Density Matrix State of a system at time t: t Cn (t ) n n orthonormal n Cn (t ) 1 2 Contain time dependent phase factors. t normalized n Density Operator (t ) t t We’ve seen this before, as a “projection operator” Can find density matrix in terms of the basis set n Matrix elements of density matrix: ij ( t ) i ( t ) j it t j Copyright – Michael D. Fayer, 2009 Two state system: t C1 ( t ) 1 C 2 ( t ) 2 t C1* ( t ) 1 C 2* ( t ) 2 Calculate matrix elements of 2×2 density matrix: 11 1 t t 1 1 C1 1 C 2 2 C1* 1 C 2* 2 1 11 C1C1* 12 1 t t 2 21 2 t t 1 12 C1C 21 C 2C1* * 2 Time dependent phase factors cancel cancel. Always have ket with its complex conjugate bra. 22 2 t t 2 22 C 2C 2* Copyright – Michael D. Fayer, 2009 In general: t Ci (t ) i i t t C i ( t ) i i j C *j ( t ) j ij ( t ) i t t j * i C k ( t ) k l C l ( t ) j k l ij ( t ) C i C *j ij density matrix element Copyright – Michael D. Fayer, 2009 2×2 Density Matrix: C1C1* (t ) * C C 2 1 C1C 2* C 2C 2* C1C1* Probability of finding system in state 1 C 2C 2* Probability of finding system in state 2 Diagonal density matrix elements probs. of finding system in various states Off Diagonal Elements “coherences” Since Cn (t ) 1 2 n T (t ) 1 Tr And trace = 1 for any dimension ij *ji Copyright – Michael D. Fayer, 2009 Time dependence of ( t ) d (t ) dt d (t ) dt d d t t t t dt dt product rule Using Schrödinger Eq. for time derivatives of t & t d t i H t dt d t i t H dt d t 1 H t dt i d t 1 t H i dt Copyright – Michael D. Fayer, 2009 Substituting: d (t ) dt d (t ) dt 1 1 H (t ) t t t t H (t ) i i 1 H ( t ) t t t t H ( t ) i density operator 1 H ( t ), ( t ) i Therefore: i ( t ) H ( t ), ( t ) The fundamental equation of the density matrix representation. Copyright – Michael D. Fayer, 2009 Density Matrix Equations of Motion i ( t ) H ( t ), ( t ) since ij C i C *j dC *j * dC i ij C i Cj dt dt * j i C C C Ci * j time derivative of density matrix elements by product rule For 2×2 case, the equation of motion is: 11 21 12 i H 11 H 21 22 H 12 11 H 22 21 12 11 22 21 12 H 11 22 H 21 H 12 H 22 i 11 [( H 11 11 H 12 21 ) ( 11 H 11 12 H 21 )] i 11 ( H 12 21 H 21 12 ) Copyright – Michael D. Fayer, 2009 11 21 12 i H 11 H 21 22 12 12 H 12 11 H 22 21 12 11 22 21 12 H 11 22 H 21 H 12 H 22 i ( H 11 12 H 12 22 ) ( 11 H 12 12 H 22 ) i ( H 11 H 22 ) 12 ( 22 11 ) H 12 Equations of Motion – from multiplying of matrices: i 11 22 ( H 12 21 H 21 12 ) 12 *21 i ( H 11 H 22 ) 12 ( 22 11 ) H 12 11 22 1 (trace of = 1) * 12 21 Copyright – Michael D. Fayer, 2009 In many problems: H H 0 H I (t ) time independent time dependent e.g., Molecule in a radiation field: H 0 molecular Hamiltonian H I ( t ) radiation field interaction (I) with molecule Natural to use basis set of H 0 H 0 n En n Write t as: (orthonormal) (time dependent phase factors) t Cn (t ) n n Eigenkets of H 0 Copyright – Michael D. Fayer, 2009 For this situation: i ( t ) HI ( t ), ( t ) time evolution of density matrix elements elements, Cij(t), (t) depends only on H I ( t ) time dependent interaction term See d S derivation i ti in i book b k – will ill prove later. l t Like first steps in time dependent perturbation theory before any approximations. In absence of H I, only time dependence from time dependent phase factors from H 0 . No changes in magnitude of coefficients Cij . Copyright – Michael D. Fayer, 2009 Time Dependent Two State Problem Revisited: Previously treated in Chapter 8 with Schrödinger Equation. Basis set 1 , 2 degenerate eigenkets of H 0 No H I H 0 1 E 1 0 1 H 0 2 E 2 0 2 Interaction H I H I 1 2 of Ch. 8 H I 2 1 The matrix H I 0 HI 0 Because degenerate states states, time dependent phase factors cancel in off-diagonal matrix elements – special case. In general, the off-diagonal elements have time dependent phase factors. Copyright – Michael D. Fayer, 2009 Use i ( t ) H I ( t ), ( t ) 11 12 11 12 0 0 2 1 22 21 22 i 0 0 HI 0 0 11 i[(0 11 21 ) ( 11 0 12 )] i ( 21 12 ) i ( 12 21 ) Multiplying matrices and subtracting gives ( 11 22 ) ( 12 21 ) i ( ) ( ) 11 22 12 21 Equations of motion of density matrix elements: 11 i ( 12 21 ) 22 i ( 12 21 ) Probabilities 12 i ( 11 22 ) 21 i ( 11 22 ) Coherences Copyright – Michael D. Fayer, 2009 Using 11 i ( 12 21 ) T k time Take i derivative d i i 11 i ( 12 21 ) Substitute 12 & 21 12 i ( 11 22 ) 21 i ( 11 22 ) 11 2 2 ( 11 22 ) 11 22 1 U i Tr Using T = 1, 1 i.e., i Then 22 1 11 and 11 2 2 4 2 11 For initial condition 11 1 at t = 0. d cos 2 ( t )ddt 2 cos(( t ))sin( i ( t ) d 2cos 2 ( t )dt 2 2 2 (sin 2 ( t ) cos 2 ( t )) but sin 2 ( t ) 1 cos 2 ( t ) then d 2cos 2 ( t )dt 2 2 2 (1 2cos 2 ( t )) 2 2 4 2 cos 2 ( t ) 11 cos 2 ( t ) / 22 sin 2 ( t ) From Ch. 8 Same result as Chapter 8 except obtained probabilities directly. No probability amplitudes. Copyright – Michael D. Fayer, 2009 Can get off-diagonal elements 12 i ( 11 22 ) Substituting: 12 i (cos 2 t sin 2 t ) 12 i cos 2 t sin 2 t dt i 2 12 sin(2 t ) 2 cos xdx (1/2) x (1/ 4)sin 2 x 2 ( 4)sin ) 2x sin xdx ((1/2)) x (1/ Since ij *ji i 2 21 sin(2 ( t) Copyright – Michael D. Fayer, 2009 Density matrix elements have no time dependent phase factors. t Ci (t ) i i t t C i ( t ) i i j C *j ( t ) j ij ( t ) i t t j * i C k ( t ) k l C l ( t ) j k l time dependent phase factor in ket, but C i ( t ) i i C *j ( t ) j j its complex conjugate is in bra bra. Product * C i ( t )C j ( t ) is 1. Kets and bras normalized, closed bracket gives 1. ij ( t ) C i ( t )C *j ( t ) ij density matrix element Time dependent coefficient, coefficient but no phase factors. factors Copyright – Michael D. Fayer, 2009 Can be time dependent phase factors in density matrix equation of motion. i ( t ) H ( t ), ( t ) For two levels, but the same in any dimension. H11 H H 21 H12 H 22 1 1s e iE1t / 2 2s e iE2 t / s – spatial H 11 1 H 1 1s H 1s e iE1t / e iE1t / 1s H 1s no time dependent phase factor H 12 1 H 2 1s H 2 s e iE1t / e iE2t / 1s H 2 s e i ( E1 E2 ) t / time dependent phase factor if E1 ≠ E2. Therefore, in general, the commutator matrix, H ( t ), ( t ) when yyou multiply p y it out,, will have time dependent phase factors if E1 ≠ E2. Copyright – Michael D. Fayer, 2009 Expectation Value of an Operator A t At Complete orthonormal basis set j t C j (t ) j j Matrix elements of A Aij i A j Derivation in book and see lecture slides A Tr ( t ) A Expectation value of A is trace of the product of density matrix with the operator matrix A . Important: ( t ) carries time dependence of coefficients. coefficients Time dependent phase factors may occur in off-diagonal matrix elements of A. Copyright – Michael D. Fayer, 2009 E Example: Average E for two state problem E E H Tr H E=0 E H H0 H I 11 T H Tr Tr T 21 E E 12 E 22 Time dependent phase factors cancel because degenerate. g Special p case. In general have time dependent phase factors. E Only y need to calculate the diagonal matrix elements. 