A Confidence Interval for a Proportion in Large Samples.

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251proport 4/28/06

A Confidence Interval for a Proportion in Large Samples.

For large samples we can use the Normal approximation to the binomial distribution. Use p for the population probability of success and q for the population probability of failure, and let p

 x n

and q

1

 p be the corresponding sample quantities. Remember that a proportion is always between zero and one. For the interval write p

 p

 z

2 s p

, where s p

 p q

. An example follows. n

Exercise 8.24 [Exercise 8.22 in 9 th edition] (Exercise 8.22 in 8 th edition): The problem asks for a 95% confidence interval for the population proportion of successes when n

200 and x

50

Solution: Since 1

  

.

95 ,

 

.

05 and z

 z

2

 z

.

05

1 .

960 . p

 x n

50

200

.

250 . q

10

.

250 p can say

1

1 .

960

P

.

190 x

1

.

250

.

750 .

So the confidence interval is p

 p

 z

2 s p

 p

 z

2 p q n n

.

250

.

750

 p

200

.

310

.

250

.

95

1 .

960 .

0009375

.

250

.

060 or .

190

 p

.

310 .

More formally, we

or make a diagram. The diagram would be a Normal curve with .250 at the center and with an area marked 95% extending from 0.190 to 0.310. Note that since the curve hits zero at .

250

3 .

90 .

0009375 , this is a good part of the area under the curve.

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