Half‐wave rectifier with capacitive filter Breadboard Elettronica II Prof. Paolo Colantonio 2 | 9 Source Elettronica II Prof. Paolo Colantonio 3 | 9 Oscilloscope Elettronica II Prof. Paolo Colantonio 4 | 9 • Let us consider a half‐wave rectifier with a capacitive load, used to produce a steadier output t1 < t < t2 D When vi > VON, the diode is ON and the current flows toward R and C. C is charging with a low RL v(t) i C v o vi VON vo(t) t2 < t < t3 The diode turns OFF and the capacitance discharge with law t VM vo Vm VON e RC vo t t1 Elettronica II Prof. Paolo Colantonio t2 t3 5 | 9 Assuming an high time constant RC>>T (period), then the exponential behaviour can be approximated with the tangent VP V vp t t3 t2 In the time interval t2‐t3, we can write vB t * V P e t* RC t* VP 1 RC Assuming t2‐t3 T, we can write T VP T V V p VP 1 RC RC From which RIPPLE Elettronica II Prof. Paolo Colantonio V T VP RC 6 | 9 iD A t1 < t < t2 Diode ON B D R iR C iD t iC t iR t C dvB t dt vB t R iC t2 < t < t3 Diode OFF vA iD vB t t1 t2 t3 The maximum current occurs at the circuit start up, when the capacitor C is discharged. I D , MAX C Elettronica II Prof. Paolo Colantonio dvB t dt C t 0 d V p sin t 2 f C V p dt t 0 7 | 9 iD vA VP vB V t Dimensioning of RC to control the Ripple V VP T RC RIPPLE T RC Dimensioning of C to reduce the maximum current in the diode I D , MAX 2 f C V p Elettronica II Prof. Paolo Colantonio 8 | 9 Setup Mount the circuit and apply a voltage signal Vpp=10V and f = 1kHz A D1N4001 B Datasheet Diode 1N4001 R C Conducting voltage V=0.65V Max current Imax=30A Work • Determine the values for R and C in order to assure in B a Ripple < 10% of maxximum output voltage Elettronica II Prof. Paolo Colantonio 9 | 9