Lecture 1 Refresher on Quantum Mechanics 1. Introduction Want to describe “mechanics” of atomic-scale things, like electrons in atoms and molecules. Why? These ultimately determine the shape, the energy, and all the properties of matter. When do we need quantum mechanics? de Broglie wavelength (1924) λ = h p = h mv h = 6.626 × 10−34 J s (Planck's constant) Car m = 1000 kg v = 100 km/hr Typical value on the highway p = 2.8 × 10−4 kg m/s λ = 2.4 × 10−38 m Too small to detect. Classical object! Electron 9.1 × 10−31 kg v = 0.01 c Typical value in atom p = 2.7 × 10−24 kg m/s λ = 2.4 × 10−10 m Comparable to size of atom. Must account for wave properties of an electron! How to describe wave properties of an electron? Schrödinger equation (1926?) Kinetic energy + Potential energy = Total Energy Expressed as differential equation (Single particle, non-relativistic): ! !2 2 ! ! ! r,t +V r,t ! r,t = !i! ! r,t 2m !t ( ) ( ) ( ) ( ) Ψ(r, t ) : wavefunction Steady-state, or time-independent: ! !2 2 ! ! r +V r ! r = E! r 2m () () () ( ) () ! r,t = ! r e !iEt () ! E: energy © Prof. W. F. Schneider CBE 60547 – Computational Chemistry University of Notre Dame Spring 2012 1/5 Lecture 1 Refresher on Quantum Mechanics 2. Postulates of Non-relativistic Quantum Mechanics Postulate I: The physical state of a system is completely described by its wavefunction Ψ. In general, Ψ is a complex function of the spatial coordinates and time. Ψ is required to be: 1. single-valued 2. continuous and twice-differentiable 3. square-integrable ( ∫ Ψ ∗ Ψdτ is defined over all finite domains) For bound systems Ψ can always be normalized such that ∫ Ψ Ψdτ = 1. ∗ Postulate II: To every physically observable quantity M there corresponds a Hermitian quantum mechanical operator M̂ . The only observable values of M are the eigenvalues of M̂ . Physical quantity Operator Expression Position x, y, z xˆ, yˆ , zˆ x⋅, y⋅, z ⋅ Linear momentum px, … pˆ x , … Angular momentum lx, … lˆx , … ⎛ ∂ ∂ ⎞ −ih⎜ y − z ⎟ , … ∂y ⎠ ⎝ ∂z Kinetic energy T Tˆ h2 2 − ∇ 2m Potential energy V Vˆ V (r ) Total energy E Ĥ −ih − ∂ ,… ∂x h2 2 ∇ + V (r ) 2m Postulate III: If a particular observable M is measured many times on many identical systems in a state Ψ, the average value of the result will be the expectation value of the operator M̂ : M = ∫ Ψ* ( Mˆ Ψ )dτ Postulate IV: The energy-invariant states of a system are solutions of the equation " Ĥ !(r,t) = i! !(r,t), Ĥ = T̂ + Vˆ "t If the system is in a time-independent stationary state, this reduces to the Schrödinger equation: Hˆ Ψ (r) = E Ψ (r) ( ( ) ( )) are called Postulate V: (The uncertainty principle.) Operators that do not commute Aˆ Bˆ Ψ ≠ Bˆ Aˆ Ψ conjugate. Conjugate observables cannot be specified together to arbitrary accuracy. For example, the error (standard deviation) in the measured position and momentum of a particle must satisfy ΔxΔpx ≥ h 2 . © Prof. W. F. Schneider CBE 60547 – Computational Chemistry