Approximate Analytical Calculation of the Skin Effect in Rectangular Wires Dieter Gerling University of Federal Defense Munich, 85579 Neubiberg, Germany Dieter.Gerling@unibw.de Abstract- It is well-known that thick wires energized with highfrequency currents show the effect, that the current mainly flows near the surface of the wire. This effect is quite well described in literature for round wires, for rectangular wires no description of similar simplicity could be found. This effect may be relevant for future electric drives, e.g. in the automotive industry. Therefore, the skin effect of rectangular wires is analyzed in this paper for the application of hybrid drives for passenger cars. Index Terms—Analytical Calculation, Rectangular Wire, Skin Effect I. INTRODUCTION In the automotive industry, currently much effort is dedicated to the development of hybrid and pure electric drives. As the voltage of the battery is limited (in many cases in the region of 120V), quite thick wires have to be used for a certain power level. In addition, high frequencies are used to reach a high maximum speed. These boundary conditions can lead to the occurrence of the skin effect in such applications (it is well-known that thick wires energized with highfrequency currents show the effect, that the current mainly flows near the surface of the wire). Moreover, sometimes rectangular wires are used to better utilize the slot area of such machines. For round wires the skin effect is well documented, see e.g. [1]. For rectangular wires a description of similar simplicity could not be found in literature. Therefore, in this paper especially the skin effect of rectangular wires is investigated. Even if it can be assumed, that for rectangular wires the skin effect is similar to round wires, a proof of this assumption and a detailed calculation method are necessary. The main task of this paper is the elaboration of a simple calculation method for the skin effect in rectangular wires. II. THE SKIN EFFECT IN RECTANGULAR WIRES A. Solution of Maxwell’s Equations The following figure 1 shows the wire under investigation. We assume that in this wire the current has only a zcomponent (i.e. into the sheet of paper or out of the sheet of paper), but this component depends on the x- and ycoordinate. This means in terms of the current density: G G J = J z ( x, y ) ⋅ ez (1) Fig. 1. System under investigation. With G G G (2) rot ( H ) = J = γE the following conclusions can be drawn: G G E = E z ( x, y ) e z and G G G H ( x, y ) = H x ( x, y ) e x + H y ( x, y ) e y , G G G where e x , e y and e z are the unit vectors in x-, y-, and zdirection, respectively. Evaluating (2) in Cartesian Coordinates gives: ∂ ∂ Hy − H x = γE z (3) ∂x ∂y With G ∂ G (4) rot ( E ) = −μ H ∂t we get in Cartesian Coordinates ∂ ∂ E z = −μ H x (5) ∂y ∂t and ∂ ∂ − E z = −μ H y (6) ∂x ∂t Differentiating (3) with respect to time and inserting (5) and (6) gives γ ∂ ∂t ⇒ Ez = ∂ 2 1 ∂ 2 μ ∂x 2 Ez + ∂ 2 1 ∂ 2 μ ∂y 2 Ez ∂ (7) E z + 2 E z = μγ E z 2 ∂x ∂y ∂t This differential equation shall be solved with the following product set-up: E z ( x, y, t ) = X ( x ) ⋅ Y ( y ) ⋅ T ( t ) (8) Inserting this set-up to (7) gives (a prime means the total differential with respect to the relevant variable): X ′′ ( x ) ⋅ Y ( y ) ⋅ T ( t ) + X ( x ) ⋅ Y ′′ ( y ) ⋅ T ( t ) = μγX ( x ) ⋅ Y ( y ) ⋅ T ′ ( t ) ⇒ μγ T′ ( t ) T (t) X ′′ ( x ) = X(x) + (9) Y ′′ ( y ) Y ( y) The left side of (9) depends only on the time, the right side only on the locus. Therefore, both sides must be constant. Evaluating firstly the left side of (9) gives: T′ ( t ) T′ ( t ) − c ⋅ T ( t ) = 0 =c ⇒ (10) T (t) With the set-up for a harmonic wave T ( t ) = e jωt jωt we get: As the right side of (12) is constant, both terms of the left side of (12) must be constant (because they depend on different coordinates). It follows: X ′′ ( x ) 2 =k X (x) ⇒ X ′′ ( x ) − k X ( x ) = 0 ⇒ X ( x ) = C1 sinh ( kx ) + C 2 cosh ( kx ) 2 (14) In total we get from (8), (12), (13) and (14): E z ( x, y, t ) = [ C1 sinh ( kx ) + C 2 cosh ( kx )] ⋅ [ C3 sinh ( A y ) + C4 cosh ( A y )] ⋅ e jωt , 2 (15) 2 k + A = jωμγ B. Calculation of the Variables From (5) and (15) we get [ C1 sinh ( kx ) + C2 cosh ( kx )] ⋅ [ A C3 cosh ( A y ) + A C4 sinh ( A y )] ⋅ e jωt 1 1 μ jω 1 1 μ jω A C3 [ C1 sinh ( kx ) + C 2 cosh ( kx )] = 0 (17) ⇒ C3 = 0 Analogously, we get from (6) and (15) C1 = 0 Summarizing (15), (17) and (18), we get: E z ( x, y, t ) = C ⋅ cosh ( kx ) ⋅ cosh ( A y ) ⋅ e 2 (18) jωt , 2 k + A = jωμγ The constant C can be calculated from jωt I ( t ) = ˆIe = a b 2 2 ∫ ∫ J z ( x, y, t ) dy dx − a 2 − (19) (20) b 2 Solving (19) and (20) for the constant C we get: C= Î 4γ k⋅A a⎞ ⎛ ⎛ sinh ⎜ k ⎟ sinh ⎜ A 2 ⎝ ⎠ ⎝ (21) b⎞ ⎟ 2⎠ Equations (19) and (21) describe the solution of the field problem inside the rectangular wire, but there is one additional equation missing for the constants k and A . Possibilities for such an additional equation are given in the following three sections C to E. (13) Analogously we get: Y ( y ) = C3 sinh ( A y ) + C4 cosh ( A y ) Hx = − − jωt jωe − c e = 0 ⇒ c = jω (11) Evaluating in a second step the right side of (9) leads to: X ′′ ( x ) Y ′′ ( y ) + = jωμγ (12) X (x) Y ( y) ⇒ H x ( y = 0, t = 0 ) = C. Evaluation of the Magnetic Field Strength In the following we assume that the absolute value of the magnetic field strength for x = a 2 , y = 0 and x = 0, y = b 2 are identical. This assumption is valid as long as the frequency is not too high (for DC current the outside circumference of the wire represents a field line) or the wire is (at least approximately) a quadratic one. The evaluation of (5), (6) and (19) gives: G⎛ a a ⎞ ⎛ ⎞ H ⎜ x = , y = 0 ⎟ = Hy ⎜ x = , y = 0 ⎟ 2 2 ⎝ ⎠ ⎝ ⎠ = = −μ ∂ ∂t 1 jωμ ⎛ a ⎞ ⋅ e jωt ⎟ ⎝ 2⎠ k ⋅ C sinh ⎜ k G⎛ b⎞ b⎞ ⎛ H ⎜ x = 0, y = ⎟ = H x ⎜ x = 0, y = ⎟ 2⎠ 2⎠ ⎝ ⎝ Hx (16) [ C1 sinh ( kx ) + C 2 cosh ( kx )] ⋅ [ A C3 cosh ( A y ) + A C4 sinh ( A y )] ⋅ e jωt Because of the symmetry, for y = 0 the value of H x must be zero for any time; therefore it must be valid even for t = 0 . It follows: = 1 jωμ (22) ⎛ b ⎞ ⋅ e jωt ⎟ ⎝ 2⎠ A ⋅ C sinh ⎜ A Consequently we get ⎛ a⎞ ⎛ b⎞ k sinh ⎜ k ⎟ = A sinh ⎜ A ⎟ ⎝ 2⎠ ⎝ 2⎠ (23) D. Calculation of the Symmetric Case The symmetric case is characterized by a = b (quadratic wire). For this we get because of the symmetry: k=A 2 ⇒ 2 k = jωμγ ⇒ k=A = 1 δ= 2 ωμγ and C= 2 Î k 4γ ⎡sinh ⎛ k a ⎞⎤ ⎜ ⎟ ⎢⎣ ⎝ 2 ⎠⎦⎥ 2 (25) E. Calculation of the (near) DC Case Taylor’s series expansion for the hyperbolic sine function with truncation after the first summand gives sinh ( x ) ≈ x (this approximation is valid for small arguments x, i.e. for example for low frequencies). This leads to ⎛ a⎞ 2 a k sinh ⎜ k ⎟ ≈ k 2 ⎝ 2⎠ (26) b⎞ ⎛ 2 b A sinh ⎜ A ⎟ ≈ A 2 ⎝ 2⎠ For the case of a DC current, i.e. ω = 0 , (19) leads to: ⇒ ω=0 ⇒ A = (24) j, δ k= k =A =0 E z ( x, y, t ) = C (27) 1 δ 1 δ j j 2b a+b 2a , δ= 2 (31) ωμγ a+b F. Evaluation of k and l for Arbitrary Geometry and Frequency Evaluating (31) for the symmetric case ( a = b ) we get the exact result (please refer to (24)). This means: The approximation of the hyperbolic sine function, that leads to k and A according to (31) is valid for arbitrary geometry and low