CSCE 430/830 Computer Architecture Basic Pipelining & Performance Adopted from Professor David Patterson

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CSCE 430/830 Computer Architecture
Basic Pipelining & Performance
Adopted from
Professor David Patterson
Electrical Engineering and Computer Sciences
University of California, Berkeley
Outline
•
•
•
•
•
•
•
MIPS – An ISA for Pipelining
5 stage pipelining
Structural and Data Hazards
Forwarding
Branch Schemes
Exceptions and Interrupts
Conclusion
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CSCE 430/830, Basic Pipelining & Performance
2
A "Typical" RISC ISA
•
•
•
•
32-bit fixed format instruction (3 formats)
32 32-bit GPR (R0 contains zero, DP take pair)
3-address, reg-reg arithmetic instruction
Single address mode for load/store:
base + displacement
– no indirection
• Simple branch conditions
• Delayed branch
see: SPARC, MIPS, HP PA-Risc, DEC Alpha, IBM PowerPC,
CDC 6600, CDC 7600, Cray-1, Cray-2, Cray-3
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3
Example: MIPS ( MIPS)
Register-Register
31
26 25
Op
21 20
Rs1
16 15
Rs2
11 10
6 5
Rd
0
Opx
Register-Immediate
31
26 25
Op
21 20
Rs1
16 15
Rd
immediate
0
Branch
31
26 25
Op
Rs1
21 20
16 15
Rs2/Opx
immediate
0
Jump / Call
31
26 25
Op
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target
CSCE 430/830, Basic Pipelining & Performance
0
4
Datapath vs Control
Datapath
Controller
signals
Control Points
• Datapath: Storage, FU, interconnect sufficient to perform the
desired functions
– Inputs are Control Points
– Outputs are signals
• Controller: State machine to orchestrate operation on the data
path
– Based on desired function and signals
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Approaching an ISA
• Instruction Set Architecture
– Defines set of operations, instruction format, hardware supported
data types, named storage, addressing modes, sequencing
• Meaning of each instruction is described by RTL (Register
Transfer Language) on architected registers and memory
• Given technology constraints assemble adequate datapath
–
–
–
–
Architected storage mapped to actual storage
Function units to do all the required operations
Possible additional storage (eg. MAR, MBR, …)
Interconnect to move information among regs and FUs
• Map each instruction to sequence of RTLs
• Collate sequences into symbolic controller state transition
diagram (STD)
• Lower symbolic STD to control points
• Implement controller
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5 Steps of MIPS Datapath
Figure A.2, Page A-8
Instruction
Fetch
Instr. Decode
Reg. Fetch
Execute
Addr. Calc
Next SEQ PC
Adder
4
Zero?
RS1
L
M
D
MUX
Data
Memory
ALU
Imm
MUX MUX
RD
Reg File
Inst
Memory
Address
IR <= mem[PC];
RS2
Write
Back
MUX
Next PC
Memory
Access
Sign
Extend
PC <= PC + 4
Reg[IRrd] <= Reg[IRrs1] opIRop Reg[IRrs2]
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WB Data
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5 Steps of MIPS Datapath
Figure A.3, Page A-9
Execute
Addr. Calc
Instr. Decode
Reg. Fetch
Next SEQ PC
Next SEQ PC
Adder
4
Zero?
RS1
MUX
MEM/WB
Data
Memory
EX/MEM
A <= Reg[IRrs1];
Imm
ALU
PC <= PC + 4
MUX MUX
IR <= mem[PC];
ID/EX
RD
Reg File
IF/ID
Memory
Address
RS2
Write
Back
MUX
Next PC
Memory
Access
WB Data
Instruction
Fetch
Sign
Extend
RD
RD
RD
B <= Reg[IRrs2]
rslt <= A opIRop B
WB <= result
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Reg[IRrd] <= WB
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Inst. Set Processor Controller
IR <= mem[PC];
PC <= PC + 4
JSR
A <= Reg[IRrs1];
JR
br
if bop(A,b)
Ifetch
opFetch-DCD
ST
B <= Reg[IRrs2]
jmp
RR
PC <= IRjaddr
r <= A opIRop B
RI
LD
r <= A opIRop IRim
r <= A + IRim
WB <= r
WB <= Mem[r]
PC <= PC+IRim
WB <= r
Reg[IRrd] <= WB
Reg[IRrd] <= WB
CSCE 430/830, Basic Pipelining & Performance
Reg[IRrd] <= WB
9
5 Steps of MIPS Datapath
Figure A.3, Page A-9
Execute
Addr. Calc
Instr. Decode
Reg. Fetch
Next SEQ PC
Next SEQ PC
Adder
4
Zero?