University of Notre Dame Spring 2012 2/5 Lecture 1 Refresher on Quantum Mechanics 3. Note on constants and units Resource on physical constants: http://physics.nist.gov/cuu/Constants/ Resource for unit conversions: http://www.digitaldutch.com/unitconverter/ Unit converter available in Calc for Gnu emacs Atomic units common for quantum mechanical calculations Atomic unit SI unit Common unit Charge e=1 1.6021×10−19 C Length a0 = 1 (bohr) 5.29177×10−11 m −31 0.529177 Å Mass me = 1 9.10938×10 Angular momentum ħ=1 1.054 572×10−34 J s Energy Eh (hartree) 4.359744×10−18 J Electrostatic force kg 9 1/(4πε0) = 1 27.2114 eV -2 8.987552×10 C N m 1.38065×10−23 J K−1 Boltzmann constant 2 8.31447 J/mol K (see http://en.wikipedia.org/wiki/Atomic_units) Energy units 1 eV = 1.60218×10−19 J = 96.485 kJ/mol = 8065.5 cm−1 = 11064 K kB 4. Example: Energy states of an electron in a box z 3D box → 3 degrees of freedom 0, ⎧ V (r ) = ⎨ ⎩∞, L 0 < x, y , z < L x, y, z ≤ 0, x, y, z ≥ L Schrødinger eq h2 ⎛ ∂ 2 ∂2 ∂ 2 ⎞ − ⎜ 2 + 2 + 2 ⎟ψ ( x, y, z ) = Eψ ( x, y, z ) 2me ⎝ ∂x ∂y ∂y ⎠ ψ ( x, y, z ) = 0, x, y, z ≤ 0, x, y, z ≥ L e− L Second-order linear partial differential equation Boundary value (eigenvalue) problem y L Separable ψ ( x, y, z ) = X ( x )Y ( y ) Z ( z ) © Prof. W. F. Schneider x CBE 60547 – Computational Chemistry University of Notre Dame Spring 2012 3/5 Lecture 1 − Refresher on Quantum Mechanics h2 ⎛ 1 ∂ 2 X ( x) 1 ∂ 2Y ( y) 1 ∂ 2 Z ( z ) ⎞ + + ⎜ ⎟ = E 2me ⎝ X ( x) ∂x 2 Y ( y) ∂y 2 Z ( z ) ∂z 2 ⎠ 0 < x, y, z < L ftn x + ftn y + ftn z = constant → each term must be constant − h2 ∂ 2 X ( x) = Ex X ( x) 2me ∂x 2 nx π x , L n 2π 2 h2 Enx = x 2 2me L X ( x) = sin X (0) = X ( L ) = 0 function that twice differentiated returns itself nx = 1, 2,3,... Solutions called eignefunctions/wavefunctions and eigenvalues Characterized by quantum number, one for each degree of freedom Normalization – require that wavefunction square integrates to 1 L C 2 ! sin 2 0 Xn = x nx ! x 2 dx " C 2 X n X n = 1 #C = ± x x L L n !x 2 sin x , 0 < X < L L L Dirac notation Note increasing nodes with increasing energy E ∝ n2 ΔE ∝ n ΔE E ∝ 1 n See Ho, JPC B 2005, 109, 20657. © Prof. W. F. Schneider CBE 60547 – Computational Chemistry University of Notre Dame Spring 2012 4/5 Lecture 1 Refresher on Quantum Mechanics 3 dimensional solution 3/2 n πy n πx n πz ⎛ 2 ⎞ ψ ( x, y, z ) = X ( x )Y ( y ) Z ( z ) = ⎜ ⎟ sin x sin y sin z L L L ⎝ L ⎠ E = Ex + E y + Ez = (n 2 x ) + n y2 + nz2 π 2 h2 2 2me L nx , ny , nz = 1, 2, 3,K One quantum number for each dof 20 (4,1,1) (3,2,2) (1,4,1) (2,3,2) (1,1,4) (2,2,3) (3,2,1) (2,3,1) (1,2,3) (3,1,1) (1,3,1) (1,1,3) (2,2,1) (1,2,2) (2,1,2) (2,1,1) (1,2,1) (1,1,2) 15 ⎛ 2 2 ⎞ E ⎜ π h 2me L2 ⎟⎠ ⎝ (3,1,2) (2,1,3) (1,3,2) (2,2,2) 10 5 (1,1,1) zero point energy 0 Degeneracy Symmetry Energy levels – depend on volume à pressure!! © Prof. W. F. Schneider CBE 60547 – Computational Chemistry University of Notre Dame Spring 2012 5/5