IEEE C802.16m-10/0005r1
Project
Title
IEEE 802.16 Broadband Wireless Access Working Group <http://ieee802.org/16>
Clean-up of the Equation for KSB,FPi (Reply Comment to #0663)
Date
Submitted
2010-01-09
Source(s)
Lei Huang
Email :
lei.huang@sg.panasonic.com
Panasonic Singapore Laboratories
Re:
IEEE 802.16 Working Group Letter Ballot Recirc #30b
Section 16.3.5.2.3 and 16.3.8.2.3
Abstract
This contribution provides the clean equations for frequency partitioning
Purpose
To be discussed and adopted by WG LB
Notice
Release
Patent
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Clean-up of the Equation for KSB,FPi (Reply Comment to #0663)
Lei Huang
Panasonic Singapore Laboratories
Introduction
The comment #0663 (C802.16m-09/2776) proposes some clean-up modifications on the equation of KSB,FPi.
However, the suggested modification is still incomplete and contains some typos. In addition, in P802.16m/D3,
the statement that DFPSC shall be zero when FPCT = 2 is not correct (see line 33, page 325). This is because
DFPSC defines the number of subbands allocated to FPi, i>0, and but when FPCT = 2, the number of subbands
allocated to FPi, i>0 is not equal to zero. Actually, when FPCT = 2, the number of subband allocated to FPi, i>0
should be KSB/2.
1
IEEE C802.16m-10/0005r1
Proposed Text
Update the following section in D3.
---------------------------------------------------- Proposed Text #1 -----------------------------------------------Make the following changes to line 21-34, including Eq. (185) on Page 325
K SB,FPi
K SB, FPi
 K SB  FPCT  1  DFPSC

DFPC

 K  FPCT  1  DFPSC
  SB
DFPC


K SF / 2


K SF
 K SB  FPCT  1  DFPSC

DFPSC


0

 K SB  FPCT  1  DFPSC


DFPSC

0

DFPSC


K SB


0
i  0, FPCT  4
i  0, FPCT , or DFPC  1
i  0, FPCT  3, DFPC  1
i  1,2, FPCT  3, DFPC  1
(185)
i  1,2, FPCT  2
i  0, FPCT  1
i  0, FPCT  4
i  0, FPCT  4
i  0, FPCT  3, DFPC  1
i  0, FPCT  3, DFPC  1
i  0, FPCT  3
i  0, FPCT  2
i  0, FPCT  2
i  0, FPCT  1
i  0, FPCT  1
(185)
When FPCT = 2, DFPSC shall be KSB/2 zero.
-----------------------------------------------------End of the Text Proposal ------------------------------------------------------------------------------------------------------ Proposed Text #2 -----------------------------------------------Make the following changes to lines 29-42, including eq. (237) on Page 499
K SB,FPi
K SB  FPCT  1  DUFPSC

DUFPC

 K  FPCT  1  UFPSC
  SB
UFPC


K SF / 2

K SF

i  0, FPCT  4
i  0, FPCT , or UFPC  1
i  0, FPCT  3, UFPC  1
i  1,2, FPCT  3, UFPC  1
i  1,2, FPCT  2
i  0, FPCT  1
2
(237)
i  0, FPCT  4
 K SB  FPCT  1  UFPSC

UFPSC
i  0, FPCT  4


0
i  0, FPCT  3,UFPC  1

i  0, FPCT  3,UFPC  1
 K SB  FPCT  1  UFPSC

K SB, FPi  
UFPSC
i  0, FPCT  3

0
i  0, FPCT  2

UFPSC
i  0, FPCT  2


K SB
i  0, FPCT  1


0
i  0, FPCT  1

When FPCT = 2, UFPSC shall be KSB/2 zero.
IEEE C802.16m-10/0005r1
(237)
-----------------------------------------------------End of the Text Proposal ---------------------------------------------------
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