Solution to Princess Gwendolynn’s Puzzle: Make a chart of the answers; note where patterns begin & end (powers of 2): 20 21 22 23 skip 1, delete 2 skip 1, delete 2, skip 3; delete 1 sk1, dl2, sk3, dl4; sk1, dl3 sk1, dl2, sk3, dl4, sk5; dl1 sk1, dl2, sk3, dl4, sk5, dl6; sk1, dl3, sk5; dl3 etc… (notice that all even numbers are eliminated on the first round) x = # of knights c = chair of choice So we have: 2(x - 2n) + 1 = c and 2(n+1) > x 2n because we are counting every other knight because we skipped the first chair (1) because we have no negative or zero chairs, and we are only concerned with the remainder beyond a power of two For 20 chairs: x = 20 2n = 24 = 16 2(20 – 16) + 1 = 2(4) + 1 = 9 For 7 chairs: x=7 2n = 22 = 4 2(7 – 4) + 1 = 2(3) + 1 = 7 For 1 chair: x=1 2n = 2 0 = 1 2(1 – 1) + 1 = 2(0) + 1 = 1 For 2 chairs: x=2 2n = 21 = 2 2(2 – 2) + 1 = 2(0) + 1 = 1