NCN Summer School: July 2011 Solar Cell Physics: recombination and generation Prof. Mark Lundstrom lundstro@purdue.edu Electrical and Computer Engineering Purdue University West Lafayette, Indiana USA copyright 2011 This material is copyrighted by Mark Lundstrom under the following Creative Commons license. Conditions for using these materials is described at http://creativecommons.org/licenses/by-nc-sa/2.5/ Lundstrom 2011 2 acknowledgement Dionisis Berdebes, Jim Moore, and Xufeng Wang played key roles in putting together this tutorial. Their assistance is much appreciated. Lundstrom 2011 3 solar cell physics A solar cell is a simple device – just a pn junction with light shining on it. To maximize efficiency, we must maximize the generation of e-h pairs and minimize the recombination of e-h pairs. This lecture is a short introduction to the physics of crystalline solar cells – specifically Si. Lundstrom 2011 4 outline 1) 2) 3) 4) 5) Introduction Recombination at short circuit Recombination at open circuit Discussion Summary Lundstrom 2011 5 dark current and recombination + N P ID s.s. excess holes s.s. excess electrons electron-injecting contact hole-injecting contact − VA + Lundstrom 2011 6 recombination in the N-type QNR - - N P + electron-injecting contact ID hole-injecting contact − VA + Anytime an electron and hole recombine anywhere within the diode, one electron flows in the external circuit. Lundstrom 2011 7 Shockley-Read-Hall recombination minority carriers injected across junction ET Fn qVA FP SRH recombination ID − VA + Lundstrom 2011 8 recombination at a contact minority carriers injected across junction Fn qVA FP ID − VA + Lundstrom 2011 9 light-current and generation Vbi − VA EF “base” (absorbing layer) “emitter” − VA + 10 ID < 0 Every time a minority electron is generated and collected, one electron flows in the external current. Lundstrom 2011 light-current and recombination 3 e-h pairs generated “emitter” 1 e in external circuit Every time a minority electron is generated and recombines before being Lundstrom 2011 11 collected, the solar cell current suffers. solar cells and recombination • Carrier recombination lowers the short-circuit current and reduces the open-circuit voltage. • To optimize solar cell performance, we need a clear understanding of how many carriers are recombining and where they are recombining. • Then we need to establish a quantitative relation between recombination and solar cell performance. Lundstrom 2011 12 solar cells and recombination J p ( 0) N Jn ( L) = J D (VA ) q ( RTOT (VA ) − GTOT ) ID L RTOT= ∫ R ( x )dx − J p ( 0) 0 P q Jn ( L) − q L GTOT = ∫ Gop ( x )dx 0 0 L x For a formal derivation of this result, see the appendix. Lundstrom 2011 13 outline 1) 2) 3) 4) 5) Introduction Recombination at short circuit Recombination at open circuit Discussion Summary Lundstrom 2011 14 generic crystalline Si solar cell SF = 1000 cm/s n+ “emitter” (0.3 μm) base doping: NA = 1016 /cm3 p-type “base” 200 um key device parameters emitter doping ND = 6 x 1019 /cm3 (198.9 μm) minority carrier lifetime (base) p+ “Back Surface Field” (BSF) (0.8 μm) τn = 34 μs base thickness W = 198.9 μm front junction depth xjf = 0.3 μm back junction depth xjb = 0.8 μm Lundstrom 2011 15 light-generated current = J D ( 0 ) q ( RTOT ( 0 ) − GTOT ) SF = 1000 cm/s n+ “emitter” (0.3 μm) 1) What is GTOT? 200 um p-type “base” 2) How is GTOT spatially distributed? 