 4.80000019 49, -0.5, 0., 4.69999981 50, -0.5, 0., 4.5999999 51, -0.400000006, 0., 4.5 52, -0.300000012, 0., 4.5 53, -0.200000003, 0., 4.5 54, -0.100000001, 0., 4.5 55, 0.100000001, 0., 4.5 56, 0.200000003, 0., 4.5 57, 0.300000012, 0., 4.5 58, 0.400000006, 0., 4.5 72 59, 0.5, 0., 4.5999999 60, 0.5, 0., 4.69999981 61, 0.5, 0., 4.80000019 62, 0.5, 0., 4.9000001 63, 0.5, 0., 5. 64, 0.5, 0., 5.0999999 65, 0.5, 0., 5.19999981 66, 0.5, 0., 5.30000019 67, 0.5, 0., 5.4000001 68, 0.5, 0., 5.5 69, 0.5, 0., 5.5999999 70, 0.5, 0., 5.69999981 71, 0.5, 0., 5.80000019 72, 0.5, 0., 5.9000001 73, 0.5, 0., 6. 74, 0.5, 0., 6.0999999 75, 0.5, 0., 6.19999981 76, 0.5, 0., 6.30000019 77, 0.5, 0., 6.4000001 78, 0.5, 0., 6.5 79, 0.5, 0., 6.5999999 80, 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-0.0667613223, 2.44523573 *Element, type=S3 1, 383, 399, 473 2, 468, 426, 455 3, 441, 436, 440 4, 460, 442, 458 325, 542, 500, 499 326, 540, 509, 501 403, 601, 566, 602 404, 603, 555, 562 *Element, type=S4R 84 5, 75, 76, 224, 200 6, 249, 224, 76, 77 7, 19, 207, 262, 18 8, 66, 67, 218, 202 9, 79, 80, 204, 251 10, 263, 253, 205, 322 11, 56, 211, 264, 55 12, 208, 20, 21, 283 13, 20, 208, 207, 19 14, 22, 283, 21, 2 15, 50, 3, 51, 234 16, 234, 51, 52, 233 17, 233, 232, 265, 302 18, 49, 303, 266, 48 19, 267, 47, 48, 266 20, 304, 268, 235, 477 21, 235, 57, 58, 477 22, 62, 63, 212, 285 23, 433, 400, 404, 452 24, 267, 327, 269, 209 25, 214, 212, 63, 64 26, 46, 209, 213, 45 27, 202, 216, 65, 66 28, 67, 68, 239, 218 29, 307, 240, 220, 310 30, 222, 244, 72, 73 31, 312, 244, 222, 314 32, 247, 222, 73, 74 33, 36, 245, 246, 35 34, 203, 249, 77, 78 35, 32, 201, 225, 31 36, 30, 250, 226, 29 37, 253, 263, 272, 204 38, 254, 26, 27, 227 39, 229, 228, 273, 274 40, 24, 229, 230, 23 41, 4, 210, 231, 54 42, 53, 232, 233, 52 43, 5, 59, 477, 58 44, 57, 235, 211, 56 45, 304, 236, 347, 268 46, 217, 43, 44, 215 47, 237, 42, 43, 217 48, 289, 305, 217, 215 49, 40, 219, 241, 39 50, 39, 241, 242, 38 51, 244, 243, 71, 72 52, 315, 247, 200, 294 53, 37, 221, 245, 36 54, 200, 247, 74, 75 55, 223, 34, 35, 246 56, 316, 249, 203, 278 57, 319, 251, 204, 272 58, 29, 226, 252, 28 59, 81, 82, 205, 253 60, 83, 84, 257, 255 61, 321, 299, 254, 227 62, 17, 206, 256, 16 63, 255, 279, 322, 205 64, 206, 262, 328, 280 65, 15, 258, 259, 14 66, 259, 258, 281, 282 67, 14, 259, 261, 13 68, 87, 1, 13, 261 69, 201, 32, 33, 248 70, 248, 33, 34, 223 71, 215, 44, 45, 213 72, 78, 79, 251, 203 73, 80, 81, 253, 204 74, 250, 30, 31, 225 85 75, 82, 83, 255, 205 76, 28, 252, 227, 27 77, 206, 17, 18, 262 78, 26, 254, 228, 25 79, 25, 228, 229, 24 80, 209, 46, 47, 267 81, 336, 363, 385, 327 82, 210, 4, 55, 264 83, 387, 386, 353, 346 84, 284, 330, 329, 301 85, 269, 287, 213, 209 86, 64, 65, 216, 214 87, 355, 364, 289, 287 88, 215, 213, 287, 289 89, 331, 332, 290, 291 90, 218, 306, 291, 202 91, 220, 240, 69, 70 92, 219, 40, 41, 238 93, 238, 41, 42, 237 94, 70, 71, 243, 220 95, 221, 37, 38, 242 96, 276, 293, 246, 245 97, 315, 294, 375, 376 98, 223, 246, 293, 295 99, 333, 334, 293, 276 100, 201, 248, 296, 297 101, 317, 318, 250, 225 102, 298, 321, 227, 252 103, 300, 335, 207, 208 104, 274, 300, 230, 229 105, 230, 300, 208, 283 106, 232, 231, 301, 265 107, 54, 231, 232, 53 108, 336, 327, 267, 266 109, 50, 234, 303, 49 110, 59, 60, 304, 477 111, 60, 61, 236, 304 112, 61, 62, 285, 236 113, 268, 347, 387, 346 114, 327, 385, 356, 269 115, 239, 270, 306, 218 116, 240, 239, 68, 69 117, 243, 271, 310, 220 118, 275, 308, 219, 238 119, 308, 