2-3: Product and Quotient Rules Objectives: Assignment:

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2-3: Product and Quotient Rules
Objectives:
Assignment:
1. To derive and use the
Product and Quotient
Rules
• P. 126-129: 1-11 odd, 15,
17, 25, 31, 35, 37, 47, 53,
66, 81, 87, 129, 131
2. To find higher-order
derivatives
• P. 128-129: 93-101 odd,
109, 111, 130, 132, 133
Warm Up 1
Recall that the Sum Rule
states that the derivative of
a sum is the sum of the
derivatives. Is the same
true for products?
Let 𝑓(π‘₯) = (π‘₯ 2 + 1)(π‘₯ − 1).
Find 𝑓′(π‘₯).
Warm Up 2
Recall that the Sum Rule
states that the derivative of
a sum is the sum of the
derivatives. Is the same
true for products?
Let 𝑓(π‘₯) = (π‘₯ 2 + 1)(π‘₯ − 1).
Expand 𝑓(π‘₯), then find 𝑓′(π‘₯).
Objective 1
You will be able to derive
and use the Product and
Quotient Rules
Exercise 1
Let 𝑓(π‘₯) and 𝑔(π‘₯) be differentiable functions.
Use the limit definition of derivative to find
𝑑
𝑓(π‘₯) βˆ™ 𝑔(π‘₯) .
𝑑π‘₯
Product Rule
The product of two differentiable functions 𝑓
and 𝑔 is also differentiable such that
𝑑
𝑓(π‘₯) βˆ™ 𝑔(π‘₯) = 𝑓 ′ π‘₯ βˆ™ 𝑔 π‘₯ + 𝑓(π‘₯) βˆ™ 𝑔′ (π‘₯)
𝑑π‘₯
Derivative of the first times the second + first times the derivative of the second
Exercise 2
Let 𝑓(π‘₯) = (π‘₯ 2 + 1)(π‘₯ − 1). Find 𝑓′(π‘₯).
Exercise 3
Find the derivative of 𝑦 = 3π‘₯ 2 sin π‘₯
Exercise 4
Find the derivative of 𝑦 = 2π‘₯ cos π‘₯ − 2 sin π‘₯
Exercise 5
Let 𝑦 = π‘₯ sin π‘₯ cos π‘₯ . Find 𝑑𝑦/𝑑π‘₯.
Product Rule
The product of three differentiable functions
𝑓, 𝑔, and β„Ž is also differentiable such that
𝑑
𝑓(π‘₯) βˆ™ 𝑔(π‘₯) βˆ™ β„Ž π‘₯
𝑑π‘₯
= 𝑓 ′ π‘₯ βˆ™ 𝑔 π‘₯ βˆ™ β„Ž π‘₯ + 𝑓 π‘₯ βˆ™ 𝑔′ π‘₯ βˆ™ β„Ž π‘₯ + 𝑓 π‘₯ βˆ™ 𝑔 π‘₯ βˆ™ β„Ž′ π‘₯
Exercise 6
Recall that the Difference
Rule states that the
derivative of a difference is
the difference of the
derivatives. Is the same
true for quotients?
Let 𝑓(π‘₯) =
π‘₯ 2 −1
.
π‘₯+1
Find 𝑓′(π‘₯).
Exercise 7
Let 𝑓(π‘₯) and 𝑔(π‘₯) be differentiable functions
for all π‘₯ such that 𝑔(π‘₯) ≠ 0. Use the limit
𝑑 𝑓(π‘₯)
definition of derivative to find
.
𝑑π‘₯ 𝑔(π‘₯)
Quotient Rule
The quotient of two differentiable functions 𝑓
and 𝑔 is also differentiable for all π‘₯ where
𝑔(π‘₯) ≠ 0 such that
𝑑 𝑓(π‘₯)
𝑔 π‘₯ βˆ™ 𝑓 ′ π‘₯ − 𝑓(π‘₯) βˆ™ 𝑔′(π‘₯)
=
𝑑π‘₯ 𝑔(π‘₯)
𝑔 π‘₯ 2
The bottom times the derivative of the top minus the top times the
derivative of the bottom all divided by the bottom squared
Exercise 8
Find the derivative of 𝑓(π‘₯) =
π‘₯ 2 −1
π‘₯+1
Exercise 9
Find the equation of line that is tangent to
𝑦=
1
3−
π‘₯
π‘₯+5
at the point (−1,1).
