Writing Inequalities Your age is Your height is LESS THAN GREATER THAN 19 years. 52 inches. a < 19 h >52 under above below over fewer than exceeds beneath more than Your speed is There are LESS THAN OR EQUAL TO GREATER THAN OR EQUAL TO 62. 42 stinkbugs. s ≤ 62 ≥ s 42 VOCABULARY at most at least maximum minimum no more than no less than Graphing Inequalities Graph 1. Draw a number line with 19 in the middle. 2. Next, draw an open circle around 19. 3. Now think: Could a = 19? …(you should be thinking)… * a cannot be 19 – Why? ... 19 is not less than 19. * Since a ≠ 19, leave the circle open. 4. Finally, draw the arrow. “less than” “greater than” <–––––– ––––––> Graphing Inequalities Graph 1. Draw a number line with 10 in the middle. 2. Next, draw an open circle around 10. 3. Now think: Could x = 10? …(you should be thinking)… * x cannot be 10 – Why? 10 is not greater than 10. * Since x ≠ 10, leave the circle open. 4. Finally, draw the arrow. “less than” “greater than” <–––––– ––––––> Graphing Inequalities Graph 1. Draw a number line with 62 in the middle. 2. Next, draw an open circle around 62. 3. Now think: Could s = 62? * s can be 62 – Why? ––> s is less than or equal to 62 * Since s could = 62, close the circle 4. Finally, draw the arrow. “less than” “greater than” <–––––– ––––––> Graphing Inequalities Graph 1. Draw a number line with 42 in the middle. 2. Next, draw an open circle around 42. 3. Now think: Could x = 42? * x can be 42 – Why? ––> x is greater than or equal to 42 * Since x could = 42, close the circle 4. Finally, draw the arrow. “less than” “greater than” <–––––– ––––––> Evaluating Inequalities 1. –15 ≥ 7 – 11x –15 ≥ 7 – 11x•3 In this inequality, could x = 3? Rewrite the inequality, but substitute 3 for x. –15 ≥ 7 – 33 Simplify the variable side. –15 ≥ –26 Now, read it... is that true? x 2. +9<7 3 a. x = 6? “Seven is less than seven?” In this inequality, could: x = –6? b. 2 –2 7 ANSWER: 6 is not a possible value for x. “Negative fifteen is greater than, or equal to, negative 26.” 11 ANSWER: –6 is not a possible value for x. c. –1 x = 30? ANSWER: 30 is a possible value for x. Evaluating Inequalities 3(3) + 4 > −5 \/ 9 + 4 > −5 \ / 13 > −5 Read it. Is that true? TRUE -- x could = 3. 3(−3) + 4 > −5 \/ −9 + 4 > −5 \ / –5 > −5 Read it. Is that true? FALSE -- x could not = –3. 7 \/ -7 \ 5 / ≤5 TRUE – x could be 7 –7 7 19 ≤ 5 FALSE – x could NOT be –7 Inequalities – Multiplying w/ Negatives Solve 1. Look at the constant attached to the variable. If the number attached to the variable is negative, you’ve got to flip the inequality. 2. Now, divide both sides by –9. Inequalities – Dividing w/ Negatives Solve –5 • 1. • –5 Look at the constant attached to the variable. Is it negative? If the number attached to the variable is negative, you’ve got to flip the inequality. 2. Now, multiply both sides by –5. –3 • • –3 Solving Inequalities 1. no flip 9 + b > –10 2. b > –19 4. –1 < 14 ≤ 23 + a no flip 3.flip –19 – x ≥ –3 –9 ≤ a y 11 no flip 5. –11 < y x ≥ –16 90 ≥ –5b flip –18 ≤ b 7. no flip y < –72 8. flip z > –24 x ≤ 24 9.The product of a number and two, less than fifteen, is at least thirty–five 10. flip 1. 5 – y > 12 6 6.flip 2 x ≥ x ≤ –10 3 5 no flip The quotient of a number and two decreased by three is no more than eleven x 2 – 3 ≤ x ≤ 28 1 1