STAAR Practice Test #7
Name:________________________
TEKS 8 (factoring)
Block:_________ Date:__________
1.
(8A) Factor: 𝑥 2 + 16𝑥 + 64
2.
(8A) Factor: 4𝑎2 − 20𝑎𝑏 + 25𝑏 2
𝐴. (𝑥 − 8) (𝑥 − 8)
𝐴. (4𝑎 – 5𝑏)(4𝑎 + 5𝑏)
𝐵. (2𝑥 + 8)(𝑥 + 8)
𝐵. (2𝑎 – 5𝑏)(2𝑎 + 5𝑏)
𝐶. (𝑥 + 8)(𝑥 + 8)
𝐶. (2𝑎 – 5𝑏)(2𝑎 – 5𝑏)
𝐷. (𝑥 + 4) (𝑥 + 4)
𝐷. (2𝑎 + 5𝑏)(2𝑎 + 5𝑏)
3. (8A) The area of a rectangular piece of wood is represented
by 2𝑟 2 − 13𝑟 + 21. Find the dimensions of the piece of wood.
4. (8A) The area of a picture is represented by the equation
𝑤 2 − 4𝑤 = 21 where w is the width of the picture. Find the
width of the picture.
9. (8A) Solve for x.
1
2
6. (8B) An object is launched
into the air. The table on the
right shows the object’s
height above the ground at
various times. Based on the
data in the table, which of
the following is closest to the
object’s height above the
ground 9 seconds after being
launched?
𝑥 2 − 5𝑥 = 18
A. 𝑥 = 5 ± √61
B. 𝑥 = −5 ± √61
C. 𝑥 = −5 ± √16
D. 𝑥 = 5 ± √16
A. 100m
A. 6𝑛(2𝑛 − 3)(𝑛 − 1)
A. 𝑥 =
B. 6𝑛(2𝑛 − 1)(𝑛 − 3)
C. 6𝑛(2𝑛 + 3)(𝑛 − 1)
C. 𝑥 =
D. 6𝑛(2𝑛 + 1)(𝑛 − 3)
10. (8B)The velocity h(t) of a volleyball being kicked in the air
is ℎ(𝑡) = −16𝑡 2 + 8𝑡 , t represents the seconds. A person
kicks a volleyball into the air with an initial upward velocity of
8 feet per second. When will the ball hit the ground?
B. 1 second
C.
1
2
second
C. 10m
D. 95m
8. (8A) Solve for x. 9𝑥 2 + 12𝑥 = 32
7. (8A) Factor Completely: 12𝑛3 − 30𝑛2 + 18𝑛
A. 0 seconds
B. 55m
D. 4 seconds
4
3
4
3
𝑜𝑟 𝑥 = −
𝑜𝑟 𝑥 =
8
3
8
3
B. 𝑥 =
D. 𝑥 =
3
4
3
4
𝑜𝑟 𝑥 =
8
3
𝑜𝑟 𝑥 = −
8
3
11. (8B) A zookeeper is buying fencing to enclose a pen at the
zoo. The pen is an isosceles right triangle. There is already a
fence along the hypotenuse, which borders a path. The area of
the pen will be 4500 square feet. The zookeeper can buy the
fencing in whole feet only. How many feet of fencing should he
buy?
A. 190
B. 95
C. 100
D. 200
Answer Key for Test #7
1
2
3
C
C
(r - 3)(2r – 7)
4
5
6
7
8
9
10
W=7
A
B
A
A
C
190