frequencies and the symmetric geometry ( a = b ) and arbitrary frequencies. The solutions (23) and (31) for the constants k and A are based on the same physical constraints (both are valid for low frequency or quadratic wire). Nevertheless, there is a difference when evaluating these equations. To estimate the deviation F between the solutions (23) and (31) depending on geometry and frequency, the solution (31) will be evaluated and the deviation analyzed like follows: ⎛ a⎞ ⎛ b⎞ (32) F = k sinh ⎜ k ⎟ − A sinh ⎜ A ⎟ ⎝ 2⎠ ⎝ 2⎠ This results in the following figure for the deviation F (figure 2 shows the real part of the complex value of the deviation F , the imaginary part is qualitatively similar to this with just a slightly lower amplitude). Consequently the constant C for the DC case becomes C= Î γ ⋅a ⋅b (28) For the case of a near DC current, i.e. low frequency, (19), (23) and (26) lead to: 2 2 a k +k = jωμγ b (29) jωμγ 2b ⇒ k= 2 a+b Analogously we get: A = jωμγ 2a (30) 2 a+b For the constant C (21) holds true. With the skin depth δ (please refer e.g. to (24) or reference [1]) we get from (29) and (30): Fig. 2. Re { F } as a function of frequency f and edge length a. In figure 2 the following conditions were considered: a frequency of 0Hz to 1000Hz; - 2 - a copper wire of cross section A wire = 3.75mm ; - a temperature of 20°C (the influence of temperature variation is similar to the influence of frequency variation, please refer to (31)); an edge length variation between 0.1mm and 3.0mm (the rectangular copper wire of 3.0mm times 1.25mm is the application described in chapter III). It can be deduced from figure 2 that the deviation F is small, if low frequency or symmetric geometry is regarded (for these cases both solutions deliver the exact result). If one of these conditions is not fulfilled, the deviation because of the used different approximations is increased. - G. Numerical Calculation of k and l for Arbitrary Geometry and Frequency At this time it can not be decided, if the deviation F coming from the different approximate calculations of k and A for arbitrary frequency and geometry has an important influence on the current density distribution inside the wire. Therefore, both solutions to calculate these parameters will be compared. This can be done only numerically, because the set of equations (19) and (23) is of transcendent nature. This numerical solution is performed using the software package MathCad. For the same conditions like in the previous section, for varying the frequency between 0Hz and 20kHz, and for varying the edge length a of the rectangular wire between 0.1mm and 10.0mm an absolute value of the failure −10 below 10 for each data point could be reached. The following figure 3 illustrates the difference between the analytical calculation (according to (31)) and the numerical calculation according to (23). As an example the parameter Re { k } is given. The results for the imaginary part and for the parameter A are similar. Re { k } Re { k} a in 0.1mm a in 0.1mm frequency in 100Hz a) Fig. 3. frequency in 100Hz b) Re { k } as a function of frequency f and edge length a a) analytical calculation according to (31) b) numerical calculation according to (23) H. Evaluation of the Edge Condition Because of the special behavior of the electromagnetic field at the edges of the regarded geometry, a certain edge condition must be fulfilled in addition to the solution of Maxwell’s equations. This edge condition means that (please refer to [2]) “the electromagnetic energy density must be integrable over any finite domain even if this domain contains