Lecture 29 Operational Amplifier frequency

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Lecture 29
Operational Amplifier frequency Response
Reading: Jaeger 12.1 and Notes
Georgia Tech
ECE 3040 - Dr. Alan Doolittle
Ideal Op Amps Used to Control Frequency Response
Low Pass Filter
Previously:
Vout
Vout
+
Vin
-
Vin
R1
=−
R2
R1
R2
Now put a capacitor in parallel with R2:
If s = jϖ ,
+
Vout
-
Vin
R1
R2
C2
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Vout
=−
Vin
Vout
Vin
R2
1
C2 s
R1
1
C2 s
R
1
=−
=− 2
1
R1
R1
R2 +
C2 s
R2


1


 1 + R2 C 2 s 
ECE 3040 - Dr. Alan Doolittle
Ideal Op Amps Used to Control Frequency Response
Low Pass Filter
+
Vout
-
Vin
R1
Vout
R
=− 2
Vin
R1
R2


1


 1 + R2 C 2 s 
C2
•At DC (s=0), the gain remains the same as before (-R2/R1).
•At high frequency, R2C2s>>1, the gain dies off with increasing frequency,
Vout
Vin
 1 


 1 
C
s
 = − 2 
≈ −
 R1 
 R1C 2 s 




1
= 2π f H = ω H
R2 C 2
•At high frequencies, more “negative feedback” reduces the overall gain
Georgia Tech
ECE 3040 - Dr. Alan Doolittle
Ideal Op Amps Used to Control Frequency Response
Low Pass Filter
AV
AV
DB
AV
DB
 R2
= 20 Log 
 R1



DB
 Vout
= 20 Log 
 Vin

 is the gain expressed in dB

-3dB drop at fH (Vout has dropped in half!)
Slope = −20 dB / Decade
fH
fH
1
=
2π R2 C 2
Log(f)
•At DC (s=0), the gain remains the same as before (-R2/R1)
•At high frequency, R2C2s>>1, the gain dies off with increasing frequency
•Implements a “Low Pass Filter”: Lower frequencies are allowed to pass the filter
without attenuation. High frequencies are strongly attenuated (do not pass).
Georgia Tech
ECE 3040 - Dr. Alan Doolittle
Ideal Op Amps Used to Control Frequency Response
High Pass Filter
+
Vout
-
Vin
R1
R2
+
Vout
Vin
R1
Vout
=−
Vin
R2
1
R1 +
C1 s
Vout
RCs
=− 2 1
Vin
1 + R1C1 s
C1
Vout
R2
=−
Vin
R1
R2
•At DC (s=0), the gain is zero.
•At high frequency, R1C1s>>1, the gain returns to it’s full
value, (-R2/R1)
Georgia Tech
ECE 3040 - Dr. Alan Doolittle
Ideal Op Amps Used to Control Frequency Response
High Pass Filter
AV
DB
AV
DB
R 
= 20 Log  2 
 R1 
-3dB drop at fH
Vout
R2 C1 s
=−
Vin
1 + R1C1 s
Slope = +20 dB / Decade
fL
Log(f)
1
fL =
2π R1C1
•At DC (s=0), the gain is zero.
•At high frequency, R1C1s>>1, the gain returns to it’s full value, (-R2/R1)
•Implements a “High Pass Filter”: Higher frequencies are allowed to pass the filter
without attenuation. Low frequencies are strongly attenuated (do not pass).
Georgia Tech
ECE 3040 - Dr. Alan Doolittle
Ideal Op Amps Used to Control Frequency Response
Band Pass Filter (combination of high and low pass filter)
+
Vou
C1
R1
Vin
Vout
Vin
1
R2
C2 s
=−
1
R1 +
C1 s
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R2
C2
Low
Pass
High
Pass
1
C2 s
1
R2 +

 R2 C1 s 
C2 s
1


=−
= −
1
1
1
+
R
C
s
+
R
C
s
2 2 
1 1 

R1 +
C1 s
R2
Vout
Vin
t
ECE 3040 - Dr. Alan Doolittle
Ideal Op Amps Used to Control Frequency Response
Band Pass Filter (combination of high and low pass filter)
 R2 C1 s 