RS1
MUX
MEM/WB
Data
Memory
EX/MEM
ALU
MUX MUX
ID/EX
Imm
Reg File
IF/ID
Memory
Address
RS2
Write
Back
MUX
Next PC
Memory
Access
WB Data
Instruction
Fetch
Sign
Extend
RD
RD
RD
• Data stationary control
– local
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decode CSCE
for each
instruction
phase
/ pipeline stage
430/830,
Basic Pipelining
& Performance
10
Visualizing Pipelining
Figure A.2, Page A-8
Time (clock cycles)
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Reg
DMem
Ifetch
Reg
DMem
Reg
ALU
DMem
Reg
ALU
O
r
d
e
r
Ifetch
ALU
I
n
s
t
r.
ALU
Cycle 1 Cycle 2 Cycle 3 Cycle 4 Cycle 5 Cycle 6 Cycle 7
Ifetch
Ifetch
Reg
Reg
CSCE 430/830, Basic Pipelining & Performance
Reg
DMem
Reg
11
Instruction-Level Parallelism
• Review of Pipelining (the laundry analogy)
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Pipelining is not quite that easy!
• Limits to pipelining: Hazards prevent next instruction
from executing during its designated clock cycle
– Structural hazards: HW cannot support this combination of
instructions (single person to fold and put clothes away)
– Data hazards: Instruction depends on result of prior instruction still
in the pipeline (missing sock)
– Control hazards: Caused by delay between the fetching of
instructions and decisions about changes in control flow (branches
and jumps).
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One Memory Port/Structural Hazards
Figure A.4, Page A-14
Time (clock cycles)
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Reg
DMem
Reg
DMem
Reg
DMem
Reg
ALU
Instr 4
Ifetch
ALU
Instr 3
DMem
ALU
O
r
d
e
r
Instr 2
Reg
ALU
I Load Ifetch
n
s
Instr 1
t
r.
ALU
Cycle 1 Cycle 2 Cycle 3 Cycle 4 Cycle 5 Cycle 6 Cycle 7
Ifetch
Ifetch
Reg
Ifetch
Reg
CSCE 430/830, Basic Pipelining & Performance
Reg
Reg
Reg
DMem
14
One Memory Port/Structural Hazards
(Similar to Figure A.5, Page A-15)
Time (clock cycles)
Stall
DMem
Ifetch
Reg
DMem
Reg
ALU
Ifetch
Bubble
Instr 3
Reg
Reg
DMem
Bubble Bubble
Ifetch
Reg
Reg
Bubble
ALU
O
r
d
e
r
Instr 2
Reg
ALU
I Load Ifetch
n
s
Instr 1
t
r.
ALU
Cycle 1 Cycle 2 Cycle 3 Cycle 4 Cycle 5 Cycle 6 Cycle 7
Bubble
Reg
DMem
How do you “bubble” the pipe?
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Speed Up Equation for Pipelining
CPIpipelined  Ideal CPI  Average Stall cycles per Inst
Cycle Timeunpipelined
Ideal CPI  Pipeline depth
Speedup 

Ideal CPI  Pipeline stall CPI
Cycle Timepipelined
For simple RISC pipeline, CPI = 1:
Cycle Timeunpipelined
Pipeline depth
Speedup 

1  Pipeline stall CPI
Cycle Timepipelined
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Example: Dual-port vs. Single-port
• Machine A: Dual ported memory (“Harvard Architecture”)
• Machine B: Single ported memory, but its pipelined
implementation has a 1.05 times faster clock rate
• Ideal CPI = 1 for both
• Loads are 40% of instructions executed
SpeedUpA = Pipeline Depth/(1 + 0) x (clockunpipe/clockpipe)
= Pipeline Depth
SpeedUpB = Pipeline Depth/(1 + 0.4 x 1) x (clockunpipe/(clockunpipe / 1.05)
= (Pipeline Depth/1.4) x 1.05
= 0.75 x Pipeline Depth
SpeedUpA / SpeedUpB = Pipeline Depth/(0.75 x Pipeline Depth) = 1.33
• Machine A is 1.33 times faster
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Data Hazard on R1
Figure A.6, Page A-17
Time (clock cycles)
and r6,r1,r7
or
r8,r1,r9
xor r10,r1,r11
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Ifetch
DMem
Reg
DMem
Ifetch
Reg
DMem
Ifetch
Reg
DMem
Ifetch
Reg
ALU
sub r4,r1,r3
Reg
ALU
Ifetch
ALU
O
r
d
e
r
add r1,r2,r3
WB
ALU
I
n
s
t
r.
