Question According to the law of definite proportions a) if the same two elements form two different compounds, they do so in the same ratio. b) it is not possible for the same two elements to form more than one compound. c) the ratio of the masses of the elements in a compound is always the same. d) the total mass after a chemical change is the same as before the change. Copyright © Houghton Mifflin Company. All rights reserved. 7|1 Answer c) the ratio of the masses of the elements in a compound is always the same. This describes the result of elements combining to form compounds. Copyright © Houghton Mifflin Company. All rights reserved. 7|2 Question Ernest Rutherford a) determined the charge of a single electron. b) proposed that cathode rays contained electrons. c) determined the existence of neutrons. d) conducted the “gold foil” experiment. Copyright © Houghton Mifflin Company. All rights reserved. 7|3 Answer d) conducted the “gold foil” experiment. Robert Millikan determined the charge of a single electron. J.J. Thomson proposed the “plum pudding” model of the atom. James Chadwick determined the existence of neutrons. Copyright © Houghton Mifflin Company. All rights reserved. 7|4 Question How many of the following did Dalton not discuss in his atomic theory? I. II. III. IV. V. a) One Isotopes Ions Protons Neutrons Electrons b) Two c) Three Copyright © Houghton Mifflin Company. All rights reserved. d) Four e) Five 7|5 Answer e) Five Dalton only addressed matter’s basic unit as atoms in his theory. Copyright © Houghton Mifflin Company. All rights reserved. 7|6 Question The element Rhenium (Re) exists as two stable isotopes and 18 unstable isotopes. Rhenium-185 isotope has in its nucleus a) b) c) d) 75 protons and 75 neutrons. 75 protons and 130 neutrons. 130 protons and 75 neutrons. 75 protons and 110 neutrons. Copyright © Houghton Mifflin Company. All rights reserved. 7|7 Answer d) 75 protons and 110 neutrons. The mass number is the sum of the protons (same as the atomic number) and neutrons. Copyright © Houghton Mifflin Company. All rights reserved. 7|8 Question Which of the following statements are true? I. The number of protons is the same for all neutral atoms of an element. II. The number of electrons is the same for all neutral atoms of an element. III. The number of neutrons is the same for all neutral atoms of an element. a) b) c) d) e) I, II, and III are all true. Only I and II are true. Only II and III are true. Only I and III are true. I, II, and III are all false. Copyright © Houghton Mifflin Company. All rights reserved. 7|9 Answer b) Only I and II are true. For neutral atoms of an element, the number of protons equals the number of electrons and is the same as the atomic number. However, the number of neutrons differs depending on the isotopes. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 10 Question 10 5B Boron (B) has two isotopes: with mass of 10.013 amu and 115B with mass of 11.009 amu. The average atomic mass of boron is 10.81 amu. The fractional abundance of each isotope is a) b) c) d) e) 0.990 of Boron-10 and 0.010 of Boron-11. 0.804 of Boron-10 and 0.196 of Boron-11. 0.500 of Boron-10 and 0.500 of Boron-11. 0.196 of Boron-10 and 0.804 of Boron-11. 0.010 of Boron-10 and 0.990 of Boron-11. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 11 Answer d) 0.196 of Boron-10 and 0.804 of Boron-11. Since the average atomic mass is closer to that of Boron-11, the fractional abundance of Boron-11 must be higher than that of Boron-10. The average atom mass is significantly less than that of Boron-11, so there is a significant fractional abundance of Boron-10. (10.013 amu × 0.196) + (11.009 amu × 0.804) = 10.81 amu Copyright © Houghton Mifflin Company. All rights reserved. 7 | 12 Question An ion is formed a) by either adding or subtracting protons from the atom. b) by either adding or subtracting electrons from the atom. c) by either adding or subtracting neutrons from the atom. d) All of the above can form an ion. e) Two of the above can form an ion. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 13 Answer b) by either adding or subtracting electrons from the atom. The atoms of an element form ions when electrons are gained or lost. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 14 Question What is the wavelength (in nm) of electromagnetic radiation that has a frequency of 7.45 × 1014/s? (Hint: c = 3.00 × 108 m/s and h = 6.63 × 10−34 J.s) a) 4.03 × 10−7 nm b) 403 nm c) 4.03 nm d) 2.24 × 1014 nm e) 1.34 × 10−6 nm Copyright © Houghton Mifflin Company. All rights reserved. 