275, 338, 368 120, 241, 219, 308, 309 121, 314, 222, 247, 315 122, 309, 311, 242, 241 123, 294, 200, 224, 277 124, 297, 296, 361, 377 125, 295, 293, 334, 340 126, 379, 378, 320, 318 127, 279, 255, 257, 324 128, 280, 323, 256, 206 129, 16, 256, 258, 15 130, 281, 323, 342, 384 131, 343, 384, 342, 392 132, 260, 257, 84, 85 133, 260, 85, 86, 326 134, 326, 261, 259, 282 135, 87, 261, 326, 86 136, 389, 344, 352, 390 137, 268, 346, 211, 235 138, 231, 210, 284, 301 139, 266, 303, 302, 336 140, 236, 285, 354, 347 141, 290, 216, 202, 291 142, 310, 271, 371, 367 143, 270, 239, 240, 307 144, 271, 243, 244, 312 86 145, 225, 201, 297, 317 146, 262, 207, 335, 328 147, 228, 254, 299, 273 148, 238, 237, 292, 275 149, 245, 221, 313, 276 150, 248, 223, 295, 296 151, 277, 224, 249, 316 152, 278, 203, 251, 319 153, 380, 272, 263, 341 154, 325, 384, 343, 324 155, 299, 321, 345, 352 156, 325, 324, 257, 260 157, 323, 281, 258, 256 158, 260, 326, 282, 325 159, 283, 22, 23, 230 160, 264, 353, 284, 210 161, 286, 212, 214, 288 162, 286, 354, 285, 212 163, 288, 214, 216, 290 164, 364, 365, 305, 289 165, 355, 287, 269, 356 166, 433, 452, 472, 453 167, 237, 217, 305, 292 168, 292, 305, 365, 357 169, 348, 366, 270, 307 170, 374, 369, 312, 314 171, 407, 423, 359, 360 172, 296, 295, 340, 361 173, 377, 362, 317, 297 174, 252, 226, 320, 298 175, 392, 342, 383, 473 176, 233, 302, 303, 234 177, 363, 336, 302, 265 178, 366, 358, 306, 270 179, 367, 348, 307, 310 180, 369, 371, 271, 312 181, 309, 308, 368, 370 182, 371, 369, 419, 394 183, 338, 401, 416, 368 184, 221, 242, 311, 313 185, 370, 372, 311, 309 186, 314, 315, 376, 374 187, 360, 359, 277, 316 188, 359, 375, 294, 277 189, 340, 391, 396, 361 190, 362, 379, 318, 317 191, 380, 341, 478, 397 192, 226, 250, 318, 320 193, 319, 272, 380, 350 194, 298, 320, 378, 381 195, 279, 351, 382, 322 196, 351, 279, 324, 343 197, 280, 383, 342, 323 198, 282, 281, 384, 325 199, 265, 301, 329, 363 200, 274, 273, 344, 349 201, 284, 353, 386, 330 202, 288, 290, 332, 337 203, 291, 306, 358, 331 204, 456, 393, 412, 440 205, 276, 313, 373, 333 206, 339, 360, 316, 278 207, 300, 274, 349, 335 208, 344, 389, 399, 349 209, 400, 387, 347, 354 210, 286, 288, 337, 404 211, 275, 292, 357, 338 212, 414, 406, 366, 348 213, 278, 319, 350, 339 214, 334, 402, 391, 340 87 215, 263, 322, 382, 341 216, 473, 399, 389, 449 217, 349, 399, 328, 335 218, 299, 352, 344, 273 219, 321, 298, 381, 345 220, 345, 403, 390, 352 221, 264, 211, 346, 353 222, 400, 433, 386, 387 223, 404, 400, 354, 286 224, 406, 412, 358, 366 225, 464, 465, 421, 423 226, 396, 445, 466, 425 227, 397, 409, 350, 380 228, 385, 363, 329, 405 229, 355, 388, 411, 364 230, 440, 436, 457, 456 231, 481, 413, 357, 365 232, 414, 442, 441, 406 233, 394, 415, 367, 371 234, 441, 442, 460, 436 235, 374, 376, 424, 417 236, 370, 395, 418, 372 237, 417, 419, 369, 374 238, 443, 422, 420, 444 239, 313, 311, 372, 373 240, 423, 421, 375, 359 241, 391, 437, 445, 396 242, 361, 396, 425, 377 243, 447, 438, 407, 408 244, 378, 410, 427, 381 245, 377, 425, 426, 362 246, 430, 448, 429, 478 247, 431, 470, 471, 432 248, 383, 280, 328, 399 249, 405, 329, 330, 453 250, 398, 332, 331, 393 251, 355, 356, 474, 388 252, 403, 345, 381, 427 253, 402, 334, 333, 422 254, 331, 358, 412, 393 255, 462, 419, 417, 463 256, 395, 370, 368, 416 257, 408, 407, 360, 339 258, 434, 388, 475, 435 259, 337, 332, 398, 479 260, 452, 404, 337, 479 261, 401, 338, 357, 413 262, 422, 333, 373, 420 263, 463, 451, 443, 462 264, 382, 431, 432, 341 265, 