singularities of the electromagnetic field. In other words, the electromagnetic energy in any finite domain must be finite”. The Poynting’s vector G G G S = E×H (33) describes the energy, that flows per time unit through the unit G area perpendicular to S . As the edge condition must be fulfilled for any finite time interval, this means that Poynting’s vector must be finite over any finite domain. The Poynting’s vector in the case of the rectangular wire is: G G G G G S = E × H = E z H x e y − E z H y ex (34) Inserting (5), (6) and (19) into (34) gives: G G G S = Ez H x ey − Ez H y ex ( = C cosh ( kx ) cosh ( A y ) e jωt ) ⎛⎜ − ∫ E z dt ⎞⎟ eG y − ⎝ μ ∂y ⎠ ∂ 1 ( C cosh ( kx ) cosh ( A y ) e jωt ) ⎛⎜ ∫ E dt ⎞⎟ eG x ⎝ μ ∂x ⎠ ∂ 1 z Further we get: G jωt S = − C cosh ( kx ) cosh ( A y ) e ( 1 ) jωμ ⋅ G ⎡⎣ C A cosh ( kx ) sinh ( A y ) e jωt e y + jωt G C k sinh ( kx ) cosh ( A y ) e e x ⎦⎤ = −1 jωμ (C 2 cosh ( kx ) cosh ( A y ) e j2 ωt (35) )⋅ G ⎡⎣ A cosh ( kx ) sinh ( A y ) e y + G k sinh ( kx ) cosh ( A y ) e x ] For a certain operating point the parameters k , A , and C (in addition to ω and μ ) are fixed values. As the wire has finite dimensions, even the variables x and y are finite. G Therefore, Poynting’s vector S is finite over any finite domain. This means that the edge condition is fulfilled for the solution given above; i.e. this solution is valid for rectangular wires (as long as the approximations are valid). III. CURRENT DENSITY DISTRIBUTION From (19) and (21) the frequency dependent current density distribution in a rectangular wire can be calculated. For the calculation in this section the time t = 0 , the temperature ϑ = 20°C , a total current of Î = 10A and a rectangular copper wire with a = 3.0mm times b = 1.25mm ( 0 ≤ x ≤ a , 0 ≤ y ≤ b ) cross section is assumed. In a first step, the analytical calculation according to (31) for the parameters k and A is used to get the result for the current density distribution. Figure 4 shows this current density distribution for 4 different frequencies. The following figure 5 shows the frequency dependent current density distribution for the same boundary conditions like in figure 4. The difference to this former calculation is that during this evaluation the numerical calculation for the parameters k and A according to (23) is used to obtain the result for the current density distribution. Some slight differences to figure 4 can be noticed at high frequency. The time dependent current density distribution is illustrated in the following figure 6. As there are some slight deviations (for high frequency) between both calculation methods, only the results of the numerical calculation according to (23) are given. The calculation was performed for a frequency of f = 20kHz . Fig. 4. Current density distribution in a rectangular copper wire (cross section 3.0mm times 1.25mm, current Î = 10A , time t = 0 , temperature ϑ = 20° C ): analytical calculation according to (31). Fig. 6. Current density distribution in a rectangular copper wire (cross section 3.0mm times 1.25mm, frequency f = 20kHz , current Î = 10A , temperature ϑ = 20° C ): numerical calculation according to (23). IV. ENTIRE SET OF MAXWELL’S EQUATIONS Fulfilling the entire set of Maxwell’s equations, the following equation (36) has to be checked: G ∂ ∂ ∂ div ( E ) = Ex + Ey + Ez = 0 (36) ∂x ∂y ∂z G As E = E z ( x, y ) is true, the condition (36) is fulfilled. Fig. 5. Current density distribution in a rectangular copper wire (cross section 3.0mm times 1.25mm, current Î = 10A , time t = 0 , temperature ϑ = 20° C ): numerical calculation according to (23). Additionally, G div ( B ) = 0 (37) G G G must be fulfilled. With H = H x ( x, y ) e x + H y ( x, y ) e y and G G B = μH we get G div ( B ) = 0 ∂ ⇔ ∂x With (5) and (6) this leads to ∂ ∂ ∂ ⎛ 1 Hx + Hy = ⎜− ∂x ∂y ∂x ⎝ μ Hx + ∂ ∂y Hy = 0 ⎞ ∂ ⎛1 ∂ ⎞ ∫ ∂y E z dt ⎟⎠ + ∂y ⎜⎝ μ ∫ ∂x E z dt ⎟⎠ ∂ = ∂ ∂ ⎡∂ ∂ ⎤ E z dt − E z dt ∫ ∫ ⎢ ⎥⎦ μ ⎣ ∂y ∂x ∂x ∂y = ∂ ∂ ⎡ ∂ ∂ ⎤ E z dt − ∫ E z dt ∫ ⎢ ⎥⎦ μ ⎣ ∂x ∂y ∂x ∂y 1 1 =0 Therefore, even condition (37) is fulfilled. V. COMPARISON TO LITERATURE DATA There are only very few papers dealing with the skin effect in rectangular wires. In addition, not the time dependent current density distribution is given in [3, 4], but the absolute value of current density or electrical field strength versus the wire cross section. Therefore, a qualitative (but no quantitative) comparison is possible and illustrated in the following figures 7 and 8. It can be deduced that the results obtained with the proposed calculation method correspond quite well with the FEM results published in literature. Nevertheless, there is some deviation along the edges of the wires. Most probably this comes from the approximative assumption mentioned in section II. Fig. 7. Comparison to literature data (left: data published in [3], right: solution according to this paper for the same boundary conditions. VI. CONCLUSION In this paper the skin effect of rectangular wires is investigated. In addition to the well-known effect of frequency and beside the influence of the wire geometry (edge lengths) even the influence of temperature and material (e.g. copper or aluminum) can be deduced very easily from the formulae given. For the rectangular wire an analytical solution could be found that is exact for the symmetric case (i.e. quadratic wire) and nearly true for low frequency and arbitrary geometry. For arbitrary geometry and frequency, the solution given is just an approximation. Two different mathematical descriptions for the approximation are given, but physically both are based on the same assumption. The solutions deviate from each other depending on frequency and geometry, but there is no criterion to decide which one fits better to reality. Evaluating Poynting’s vector, it could be proven that the necessary edge condition according to [2] is fulfilled for the solution given. The analytical calculation of the current density distribution deduced in this paper shows (in accordance to the FEM results known from literature) that with increasing frequency the current is displaced more and more to the corners of the wire. This is different to round wires, where the entire circumference is conducting the current. For the example of winding characteristics of nowadays hybrid electric drives for the automotive industry (typical rectangular copper wire with a = 3.0mm times b = 1.25mm cross section), it could be shown that even for the critical case of high frequency up to f = 1000Hz , the approximate analytical solution is fairly good enough to describe the current density distribution. Therefore, even the AC loss calculation will be fairly good using the approximate analytical solution. Consequently, for practical AC loss calculation this simple and time efficient approximate analytical calculation method may be used to evaluate the application envisaged. REFERENCES [1] [2] [3] [4] Fig. 8. Comparison to literature data (left: data published in [4], right: solution according to this paper for the same boundary conditions. K. Simonyi, Theoretische Elektrotechnik, VEB Deutscher Verlag der Wissenschaften, Berlin, 1980 (in German). J. 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