Chapter 4 Series Circuits ISU EE C.Y. Lee Objectives Identify a series circuit Determine the current in a series circuit Determine total series resistance Apply Ohm’s law in series circuits Determine the total effect of voltage sources in series Apply Kirchhoff’s voltage law Use a series circuit as a voltage divider Determine power in a series circuit ISU EE 2 C.Y. Lee Resistors in Series A series circuit provides only one path for current between two points ISU EE 3 C.Y. Lee Current in a Series Circuit The current is the same through all points in a series circuit ISU EE 4 C.Y. Lee Current in a Series Circuit Current entering any point in a series circuit is the same as the current leaving that point ISU EE 5 C.Y. Lee Current in a Series Circuit Example: How much current does ammeter 1 and ammeter 2 indicate, respectively ? 500 IA1 = IA2 = 100 V/500 Ω = 0.2 A ISU EE 6 C.Y. Lee Total Series Resistance The total resistance of a series circuit is equal to the sum of the resistances of each individual series resistor RT = R1 + R2 + R3 + . . . + Rn ISU EE 7 C.Y. Lee Ohm’s Law in Series Circuits If you know the total voltage and the total resistance, you can determine the total current by using: IT = VT/RT Example: Find the current in below circuit RT = 82 + 18 + 15 + 10 = 125 Ω I = VT/RT = 25/125 = 0.2 A ISU EE 8 C.Y. Lee Ohm’s Law in Series Circuits If you know the voltage drop across one of the series resistors, you can determine the current by using: I = VR/R Example: Find the current in below circuit I = VR/R = 2/10 = 0.2 A ISU EE 9 C.Y. Lee Ohm’s Law in Series Circuits If you know the total current, you can find the voltage drop across any of the series resistors by using: VR = ITR Example: Find the voltage drop in R1 resistor RT = 82 + 18 + 15 + 10 = 125 Ω I = VT/RT = 25/125 = 0.2 A VR1 = 0.2 × 82 = 16.4 V ISU EE 10 C.Y. Lee Ohm’s Law in Series Circuits − + 16.4 25V 200 ISU EE 11 C.Y. Lee Voltage Sources in Series When two or more voltage sources are in series, the total voltage is equal to the the algebraic sum (including polarities of the sources) of the individual source voltages ISU EE 12 C.Y. Lee Voltage Sources in Series Example: Determine VS(tot) in below circuit ?V VS(tot) = 25 V − 15 V = 10 V ISU EE 13 C.Y. Lee Kirchhoff’s Voltage Law (KVL) The algebraic sum of all the voltage drops around a single closed loop in a circuit is equal to the total source voltage in that loop VS = V1 + V2 + V3 + … + Vn ISU EE 14 C.Y. Lee Another Way to state Kirchhoff’s Voltage Law The algebraic sum of all voltages (both sources and drops) around a closed path is zero Loop VS VS = V1 + V2 + V3 + … + Vn VS - V1 - V2 - V3 - … - Vn = 0 ISU EE 15 Vn V3 V2 V1 C.Y. Lee Kirchhoff’s Voltage Law Example: Determine the VS in below circuit − 8V + − 16 V + + 32 V + − 24 V − VS = 32 + 24 + 16 + 8 + 8 = 88 V ISU EE 16 C.Y. Lee Voltage Dividers Since each resistor has the same current, the voltage drops are proportional to the resistance values ISU EE 17 C.Y. Lee Voltage-Divider Formula The voltage drop Vx across any resistor or combination of resistors in a series circuit RX VX = VS RT ISU EE (V) 18 C.Y. Lee Application of Voltage Dividers A voltage divider used for volume control 2 3 1 1 2 3 ISU EE 19 C.Y. Lee Power in a Series Circuit The total amount of power in a series resistive circuit is equal to the sum of the powers in each resistor in series PT = P1 + P2 + . . . + Pn PT = IVS PT = I 2 RT VS2 PT = RT ISU EE PT = (15)2/(10+12+56+22) = 2.25 W 20 C.Y. Lee Circuit Ground Voltage is relative This reference point in a circuit is usually the ground point ISU EE 21 C.Y. Lee Measuring Voltages with Respect to Ground (Negative ground) ISU EE (Positive ground) 22 C.Y. Lee Open Circuit An open in a series circuit prevents current When an open occurs in a series circuit, all of the source voltage appears across the open ISU EE 23 C.Y. Lee A Short in a Series Circuit The voltage across a shorted series component (or circuit) is 0 volts ISU EE 24 C.Y. Lee Summary Current is the same at all points in a series circuit The total resistance between any two points in a series circuit is equal to the sum of all resistors connected in series between those two points Voltage sources in series add algebraically Kirchhoff’s voltage law (KVL): The sum of the voltage drops equals the total source voltage Alternative KVL: The algebraic sum of all the voltages around a closed loop is zero ISU EE 25 C.Y. Lee Summary A voltage divider is a series arrangement of resistors Ground is zero volts with respect to all points referenced to it in the circuit The voltage across an open series element equals the source voltage The voltage across a shorted series component is 0 volts ISU EE 26 C.Y. Lee