Unit 3 HW 10
p. 145 # 3, 5, 7, 9, 11
p. 152 # 1, 3, 6, 14, 16, 22
Mrs. McCaleb
p. 145
3
a) right
5.
1.
2.
3.
b) obtuse c) right
Statements
Circle O
OC = OD
ΔCOD is isosceles
d) acute
e) right
f) acute (equilateral!)
Reasons
1. Given
2. All radii of a circle are =
3. Def isosceles
7. We covered 2 sections today, so when you do this problem you are not
supposed to have learned the picture thm yet . . . so you would do this proof by
drawing in DB, proving that the 2 triangles are congruent by SSS, so the angles
are congruent by CPCTC. But we DO know the picture thm, so please feel free to
use it!!
1.
2.
9.
1.
2.
3.
4.
5.
Statements
AD = CD
<A = <C
Reasons
1. Given
2.
Statements
JF = JG
<EFJ = <HGJ
F and G trisect EH
EF = GH
ΔEFJ = ΔHGJ
JE = JH
OR
<E = <H
ΔEHJ is isosceles
Reasons
1. Given
2. Def trisect
3. SAS
4. CPCTC
5. Def isosceles
11. 10 = x + 7
3=x
plug in for sides: 10, 10, -2 NOT POSSIBLE
10 = 2x – 8
18 = 2x
9=x
plug in for sides: 10, 10, 16 Perimeter = 36 (works!)
2x – 8 = x + 7
x = 15 plug in for sides: 10, 22, 22 Perimeter = 54 (too big, perimeter has
to be less than 45)
The only way it works is VS = SY, so the base is VY
p. 152
1.
1.
2.
3.
4.
3.
1.
2.
3.
4.
Statements
AB = AC
<ABC = <ACB
<ABC supp <1
<ACB supp <2
<1 = <2
Reasons
1. Given
2.
3. Def linear pair
Statements
SX = TY
WX = YZ
SW = TZ
ΔSXW = ΔTYZ
<W = <Z
RW = RZ
Reasons
1. Given
4. Supplements of = angles are =
2. SSS
3. CPCTC
4.
6.
1.
2.
3.
4.
5.
6.
7.
Statements
<5 = <6
JG is an altitude
<JGF & <JGH are right
<JGF = <JGH
JG = JG
ΔJGF = ΔJGH
JF = JH
OR
<F = H
ΔFJH is isosceles
Reasons
1. Given
2.
3.
4.
5.
6.
Def altitude
Right angle thm
Reflexive
ASA
CPCTC
7. Def isosceles
J
14.
Given: JA = JM
JB is a median
Prove: JB bisects <AJM
2 1
M
1.
2.
3.
4.
5.
6.
16.
1.
2.
3.
4.
5.
B
Statements
JA = JM
JB is a median
MB = AB
JB = JB
ΔJBM = ΔJBA
<1 = <2
JB bisects <AJM
Reasons
1. Given
Statements
NP = VT
<P = <V
PR = ST
PS = TR
ΔPNS = ΔTVR
<WRS = <WSR
ΔWRS is isosceles
Reasons
1. Given
2.
3.
4.
5.
6.
2.
3.
4.
5.
A
Def median
Reflexive
ASA
CPCTC
Def bisect
Segment Addition Property
SSS
CPCTC
Def isosceles
22.
1.
2.
3.
4.
5.
6.
7.
8.
Statements
FG = JH
<FGH = <JHG
GH = HG
ΔFGH = ΔJHG
<GFH = <HJG
<FKG = <JKH
ΔFGK = ΔJHK
FK = JK
ΔFKJ is isosceles
Reasons
1. Given
2.
3.
4.
5.
6.
7.
8.
Reflexive Property
SAS
CPCTC
Vertical < Thm
AAS
CPCTC
Def isosceles