MEM
ALU
IF ID/RF EX
Reg
CSCE 430/830, Basic Pipelining & Performance
Reg
Reg
Reg
DMem
18
Reg
Three Generic Data Hazards
• Read After Write (RAW)
InstrJ tries to read operand before InstrI writes it
I: add r1,r2,r3
J: sub r4,r1,r3
• Caused by a “Dependence” (in compiler
nomenclature). This hazard results from an actual
need for communication.
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Three Generic Data Hazards
• Write After Read (WAR)
InstrJ writes operand before InstrI reads it
I: sub r4,r1,r3
J: add r1,r2,r3
K: mul r6,r1,r7
• Called an “anti-dependence” by compiler writers.
This results from reuse of the name “r1”.
• Can it happen in MIPS 5 stage pipeline?
– All instructions take 5 stages, and
– Reads are always in stage 2, and
– Writes are always in stage 5
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Three Generic Data Hazards
• Write After Write (WAW)
InstrJ writes operand before InstrI writes it.
I: sub r1,r4,r3
J: add r1,r2,r3
K: mul r6,r1,r7
• Called an “output dependence” by compiler writers
This also results from the reuse of name “r1”.
• Can’t happen in MIPS 5 stage pipeline because:
– All instructions take 5 stages, and
– Writes are always in stage 5
• Will see WAR and WAW in more complicated pipes
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Forwarding to Avoid Data Hazard
Figure A.7, Page A-19
or
r8,r1,r9
xor r10,r1,r11
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Reg
DMem
Ifetch
Reg
DMem
Ifetch
Reg
DMem
Ifetch
Reg
ALU
and r6,r1,r7
Ifetch
DMem
ALU
sub r4,r1,r3
Reg
ALU
O
r
d
e
r
add r1,r2,r3 Ifetch
ALU
I
n
s
t
r.
ALU
Time (clock cycles)
Reg
Reg
CSCE 430/830, Basic Pipelining & Performance
Reg
Reg
DMem
22
Reg
HW Change for Forwarding
Figure A.23, Page A-37
NextPC
mux
MEM/WR
EX/MEM
ALU
mux
ID/EX
Registers
Data
Memory
mux
Immediate
What circuit detects and resolves this hazard?
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Forwarding to Avoid LW-SW Data Hazard
Figure A.8, Page A-20
or
r8,r6,r9
xor r10,r9,r11
Reg
DMem
Ifetch
Reg
DMem
Ifetch
Reg
DMem
Ifetch
Reg
ALU
sw r4,12(r1)
Ifetch
DMem
ALU
lw r4, 0(r1)
Reg
ALU
O
r
d
e
r
add r1,r2,r3 Ifetch
ALU
I
n
s
t
r.
ALU
Time (clock cycles)
Reg
Reg
Reg
Reg
DMem
Any hazard that cannot be avoided with forwarding?
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Reg
Data Hazard Even with Forwarding
Figure A.9, Page A-21
and r6,r1,r7
or
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r8,r1,r9
DMem
Ifetch
Reg
DMem
Reg
Ifetch
Ifetch
Reg
Reg
CSCE 430/830, Basic Pipelining & Performance
Reg
DMem
ALU
O
r
d
e
r
sub r4,r1,r6
Reg
ALU
lw r1, 0(r2)Ifetch
ALU
I
n
s
t
r.
ALU
Time (clock cycles)
Reg
Reg
DMem
25
Data Hazard Even with Forwarding
(Similar to Figure A.10, Page A-21)
and r6,r1,r7
or r8,r1,r9
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Reg
DMem
Ifetch
Reg
Bubble
Ifetch
Bubble
Reg
Bubble
Ifetch
Reg
CSCE 430/830, Basic Pipelining & Performance
How is this detected?