11 E 12 21 22 E E ( 11 22 ) ( 12 21 ) i 2 22 sin i 2 ( t ) 12 sin(2 i (2 t ) H E (cos 2 t sin 2 t ) i (sin 2 t sin 2 t ) 2 11 cos 2 ( t ) E i 2 21 sin(2 t ) Copyright – Michael D. Fayer, 2009 Coherent Coupling by of Energy Levels by Radiation Field Two state problem 2 E = 0 1 0/2 radiation field Zero of energy half way between states. - 0/2 2 electronic states S0 S1 2 vibrational states V0 V1 NMR – 2 spin state, magnetic transition dipole In general, if radiation field frequency is near E, and other transitions are far off resonance, can treat as a 2 state system. Copyright – Michael D. Fayer, 2009 Molecular Eigenstates as Basis H0 1 0 1 2 0 H0 2 2 2 Zero of energy half way between states. Interaction due to application of optical field (light) on or near resonance. H I ( t ) e x 12 E0 cos(( t ) e x 12 transition dipole p operator p x polarized light E0 amplitude Copyright – Michael D. Fayer, 2009 H I couples states 1 H I ( t ) 2 E0 cos( t ) 1 e x 12 2 E0 cos( t ) e i 0 t / 2 E0 cos( t ) e take out time dependent phase factors 1 e x12 2 e i 0t / 2 i0 t is value of transition dipole bracket bracket, Note – time independent kets. No phase factors. Have taken phase factors out. 2 H I ( t ) 1 * E0 cos( t )e i 0t T k reall (doesn’t Take (d ’t change h results) lt ) Define Rabi Frequency, 1 1 E0 Then 1 H I ( t ) 2 1 cos( t )e i 0t 2 H I ( t ) 1 1 cos( t )e i 0t H I ( t ) matrix: 0 H I (t ) i 0 t 1 cos( t )e 1 cos( t )e i t 0 0 Copyright – Michael D. Fayer, 2009 General state of system t C1 ( t ) 1 C 2 ( t ) 2 i ( t ) H I ( t )), ( t ) Use 0 i 1 cos( t )e i 0 t 1 cos( t )e i t 11 12 0 22 21 0 11 12 0 i 0 t 21 22 1 cos( t )e 11 21 0 0 12 1 cos( t )e i t 22 i cos( t ) e i 0t e i 0t 12 21 1 i 0 t i co s( t ) e ( 11 22 ) 1 i1cos( t )e i0t ( 11 22 ) i1cos( t ) e i 0 t 12 e i 0t 21 Blue diagonal Red off-diagonal Copyright – Michael D. Fayer, 2009 Equations of Motion of Density Matrix Elements 11 i1cos( t ) e i 0t 12 e i 0t 21 22 i1cos( t ) e i 0t 12 e i 0t 21 12 i1cos( t )e i 0t ( 11 22 ) 21 i1cos( t )e i 0t ( 11 22 ) 11 22 1 * 12 21 11 22 12 *21 T Treatment exact to this hi point i Copyright – Michael D. Fayer, 2009 Rotating Wave Approximation 1 i t cos(( t ) e e i t 2 Put this into equations of motion Will have terms like e i ( 0 ) t and e i ( 0 ) t But 0 Terms with ( 0 ) 2 0 off resonance Don Don’tt cause transitions Looks like high frequency Stark Effect Bloch – Siegert g Shift Small but sometimes measurable shift in energy. Drop these terms! Copyright – Michael D. Fayer, 2009 With Rotating Wave Approximation Equations of motion of density matrix 11 i e 2 1 22 i 12 i e 2 1 1 2 21 i i ( 0 ) t 12 e i ( 0 )t 21 i ( 0 ) t 12 e i (0 ) t 21 e i ( 0 ) t ( 11 22 ) 1 2 e i ( 0 ) t ( 11 22 ) These are the Optical Bloch Equations for optical transitions or just j st the Bloch Eq Equations ations for NMR. NMR (NMR - 1 m H1 ) Copyright – Michael D. Fayer, 2009 Consider on resonance case = 0 11 i 2 22 i 12 i 1 1 2 1 2 21 i e i ( 0 ) t 12 e i ( 0 ) t 21 e 1 2 e i ( 0 ) t 12 e i ( 0 ) t 21 i ( 0 ) t e ( 11 22 ) i ( 0 ) t E Equations ti reduce d to t 11 i 1 2 ( 11 22 ) All of the phase factors = 1. 