Vout
1


= −
1
1
+
Vin
+
R
C
s
R
C
s
2 2 
1 1 

AV
DB
AV
DB
 R2
= 20 Log 
 R1



1
fL =
2π R1C1
1
fH =
2π R2 C 2
fH
fL
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Slopes = − 20 dB / Decade
+
-3dB drop at fH
f L << f H
Log(f)
ECE 3040 - Dr. Alan Doolittle
Ideal Op Amps Used to Control Frequency Response
Band Pass Filter (combination of high and low pass filter)
 R2 C1 s 

Vout
1


= −
1
1
+
Vin
+
R
C
s
R
C
s
2 2 
1 1 

AV
Slopes = − 20 dB / Decade
+
DB
AV
DB
R 
= 20 Log  2 
 R1 
More than a -3dB drop at fL and fH
fL < fH
fL
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fH
and
fL → fH
Log(f)
ECE 3040 - Dr. Alan Doolittle
General Frequency Response of a Circuit
Poles and Zeros
Generally, a circuit’s transfer function (frequency dependent gain expression) can be written as the
ratio of polynomials:
vout
(τ 1z s )(1 + τ 2 z s )(1 + τ 2 z s )...
(
τ 1zϖ ) 1 − (τ 2 zϖ )2 1 − (τ 3 zϖ )2 ...
vout
=A
=A
2
2
2
(1 + τ 1 p s )(1 + τ 2 p s )(1 + τ 3 p s )...
vin
vin
1 − (τ ϖ ) 1 − (τ ϖ ) 1 − (τ ϖ ) ...
1p
2p
3p
Complex Roots of the numerator polynomial are called “zeros” while complex roots of the
denominator polynomial are called “poles”
Each zero causes the transfer function to “break to higher gain” (slope increases by 20 dB/decade)
Each pole causes the transfer function to “break to lower gain” (slope decreases by 20 dB/decade)




-20
dB
/D
ec a
Typically, τ=RC
de
0 dB/Decade
dB
/D
eca
de
2
0 dB/Decade
40
 vout
20 Log 
 vin
e
B/D
d
0
e
ca d
2
eca
D
/
B
0d
de
ϖ=
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1
τ 2z
ϖ=
1
τ1p
ϖ=
1
τ 2p
ϖ=
1
τ 3p
ϖ=
1
ϖ
τ 3z
ECE 3040 - Dr. Alan Doolittle
Real Op Amp Frequency Response
•To this point we have assumed the open loop gain, AOpen Loop, of
the op amp is constant at all frequencies.
•Real Op amps have a frequency dependant open loop gain.
AOpenLoop ( s ) =
AOϖ B
ϖT
=
s +ϖ B s +ϖ B
where,
s = jϖ
AO ≡ Open loop gain at DC
ϖ B ≡ Open loop bandwidth
(
)
ϖ T ≡ Unity - gain frequency frequency where AOpenLoop ( s ) = 1
Georgia Tech
ECE 3040 - Dr. Alan Doolittle
Real Op Amp Frequency Response
AOpenLoop ( jϖ ) =
AOpenLoop ( jϖ ) =
AOϖ B
ϖ 2 +ϖ B2
AO
ϖ2
1+
ϖ B2
At Low Frequencies: AOpenLoop = AO
At High Frequencies: AOpenLoop ≈
AOϖ B
ϖ
=
ϖT
ϖ
For most frequencies of interest, ω>>ωB , the product of the gain and frequency is
a constant, ωT
ϖ
f T = T ≡ Gain − Bandwidth Pr oduct (GBW )
2π
Georgia Tech
ECE 3040 - Dr. Alan Doolittle
Real Op Amp Frequency Response
For the "741" Op Amp,
AO ~ 200,000 = 106 dB
ϖ B ~ (2π ) 5 Hz
ϖ T ~ (2π ) 1 MHz
GBW
For the " Op 07" Op Amp,
AO ~ 12,000,000 = 141 dB
ϖ B ~ (2π ) 0.05 Hz
ϖ T ~ (2π ) 0.6 MHz
GBW
If the open loop bandwidth is so small, how can the op amp be useful?
The answer to this is found by considering the closed loop gain.
Georgia Tech
ECE 3040 - Dr. Alan Doolittle
Real Op Amp Frequency Response
Previously, we found that the closed loop gain for the Noninverting configuration was (for finite open loop gain):
AV ,ClosedLoop
AOpenLoop
Vout
R1
=
=
, where β =
Vin 1 + β AOpenLoop
R1 + R 2
Using the frequency dependent open loop gain:
AV ,ClosedLoop =
AV ,ClosedLoop
AV ,ClosedLoop
AOpenLoop
Vout
=
Vin 1 + β AOpenLoop
 AOϖ B 


s +ϖ B 
= 
Aϖ
1 + β  O B
 s +ϖ B
Low
AOϖ B
=
Pass
 s + ϖ B (1 + β AO )