Try rewriting as a
single fraction
Pay attention to
parenthesis when
differentiating
9
𝑦= 2
5π‘₯
−3 3π‘₯ − 2π‘₯ 2
𝑦=
7π‘₯
5π‘₯ 4
𝑦=
8
π‘₯ + require
1
None of these
=
the𝑦Quotient
π‘₯ − 1Rule
π‘₯ 2 + 3π‘₯
𝑦=
6
Exercise 10
Which of the following does not belong?
Exercise 11
Find the derivative of each function.
1. 𝑦 = tan π‘₯
2. 𝑦 = sec π‘₯
Trigonometric Derivatives
𝑑
tan π‘₯ = sec 2 π‘₯
𝑑π‘₯
𝑑
cot π‘₯ = − csc 2 π‘₯
𝑑π‘₯
𝑑
sec π‘₯ = sec π‘₯ tan π‘₯
𝑑π‘₯
𝑑
csc π‘₯ = − csc π‘₯ cot π‘₯
𝑑π‘₯
Exercise 12
Differentiate both forms of
1 − cos π‘₯
𝑦=
= csc π‘₯ − cot π‘₯
sin π‘₯
Objective 2
You will be able to find
higher-order derivatives
Exercise 13
Let 𝑓(π‘₯) = π‘₯ 2 + 3π‘₯ − 5. Find the
instantaneous rate of change at π‘₯ = 𝑐. What
is the rate of change of the instantaneous
rate of change?
Higher-Order Derivatives
The derivative of a function gives the rate of
change of that function, which could also be
changing…
βˆ† π‘‘π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’
βˆ† π‘‘π‘–π‘šπ‘’
βˆ† π‘£π‘’π‘™π‘œπ‘π‘–π‘‘π‘¦
βˆ† π‘‘π‘–π‘šπ‘’
βˆ† π‘Žπ‘π‘π‘’π‘™π‘’π‘Ÿπ‘‘π‘–π‘œπ‘›
βˆ† π‘‘π‘–π‘šπ‘’
βˆ† π‘—π‘’π‘Ÿπ‘˜
βˆ† π‘‘π‘–π‘šπ‘’
1st derivative
2nd derivative
3rd derivative
4th derivative
Velocity
Acceleration
Jerk
Jounce
Higher-Order Derivatives
The derivative of the first derivative is called the second
derivative. The derivative of the second derivative is
the third derivative…
1st derivative
𝑦′
𝑓′(π‘₯)
2nd derivative
𝑦′′
𝑓′′(π‘₯)
3rd derivative
𝑦′′′
𝑓′′′(π‘₯)
4th
derivative
𝑦 (4)
𝑓
4
derivative
𝑦 (𝑛)
𝑓
𝑛
𝑛th
(π‘₯)
(π‘₯)
𝑑𝑦
𝑑π‘₯
𝑑2𝑦
𝑑π‘₯ 2
𝑑
𝑓(π‘₯)
𝑑π‘₯
𝑑2
𝑓(π‘₯)
𝑑π‘₯ 2
𝑑3𝑦
𝑑π‘₯ 3
𝑑4𝑦
𝑑π‘₯ 4
𝑑𝑛 𝑦
𝑑π‘₯ 𝑛
𝑑3
𝑓(π‘₯)
𝑑π‘₯ 3
𝑑4
𝑓(π‘₯)
𝑑π‘₯ 4
𝑑𝑛
𝑓(π‘₯)
𝑑π‘₯ 𝑛
𝐷π‘₯ 𝑦
𝐷π‘₯2 𝑦
𝐷π‘₯3 𝑦
𝐷π‘₯4 𝑦
𝐷π‘₯𝑛 𝑦
Exercise 14
Find the second derivative of 𝑦 = π‘₯ sin π‘₯.
Exercise 15
Label each
function
as 𝑓, 𝑓′,
𝑓′′, and
𝑓′′′.
Exercise 15
Label each
function
as 𝑓, 𝑓′,
𝑓′′, and
𝑓′′′.
2-3: Product and Quotient Rules
Objectives:
Assignment:
1. To derive and use the
Product and Quotient
Rules
• P. 126-129: 1-11 odd, 15,
17, 25, 31, 35, 37, 47, 53,
66, 81, 87, 129, 131
2. To find higher-order
derivatives
• P. 128-129: 93-101 odd,
109, 111, 130, 132, 133
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