DMem
Reg
Reg
Reg
DMem
ALU
sub r4,r1,r6
Ifetch
ALU
O
r
d
e
r
lw r1, 0(r2)
ALU
I
n
s
t
r.
ALU
Time (clock cycles)
DMem
26
Software Scheduling to Avoid Load
Hazards
Try producing fast code for
a = b + c;
d = e – f;
assuming a, b, c, d ,e, and f in memory.
Slow code:
LW
LW
ADD
SW
LW
LW
SUB
SW
Rb,b
Rc,c
Ra,Rb,Rc
a,Ra
Re,e
Rf,f
Rd,Re,Rf
d,Rd
Fast code:
LW
LW
LW
ADD
LW
SW
SUB
SW
Rb,b
Rc,c
Re,e
Ra,Rb,Rc
Rf,f
a,Ra
Rd,Re,Rf
d,Rd
Compiler optimizes for performance. Hardware checks for safety.
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Outline
•
•
Review
Quantify and summarize performance
– Ratios, Geometric Mean, Multiplicative Standard Deviation
•
•
•
•
•
•
•
•
F&P: Benchmarks age, disks fail,1 point fail
danger
MIPS – An ISA for Pipelining
5 stage pipelining
Structural and Data Hazards
Forwarding
Branch Schemes
Exceptions and Interrupts
Conclusion
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r6,r1,r7
22: add r8,r1,r9
Ifetch
Reg
DMem
Ifetch
Reg
DMem
Ifetch
Reg
DMem
Ifetch
Reg
ALU
18: or
DMem
ALU
14: and r2,r3,r5
Reg
ALU
Ifetch
ALU
10: beq r1,r3,36
ALU
Control Hazard on Branches
Three Stage Stall
36: xor r10,r1,r11
Reg
Reg
Reg
Reg
DMem
What do you do with the 3 instructions in between?
How do you do it?
Where is the “commit”?
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Reg
Branch Stall Impact
• If CPI = 1, 30% branch,
Stall 3 cycles => new CPI = 1.9!
• Two part solution:
– Determine branch outcome sooner, AND
– Compute taken branch (target) address earlier
• MIPS branch tests if register = 0 or  0
• MIPS Solution:
– Move Zero test to ID/RF stage
– Adder to calculate new PC in ID/RF stage
– 1 clock cycle penalty for branch versus 3
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Pipelined MIPS Datapath
Figure A.24, page A-38
Instruction
Fetch
Memory
Access
Write
Back
Adder
Adder
MUX
Next
SEQ PC
Next PC
Zero?
RS1
MUX
MEM/WB
Data
Memory
EX/MEM
ALU
MUX
ID/EX
Imm
Reg File
IF/ID
Memory
Address
RS2
WB Data
4
Execute
Addr. Calc
Instr. Decode
Reg. Fetch
Sign
Extend
RD
RD
RD
• Interplay of instruction set design and cycle time.
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Four Branch Hazard Alternatives
#1: Stall until branch direction is clear
#2: Predict Branch Not Taken
–
–
–
–
–
Execute successor instructions in sequence
“Squash” instructions in pipeline if branch actually taken
Advantage of late pipeline state update
47% MIPS branches not taken on average
PC+4 already calculated, so use it to get next instruction
#3: Predict Branch Taken
– 53% MIPS branches taken on average
– But haven’t calculated branch target address in MIPS
» MIPS still incurs 1 cycle branch penalty
» Other machines: branch target known before outcome
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Four Branch Hazard Alternatives
#4: Delayed Branch
– Define branch to take place AFTER a following instruction
branch instruction
sequential successor1
sequential successor2
........
