2-3: Product and Quotient Rules Objectives: Assignment: 1. To derive and use the Product and Quotient Rules • P. 126-129: 1-11 odd, 15, 17, 25, 31, 35, 37, 47, 53, 66, 81, 87, 129, 131 2. To find higher-order derivatives • P. 128-129: 93-101 odd, 109, 111, 130, 132, 133 Warm Up 1 Recall that the Sum Rule states that the derivative of a sum is the sum of the derivatives. Is the same true for products? Let π(π₯) = (π₯ 2 + 1)(π₯ − 1). Find π′(π₯). Warm Up 2 Recall that the Sum Rule states that the derivative of a sum is the sum of the derivatives. Is the same true for products? Let π(π₯) = (π₯ 2 + 1)(π₯ − 1). Expand π(π₯), then find π′(π₯). Objective 1 You will be able to derive and use the Product and Quotient Rules Exercise 1 Let π(π₯) and π(π₯) be differentiable functions. Use the limit definition of derivative to find π π(π₯) β π(π₯) . ππ₯ Product Rule The product of two differentiable functions π and π is also differentiable such that π π(π₯) β π(π₯) = π ′ π₯ β π π₯ + π(π₯) β π′ (π₯) ππ₯ Derivative of the first times the second + first times the derivative of the second Exercise 2 Let π(π₯) = (π₯ 2 + 1)(π₯ − 1). Find π′(π₯). Exercise 3 Find the derivative of π¦ = 3π₯ 2 sin π₯ Exercise 4 Find the derivative of π¦ = 2π₯ cos π₯ − 2 sin π₯ Exercise 5 Let π¦ = π₯ sin π₯ cos π₯ . Find ππ¦/ππ₯. Product Rule The product of three differentiable functions π, π, and β is also differentiable such that π π(π₯) β π(π₯) β β π₯ ππ₯ = π ′ π₯ β π π₯ β β π₯ + π π₯ β π′ π₯ β β π₯ + π π₯ β π π₯ β β′ π₯ Exercise 6 Recall that the Difference Rule states that the derivative of a difference is the difference of the derivatives. Is the same true for quotients? Let π(π₯) = π₯ 2 −1 . π₯+1 Find π′(π₯). Exercise 7 Let π(π₯) and π(π₯) be differentiable functions for all π₯ such that π(π₯) ≠ 0. Use the limit π π(π₯) definition of derivative to find . ππ₯ π(π₯) Quotient Rule The quotient of two differentiable functions π and π is also differentiable for all π₯ where π(π₯) ≠ 0 such that π π(π₯) π π₯ β π ′ π₯ − π(π₯) β π′(π₯) = ππ₯ π(π₯) π π₯ 2 The bottom times the derivative of the top minus the top times the derivative of the bottom all divided by the bottom squared Exercise 8 Find the derivative of π(π₯) = π₯ 2 −1 π₯+1 Exercise 9 Find the equation of line that is tangent to π¦= 1 3− π₯ π₯+5 at the point (−1,1). Try rewriting as a single fraction Pay attention to parenthesis when differentiating 9 π¦= 2 5π₯ −3 3π₯ − 2π₯ 2 π¦= 7π₯ 5π₯ 4 π¦= 8 π₯ + require 1 None of these = theπ¦Quotient π₯ − 1Rule π₯ 2 + 3π₯ π¦= 6 Exercise 10 Which of the following does not belong? Exercise 11 Find the derivative of each function. 1. π¦ = tan π₯ 2. π¦ = sec π₯ Trigonometric Derivatives π tan π₯ = sec 2 π₯ ππ₯ π cot π₯ = − csc 2 π₯ ππ₯ π sec π₯ = sec π₯ tan π₯ ππ₯ π csc π₯ = − csc π₯ cot π₯ ππ₯ Exercise 12 Differentiate both forms of 1 − cos π₯ π¦= = csc π₯ − cot π₯ sin π₯ Objective 2 You will be able to find higher-order derivatives Exercise 13 Let π(π₯) = π₯ 2 + 3π₯ − 5. Find the instantaneous rate of change at π₯ = π. What is the rate of change of the instantaneous rate of change? Higher-Order Derivatives The derivative of a function gives the rate of change of that function, which could also be changing… β πππ π‘ππππ β π‘πππ β π£ππππππ‘π¦ β π‘πππ β ππππππππ‘πππ β π‘πππ β ππππ β π‘πππ 1st derivative 2nd derivative 3rd derivative 4th derivative Velocity Acceleration Jerk Jounce Higher-Order Derivatives The derivative of the first derivative is called the second derivative. The derivative of the second derivative is the third derivative… 1st derivative π¦′ π′(π₯) 2nd derivative π¦′′ π′′(π₯) 3rd derivative π¦′′′ π′′′(π₯) 4th derivative π¦ (4) π 4 derivative π¦ (π) π π πth (π₯) (π₯) ππ¦ ππ₯ π2π¦ ππ₯ 2 π π(π₯) ππ₯ π2 π(π₯) ππ₯ 2 π3π¦ ππ₯ 3 π4π¦ ππ₯ 4 ππ π¦ ππ₯ π π3 π(π₯) ππ₯ 3 π4 π(π₯) ππ₯ 4 ππ π(π₯) ππ₯ π π·π₯ π¦ π·π₯2 π¦ π·π₯3 π¦ π·π₯4 π¦ π·π₯π π¦ Exercise 14 Find the second derivative of π¦ = π₯ sin π₯. Exercise 15 Label each function as π, π′, π′′, and π′′′. Exercise 15 Label each function as π, π′, π′′, and π′′′. 2-3: Product and Quotient Rules Objectives: Assignment: 1. To derive and use the Product and Quotient Rules • P. 126-129: 1-11 odd, 15, 17, 25, 31, 35, 37, 47, 53, 66, 81, 87, 129, 131 2. To find higher-order derivatives • P. 128-129: 93-101 odd, 109, 111, 130, 132, 133