+12v
Qu. 1. Using the following formula, calculate the voltage in
the potential divider at the point ‘Vout.’
Vout = V x
R1
100Ω
R2

R1 + R2
Vout
R2
300Ω
0v
Qu. 2. The variable resistor shown in the diagram is set
at exactly half way.
+5v
Vout
What is the voltage present at Vout?
0v
+10v
Qu. 3. The following thermistor has a resistance of
30kohms at 20°C. What would be the output
voltage at Vout with a temperature of 20°C?
R1
20kΩ
Vout
R2
Thermistor
0v
Qu. 4. The following potential divider
has been connected to produce
a voltage at Vout of 6 volts.
A voltmeter with a resistance of
10kohms is connected between
Vout and 0v. What will be the
reading on the meter and why?
+12v
+12v
R1
10kΩ
R1
10kΩ
Vout
Vout
R2
10kΩ
R2
10kΩ
0v
V
0v
+10v
Qu. 5. What are the voltages present at V1 and V2?
R1
100Ω
V1
R2
200Ω
V2
R3
200Ω
PTD- 96
0v
(10kΩ)
Answers to WS1.2
Q1/
9 volts
Q2/
2.5 volts
Q3/
6 volts
Q4/
4 volts, because the meter will act as a resistor and combined with R2, would
give a total resistance of 5 Kohms, instead of 10 Kohms.
Q5/
V1 = 8 volts
V2 = 4 volts