7 | 15 Answer b) 403 nm For all electromagnetic radiation c = . So, c 9 3.00 108 m/ s 10 nm 7 = 4.02 10 m = 402 nm. 14 7.45 10 / s 1m Be sure to convert to the desired units. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 16 Question Which form of electromagnetic radiation has the shortest wavelengths? a) b) c) d) e) Gamma rays Microwaves Radio waves Infrared radiation X-rays Copyright © Houghton Mifflin Company. All rights reserved. 7 | 17 Answer a) Gamma rays The radiation with the shortest wavelength is of highest energy. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 18 Question Which form of electromagnetic radiation has the lowest energy? a) b) c) d) Red light Yellow light Blue light All visible light has the same energy. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 19 Answer a) Red light Red light is closest to the infrared region and so it has the lowest energy. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 20 Question Which form of electromagnetic radiation has the shortest wavelength? a) b) c) d) Red light Yellow light Blue light All visible light has the same wavelength. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 21 Answer c) Blue light The radiation with the shortest wavelength is of highest energy. Blue light is closest to ultraviolet light. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 22 Question Which form of electromagnetic radiation has the lowest frequency? a) b) c) d) Red light Yellow light Blue light All visible light has the same frequency. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 23 Answer a) Red light The radiation with the lowest frequency has the lowest energy. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 24 Question Which form of electromagnetic radiation has the slowest speed? a) b) c) d) Red light Yellow light Blue light All visible light has the same speed. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 25 Answer d) All visible light has the same speed. All electromagnetic radiation, which includes visible light, has the same speed ~3.00 × 108 m/s. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 26 Question The photoelectric effect predicts that a) electrons can be ejected from the surface of a metal using a vacuum. b) electrons can be ejected from the surface of a metal using light with a frequency greater than a certain threshold value. c) electrons can be ejected from the surface of a metal using light with a frequency less than a certain value. d) electrons can be ejected from the surface of a metal using light with a frequency greater than a certain threshold value that is the same for all metals. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 27 Answer b) electrons can be ejected from the surface of a metal using light with a frequency greater than a certain threshold value. The photoelectric effect predicts that electrons can be ejected from the surface of a metal using light with a frequency greater than a certain threshold value. The threshold value is characteristic of the metal. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 28 Question From the following list of observations, choose the one that most clearly supports the following conclusion: Electrons have wave properties. a) b) c) d) e) Emission spectrum of hydrogen The photoelectric effect Scattering of alpha particles by metal foil Diffraction Cathode “rays” Copyright © Houghton Mifflin Company. All rights reserved. 7 | 29 Answer d) Diffraction Diffraction patterns are produced by waves. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 30 Question From the following list of observations, choose the one that most clearly supports the following conclusion: Electrons in atoms have quantized energies. a) b) c) d) e) Emission spectrum of hydrogen The photoelectric effect Scattering of alpha particles by metal foil Diffraction Cathode “rays” Copyright © Houghton Mifflin Company. All rights reserved. 7 | 31 Answer a) Emission spectrum of hydrogen The emission spectrum shows only certain colors of light, providing support for quantized energy levels. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 32 Question Which of the following statements is false? a) The energy of electromagnetic radiation increases as its frequency increases. b) An excited atom can return to its ground state by absorbing electromagnetic radiation. c) An electron in the n = 4 state in the hydrogen atom can go to the n = 2 state by emitting electromagnetic radiation at the appropriate frequency. d) The frequency and wavelength of electromagnetic radiation are inversely proportional to each other. