ENGINEERING 2000
FINAL EXAMINATION
December 2006
1- Determine the projected component of the 100-lb force acting along the axis BC of the
pipe.
FCB  10.5(0.802iˆ  0.534 ˆj  0.267kˆ)lb
ENGINEERING 2000
FINAL EXAMINATION
December 2006
2- Determine the tension in the cables AB, AC and AD required to hold the 60-lb weight
in equilibrium.
ENGINEERING 2000
FINAL EXAMINATION
December 2006
3- If the applied force is F  {4iˆ - 12ˆj  2kˆ} N , determine the magnitude of the moment of
this force about the x axis.
4- Determine the magnitude of the force F so that the resultant couple moment is
450 lb.ft, counterclockwise.
5- Replace the force and load system by an equivalent force and determine its position
along the beam measured from A.
FR  500  150(6)  50(6) / 2  1550lb
 1550 x  500(9)  900(3)  150(4)
x  5.03 ft
ENGINEERING 2000
FINAL EXAMINATION
December 2006
6- Determine the forces in members CD, CJ, JG and GF and state in these members are
in tension or compression.
FCD  FDE  0 Zero force members (apply method of joints at D)
M
A
 0  E y (6)  6(4.5)  6(3)
E y  7.5kN
M
J
 0  7.5(1.5)  FGF (2)
FGF  5.625kN (T)
 2 
 0  6(1.5)  FJG 
(3)
 2.5 
FJG  3.75kN (T)
 2 
 M G  0  6(1.5)  7.5(3)  FCJ  2.5 (3)  0
FCJ  5.625kN (C)
M
E
ENGINEERING 2000
FINAL EXAMINATION
December 2006
7- Determine the tension in the cables and the components of reaction acting on the
smooth collar at A necessary to hold the 50-lb sign in equilibrium. The center of gravity
for the sign is at G.