sequential successorn
branch target if taken
Branch delay of length n
– 1 slot delay allows proper decision and branch target
address in 5 stage pipeline
– MIPS uses this
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Scheduling Branch Delay Slots (Fig A.14)
A. From before branch
add $1,$2,$3
if $2=0 then
delay slot
becomes
B. From branch target
sub $4,$5,$6
add $1,$2,$3
if $1=0 then
delay slot
becomes
if $2=0 then
add $1,$2,$3
add $1,$2,$3
if $1=0 then
sub $4,$5,$6
C. From fall through
add $1,$2,$3
if $1=0 then
delay slot
sub $4,$5,$6
becomes
add $1,$2,$3
if $1=0 then
sub $4,$5,$6
• A is the best choice, fills delay slot
• In B, the sub instruction may need to be copied, increasing IC
• In B and C, must be okay to execute sub when branch fails
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Delayed Branch
• Compiler effectiveness for single branch delay slot:
– Fills about 60% of branch delay slots
– About 80% of instructions executed in branch delay slots useful
in computation
– About 50% (60% x 80%) of slots usefully filled
• Delayed Branch downside: As processor go to
deeper pipelines and multiple issue, the branch
delay grows and need more than one delay slot
– Delayed branching has lost popularity compared to more
expensive but more flexible dynamic approaches
– Growth in available transistors has made dynamic approaches
relatively cheaper
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Evaluating Branch Alternatives
Pipeline speedup =
Pipeline depth
1 +Branch frequency Branch penalty
Assume 4% unconditional branch, 6% conditional branchuntaken, 10% conditional branch-taken
Scheduling
Branch CPI speedup v. speedup v.
scheme
penalty
unpipelined
stall
Stall pipeline
3 1.60
3.1
1.0
Predict taken
1 1.20
4.2
1.33
Predict not taken
1 1.14
4.4
1.40
Delayed branch
0.5 1.10
4.5
1.45
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More branch evaluations
• Suppose the branch frequencies (as percentage of all
instructions) of 15% cond. Branches, 1% jumps and calls,
and 60% cond. Branches are taken. Consider a 4-stage
pipeline where branch is resolved at the end of the 2nd
cycle for uncond. Branches and at the end of the 3rd cycle
for cond. Branches. How much faster would the machine
be without any branch hazards, ignoring other pipeline
stalls?
Pipeline speedupideal = Pipeline depth/(1+Pipeline stalls)
= 4/(1+0) = 4
Pipeline stallsreal = (1x1%) + (2x9%) + (1x6%) = 0.24
Pipeline speedupreal = 4/(1+0.24) = 3.23
Pipeline speedupwithout control hazards = 4/3.23 = 1.24
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More branch question
• A reduced hardware implementation of the
classic 5-stage RISC pipeline might use the EX
stage hardware to perform a branch instruction
comparison and then not actually deliver the
branch target PC to the IF stage until the clock
cycle in which the branch reaches the MEM
stage. Control hazard stalls can be reduced by
resolving branch instructions in ID, but
improving performance in one aspect may reduce
performance in other circumstances.
• How does determining branch outcome in the ID
stage have the potential to increase data hazard
stall cycles?
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Problems with Pipelining
• Exception: An unusual event happens to an
instruction during its execution
– Examples: divide by zero, undefined opcode
• Interrupt: Hardware signal to switch the
processor to a new instruction stream
– Example: a sound card interrupts when it needs more audio
output samples (an audio “click” happens if it is left waiting)
• Problem: It must appear that the exception or
interrupt must appear between 2 instructions (Ii
and Ii+1)
– The effect of all instructions up to and including Ii is totally
complete
– No effect of any instruction after Ii can take place
• The interrupt (exception) handler either aborts
program or restarts at instruction Ii+1
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Precise Exceptions in Static Pipelines
Key observation: architected state only
change in memory and register write stages.
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And In Conclusion: Control and Pipelining
• Quantify and summarize performance
– Ratios, Geometric Mean, Multiplicative Standard Deviation
•
•
•
•
•
F&P: Benchmarks age, disks fail,1 point fail danger
Next time: Read Appendix A, record bugs online!
Control VIA State Machines and Microprogramming
Just overlap tasks; easy if tasks are independent
Speed Up  Pipeline Depth; if ideal CPI is 1, then:
Cycle Timeunpipelined
Pipeline depth
Speedup 

1  Pipeline stall CPI
Cycle Timepipelined
• Hazards limit performance on computers:
– Structural: need more HW resources
– Data (RAW,WAR,WAW): need forwarding, compiler scheduling
– Control: delayed branch, prediction
• Exceptions, Interrupts add complexity
• Next time: Read Appendix C, record bugs online!
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