251x0472 11/22/04 ECO251 QBA1 THIRD EXAM Dec 1, 2004 Name: _____________________ Student Number: _____________________ Class Time (Circle) 10am 11am 1pm 2pm Part I: 8 points. z follows the standardized Normal distribution z ~ N 0,1 . Find the following. Make diagrams! (0.5 extra credit for each useful diagrams) 1. P2.12 z 1.67 2. P1.67 z 1.45 3. Pz 1.45 4. P1.45 z 3.64 251x0472 11/22/04 Part II: (22+ points) Do all the following: All questions are 2 points each except as marked. Exam is normed on 50 points including take-home. (Showing your work can give partial credit on some problems! In open-ended questions it is expected. Please indicate clearly what sections of the problem you are answering and what formulas you are using. Neatness counts!) Remember that you may not be able to finish this section, so ration your time on each problem. [Numbers in brackets are a cumulative total] 1. The covariance a) must be between -1 and +1. b) must be positive. c) can be positive or negative. d) must be between zero and +1 2. The portfolio expected return of two investments a) will be higher when the covariance is zero. b) will be higher when the covariance is negative. c) will be higher when the covariance is positive. d) does not depend on the covariance. 3. An average of 16 customers arrive at a checkout counter every minute and we want to find the probability that more than 22 will show in a given minute, the Poisson distribution will be used with a standard deviation of a) 2 b) 4 c) 16 d) here is not enough information. 4. (Mansfield) From experience, the director of a computer center knows that any one of the twentyfive PCs in the room is broken 4% of the time. Whether or not any given PC is broken does not depend on how much it is used; they just seem to break down randomly. What type of probability distribution would be used to figure out the probability that more than eight of the PCs will be broken down at the same time? a) binomial distribution. b) Poisson distribution. c) hypergeometric distribution. d) none of the above. 5. You receive two tickets for a sold-out concert. You call four potential dates for the evening. You think that there is a chance of 13 that each of the individuals would call back and agree to go to a concert with you. You will be very embarrassed if more than one accepts. What is the probability that exactly one out of the four says ‘yes?’ (Extra credit: Do this last! What is the probability that you are embarrassed?) Show your work! (3) [11] 2 251x0472 11/22/04 Questions 6-10 are based on exhibit 1. Show your work if you expect full credit! Exhibit 1: The table below shows average Fahrenheit temperature and yield in lbs./acre for an industrial crop. F Y 63 10 70 15 . 75 17 79 16 80 20 The following calculations are done for you. One more column is needed. Row x x2 y 1 2 3 4 5 63 70 75 79 80 367 3969 4900 5625 6241 6400 27135 10 15 17 16 20 78 y2 100 225 289 256 400 1270 6. Find the sample standard deviation of Fahrenheit temperatures, x (2) 7. Find the sample covariance between Fahrenheit temperature and yield.(3) 8. Find the sample correlation between Fahrenheit temperature and yield. (2) [18] 9. If the conversion formula for Celsius temperature is C = 5/9(F-32), find the covariance between Celsius temperature and yield. (Hint: You are finding the sample covariance between two random variables, one of which is w 5 9 x 1609 and the other of which is v 1y 0 . (2) 10. If the conversion formula for Celsius temperature is C = 5/9(F-32), find the correlation between Celsius temperature and yield. (2) [22] 3 251x0472 11/22/04 11. We have twenty units of equipment in a bin of which five are defective. Pull three out at random. What is the probability that exactly one will be defective if we: a. sample without replacement? (3) b. sample with replacement? (2) c. If we sample with replacement, what is he probability that the first item that we find that is defective is the third item that we pick? (2) [29] To get full credit for this problem, identify the distribution that you are using and show your work! 12. If ten people are selected at random from a large (continuous) population what is the probability that more than half (which is not exactly six) make more than the median income? To get full credit for this problem, identify the distribution that you are using and show your work! (2) [31] 13. If x is a random variable with a mean of 7 and a standard deviation of 6, find a. Cov8x 4, 9 x 3 (3) b. Corr8x 4, 9 x 3 (2) [36] 4 251x0472 11/22/04 ECO251 QBA1 THIRD EXAM Dec 1, 2004 TAKE HOME SECTION Name: _________________________ Student Number: _________________________ Throughout this exam show your work! Please indicate clearly what sections of the problem you are answering and what formulas you are using. Part III. Do all the Following (20 Points) Show your work! 1. As everyone knows, a jorcillator has two components, a phillinx and a flubberall. It seems that the jorcillator works as long as one component works. For example, if the Phillinx failed last year and the flubberall fails this year, the