Point Reflection Here, ∆ABC is reflected through point p and its image ∆A'B'C' is formed. Step 1) From each vertex of ABC, a segment is drawn through p to its image such that the distance from the vertex to point p is equal to the distance from point p to its image. Step 2) The images are connected to form ∆A'B'C' . Which is the reflection of ∆ABC through point p. A reflection in a point p – is a transformation of the plane such that: 1) The image of the fixed point P is P 2) For all other points, the image of K is K' where P is the midpoint of KK ' . In symbols: Rp(A) = A' under the reflection in point P, the image of A is A' Rp(B) = B' under the reflection in point P, the image of B is B' Rp(C) = C' under the reflection in point P, the image of C is C' The most common point refection in Coordinate Geometry is a reflection in the origin (0,0) Under a reflection in point 0, the origin, P(x, y) → P'(-x, -y) Or R0(x, y) = (-x, -y) The properties preserved under a point reflection are the same as those for line reflection (distance, angle measure, parallelism, collinearity and midpoints) To Find reflections of any point: Use the midpoint formula to find the image Ex 1) Given A(5, 5) and P(3, 2). When A is reflected in point p find the coordinates of A'. m( x1 x2 y 2 y1 , ) 2 2 5 x2 3 2 5 y2 2 2 6 = 5 + x2 x2 = 1 4 = 5 + y2 y2 = -1 A' = (1, -1) Ex 2) Given A(6, 3) and A'(2, -2) find the point of reflection ("midpoint"). Ex 3) a) Using the rule (x, y) → (-x, -y) find the images of A(2, 1), B(4, 5), C(-1, 3), namely A', B' and C' b) On one set of axes, draw ∆ABC and ∆A'B'C' c) Find the coordinates of M, the midpoint of AB . d) Using AB and M and their images, show that a midpoint is preserved under this transformation. Ans: a) A'(-2, -1), B'(-4, -5), C'(1, -3) c) (3, 3) d) image of (3, 3) is (-3, -3) midpoint of A' B' is (-3, -3)