386, 433, 453, 330 266, 365, 364, 411, 481 267, 339, 350, 409, 408 268, 454, 467, 429, 448 269, 455, 438, 447, 482 270, 410, 378, 379, 428 271, 428, 379, 362, 426 272, 440, 412, 406, 441 273, 457, 413, 481, 434 274, 415, 414, 348, 367 275, 416, 460, 458, 395 276, 394, 450, 459, 415 277, 401, 436, 460, 416 278, 372, 418, 420, 373 279, 395, 458, 461, 418 280, 462, 443, 444, 450 281, 376, 375, 421, 424 282, 465, 445, 437, 446 283, 407, 438, 464, 423 284, 438, 455, 466, 464 88 285, 467, 468, 480, 429 286, 427, 439, 469, 403 287, 471, 470, 469, 439 288, 431, 382, 351, 476 289, 341, 432, 430, 478 290, 385, 405, 474, 356 291, 434, 481, 411, 388 292, 435, 398, 393, 456 293, 449, 389, 390, 470 294, 476, 392, 473, 449 295, 474, 405, 453, 472 296, 436, 401, 413, 457 297, 437, 391, 402, 451 298, 451, 402, 422, 443 299, 408, 409, 482, 447 300, 439, 427, 410, 454 301, 454, 410, 428, 467 302, 442, 414, 415, 459 303, 444, 420, 418, 461 304, 424, 446, 463, 417 305, 419, 462, 450, 394 306, 464, 466, 445, 465 307, 446, 424, 421, 465 308, 446, 437, 451, 463 309, 409, 397, 480, 482 310, 468, 455, 482, 480 311, 430, 432, 471, 448 312, 439, 454, 448, 471 313, 343, 392, 476, 351 314, 403, 469, 470, 390 315, 459, 461, 458, 442 316, 475, 472, 452, 479 317, 428, 426, 468, 467 318, 455, 426, 425, 466 319, 475, 388, 474, 472 320, 434, 435, 456, 457 321, 461, 459, 450, 444 322, 449, 470, 431, 476 323, 398, 435, 475, 479 324, 397, 478, 429, 480 327, 522, 98, 99, 534 328, 521, 522, 514, 513 329, 514, 507, 541, 513 330, 505, 506, 498, 497 331, 497, 90, 91, 505 332, 505, 91, 92, 512 333, 538, 537, 513, 541 334, 97, 521, 520, 96 335, 521, 97, 98, 522 336, 89, 90, 497, 490 337, 497, 498, 491, 490 338, 498, 499, 492, 491 339, 499, 500, 493, 492 340, 500, 539, 494, 493 341, 495, 501, 502, 535 342, 503, 496, 535, 502 343, 526, 504, 108, 109 344, 526, 529, 489, 496 345, 110, 5, 58, 529 346, 4, 54, 486, 533 347, 493, 494, 533, 486 348, 483, 88, 89, 490 349, 490, 491, 484, 483 350, 491, 492, 485, 484 351, 492, 493, 486, 485 352, 54, 53, 485, 486 353, 484, 485, 53, 52 354, 52, 51, 483, 484 355, 92, 93, 519, 512 356, 96, 520, 532, 95 89 357, 519, 532, 520, 537 358, 519, 93, 94, 532 359, 95, 532, 94, 6 360, 534, 99, 100, 523 361, 522, 534, 515, 514 362, 540, 508, 515, 516 363, 540, 501, 539, 508 364, 500, 507, 508, 539 365, 514, 515, 508, 507 366, 516, 515, 534, 523 367, 530, 527, 105, 106 368, 527, 518, 525, 531 369, 528, 511, 536, 530 370, 528, 504, 503, 511 371, 107, 108, 504, 528 372, 102, 525, 524, 101 373, 7, 104, 531, 103 374, 487, 488, 56, 55 375, 489, 488, 535, 496 376, 503, 504, 526, 496 377, 529, 526, 109, 110 378, 489, 529, 58, 57 379, 488, 489, 57, 56 380, 494, 495, 487, 533 381, 501, 495, 494, 539 382, 533, 487, 55, 4 383, 488, 487, 495, 535 384, 506, 542, 499, 498 385, 510, 502, 501, 509 386, 510, 518, 536, 511 387, 502, 510, 511, 503 388, 538, 506, 505, 512 389, 542, 541, 507, 500 390, 510, 509, 517, 518 391, 518, 517, 524, 525 392, 521, 513, 537, 520 393, 517, 509, 540, 516 394, 517, 516, 523, 524 395, 527, 530, 536, 518 396, 101, 524, 523, 100 397, 88, 483, 51, 3 398, 102, 103, 531, 525 399, 104, 105, 527, 531 400, 107, 528, 530, 106 401, 519, 537, 538, 512 402, 538, 541, 542, 506 405, 549, 556, 591, 585 406, 586, 547, 548, 594 407, 100, 99, 592, 586 408, 543, 111, 112, 550 409, 112, 113, 557, 550 410, 558, 557, 564, 565 411, 574, 573, 581, 596 412, 596, 582, 575, 574 413, 122, 582, 596, 9 414, 582, 122, 123, 583 415, 124, 584, 583, 123 416, 577, 576, 583, 584 