3) What is RTOT? (198.9 μm) 4) How is RTOT spatially distributed? p+ “Back Surface Field” (BSF) (0.8 μm) 5) How do things change if we remove the BSF? Lundstrom 2011 16 light-generated current: numbers J SC= J D (V= 0= ) q ( RTOT − GTOT ) A n+ “emitter” (0.3 μm) ∞ WD ≈ 0.3 µ m GMAX = 17 -2 -1 2.97 10 cm s G x = dx × ( ) op ∫ 200 um 0 2L p-type “base” (198.9 μm) G= TOT 0 Ln ≈ 320 µ m p+ “Back Surface Field” (BSF) (0.8 μm) 17 -2 -1 G x = dx 2.79 × 10 cm s ( ) ∫ op J SC 39.4 mA/cm 2 = = 2.46 ×1017 cm -2s -1 q q RTOT (= 0 ) 3.31×1016 cm -2s -1 17 CE = 0.88 Lundstrom 2011 light-generated current: understanding entire device near surface xj 18 Lundstrom 2011 x j + WD light-generated current: summary ∞ GMAX = )dx 2.97 ×10 cm s ∫ Gop ( x = 17 -2 -1 2L G= TOT 0 low lifetime (Auger recombination) surface recombination 19 good collection Lundstrom 2011 17 -2 -1 G x = dx 2.79 × 10 cm s ( ) ∫ op 0 minority carrier lifetime BSF recombination at short circuit entire device near surface xj 20 Lundstrom 2011 x j + WD recombination at short circuit: summary J SC 39.4 mA/cm 2 = = 2.46 ×1017 cm -2s -1 q q RTOT (= 0 ) 3.31×1016 cm -2s -1 (0.37) (0.49) (0.14) low lifetime (Auger recombination) surface recombination 21 good collection Lundstrom 2011 minority carrier lifetime BSF about recombination in the base expect: R ( x ) ≈ d 2 ∆n ∆n − = 0 2 dx Ln ∆n ( x ) τn We find the excess minority electron profile by solving the minority carrier diffusion equation: ∆n Jn = ( L′ ) q sback ∆n ( L′ ) d −R ( J n −q ) = dx d ∆n J n ≈ qDn dx ′ ) q s j ∆n ( 0′ ) J n ( 0= 0=′ x j + W L′= L − xBSF x xj +W 22 Ln = Dnτ n Lundstrom 2011 L Adept simulation results R ( x) ≈ ∆n ( x ) τn ∆n ( x ) 23 Lundstrom 2011 the BSF ∆E = 0.13 eV EC Sback ≈ υ th e− ∆E kBT EI EF ; 0.6 × 10 7 cm s EV What happens if we remove the BSF? EC Sback ≈ υ th EI EF EV 24 Lundstrom 2011 ; 1 × 10 7 cm s without the BSF BSF no BSF Without BSF With BSF 25 J SC = 39.4 mA/cm 2 J SC = 38.2 mA/cm 2 qRTOT = 5.3 mA/cm 2 qRTOT = 6.5 mA/cm 2 CE = 0.88 Lundstrom 2011 CE = 0.85 internal quantum efficiency With BSF No BSF J D (V = 0, λ ) IQE = Finc ( λ ) 26 Lundstrom 2011 questions 1) Can you determine a way to find the actual back surface recombination velocity from the Adept simulation results. (Hint: Use plots of n(x) and Jn(x).) 2) How much could the performance improve if the back surface recombination velocity could be reduced to zero? 3) With the original BSF, how much would the performance increase if the minority carrier lifetime was 10 times longer? 4) In the original design, how would the short-circuit current change if the base was twice as thick? 5) Since most of the recombination loss occurs in the emitter, why not just make the emitter junction depth a lot smaller? 27 Lundstrom 2011 2D effects ID VD I ( x) V ( x ) < VD xj dR = ρ S ρ= S dx W ρ 1 = x j N D qµn x j distributed series resistance 28 Lundstrom 2011 outline 1) 2) 3) 4) 5) Introduction Recombination at short circuit Recombination at open circuit Discussion Summary Lundstrom 2011 29 dark I-V = J D (VA ) q ( RTOT (VA ) − GTOT ) = 0 q ( RTOT = (VA VOC ) − GTOT ) Under open circuit conditions: RTOT = GTOT (VA V= OC ) Lundstrom 2011 30 superposition JD = J D (VA ) q ( RTOT (VA ) − GTOT ) dark IV J SC dark: J dark D (VA ) = q R dark TOT (VA ) = J D J 0 ( e qVD − 1) VA VOC illuminated: light = J Dlight (VA ) q ( RTOT (VA ) − GTOT ) − J SC JL < 0 superposition: illuminated at VOC: light RTOT (VOC ) = GTOT nk B T ? Lundstrom 2011 J Ddark (VOC ) = J SC dark RTOT (VOC ) = J SC q 31 dark current characteristics (sketch) = J Ddark (VA ) J 0 ( e qVA J Ddark = (VA ) J 01 ( eqVA nk B T kBT − 1) − 1) + J 02 ( e qVA 2 kBT − 1) series resistance or… n=1 log10 J Ddark shunt resistance or… n=2 VA Lundstrom 2011 32 dark current characteristics (Adept) = J Ddark (VA ) J 0 ( e qVA ( J Ddark = (VA ) J 01 eqVA nk B T kBT − 1) ) ( − 1 + J 02 e qVA 2 kBT ) −1 n >1 n =1 n≈2 Lundstrom 