phillinx fails this year. This problem, which is a simplified version of Problem H4 has three time periods, last year, this year and Ever After (after this year). You have been in Tibet for the last year, so you have no idea on what actually happened last year. The probability of the phillinx failing is given by a standardized Normal Distribution, so , if z represents the life of the Phillinx, the probability of the phillinx failing last year is Pz 0 , the probability of it failing this year is P0 z 1 and the probability of it lasting into the Ever After is Pz 1 . The probability of the Flubberall failing is given by a Continuous Uniform Distribution, where c 1 and d 2 f , where f is the fourth digit of your student number, divided by 10. For example if Seymour’s student number is 012345, his value of d 2 .3 2.3 . If the fourth digit of your student number is zero, use d 3.1 . If x represents the life of the Phillinx, the probability of the phillinx failing last year is Px 0 , the probability of it failing this year is P0 x 1 and the probability of it lasting into the Ever After is Px 1 . Failure of components is assumed to be independent, so that, if the probability of the Phillinx failing in the first year is .1 and the probability of the Flubberall failing last year is .7, the probability of both components failing last year is (.1) (.7) =.07 (This is not necessarily the probability that the jorcillator failed last year!) a) What is the probability the Flubberall failed last year? This year? After this year? (1.5) b) What is the probability the Phillinx failed last year? This year? After this year? (1.5) c) What is the probability that the jorcillator failed last year? (2) d) What is the probability that the jorcillator will fail this year? (2) e) What is the probability that the jorcillator will fail in the Ever After.? (2) f) Using the probabilities that you found in c) – e) , associate the number -0.5 with last year, 0.5 with this year and 2.0 with Ever after and find the expected value and standard deviation of the life of the jorcillator. (2) 5 251x0472 11/22/04 2. (Bowerman and O’Connell, modified) An air traffic control center experiences a week with 3 errors (planes placed too close together either vertically or horizontally). On the basis of records of the center, you decide that the center has an average number of errors of d 10 per week, where d is the number you used in the previous problem. a) (4) Compute a Poisson table with the following values P0 , P 1 , P2 , P3 and P4 . The easiest way to do this is to assume that P5 and any probabilities above it are essentially zero and to assume that after you have computed P0 through P3 , that P4 is whatever is required to make this a valid distribution. Example: If d 4.0, you would assume that the mean is 0.40 and would compute e 0.40 .67032 . Using that in the Poisson formula, you would find the following P0 .6703 , P1 .2681 , P2 .0536 and P3 .0072 . In order to get a valid distribution, you need P4 .0008 . (If you check this against the Poisson table you will find that the actual value of P4 is .0007, but the difference won’t affect your results.) You can see if you are on the right track for your numbers by comparing your results with the Poisson tables for parameters of 0.3 and 0.4. Your results should be close. b) (3)To test the hypothesis that the mean is still the value of d 10 that you are using, you compute the probability that, if the hypothesis is true you would get results as extreme or more extreme than you actually got. In this case that would be Px 3 . If the probability is less than 1%, you can say that you strongly doubt that the hypothesis is correct and demand an investigation. If the probability is between 1% and 5% you can say that you somewhat doubt that the hypothesis is correct and suggest that the controllers clean up their act. If the probability is above 5%, you would have to say that you cannot doubt the hypothesis and you would have to shut up. In view of the probability you computed, what would you do? c) (2)Using the table that you have made, repeat the analysis assuming that during the week there were 2 errors instead of 3. 3. (Extra Credit) (Bowerman and O’Connell, modified) a) A young nurse observes that 8 of the last 30000 patients of a hospital went into a coma during anesthesia. Upon investigation she finds that nationally 6 out of 100000 patients go into comas after anesthesia (This is 0.006 per cent!). Assume that the national probability is correct and that the Binomial distribution is appropriate, what is the mean number of patients out of 30000 that will go into a coma? Find the probability of 8 or more people out of 30000 going into a coma. Explain whether we have a binomial table that will do this. If not, show that this is an appropriate place to use a Poisson distribution and use the Poisson tables to find the probability that x 8. Use the approach in the previous problem to see if the number of comas is consistent with the national rate. b) How would you change your opinion if the number that went into a coma was 6? 6