417, 570, 569, 576, 577 418, 605, 563, 562, 561 419, 603, 562, 563, 556 420, 556, 549, 548, 603 421, 594, 593, 102, 101 422, 598, 592, 546, 553 423, 99, 98, 546, 592 424, 98, 97, 545, 546 425, 95, 6, 111, 543 426, 557, 113, 114, 564 427, 564, 571, 600, 565 428, 573, 572, 580, 581 90 429, 121, 581, 580, 120 430, 581, 121, 9, 596 431, 564, 114, 115, 571 432, 599, 572, 601, 600 433, 579, 119, 120, 580 434, 115, 116, 578, 571 435, 119, 579, 595, 118 436, 578, 595, 579, 599 437, 578, 116, 117, 595 438, 118, 595, 117, 8 439, 584, 124, 125, 587 440, 127, 590, 587, 126 441, 126, 587, 125, 10 442, 129, 589, 588, 128 443, 130, 591, 589, 129 444, 584, 587, 590, 577 445, 570, 588, 589, 563 446, 589, 591, 556, 563 447, 585, 597, 593, 549 448, 7, 103, 597, 132 449, 96, 95, 543, 544 450, 549, 593, 594, 548 451, 97, 96, 544, 545 452, 544, 543, 550, 551 453, 552, 551, 558, 559 454, 567, 604, 602, 566 455, 568, 567, 574, 575 456, 576, 575, 582, 583 457, 545, 544, 551, 552 458, 560, 553, 552, 559 459, 560, 568, 561, 554 460, 569, 568, 575, 576 461, 546, 545, 552, 553 462, 553, 560, 554, 598 463, 570, 563, 605, 569 464, 592, 598, 547, 586 465, 555, 554, 561, 562 466, 547, 555, 603, 548 467, 551, 550, 557, 558 468, 559, 558, 565, 602 469, 567, 566, 573, 574 470, 554, 555, 547, 598 471, 560, 604, 567, 568 472, 604, 560, 559, 602 473, 561, 568, 569, 605 474, 588, 570, 577, 590 475, 572, 573, 566, 601 476, 580, 572, 599, 579 477, 586, 594, 101, 100 478, 585, 131, 132, 597 479, 593, 597, 103, 102 480, 590, 127, 128, 588 481, 591, 130, 131, 585 482, 571, 578, 599, 600 483, 601, 602, 565, 600 484, 634, 187, 188, 658 485, 658, 188, 189, 608 486, 614, 191, 192, 662 487, 664, 194, 195, 666 488, 628, 178, 179, 648 489, 612, 121, 120, 615 490, 121, 612, 611, 9 491, 118, 8, 133, 672 492, 640, 639, 673, 713 493, 11, 162, 887, 161 494, 162, 163, 674, 887 495, 164, 165, 618, 617 496, 617, 714, 739, 674 497, 644, 717, 675, 643 498, 173, 620, 621, 172 91 499, 717, 752, 777, 675 500, 158, 641, 642, 157 501, 175, 624, 622, 174 502, 177, 610, 626, 176 503, 156, 623, 625, 155 504, 648, 179, 180, 649 505, 184, 632, 653, 183 506, 653, 632, 724, 678 507, 185, 656, 632, 184 508, 654, 147, 148, 631 509, 143, 607, 635, 142 510, 660, 614, 696, 679 511, 140, 636, 661, 139 512, 664, 666, 689, 680 513, 137, 663, 638, 136 514, 136, 638, 639, 135 515, 118, 672, 613, 119 516, 616, 160, 161, 887 517, 159, 697, 641, 158 518, 676, 619, 643, 675 519, 619, 618, 165, 166 520, 167, 168, 644, 643 521, 677, 682, 622, 624 522, 172, 621, 645, 171 523, 621, 683, 699, 645 524, 170, 12, 171, 645 525, 627, 154, 155, 625 526, 647, 646, 684, 685 527, 178, 628, 610, 177 528, 151, 629, 650, 150 529, 150, 650, 651, 149 530, 629, 647, 685, 721 531, 633, 655, 706, 707 532, 186, 606, 656, 185 533, 633, 145, 146, 655 534, 696, 732, 750, 741 535, 139, 661, 637, 138 536, 193, 609, 662, 192 537, 138, 637, 663, 137 538, 666, 195, 196, 668 539, 668, 736, 689, 666 540, 9, 611, 665, 122 541, 695, 711, 742, 760 542, 755, 736, 737, 794 543, 123, 667, 669, 124 544, 669, 667, 691, 692 545, 124, 669, 671, 125 546, 199, 10, 125, 671 547, 725, 723, 758, 743 548, 606, 186, 187, 634 549, 607, 143, 144, 657 550, 657, 144, 145, 633 551, 608, 189, 190, 660 552, 660, 190, 191, 614 553, 609, 193, 194, 664 554, 690, 611, 612, 694 555, 615, 120, 119, 613 556, 639, 638, 695, 673 557, 135, 639, 640, 134 558, 141, 659, 636, 140 559, 614, 662, 732, 696 560, 163, 164, 617, 674 561, 160, 616, 697, 159 562, 166, 167, 643, 619 563, 677, 744, 