ELEG-212 Signal Processing and Communications READING ASSIGNMENTS a This Lecture: `Chapter 2, Section 2-6 a Other Reading: `Appendix A: Complex Numbers `Appendix B: MATLAB `Next Lecture: start Chapter 3 LECTURE #3 Phasor Addition Theorem a Lab 0 is this week – room change `Sec. 10: eCALC II, 140 DuPont (Tuesday, 4:00) `Sec. 11: eCALC I, 046 Colburn (Wednesday, 3:30) `Secs. 12&13: eCALC II, 140 DuPont (Thursday, 3:30) `Memory sticks/jump drives make saving work easy ECE-212 Signal Processing First LECTURE OBJECTIVES Euler’s FORMULA aPhasors = Complex Amplitude aComplex Exponential `Complex Numbers represent Sinusoids `Real part is cosine `Imaginary part is sine `Magnitude is one z (t ) = Xe jωt = ( Ae jϕ )e jωt e jθ = cos(θ ) + j sin(θ ) Develop the ABSTRACTION: Adding Sinusoids = Complex Addition e jωt = cos(ω t ) + j sin(ω t ) PHASOR ADDITION THEOREM ECE-212 Signal Processing First 2 3 ECE-212 Signal Processing First 5 1 AVOID Trigonometry Euler’s FORMULA aAlgebra, even complex, is EASIER !!! aCan you recall cos(θ1+θ2) ? aComplex Exponential aUse: real part of ej(θ1+θ2) `Real part is cosine `Imaginary part is sine `Magnitude is one = cos(θ1+θ2) e j (θ1 +θ 2 ) = e jθ1 e jθ 2 = (cosθ1 + j sin θ1 )(cosθ 2 + j sin θ 2 ) = (cosθ1 cosθ 2 − sin θ1 sin θ 2 ) + j (...) ECE-212 Signal Processing First 6 Real & Imaginary Part Plots e jθ = cos(θ ) + j sin(θ ) e jωt = cos(ω t ) + j sin(ω t ) ECE-212 Signal Processing First 7 COMPLEX EXPONENTIAL e jω t = cos(ω t ) + j sin(ω t ) aInterpret this as a Rotating Vector PHASE DIFFERENCE `θ = ωt `Angle changes vs. time `ex: ω=20π rad/s `Rotates 0.2π in 0.01 secs = π/2 e jθ = cos(θ ) + j sin(θ ) ECE-212 Signal Processing First 8 ECE-212 Signal Processing First 9 2 Rotating Phasor Cos = REAL PART Real Part of Euler’s See Demo on CD-ROM Chapter 2 cos(ω t) = ℜe{e jω t } General Sinusoid x(t) = Acos(ω t + ϕ ) So, A cos(ω t + ϕ ) = ℜe{Ae } = ℜe{Ae ϕ e ω } j (ω t +ϕ ) j ECE-212 Signal Processing First 10 COMPLEX AMPLITUDE ECE-212 j t Signal Processing First 11 WANT to ADD SINUSOIDS General Sinusoid x(t) = Acos(ω t + ϕ ) = ℜe{Ae jϕ e jω t } aALL SINUSOIDS have SAME FREQUENCY aHOW to GET {Amp,Phase} of RESULT ? Sinusoid = REAL PART of (Aejφ)ejωt x(t) = ℜe {Xe jω t }= ℜe{z(t)} Complex AMPLITUDE = X z(t) = Xe ECE-212 jω t Signal Processing First X = Ae jϕ 12 ECE-212 Signal Processing First 14 3 ADD SINUSOIDS PHASOR ADDITION RULE aSum Sinusoid has SAME Frequency Get the new complex amplitude by complex addition ECE-212 Signal Processing First 15 ECE-212 Signal Processing First 16 ADD SINUSOIDS EXAMPLE Phasor Addition Proof tm1 tm2 tm3 ECE-212 Signal Processing First 17 ECE-212 Signal Processing First 20 4 Convert Time-Shift to Phase Phasor Add: Numerical aMeasure peak times: aConvert Polar to Cartesian `tm1=-0.0194, tm2=-0.0556, tm3=-0.0394 `X1 = 0.5814 + j1.597 `X2 = -1.785 - j0.6498 `sum = X3 = -1.204 + j0.9476 aConvert to phase (T=0.1) `φ1=-ωtm1 =-(2π/T)tm1 =70π/180, `φ2= 200π/180 aAmplitudes aConvert back to Polar `A1=1.7, A2=1.9, A3=1.532 ECE-212 Signal Processing First 21 ADD SINUSOIDS `X3 = 1.532 at angle 141.79π/180 `This is the sumSignal of Processing the complex amplitudes ECE-212 First 22 PHASOR EXAMPLES X1 VECTOR (PHASOR) ADD ECE-212 X3 X2 Signal Processing First 23 ECE-212 Signal Processing First 24 5