Q1. In the circuit below the battery has negligible internal
resistance.
A
P
30Ω
Q
6V
30Ω
R
30Ω
S
a) What is the p.d. between i) P and S?……………………
ii)P and Q?……………………
iii)S and Q?…………………..
b) What is the current through each of the resistors?
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c) What is the current through the ammeter?
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Q2. On the axes below draw the graph for a lamp.
I
V
0
Q3. On the axes below draw the graph for a diode.
I
V
0
Q4. A cell is connected across a conductor. The current
flowing in the conductor is 80mA
i)
Calculate the charge that flows past a point in the
conductor in 2 minutes
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ii)Calculate the number of electron charge carriers passing the
same point in this time.
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iii) If 17.2 J of energy is transferred to the conductor in this
time, find the p.d. across the conductor.
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Q5. The circuit below is used to find the internal resistance
and emf of a dry cell.
V
∈
r
R
A
Use the readings on the next slide to find the
values of emf and internal resistance.( Hint: Draw
a straight line graph of V(y axis) against I (on x
axis)).
Reading on
Voltmeter/V
2.0
Reading on
ammeter/A
0.03
1.5
0.07
1.0
0.10
0.5
0.14
Q6.In the potential divider circuit below assume that the
internal resistance of the cell is negligible and the
resistance of the voltmeter is infinite.
12V
10Ω
20Ω
V
a) What is the voltmeter reading?
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b)The 10Ω resistor is replaced by a 60Ω resistor. Calculate the p.d.
across the 60Ω resistor
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c) Explain why the voltmeter reading across the 20Ω
resistor has changed.
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d) A 90Ω resistor is now placed in parallel with the 20Ω.
Explain what will happen to the voltmeter reading
without further calculation.
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Q7.
a)Define resistivity
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b) Calculate the resistance of 30cm of copper wire which
has a diameter of 2mm.
The resistivity of copper is1.6x10-8Ωm.
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Q8.a) A light bulb of resistance 1200Ω is powered by a 240v supply.
Calculate the following:
i)
The current flowing through the bulb.
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ii) The amount of charge which passes through the bulb in 5 minutes.
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iii) The energy dissipated by the bulb in 5 minutes.
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