Name
Alg1
Easter 2007 Review
Due: Monday, 4/16/07
DO IN NB
Part I:
Let/Solve/Check
1) A store sells hats for $12 and ties for $22. Last weekend the store sold 7 fewer ties
than double the amount of hats and the sales were $2,926. How many of each were sold?
2) A store sells hats for $12 and ties for $22. 160 total items were sold and total sales
were $2,430. How many of each were sold?
3) A phone call cost $5.19. Introductory minutes cost $.21/min and additional minutes
are $.13/min. If there were 3 more additional minutes than triple the introductory
minutes, how many minutes were billed at each rate?
4) A 31-minute phone call cost $5.07. Introductory minutes cost $.21/min and additional
minutes are $.13/min. How many minutes were billed at each rate?
5) Find 5 consecutive integers with the sum of -905.
6) Find 4 consecutive even integers such that the sum of the 2nd and 4th is 176.
7) Find 6 consecutive odd integers such that the sum of the 4th and the 6th is 139 less than
5 times the 3rd.
Solve Algebraically and Check:
8) 5x + 7y = -2
9) 9x + 4y = -36
11x - 8y = 136
-7x + 15y = 28
10) 8x - 5y = 1
11) 11x + 4y =19
6x - 11y = -79
-7x + 9y = 138
Solve and Graph:
12) 2 | 12x – 4 | - 11 .
-7
> -11
Multiply:
14) (3x + 8)(2x – 7)
17) (5x – 2)(4x2 + 2x – 5)
13) 3| 8x – 4 |
12
+ 14 > 23
15) (3x – 4)2
16) (5x + 6)3
18) (3x2 + 7x + 2)(8x2 -5x + 4)
Part II:
Solve each equation: (linear and quadratic together... round to the hundredth if necessary.)
1) 20 - (5/8)x = 40
2) 6(7x - 2) = 8(4x + 1)
3) 2(5x - 4) - 3(4x + 3) = -43
2
2
4) x + 44 = 15x
5) 3x + 18x = 81
6) 3x2 = 5x + 5
7) 11x - 5 = 7x - 53 8) 6(3x + 1) + 5(10 - 4x)= 39
9) ¼x - 33 = -49
2
10) 7x - 1 = 3x
11) 9(3x + 1) = 8(5x + 6)
12) 15x = x2 – 16
2
13) x + 8x = 12
14) 9(4x + 7) - 6(7x + 10) = -54
15) 44 = 20 - 2x
2
2
16) 4x - 128 = 16x 17) 3x - 8x + 6 = x + 6
18) 7(6x + 2) = 10(3x + 5)
19) 3x2 + 13x - 12 = 9x2 - 11x - 12
20) 2x2 - 14 = 10x
Name
Alg1
Easter 2007 Review
Due: Monday, 4/16/07
DO IN NB
Part III:
Parallel/Perpendicular: (Graph all 3 lines for each question)
a) Use the two points to find the equation of the line.
b) For the line found in part a, find a line that is parallel and passes through the given point.
c) Find the equation of a line that is perpendicular and passes through the given point.
Given Line:
1) (-5, 13) (3, -11)
2) (-6,0) (-6,5)
3) (2,6)(2,-19)
4) (-4,2) (8,5)
Parallel:
(4,-9)
(4,3)
(5,14)
(-4, 10)
Solve Each System Graphically and check:
5) y + 1 = -3(x – 2)
11x – 11y = 77
Graph each inequality
7) y + 6 > - ¼ (x – 12)
9) x > 4
Perpendicular:
(3,6)
(6,-7)
(5,-8)
(-6,-8)
6) y + 4 = - ¾ (x – 8)
y=8
8) 36x – 12y > 12
y < -5
10) y – 4 > -2(x + 1)
13x – 52y > 52