776, 682 564, 174, 622, 620, 173 565, 624, 175, 176, 626 566, 715, 700, 623, 642 567, 623, 156, 157, 642 568, 740, 745, 681, 676 92 569, 626, 610, 703, 701 570, 814, 747, 764, 800 571, 704, 705, 753, 764 572, 154, 627, 646, 153 573, 181, 630, 649, 180 574, 705, 704, 628, 648 575, 629, 151, 152, 647 576, 647, 152, 153, 646 577, 630, 181, 182, 652 578, 652, 182, 183, 653 579, 631, 148, 149, 651 580, 743, 748, 693, 725 581, 693, 706, 655, 654 582, 655, 146, 147, 654 583, 767, 749, 707, 706 584, 142, 635, 659, 141 585, 657, 633, 707, 708 586, 732, 733, 791, 750 587, 711, 734, 772, 742 588, 713, 712, 615, 613 589, 672, 640, 713, 613 590, 618, 681, 714, 617 591, 641, 697, 751, 698 592, 644, 168, 169, 699 593, 682, 716, 620, 622 594, 170, 645, 699, 169 595, 683, 716, 752, 717 596, 700, 702, 625, 623 597, 722, 719, 630, 652 598, 719, 720, 649, 630 599, 796, 779, 778, 805 600, 678, 722, 652, 653 601, 650, 629, 721, 686 602, 632, 656, 726, 724 603, 631, 651, 723, 725 604, 687, 727, 606, 634 605, 679, 728, 608, 660 606, 728, 679, 788, 754 607, 607, 657, 708, 709 608, 688, 731, 636, 659 609, 662, 609, 733, 732 610, 680, 733, 609, 664 611, 731, 710, 661, 636 612, 668, 196, 197, 670 613, 665, 611, 690, 735 614, 122, 665, 667, 123 615, 689, 736, 755, 773 616, 670, 197, 198, 738 617, 738, 671, 669, 692 618, 199, 671, 738, 198 619, 672, 133, 134, 640 620, 638, 663, 711, 695 621, 712, 694, 612, 615 622, 616, 887, 674, 739 623, 619, 676, 681, 618 624, 624, 626, 701, 677 625, 804, 745, 740, 849 626, 686, 723, 651, 650 627, 734, 711, 663, 637 628, 739, 714, 798, 751 629, 716, 683, 621, 620 630, 644, 699, 683, 717 631, 646, 627, 718, 684 632, 704, 703, 610, 628 633, 721, 685, 781, 757 634, 757, 783, 686, 721 635, 634, 658, 729, 687 636, 659, 635, 730, 688 637, 755, 794, 759, 809 638, 760, 799, 774, 775 93 639, 737, 736, 668, 670 640, 735, 691, 667, 665 641, 670, 738, 692, 737 642, 654, 631, 725, 693 643, 710, 734, 637, 661 644, 688, 730, 769, 789 645, 715, 642, 641, 698 646, 746, 700, 715, 756 647, 746, 763, 702, 700 648, 627, 625, 702, 718 649, 819, 876, 843, 816 650, 648, 649, 720, 705 651, 718, 702, 763, 765 652, 818, 795, 870, 844 653, 706, 693, 748, 767 654, 836, 787, 768, 821 655, 709, 708, 770, 771 656, 771, 770, 803, 815 657, 749, 770, 708, 707 658, 635, 607, 709, 730 659, 761, 792, 710, 731 660, 760, 742, 845, 799 661, 713, 673, 775, 712 662, 829, 849, 740, 777 663, 777, 752, 776, 829 664, 678, 724, 784, 782 665, 720, 719, 779, 780 666, 778, 779, 719, 722 667, 765, 766, 684, 718 668, 783, 758, 723, 686 669, 782, 806, 805, 778 670, 727, 726, 656, 606 671, 687, 729, 768, 787 672, 727, 687, 787, 785 673, 784, 807, 806, 782 674, 658, 608, 728, 729 675, 741, 788, 679, 696 676, 789, 769, 808, 839 677, 689, 773, 790, 680 678, 792, 772, 734, 710 679, 692, 691, 794, 737 680, 616, 739, 751, 697 681, 740, 676, 675, 777 682, 776, 752, 716, 682 683, 792, 761, 842, 810 684, 774, 694, 712, 775 685, 793, 774, 799, 811 686, 701, 762, 744, 677 687, 701, 703, 747, 762 688, 798, 828, 698, 751 689, 703, 704, 764, 747 690, 754, 768, 729, 728 691, 802, 812, 767, 748 692, 888, 864, 858, 885 693, 705, 720, 780, 753 694, 876, 875, 850, 843 695, 691, 735, 759, 794 696, 715, 698, 828, 756 697, 781, 766, 819, 816 698, 782, 778, 722, 678 699, 735, 690, 793, 759 700, 774, 793, 690, 694 701, 695, 760, 775, 673 702, 731, 688, 789, 761 703, 746, 795, 818, 763 704, 765, 801, 819, 766 705, 766, 781, 685, 684 706, 786, 820, 807, 784 707, 848, 823, 812, 880 708, 730, 709, 771, 769 