22 i 12 i 1 2 1 2 21 i 12 21 12 21 ( 11 22 ) 1 2 ( 11 22 ) These are IDENTICAL to the degenerate time dependent 2 state problem with = 1/2. Copyright – Michael D. Fayer, 2009 On resonance coupling to time dependent radiation field induces transitions. 2 Looks identical to time independent coupling of two degenerate states. E 0 In effect, the on resonance radiation field “removes” energy differences and time dependence of field. Start in ground state, 1 Th Then 11 cos ( 2 22 sin 2 ( 1 t 2 1 t 2 populations 0 1 11 1; 22 0, 12 0, 21 0 at t = 0. i 2 ) 12 sin(1t ) ) 21 sin(1t ) i 2 coherences Copyright – Michael D. Fayer, 2009 11 cos 2 ( Recall 1 t 2 22 sin 2 ( ) 1 t 2 ) populations 1 E0 Rabi Frequency 1t 11 0, 22 1 This is called a pulse inversion, all population in excited state. 1t 2 11 0.5, 22 0.5 As t is increased, population oscillates between ground and excited state at Rabi frequency. Transient Nutation Coherent Coupling 22 – excited staate prob. This is called a /2 pulse Maximizes off diagonal elements 12, 21 pulse 1 0.8 0.6 0.4 0.2 2 2 pulse 4 t 6 8 Copyright – Michael D. Fayer, 2009 Off Resonance Coherent Coupling 0 Amount radiation field frequency is off resonance from transition frequency. Define e 2 For same initial conditions: 2 1 1/ 2 Effective Field 1 = E0 - Rabi frequency 11 1; 22 0, 12 0, 21 0 Solutions of Optical Bloch Equations 12 2 11 1 2 sin (e t /2) e 12 12 2 22 2 sin (e t /2) e 1 i e 21 2 sin( e t ) sin 2 ( e t /2) e i t e 2 Oscillations Faster e Max excited state probability: 1 i e i t 2 sin( t ) sin ( t /2) e e e 2 e 2 max 22 12 2 e (Like non-degenerate time dependent 2-state problem) Copyright – Michael D. Fayer, 2009 Near Resonance Case - Important 1 Then e 2 2 1 1/ 2 e 1 11, 22 reduce to on resonance case. i 12 sin(1t )e i t 2 i 21 sin(1t )e i t 2 Same as resonance case p for p phase factor except For /2 pulse, maximizes 12, 21 1t = /2 But t << /2 0 because 1 Then, 12, 21 virtually identical to on resonance case and 11, 22 same as on resonance case. This is the basis of Fourier Transform NMR. Although spins have different chemical shifts, make ω1 big enough, all look like on resonance. Copyright – Michael D. Fayer, 2009 Free Precession = 1t Aft pulse After l off (fli angle) (flip l ) On or near resonance i 12 sin 2 i 21 sin 2 11 cos 2 ( /2) 22 sin i 2 ( /2) After pulse – no radiation field. Hamiltonian is H0 i H 0, 0 0 /2 H0 0 /2 0 Copyright – Michael D. Fayer, 2009 i H 0, 0 0 /2 H0 0 /2 0 0 11 12 i 0 /2 0 /2 2 1 22 0 0 11 12 0 /2 0 /2 0 22 21 11 0 22 0 12 i 0 12 t = 0 is at end of pulse 21 i 0 21 Solutions 11 = a constant = 11((0)) 12 12 (0)e (0)e i 0t 22 = a constant = 22(0) 21 21 (0)e i0t Populations don’t change. Off-diagonal density matrix elements Only time dependent phase factor Copyright – Michael D. Fayer, 2009 Off-diagonal density matrix elements after pulse ends (t = 0). . Recall e x 12 p value of transition dipole p Consider expectation Tr 1 1 0 2 11 (0) Tr Tr 21 (0)e i 0t 2 0 No time dependent phase factors because because matrix elements involve time independent kets kets. Phase factors were taken out as part of the derivation. 