4-4: Fun Theorems, 2 Objectives: Assignment:

advertisement
4-4: Fun Theorems, 2
Objectives:
Assignment:
1. To find the average value • P. 291-292: 47-50, 54-60,
of a function
63
2. To understand and use
the Second Fundamental • P. 293: 75-91 odd
Theorem of Calculus
Warm Up
Find the value of 𝑐
guaranteed by the
MVT for integrals for
𝑓(π‘₯) = 1 + π‘₯ 2 on the
interval −1,2 .
Mean Value Theorem (Integrals)
If 𝑓 is a continuous
function on π‘Ž, 𝑏 , then
there exists a number
𝑐 in π‘Ž, 𝑏 such that
𝑏
𝑓(π‘₯) 𝑑π‘₯ = 𝑓 𝑐 𝑏 − π‘Ž
π‘Ž
Mean Value Rectangle
There exists a
rectangle whose
base is the width
of the interval,
whose height is a
function value and
whose area is
equal to the area
under the curve.
Objective 1
You will be able to find
the average value of a
function
Average Value
If 𝑓 is integrable
on π‘Ž, 𝑏 , then the
average value of
𝑓 on π‘Ž, 𝑏 is
1
𝑏−π‘Ž
𝑏
𝑓 π‘₯ 𝑑π‘₯
π‘Ž
Average Value
If 𝑓 is integrable
on π‘Ž, 𝑏 , then the
average value of
𝑓 on π‘Ž, 𝑏 is
1
𝑏−π‘Ž
𝑏
𝑓 π‘₯ 𝑑π‘₯
π‘Ž
Average Value
Partition π‘Ž, 𝑏 such that βˆ†π‘₯ =
value in the 𝑖th subinterval.
𝑏−π‘Ž
,
𝑛
where π‘₯𝑖∗ is any
𝑓 π‘₯1∗ + 𝑓 π‘₯2∗ + 𝑓 π‘₯3∗ + β‹― + 𝑓 π‘₯𝑛∗
Average =
𝑛
Almost a
Riemann sum
1
=
𝑛
𝑛
𝑓
𝑏−π‘Ž
𝑏−π‘Ž
π‘₯𝑖∗
𝑖=1
1
=
𝑏−π‘Ž
𝑛
𝑓
𝑖=1
π‘₯𝑖∗
𝑏−π‘Ž
𝑛
Take the limit as 𝑛 → ∞
=
1
𝑏−π‘Ž
1
=
𝑏−π‘Ž
𝑛
𝑓 π‘₯𝑖∗ βˆ†π‘₯
𝑖=1
𝑏
𝑓 π‘₯ 𝑑π‘₯
π‘Ž
Exercise 1
Find the average value
of 𝑓 π‘₯ = 3π‘₯ 2 − 2π‘₯ on
1,4 .
Exercise 2
If the function 𝑓 π‘₯ = π‘₯ 3 has an average
value of 9 on the closed interval 0, π‘˜ , then
what is the value of π‘˜?
Exercise 3
Show that the average velocity of a car over
a time interval 𝑑1 , 𝑑2 is equal to the average
of value of its velocity function.
The average
value of a function
𝑓 is equivalent to
the slope of the
secant line of the
antiderivative of 𝑓.
Objective 2
You will be able to understand
and use the Second Fundamental
Theorem of Calculus
Definite Versus Indefinite
Remember that a definite integral yields a
number; however…
Definite Integral
Indefinite Integral
Number
Family of functions
Net area above/below 𝑓
Antiderivative of 𝑓′
Definite Versus Indefinite
Remember that a definite integral yields a
number; however…
Definite Integral
Number
Net area above/below 𝑓
There is a way
to define a
function based
on a definite
integral
Exercise 4
Evaluate 𝐹 π‘₯ =
your answer.
π‘₯
0
𝑑 + 1 𝑑𝑑 and interpret
𝑓 𝑑 =𝑑+1
𝐹(π‘₯) is an accumulation function:
𝐹 2 =4
Area over 0,2 = 4
𝐹 4 = 12
Area over 0,4 = 12
𝐹(π‘₯)
Number Versus Function
Remember that a definite integral yields a
number; however…
Definite Integral as a Number:
𝑏
𝑓 π‘₯ 𝑑π‘₯
Variable
Definite Integral as a Function:
π‘₯
𝐹 π‘₯ =
𝑓 𝑑 𝑑𝑑
π‘Ž
π‘Ž
Constant
Constants
Function of π‘₯
Function of 𝑑
Exercise 5
Evaluate 𝐹 π‘₯ =
and πœ‹/2.
π‘₯
cos 𝑑 𝑑𝑑
0
at π‘₯ = 0, πœ‹/6, πœ‹/4, πœ‹/3,
Now, what do
you get if you
take the
derivative of
𝐹(π‘₯)?
2nd Fundamental Theorem of Calculus
If 𝑓 is continuous
on and open
interval containing
π‘Ž, then for every π‘₯
in the interval
Insert Proof Here
𝑑
𝑑π‘₯
π‘₯
𝑓 𝑑 𝑑𝑑 = 𝑓 π‘₯
π‘Ž
Exercise 6
Evaluate
𝑑
𝑑π‘₯
π‘₯
0
𝑑 2 + 1 𝑑𝑑
Exercise 7
Find the derivative of 𝐹 π‘₯ =
π‘₯3
cos
𝑑
𝑑𝑑.
πœ‹/2
4-4: Fun Theorems, 2
Objectives:
Assignment:
1. To find the average value • P. 291-292: 47-50, 54-60,
of a function
63
2. To understand and use
the Second Fundamental • P. 293: 75-91 odd
Theorem of Calculus
Download