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 33 Answer b) An excited atom can return to its ground state by absorbing electromagnetic radiation. An excited atom returns to its ground state by releasing energy in the form of electromagnetic radiation. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 34 Question For which of the following electron transitions for a hydrogen atom does the light emitted have the longest wavelength? a) b) c) d) e) n = 4 to n = 3 n = 4 to n = 2 n = 4 to n = 1 n = 3 to n = 2 n = 2 to n = 1 Copyright © Houghton Mifflin Company. All rights reserved. 7 | 35 Answer a) n = 4 to n = 3 Energy is inversely related to wavelength, so the smaller the energy change, the longer the wavelength. The transition n = 4 to n = 3 has the smallest energy change of all of the options. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 36 Question The quantum number n a) can have the value of any integer. b) distinguishes orbitals with different shapes. c) is known as the principal quantum number. d) refers to the orientation of the spin axis of the electron. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 37 Answer c) is known as the principal quantum number. The principal quantum number is n and can have only positive integer values of 1, 2, 3, and so on. The quantum number l distinguishes orbitals with different shapes. The quantum number ms refers to the orientation of the spin axis of the electron. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 38 Question If the l quantum number is 3, what are the possible values of ml ? a) 3, 2, 1 b) 3, 2, 1, 0 c) 3, 2, 1, 0, −1, −2, −3 d) 2, 1 e) 2, 1, 0 f) 2, 1, 0, −1, −2 Copyright © Houghton Mifflin Company. All rights reserved. 7 | 39 Answer c) 3, 2, 1, 0, −1, −2, −3 The allowed values for ml are the integers between −l and l. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 40 Question What is the subshell notation when n = 3, and l = 2? a) b) c) d) 3s 3p 3d 3f Copyright © Houghton Mifflin Company. All rights reserved. 7 | 41 Answer c) 3d The subshell notation includes the principal quantum number n followed by the letter designation for the orbital type (l = 0 is denoted by s; l = 1 is denoted by p; l = 2 is denoted by d; and l = 3 is denoted by f). Copyright © Houghton Mifflin Company. All rights reserved. 7 | 42 Question A ground state electron in the hydrogen atom is given just enough energy to get to n = 2. Which orbital will the electron occupy? a) b) c) d) e) The 2s orbital The 2px orbital The 2py orbital The 2pz orbital Each of the above is equally likely. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 43 Answer e) Each of the above is equally likely. Because the hydrogen atom has only one electron, the 2s and 2p orbitals are degenerate (have the same energy). Copyright © Houghton Mifflin Company. All rights reserved. 7 | 44 Question Which of the following combinations of quantum numbers is not allowed? a) b) c) d) e) n l ml ms 1 3 2 4 4 1 0 1 3 2 0 0 −1 −2 0 ½ −½ ½ −½ ½ Copyright © Houghton Mifflin Company. All rights reserved. 7 | 45 Answer a) 1 1 0 ½ Electrons with n = 1 can only have values for l of 0. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 46 Question How many electrons can be described by the quantum numbers n = 3, l = 3, ml = 1? a) 0 b) 1 c) 2 d) 6 e) 10 f) 14 Copyright © Houghton Mifflin Company. All rights reserved. 7 | 47 Answer a) 0 Electrons with n = 3 can only have values for l of 0, 1, or 2. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 48 Question How many electrons can be described by the quantum numbers n = 3, l = 2, ml = −1? a) b) c) d) e) f) 0 1 2 6 10 14 Copyright © Houghton Mifflin Company. All rights reserved. 7 | 49 Answer c) 2 Electrons with n = 3 can have values for l of 0, 1, or 2. Electrons with l = 2 can have values for ml of −2, −1, 0, 1, or 2. Thus, n = 3, l = 2, ml = −1 is allowed. Since ml can be +1/2 or −1/2, two electrons can share these values of n, l, and ml . Copyright © Houghton Mifflin Company. All rights reserved. 7 | 50 Question According to the Aufbau principle (or the building-up principle), in writing a groundstate electron configuration of an atom, the orbital that is filled immediately after the 3d orbital is filled is a) the 3p orbital. b) the 4p orbital. c) the 4s orbital. d) the 4d orbital. e) the 3f orbital. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 51 Answer b) the 4p orbital. The correct order of filling orbitals according to the Aufbau principle is 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, ... Copyright © Houghton Mifflin Company. All rights reserved. 7 | 52 Question How many of the following electron configurations for the species in their ground state are correct? Ca: Mg: V: As: P: a) b) c) d) e) 1s22s22p63s23p64s2 1s22s22p63s1 [Ar] 3s23d3 [Ar] 4s23d104p3 1s22s22p63p5 One Two Three Four Five Copyright © Houghton Mifflin Company. All rights reserved. 7 | 53 Answer b) Two The correct electron configurations are Ca: 1s22s22p63s23p64s2 Mg:1s22s22p63s2 V: [Ar] 4s23d3 As: [Ar] 4s23d104p3 P: 1s22s22p63s23p5 So, only Ca and As were correct. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 54 Question Of the following elements, which has occupied d orbitals in its ground-state neutral atoms? a) b) c) d) e) Ba Ca Si P Cl Copyright © Houghton Mifflin Company. All rights reserved. 7 | 55 Answer a) Ba In order for an element to have occupied d orbitals in its ground-state neutral atoms it must have an atomic number greater than 20. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 56 Question In which groups do all the elements have the same number of valence electrons? a) b) c) d) e) P, S, Cl Ag, Cd, Ar Na, Ca, Ba P, As, Se None of these Copyright © Houghton Mifflin Company. All rights reserved. 7 | 57 Answer e) None of these Elements will have the same number of valence electrons if they are in the same group in the periodic table. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 58 Question An element X has a ground state valence electron configuration of ns2np5. Which formula for the compound composed of element X and nitrogen is most likely? a) b) c) d) e) NX NX7 NX2 NX3 NX5 Copyright © Houghton Mifflin Company. All rights reserved. 7 | 59 Answer d) NX3 An element with the valence electron configuration ns2np5 is a halogen. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 60 Question The correct ground-state electron configuration of copper is a) b) c) d) e) [Ar] 3d94s2. [Ar] 3d104s1. [Ar] 3d74s2. [Ar] 3d84s2. None are correct. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 61 Answer b) [Ar] 3d104s1. Copper (Z = 29) is one of the exceptions to the building-up principle. It is more stable to have a filled 3d orbital and a half-filled 4s orbital than to have a filled 4s orbital and a partially filled 3d orbital. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 62 Question Which of the following elements have ground-state electron configurations that are paramagnetic? a) b) c) d) e) Ca Zn Ne C None of these Copyright © Houghton Mifflin Company. All rights reserved. 7 | 63 Answer d) C Paramagnetic substances have unpaired electrons. Since all of the orbitals are filled in Ca, Zn, and Ne, all of the electrons are paired. The electron configuration for C is 1s22s22p2. Since there are three 2p orbitals, Hund’s rule predicts that the two 2p electrons will be unpaired. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 64 Question Consider the following orderings. I. Al < Si < P < Cl II. Be < Mg < Ca < Sr III. I < Br < Cl < F IV. F < Mg < Na < K Which of these give(s) a correct trend in size? a) b) c) d) e) I II III IV At least two of the above give a correct trend in size. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 65 Answer e) At least two of the above give a correct trend in size. Concerning size, atoms increase going down in groups and decrease going across in periods. II. Be < Mg < Ca < Sr and IV. F < Mg < Na < K are correct. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 66 Question Consider the following orderings. I. II. III. IV. Al < Si < P < Cl Be < Mg < Ca < Sr I < Br < Cl < F Na+ < Mg2+ < Al3+ < Si4+ Which of these give(s) a correct trend in ionization energy? a) b) c) d) III I and II I and IV I, III, and IV Copyright © Houghton Mifflin Company. All rights reserved. 7 | 67 Answer d) I, III, and IV Ionization energy increases with increased positive charge and decreases going down in a group. Going across in a period, ionization energy tends to increase with some variations. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 68 Question The first ionization energy of magnesium is about 700 kJ/mol. A good estimate for the second ionization energy of magnesium is about a) 700 kJ/mol. b) 1400 kJ/mol. c) 70,000 kJ/mol. d) −700 kJ/mol. e) −1400 kJ/mol. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 69 Answer b) 1400 kJ/mol. The second ionization energy (IE) should be larger than the first ionization energy since the electron is being taken from a positive ion. In this case, the second electron is taken from the same energy level as the first, so while the second IE should be greater, it will not be as great as shown in choice c). Copyright © Houghton Mifflin Company. All rights reserved. 7 | 70 Question A hypothetical element, X, has the following ionization values: First ionization energy: 800 kJ/mol Second ionization energy: 2450 kJ/mol Third ionization energy: 3700 kJ/mol Fourth ionization energy: 25,000 kJ/mol Fifth ionization energy: 32,800 kJ/mol. To what family of the periodic table is this element most likely to belong to? a) b) c) d) e) Group IA Group IIA Group IIIA Group IVA Group VA Copyright © Houghton Mifflin Company. All rights reserved. 7 | 71 Answer c) Group IIIA The ionization energy of all elements increases from the first ionization energy to the second ionization energy, to the third ionization energy, and so on, since the electron is being taken from an increasingly positive ion. There is a very large increase in ionization energy when removing an electron from a noble-gas configuration—here, the fourth ionization energy removes an electron from the X3+ ion. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 72 Question Which of the following concerning second ionization energy values is true? a) That of Al is higher than that of Mg because Mg wants to lose the second electron, so it is easier to take the second electron away. b) That of Al is higher than that of Mg because the electrons are taken from the same energy level, but the Al atom has one more proton and Al+ has a filled 3s orbital. c) That of Al is lower than that of Mg because Mg wants to lose the second electron, thus the energy change is greater. d) That of Al is lower than that of Mg because the second electron taken from Al is in a p orbital, thus it is easier to take. e) The second ionization energies are equal for Al and Mg. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 73 Answer b) That of Al is higher than that of Mg because the electrons are taken from the same energy level, but the Al atom has one more proton and Al+ has a filled 3s orbital. In both cases, the electron is taken from a 3s orbital. Filled orbitals are more stable than partially filled orbitals. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 74 Question For the atoms Li, N, F, and Na, which of the following is the correct order from smallest to largest atomic radius? a) b) c) d) e) Na, F, N, Li Na, Li, N, F Li, N, F, Na N, F, Na, Li F, N, Li, Na Copyright © Houghton Mifflin Company. All rights reserved. 7 | 75 Answer e) F, N, Li, Na Atomic radius decreases across a row of the periodic table and increases down a column of the periodic table. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 76 Question Which of the following correctly ranks the first ionization energies of O, F, Na, S, and Cs from smallest to largest? a) b) c) d) e) Cs, Na, S, O, F Cs, S, Na, O, F F, O, Na, S, Cs F, O, S, Na, Cs Na, S, Cs, F, O Copyright © Houghton Mifflin Company. All rights reserved. 7 | 77 Answer a) Cs, Na, S, O, F Ionization energy increases across a row of the periodic table and decreases down a column of the periodic table. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 78 Question Sodium losing an electron is an ________ process and fluorine losing an electron is an _______ process. a) b) c) d) endothermic, exothermic exothermic, endothermic endothermic, endothermic exothermic, exothermic Copyright © Houghton Mifflin Company. All rights reserved. 7 | 79 Answer c) endothermic, endothermic Losing an electron from an atom requires energy, which means this reaction is endothermic. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 80 Question Which of the following oxides are acidic? a) b) c) d) e) Na2O CaO N2O5 All of the above None of the above Copyright © Houghton Mifflin Company. All rights reserved. 7 | 81 Answer c) N2O5 Most nonmetal oxides are acidic. Most metal oxides are basic. Oxides of elements in the periodic table near the transition between metals and nonmetals may be amphoteric oxides. Copyright © Houghton Mifflin Company. All rights reserved. 7 | 82