94 709, 840, 791, 790, 813 710, 823, 848, 847, 803 711, 741, 822, 838, 788 712, 873, 826, 809, 856 713, 733, 680, 790, 791 714, 773, 826, 813, 790 715, 681, 745, 798, 714 716, 860, 827, 804, 849 717, 744, 797, 829, 776 718, 779, 796, 830, 780 719, 874, 830, 796, 857 720, 724, 726, 786, 784 721, 833, 877, 851, 832 722, 853, 852, 861, 879 723, 726, 727, 785, 786 724, 832, 851, 853, 834 725, 832, 834, 758, 783 726, 854, 847, 848, 865 727, 815, 808, 769, 771 728, 885, 858, 855, 863 729, 761, 789, 839, 842 730, 759, 793, 856, 809 731, 795, 746, 756, 827 732, 851, 857, 852, 853 733, 797, 744, 762, 817 734, 817, 762, 747, 814 735, 804, 828, 798, 745 736, 825, 772, 792, 810 737, 855, 810, 842, 883 738, 800, 764, 753, 831 739, 831, 753, 780, 830 740, 765, 763, 818, 801 741, 748, 743, 835, 802 742, 770, 749, 823, 803 743, 869, 868, 859, 862 744, 816, 833, 757, 781 745, 820, 786, 785, 837 746, 743, 758, 834, 835 747, 869, 815, 803, 847 748, 773, 755, 809, 826 749, 864, 811, 799, 845 750, 885, 840, 813, 888 751, 825, 858, 864, 845 752, 749, 767, 812, 823 753, 836, 854, 865, 837 754, 814, 846, 867, 817 755, 859, 824, 838, 882 756, 866, 870, 860, 849 757, 844, 871, 801, 818 758, 837, 785, 787, 836 759, 865, 848, 880, 881 760, 821, 768, 754, 824 761, 824, 754, 788, 838 762, 822, 741, 750, 841 763, 841, 750, 791, 840 764, 742, 772, 825, 845 765, 873, 856, 864, 888 766, 805, 852, 857, 796 767, 871, 846, 875, 876 768, 833, 832, 783, 757 769, 816, 843, 877, 833 770, 879, 861, 878, 872 771, 834, 853, 879, 835 772, 881, 880, 872, 878 773, 837, 865, 881, 820 774, 862, 859, 882, 884 775, 863, 855, 883, 886 776, 808, 862, 884, 839 777, 886, 883, 884, 882 778, 877, 874, 857, 851 95 779, 870, 866, 867, 844 780, 846, 814, 800, 875 781, 875, 800, 831, 850 782, 824, 859, 868, 821 783, 880, 812, 802, 872 784, 810, 855, 858, 825 785, 888, 813, 826, 873 786, 849, 829, 797, 866 787, 866, 797, 817, 867 788, 850, 831, 830, 874 789, 852, 805, 806, 861 790, 861, 806, 807, 878 791, 854, 836, 821, 868 792, 883, 842, 839, 884 793, 840, 885, 863, 841 794, 856, 793, 811, 864 795, 843, 850, 874, 877 796, 882, 838, 822, 886 797, 815, 869, 862, 808 798, 795, 827, 860, 870 799, 878, 807, 820, 881 800, 841, 863, 886, 822 801, 872, 802, 835, 879 802, 844, 867, 846, 871 803, 847, 854, 868, 869 804, 819, 801, 871, 876 805, 804, 827, 756, 828 *Nset, nset=_PickedSet42, internal, generate 1, 888, 1 *Elset, elset=_PickedSet42, internal, generate 1, 805, 1 *Nset, nset=_PickedSet51, internal, generate 1, 888, 1 *Elset, elset=_PickedSet51, internal, generate 1, 805, 1 *Nset, nset=_PickedSet52, internal 6, 7, 8, 9, 10, 95, 96, 97, 98, 99, 100, 101, 102, 103, 111, 112 113, 114, 115, 116, 117, 118, 119, 120, 121, 122, 123, 124, 125, 126, 127, 128 129, 130, 131, 132, 543, 544, 545, 546, 547, 548, 549, 550, 551, 552, 553, 554 555, 556, 557, 558, 559, 560, 561, 562, 563, 564, 565, 566, 567, 568, 569, 570 571, 572, 573, 574, 575, 576, 577, 578, 579, 580, 581, 582, 583, 584, 585, 586 587, 588, 589, 590, 591, 592, 593, 594, 595, 596, 597, 598, 599, 600, 601, 602 603, 604, 605 *Elset, elset=_PickedSet52, internal, generate 403, 483, 1 *Orientation, name=Ori-1 0., 0., 1., 0., 1., 0. 