12 (0)e i 0t 0 22 (0) 0 12 (0)e i 0t 21 (0)e i 0t For a flip angle sin sin( 0 t ) Oscillating electric dipole (magnetic dipole - NMR) att frequency f 0, Oscillating O ill ti E E-field fi ld ((magnett fi field) ld) I E 2 for ensemble, coherent emission t = 0, end of pulse Free precession. Rot. wave approx. Tip of vector goes in circle. Copyright – Michael D. Fayer, 2009 Pure and Mixed Density Matrix Up to this point - pure density matrix. One system or many identical systems. systems Mixed density matrix Describes nature of a collection of sub-ensembles each with different properties. The subensembles are not interacting. Pk probability of having kth sub-ensemble with density matrix, k. 0 P1 , P2 , Pk , 1 and P k 1 Sum of probabilities is unity. k Density matrix for mixed systems ( t ) Pk k ( t ) k or integral if continuous distribution Total density matrix is the sum of the individual density matrices times their probabilities. Because density matrix is at probability level, can sum (see Errata and Addenda). Copyright – Michael D. Fayer, 2009 Example: Light coupled to two different transitions – free precession 01 02 Light frequency in the middle of 01 & 02. Difference between 01 & 02 small compared to 1 and both near resonance. Equal probabilities P1=0.5 and P2=0.5 For a given pulse of radiation field, both sub-ensembles will have same flip angle . Calculate Tr ( t ) Pk Tr k k Copyright – Michael D. Fayer, 2009 Pure density matrix result for flip angle : sin sin( 0 t ) For 2 transitions - P1=0.5 and P2=0.5 1 sin sin( 01t ) sin(02 t ) 2 1 1 sin sin ( 01 02 )t cos ( 01 02 )t 2 2 from trig. identities Call: center frequency 0, shift from the center then, 01 = 0 + and 02 = 0 - , with << 0 Therefore, sin sin( 0 t )cos( t ) high freq freq. oscillation low freq freq. oscillation oscillation, beat Beat gives transition frequencies – FT-NMR Copyright – Michael D. Fayer, 2009 Equal amplitudes – 100% modulation, ω01 = 20.5; ω01 = 19.5 2 1 5 10 15 20 -1 -2 Copyright – Michael D. Fayer, 2009 Amplitudes 2:1 – not 100% modulation , ω01 = 20.5; ω01 = 19.5 1 0.5 5 10 15 20 -0.5 -1 Copyright – Michael D. Fayer, 2009 Amplitudes 9:1 – not 100% modulation , ω01 = 20.5; ω01 = 19.5 1 0.5 5 10 15 20 -0.5 -1 Copyright – Michael D. Fayer, 2009 Equal amplitudes – 100% modulation, ω01 = 21; ω01 = 19 2 1 5 10 15 20 -1 -2 Copyright – Michael D. Fayer, 2009 center freq Free Induction Decay 0 Identical molecules have range of transition frequencies. Different solvent environments. Doppler shifts, etc. h frequency of particular molecule Gaussian envelope Frequently, distribution is a Gaussian probability of finding a molecule at a particular frequency. 1 ( h 0 )2 / 2 2 e 2 standard deviation 2 normalization constant Then (t ) 1 2 2 e ( h 0 )2 / 2 2 ( h , t )d h probability, Ph pure density matrix Copyright – Michael D. Fayer, 2009 Radiation field at = 0 line center 1 >> – all transitions near resonance Apply pulse with flip angle Calculate , transition dipole expectation value. Following pulse, each sub-ensemble will undergo free precession at h Tr ( t ) 1 2 2 e ( h 0 )2 / 2 2 Tr ( h , t ) d h U i result Using l for f single i l frequency f h and d fli flip angle l sin 2 2 e ( h 0 )2 / 2 2 sin( h t )d h Copyright – Michael D. Fayer, 2009 Substituting = (h – 0), frequency of a molecule as difference from center frequency (light frequency). Then h = ( +0) and dωh = d. With the trig identity: sin( x y ) sin( x )cos( y ) cos( x )sin( y ) sin cos( 0 t ) e 2 2 2 / 2 2 sin( t ) d sin( 0 t ) e 2 / 2 2 cos( t ) d First integral zero; integral of an even function multiplying an odd function. sin sin( 0 t )e t 2 / 2( 1 / )2 Oscillation at 0; decaying amplitude Gaussian decay with standard deviation in time 1/ (Free Induction Decay) Phase relationships lost Coherent Emission Decays Off-diagonal density matrix elements – coherence; diagonal - magnitude Copyright – Michael D. Fayer, 2009 sin sin( 0 t )e flip angle t 2 / 2( 1 / )2 light frequency free induction decay 1 0.8 0.6 Decay of oscillating macroscopic dipole. Free induction decay. E 0.4 2 I E 0.2 0.5 t = 0 1 1.5 2 2.5 3 t = t' 2 Coherent emission of light. higher frequencies rotating frame at center freq., 0 lower frequencies Copyright – Michael D. Fayer, 2009 Proof that only need consider i ( t ) HI ( t ), ( t ) when working in basis set of eigenvectors of H. Working with basis set of eigenkets of time independent piece of Hamiltonian, Hamiltonian H0, the time dependence of the density matrix depends only on the time dependent piece of the Hamiltonian, HI. Total Hamiltonian H H 0 H I (t ) H 0 time independent H 0 n En n Use n as basis set. t Cn (t ) n n Copyright – Michael D. Fayer, 2009 Time derivative of density operator (using chain rule) d d dt t t t dt t (A) Use Schrödinger Equation 1 1 H (t ) t t t t H (t ) i i 1 1 1 1 H0 t t HI t t t t H0 t t HI i i i i (B) Substitute expansion t C n ( t ) n into derivative terms in eq. (A). n d d * C n t t C n dt n dt n n n d d C n n t C n n t t C n* n t C n* n dt dt n n n n (B) = (C) (C) Copyright – Michael D. Fayer, 2009 Using Schrödinger Equation 1 d C n n d t i H 0 t n Right g multiply p y top p eq. q by y t . 1 * d C n n d t i t H 0 n Left multiply bottom equation by t . Gives d 1 C n t H0 t t n d t i n 1 * d t Cn n t t H0 d t i n Using these see that the 1st and 3rd terms in (B) cancel the 2nd and 4th terms in (C). 1 1 1 1 H0 t t HI t t t t H0 t t HI i i i i (B) d d C n n t C n n t t C n* n t C n* n dt dt n n n n (C) Copyright – Michael D. Fayer, 2009 After canceling terms, (B) = (C) becomes 1 * C n n t t C n n i H I , n n Consider the ij matrix element of this expression. expression The matrix elements of the left hand side are * Cn i n t j i t Cn n j * n n C i C *j C i C j ij i ( t ) H I ( t ), ( t ) In the basis set of the eigenvectors of H0, H0 cancels out of equation of motion of density matrix. Copyright – Michael D. Fayer, 2009 Proof that t A t = A Tr ( t ) A Expectation value A t At j complete orthonormal basis set. t C j (t ) j j Matrix elements of A Aij i A j t A t C i* i A C j j i j C i* ( t )C j ( t ) i A j i, j Copyright – Michael D. Fayer, 2009 ji j ( t ) i note t order d jt t i C i* ( t )C j ( t ) Then t A t j (t ) i i A j i, j Matrix multiplication, Chapter 13 (13.18) N ckj bki aij i 1 t At like matrix multiplication but only diagonal elements – j on both sides. g elements. Also, double sum. Sum over j – sum diagonal Therefore, A Tr ( t ) A Copyright – Michael D. Fayer, 2009