AOϖ B
AO


(1 + β AO )
ϖ B (1 + β AO )
1
=
=
=

s
s
s
+1
+1 1+
ϖ B (1 + β AO )
ϖ B (1 + β AO )
 ϖH


A
 V ,ClosedLoop


@ DC
where,
ϖ H ≡ Upper Cutoff Frequency (Closed Loop Bandwith ) = ϖ B (1 + β AO )
Georgia Tech
ECE 3040 - Dr. Alan Doolittle
Real Op Amp Frequency Response
Open LoopGain
The closed Loop
Amplifier has a
lower gain than
the Open Loop
Amplifier
ϖH
Closed Loop Bandwidth
ϖT
= ϖ B (1 + β AO ) =
AV ,ClosedLoop
Closed LoopGain
@ DC
Closed Loop DC Gain
AV ,ClosedLoop =
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AOpenLoop
1 + β AOpenLoop
The closed Loop Amplifier has a higher
bandwidth than the Open Loop Amplifier
ECE 3040 - Dr. Alan Doolittle
Real Op Amp Frequency Response
Closed Loop Gain set
by feedback network
below ωH
Closed Loop Gain
set Open Loop
Gain above ωH
(Gain
x Bandwidth
) Open
Loop
= (Gain x Bandwidth
) Closed
Loop
Example: 741 Op Amp is used as a low pass filter with fL=10kHz. What is the
maximum voltage gain possible for this circuit?
From before, we can write:
(200 , 000
x 5 ) Open
(Gain ) Closed
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Loop
Loop
= (Gain x 10 , 000
= 100 V
V
) Closed
Loop
Maximum
ECE 3040 - Dr. Alan Doolittle
Real Op Amp Frequency Response
For the Inverting Configuration:
By sup erposition,
+
vVin
R1
Vout
R2
v − = vout
R1
R2
+ vin
R1 + R2
R1 + R2
R2
v − = vout β + vin β
R1
but ,
vout = −v − AV ,OpenLoop
so,
−
vout
AV ,OpenLoop
AV ,ClosedLoop
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= vout β + vin β
R2
R1
AV ,OpenLoop β
vout
=
=
vin 1 + AV ,OpenLoop β
 R2 
 −

 R1 
ECE 3040 - Dr. Alan Doolittle
Real Op Amp Frequency Response
Inserting the frequency dependent open loop gain:
AV ,ClosedLoop
AV ,OpenLoop β  R2
 −
=
1 + AV ,OpenLoop β  R1
AV ,ClosedLoop
 AOϖ B 

 β
s +ϖ B 

=
Aϖ 
1 +  O B  β
 s +ϖ B 
AV ,ClosedLoop =
AV ,ClosedLoop
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


 R2 
AOϖ B β
 −
 =
 R1  s + ϖ B + AOϖ B β

AOϖ B β
 −
s + ϖ B (1 + AO β ) 
 R2 
 −

 R1 
AOϖ B β
ϖ B (1 + AO β )  R2 
R2 
 −

 =
R1  s + ϖ B (1 + AO β )  R1 
ϖ B (1 + AO β )
 AO β  R2  

 −
 
 (1 + AO β )  R1  
=

s

+1 
 ϖ B (1 + AO β )



ECE 3040 - Dr. Alan Doolittle
Real Op Amp Frequency Response
AV ,ClosedLoop
 AO β  R2  

 −
 
 (1 + AO β )  R1  
=

s

+1 
 ϖ B (1 + AO β )



AV ,ClosedLoop




1

A
=

 V ,ClosedLoop
s
1+

(
)
+
ϖ
1
β
A
B
O


Closed Loop Bandwidth
ϖ H = ϖ B (1 + β AO ) =
ϖT
AV ,ClosedLoop
Closed Loop DC Gain
AV ,ClosedLoop
@ DC
@ DC
AV ,OpenLoop β  R2 
 −

=
1 + AV ,OpenLoop β  R1 
The frequency behavior is the same as for the the Non-Inverting case!
Georgia Tech
ECE 3040 - Dr. Alan Doolittle
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