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STAAR Practice Test #7 Name:________________________ TEKS 8 (factoring) Block:_________ Date:__________ 1. (8A) Factor: 𝑥 2 + 16𝑥 + 64 2. (8A) Factor: 4𝑎2 − 20𝑎𝑏 + 25𝑏 2 𝐴. (𝑥 − 8) (𝑥 − 8) 𝐴. (4𝑎 – 5𝑏)(4𝑎 + 5𝑏) 𝐵. (2𝑥 + 8)(𝑥 + 8) 𝐵. (2𝑎 – 5𝑏)(2𝑎 + 5𝑏) 𝐶. (𝑥 + 8)(𝑥 + 8) 𝐶. (2𝑎 – 5𝑏)(2𝑎 – 5𝑏) 𝐷. (𝑥 + 4) (𝑥 + 4) 𝐷. (2𝑎 + 5𝑏)(2𝑎 + 5𝑏) 3. (8A) The area of a rectangular piece of wood is represented by 2𝑟 2 − 13𝑟 + 21. Find the dimensions of the piece of wood. 4. (8A) The area of a picture is represented by the equation 𝑤 2 − 4𝑤 = 21 where w is the width of the picture. Find the width of the picture. 9. (8A) Solve for x. 1 2 6. (8B) An object is launched into the air. The table on the right shows the object’s height above the ground at various times. Based on the data in the table, which of the following is closest to the object’s height above the ground 9 seconds after being launched? 𝑥 2 − 5𝑥 = 18 A. 𝑥 = 5 ± √61 B. 𝑥 = −5 ± √61 C. 𝑥 = −5 ± √16 D. 𝑥 = 5 ± √16 A. 100m A. 6𝑛(2𝑛 − 3)(𝑛 − 1) A. 𝑥 = B. 6𝑛(2𝑛 − 1)(𝑛 − 3) C. 6𝑛(2𝑛 + 3)(𝑛 − 1) C. 𝑥 = D. 6𝑛(2𝑛 + 1)(𝑛 − 3) 10. (8B)The velocity h(t) of a volleyball being kicked in the air is ℎ(𝑡) = −16𝑡 2 + 8𝑡 , t represents the seconds. A person kicks a volleyball into the air with an initial upward velocity of 8 feet per second. When will the ball hit the ground? B. 1 second C. 1 2 second C. 10m D. 95m 8. (8A) Solve for x. 9𝑥 2 + 12𝑥 = 32 7. (8A) Factor Completely: 12𝑛3 − 30𝑛2 + 18𝑛 A. 0 seconds B. 55m D. 4 seconds 4 3 4 3 𝑜𝑟 𝑥 = − 𝑜𝑟 𝑥 = 8 3 8 3 B. 𝑥 = D. 𝑥 = 3 4 3 4 𝑜𝑟 𝑥 = 8 3 𝑜𝑟 𝑥 = − 8 3 11. (8B) A zookeeper is buying fencing to enclose a pen at the zoo. The pen is an isosceles right triangle. There is already a fence along the hypotenuse, which borders a path. The area of the pen will be 4500 square feet. The zookeeper can buy the fencing in whole feet only. How many feet of fencing should he buy? A. 190 B. 95 C. 100 D. 200 Answer Key for Test #7 1 2 3 C C (r - 3)(2r – 7) 4 5 6 7 8 9 10 W=7 A B A A C 190