2011 33 what determines J0 and n? ( = J Ddark (VA ) J 0 e qVA nk B T ) −1 dark J Adark (VA ) = q RTOT (VA ) Answer: Electron-hole recombination determines I0. The location of recombination within the solar cell determines the ideality factor, n. Lundstrom 2011 34 recombination in the dark (VA = 0.7 V) Emitter Base Lundstrom 2011 35 recombination summary: (VA = 0.7 V) Short-circuit recombination qRTOT ( 0 ) = 5.3 mA/cm light VA = 0.7 V recombination dark qRTOT ( 0.7 ) = 465 mA/cm 2 2 Lundstrom 2011 36 what happens if we remove the BSF? (VA = 0.7 V) Without BSF With BSF ~70% ~85% J D ( 0.7 ) = 1372 mA/cm 2 J D ( 0.7 ) = 644 mA/cm 2 Lundstrom 2011 37 dark current physics (n = 1) I D (VA ) = qRTOT (VA ) FB: minority carriers injected across junction 1) Recombination in QNRs: Fn ID > 0 qVA FP 2) Electrons and holes can also recombine within the SCR of the junction. Lundstrom 2011 38 n = 1 device physics I D (VA ) = qRTOT (VA ) nP ( 0′ ) ≈ n0 P e qVA kBT q (Vbi − VA ) Qn qRTOT (VA ) = tn ni2 qVA Qn ∝ e NA ( Fn FP kBT ) −1 tn : minority carier lifetime n0P ≈ ni2 N A or base transit time Recombination in quasi-neutral regions gives rise to n = 1 currents. Lundstrom 2011 39 dark current characteristics (sketch) = J Ddark (VA ) J 0 ( e qVA J Ddark = (VA ) J 01 ( eqVA nk B T kBT − 1) − 1) + J 02 ( e qVA 2 kBT − 1) series resistance or… n=1 log10 J Ddark shunt resistance or… n=2 VA Lundstrom 2011 40 recombination in the dark (VA = 0.2 V) base region emitter region Lundstrom 2011 41 recombination summary: (VA = 0.2 V) VA = 0.7 V recombination VA = 0.2 V recombination dark qRTOT ( 0.7 ) = 465 mA/cm 2 dark qRTOT ( 0.7=) 8.4 ×10−6 mA/cm 2 Lundstrom 2011 42 dark current physics I D (VA ) = qRTOT (VA ) FB: minority carriers injected across junction 1) Recombination in QNRs: Fn ID > 0 qVA FP 2) Electrons and holes can also recombine within the SCR of the junction. Lundstrom 2011 43 recombination in SCRs dark J D (VA ) = qRTOT (VA ) q (Vbi − VA ) Fn np = ni2 e qVA Maximum recombination occurs when n(x) ≈ p(x) n ( x ) p ( x ) = ni2 e qVA FP nˆ ≈ pˆ ∝ ni e qVA dark qRTOT (VA ) ∝ kBT kBT 2 kBT qni e qVA 2 kBT τ eff Recombination in space-charge regions gives rise to n = 2 currents. Lundstrom 2011 44 recombination in SCR J D (VA ) = qRTOT (VA ) nˆ ≈ pˆ ∝ ni e qVA Rˆ (V= A) 2 kBT ni e qVA / 2 kBT nˆ = τ eff τ eff J D (VA ) = q Rˆ Weff Weff = E ˆ = 2.3 × 104 V cm = Weff k BT q ≈ 11 nm ˆ E Lundstrom 2011 k BT q Eˆ 45 dark IV ( = J D (VA ) J 02 e qVA 2 kBT ) ( ) ( 1k B T − 1 + J 01 e qVA = − 1 J 0 e qVA Recombination in depletion regions Recombination in neutral regions J 02 ∝ ni ∝ e − EG / 2 kBT J 01 ∝ ni2 ∝ e − EG / kBT large bandgaps and low temperatures nk B T ) −1 small bandgaps and high temperatures Lundstrom 2011 46 questions 1) What do you expect to happen if the BSF were removed? Run an Adept simulation to confirm. 2) What do you expect to happen if the minority carrier lifetime were reduced to 0.1 microseconds? Run an Adept simulation. 3) Why is recombination in the emitter so important under shortcircuit conditions, but not under FB in the dark? 4) How much could VOC be increased if a BSF with near-zero surface recombination velocity could be achieved? 