3, 0. ** Region: (TFBsection:Picked), (Material Orientation:Picked) *Elset, elset=_I1, internal 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96 97, 98, 99, 100, 101, 102, 103, 104, 105, 106, 107, 108, 109, 110, 111, 112 113, 114, 115, 116, 117, 118, 119, 120, 121, 122, 123, 124, 125, 126, 127, 128 129, 130, 131, 132, 133, 134, 135, 136, 137, 138, 139, 140, 141, 142, 143, 144 145, 146, 147, 148, 149, 150, 151, 152, 153, 154, 155, 156, 157, 158, 159, 160 161, 162, 163, 164, 165, 166, 167, 168, 169, 170, 171, 172, 173, 174, 175, 176 177, 178, 179, 180, 181, 182, 183, 184, 185, 186, 187, 188, 189, 190, 191, 192 193, 194, 195, 196, 197, 198, 199, 200, 201, 202, 203, 204, 205, 206, 207, 208 209, 210, 211, 212, 213, 214, 215, 216, 217, 218, 219, 220, 221, 222, 223, 224 225, 226, 227, 228, 229, 230, 231, 232, 233, 234, 235, 236, 237, 238, 239, 240 241, 242, 243, 244, 245, 246, 247, 248, 249, 250, 251, 252, 253, 254, 255, 256 257, 258, 259, 260, 261, 262, 263, 264, 265, 266, 267, 268, 269, 270, 271, 272 273, 274, 275, 276, 277, 278, 279, 280, 281, 282, 283, 284, 285, 286, 287, 288 289, 290, 291, 292, 293, 294, 295, 296, 297, 298, 299, 300, 301, 302, 303, 304 305, 306, 307, 308, 309, 310, 311, 312, 313, 314, 315, 316, 317, 318, 319, 320 96 321, 322, 323, 324, 325, 326, 327, 328, 329, 330, 331, 332, 333, 334, 335, 336 337, 338, 339, 340, 341, 342, 343, 344, 345, 346, 347, 348, 349, 350, 351, 352 353, 354, 355, 356, 357, 358, 359, 360, 361, 362, 363, 364, 365, 366, 367, 368 369, 370, 371, 372, 373, 374, 375, 376, 377, 378, 379, 380, 381, 382, 383, 384 385, 386, 387, 388, 389, 390, 391, 392, 393, 394, 395, 396, 397, 398, 399, 400 401, 402, 484, 485, 486, 487, 488, 489, 490, 491, 492, 493, 494, 495, 496, 497 498, 499, 500, 501, 502, 503, 504, 505, 506, 507, 508, 509, 510, 511, 512, 513 514, 515, 516, 517, 518, 519, 520, 521, 522, 523, 524, 525, 526, 527, 528, 529 530, 531, 532, 533, 534, 535, 536, 537, 538, 539, 540, 541, 542, 543, 544, 545 546, 547, 548, 549, 550, 551, 552, 553, 554, 555, 556, 557, 558, 559, 560, 561 562, 563, 564, 565, 566, 567, 568, 569, 570, 571, 572, 573, 574, 575, 576, 577 578, 579, 580, 581, 582, 583, 584, 585, 586, 587, 588, 589, 590, 591, 592, 593 594, 595, 596, 597, 598, 599, 600, 601, 602, 603, 604, 605, 606, 607, 608, 609 610, 611, 612, 613, 614, 615, 616, 617, 618, 619, 620, 621, 622, 623, 624, 625 626, 627, 628, 629, 630, 631, 632, 633, 634, 635, 636, 637, 638, 639, 640, 641 642, 643, 644, 645, 646, 647, 648, 649, 650, 651, 652, 653, 654, 655, 656, 657 658, 659, 660, 661, 662, 663, 664, 665, 666, 667, 668, 669, 670, 671, 672, 673 674, 675, 676, 677, 678, 679, 680, 681, 682, 683, 684, 685, 686, 687, 688, 689 690, 691, 692, 693, 694, 695, 696, 697, 698, 699, 700, 701, 702, 703, 704, 705 706, 707, 708, 709, 710, 711, 712, 713, 714, 715, 716, 717, 718, 719, 720, 721 722, 723, 724, 725, 726, 727, 728, 729, 730, 731, 732, 733, 734, 735, 736, 737 738, 739, 740, 741, 742, 743, 744, 745, 746, 747, 748, 749, 750, 751, 752, 753 754, 755, 756, 757, 758, 759, 760, 761, 762, 763, 764, 765, 766, 767, 768, 769 770, 771, 772, 773, 774, 775, 776, 777, 778, 779, 780, 781, 782, 783, 784, 785 786, 787, 788, 789, 790, 791, 792, 793, 794, 795, 796, 797, 798, 799, 800, 801 802, 803, 804, 805 ** Section: TFBsection *Shell Section, elset=_I1, orientation=Ori-1, material=Steel 0.25, 5 *Orientation, name=Ori-2 0., 0., 1., 0., 1., 0. 