5) Series resistance affects the dark current, but it has no effect at open-circuit. What are the implications? Lundstrom 2011 47 outline 1) 2) 3) 4) 5) Introduction Recombination at short circuit Recombination at open circuit Discussion Summary Lundstrom 2011 48 reducing recombination higher material quality (longer lifetimes) thinner base layer (but optically thick) J D (VA ) q ( RTOT (VA ) − GTOT ) built-in fields back-surface-fields / minority carrier mirrors reducing contact areas …. Lundstrom 2011 49 high-efficiency Si solar cells 24.5% at 1 sun Martin Green Group UNSW – Zhao, et al, 1998 Lundstrom 2011 50 how good is superposition? V = 0.62 V - Dark VOC = 0.62 V - Illuminated Lundstrom 2011 51 how good is superposition? (ii) dark JJDdark J Dlight J Ddark + J Dlight (V = 0 ) superposition Lundstrom 2011 52 outline 1) 2) 3) 4) 5) Introduction Recombination at short circuit Recombination at open circuit Discussion Summary Lundstrom 2011 53 summary 1) Diode current = q times (total recombination – total generation) 2) At VOC, recombination = optical generation 3) At V = 0, recombination lowers the collection efficiency 4) Dark current tells us much about the internal recombination mechanisms 5) Solar cell design is all about maximizing total generation and minimizing total recombination. 6) Simulations can be useful for understanding –especially 2011 54 if you look “inside” andLundstrom not just at the IV. questions 1) 2) 3) 4) 5) Introduction Recombination at short circuit Recombination at open circuit Discussion Summary Lundstrom 2011 55 Appendices 1) Formal derivation of the relation between current and recombination/generation. 2) Mathematical justification of superposition Lundstrom 2011 56 Appendix 1: current and recombination Formal derivation of the relation between current and recombination/generation. J p ( 0) N Jn ( L) J= q ( RTOT − GTOT ) D (V ) ID L RTOT= ∫ R ( x )dx − J p ( 0) 0 P q Jn ( L) − q L GTOT = ∫ Gop ( x )dx 0 0 L x Lundstrom 2011 57 continuity equation for electrons Wabash River Rate of increase of water level in lake ∂n ∂t = = (in flow - outflow) + rain - evaporation −∇ • J n −q ( Lundstrom 58 2011 )+ G − R 58 solar cell physics “semiconductor equations” Conservation Laws: ∇• D =ρ ) (G q ∇• Jp = ( D= κε 0 E = −κε 0∇V ρ= q( p − n + N D+ − N A− ) q ∇ • J n −= ( Relations: op ) (G (steady-state) op − R) J= nq µn E + qDn∇n n J= pq µ p E − qD p ∇p p − R) R = f (n, p ) Gop = optical generation rate etc. Lundstrom 201159 diode current and recombination ∇ • J n −= q ( ) (G op − R) d ( J n −q ) = Gop − R dx L L 0 0 ID (1D) ID N P 0 L = ∫ dJ n q ∫ R ( x ) − Gop ( x ) dx L J n ( L ) − J n ( 0= ) q ∫ R ( x ) − Gop ( x ) dx 0 Lundstrom 2011 60 x current and recombination-generation L J n ( L ) − J n ( 0= ) q ∫ R ( x ) − Gop ( x ) d + J p (x0 ) − J p ( 0 ) 0 L − { J n ( 0 ) + J p ( 0 )} = J D (V ) = q ∫ R ( x ) − Gop ( x ) dx − J n ( L ) − J p ( 0 ) 0 J= q ( RTOT − GTOT ) D (V ) ID L qRTOT = q ∫ R ( x )dx − J n ( L ) − J p ( 0 ) 0 L GTOT = ∫ Gop ( x )dx N P 0 L 0 61 2011 Lundstrom x 61 current and generation-recombination = J D (VA ) q ( RTOT (VA ) − GTOT ) The diode current is q times the total recombination minus the total generation. The total recombination is the integrated recombination rate within the device plus the flux of minority carriers into each contact. Lundstrom 2011 62 62 Appendix 2: justifying superposition = J D (VA ) q ( RTOT (VA ) − GTOT ) (valid in light or dark) dark J Ddark (VA ) = qRTOT (VA ) (dark current) light = J Dlight ( 0 ) q ( RTOT ( 0 ) − GTOT ) (short circuit current) J Dsuper (= VA ) J Ddark + J Dlight ( 0 ) (principle of superposition) dark light J Dsuper (VA ) = qRTOT (VA ) + q ( RTOT ( 0 ) − GTOT ) Lundstrom 2011 (How does this compare to the exact answer?) 63 mathematical justification for superposition ( ) ( ( ) J D V A = q RTOT V A − GTOT ( ) ( ( ) ( ) ( ) ( ) light J Dlight V A = q RTOT V A − GTOT (valid in light or dark) ) () dark light V A + q RTOT 0 − GTOT J Dsuper V A = qRTOT ( ) ( ) () light dark light RTOT V A = RTOT V A + RTOT 0 ?? ) (principle of superposition) (criterion to justify superposition) Lundstrom 2011 64