3, 0. ** Region: (TFBsection:Picked), (Material Orientation:Picked) *Elset, elset=_I2, internal, generate 403, 483, 1 ** Section: TFBsection *Shell Section, elset=_I2, orientation=Ori-2, material=Steel 0.25, 5 *End Part ** ** ** ASSEMBLY ** *Assembly, name=Assembly ** *Instance, name=TFBshell-1, part=TFBshell *End Instance ** *Nset, nset=Set-1, instance=TFBshell-1 11, 12, 162, 163, 164, 165, 166, 167, 168, 169, 170 *Elset, elset=Set-1, instance=TFBshell-1 493, 494, 495, 519, 520, 524, 560, 562, 592, 594 *Nset, nset=Set-2, instance=TFBshell-1 8, 9, 10, 118, 119, 120, 121, 122, 123, 124, 125 *Elset, elset=Set-2, instance=TFBshell-1 413, 414, 415, 429, 430, 433, 435, 438, 439, 441, 489, 490, 491, 515, 540, 543 545, 546, 555, 614 *Nset, nset=Set-3, instance=TFBshell-1 6, 7, 95, 96, 97, 98, 99, 100, 101, 102, 103 *Elset, elset=Set-3, instance=TFBshell-1 327, 334, 335, 356, 359, 360, 372, 373, 396, 398, 407, 421, 423, 424, 425, 448 449, 451, 477, 479 *Nset, nset=Set-4, instance=TFBshell-1 3, 4, 5, 51, 52, 53, 54, 55, 56, 57, 58 *Elset, elset=Set-4, instance=TFBshell-1 11, 15, 16, 21, 41, 42, 43, 44, 82, 107, 345, 346, 352, 353, 354, 374 378, 379, 382, 397 *Nset, nset=Set-5, instance=TFBshell-1 1, 2, 13, 14, 15, 16, 17, 18, 19, 20, 21 *Elset, elset=Set-5, instance=TFBshell-1 97 7, 12, 13, 14, 62, 65, 67, 68, 77, 129 *Nset, nset=_PickedSet33, internal, instance=TFBshell-1 11, 12, 162, 163, 164, 165, 166, 167, 168, 169, 170 *Elset, elset=_PickedSet33, internal, instance=TFBshell-1 493, 494, 495, 519, 520, 524, 560, 562, 592, 594 *Elset, elset=__PickedSurf32_E4, internal, instance=TFBshell-1 7, 13, 62, 65, 67, 129 *Elset, elset=__PickedSurf32_E2, internal, instance=TFBshell-1 12, 68, 77 *Elset, elset=__PickedSurf32_E3, internal, instance=TFBshell-1 14, *Surface, type=ELEMENT, name=_PickedSurf32, internal __PickedSurf32_E4, E4 __PickedSurf32_E2, E2 __PickedSurf32_E3, E3 *Nset, nset=_T-TFBshell-1-ProjectCoords, internal _PickedSet33, *Transform, nset=_T-TFBshell-1-ProjectCoords 0., 0., 1., 0., 1., 0. *End Assembly ** ** MATERIALS ** *Material, name=Steel ** Mild Steel *Elastic 3e+07, 0.3 ** ** BOUNDARY CONDITIONS ** ** Name: FixedEnd Type: Displacement/Rotation *Boundary _PickedSet33, 1, 1 _PickedSet33, 2, 2 _PickedSet33, 3, 3 _PickedSet33, 4, 4 _PickedSet33, 5, 5 _PickedSet33, 6, 6 ** ---------------------------------------------------------------** ** STEP: EndLoad ** *Step, name=EndLoad 10lbs on Free End *Static 1., 1., 1e-05, 1. ** ** LOADS ** ** Name: Endload10lbs Type: Shell edge load *Dsload, constant resultant=YES _PickedSurf32, EDTRA, 10. ** ** OUTPUT REQUESTS ** *Restart, write, frequency=0 ** ** FIELD OUTPUT: whole model ** *Output, field *Node Output RF, TF, U *Element Output, directions=YES 1, 3, 5 E, S ** ** FIELD OUTPUT: x-1 values ** *Node Output, nset=Set-1 U, 98 *Element Output, elset=Set-1, directions=YES 1, 3, 5 E, S ** ** FIELD OUTPUT: x-2 values ** *Node Output, nset=Set-2 U, *Element Output, elset=Set-2, directions=YES 1, 3, 5 E, S ** ** FIELD OUTPUT: x-3 values ** *Node Output, nset=Set-3 U, *Element Output, elset=Set-3, directions=YES 1, 3, 5 E, S ** ** FIELD OUTPUT: x-4 values ** *Node Output, nset=Set-4 U, *Element Output, elset=Set-4, directions=YES 1, 3, 5 E, S ** ** FIELD OUTPUT: x-5 values ** *Node Output, nset=Set-5 U, *Element Output, elset=Set-5, directions=YES 1, 3, 5 E, S ** ** HISTORY OUTPUT: H-Output-1 ** *Output, history, variable=PRESELECT *End Step 99 8. References [a] Shames, Irving H. and Francis A. Cozzarelli. 1997. Elastic and Inelastic Stress Analysis, Revised Printing. Boca Raton, Florida: Taylor and Francis. [b] Gere, James A. 2003. Mechanics of Materials, 6th Edition. Tampa, Florida: Thomson-Engineering. [c] Gibson, Ronald F. 2012. Principles of Composite Material Mechanics, 3rd Edition. Boca Raton, Florida: Taylor and Francis. [d] Timoshenko, Stephen P. 1970. Theory of Elasticity. McGraw-Hill. 100 Albany, New York: