9.5A Graph Hyperbolas Algebra II Hyperbolas • Like an ellipse but instead of the sum of distances it is the difference • A hyperbola is the set of all points P such that the differences from P to two fixed points, called foci, is constant • The line thru the foci intersects the hyperbola @ two points (the vertices) • The line segment joining the vertices is the transverse axis, and it’s midpoint is the center of the hyperbola. • Has 2 branches and 2 asymptotes • The asymptotes contain the diagonals of a rectangle centered at the hyperbolas center Asymptotes Vertex (-a,0) (0,b) Vertex (a,0) Focus Focus (0,-b) This is an example of a horizontal transverse axis Vertical transverse axis 2 2 y x 2 1 2 a b Standard Form of Hyperbola w/ center @ origin Transverse Equation Asymptotes Vertices Axis Horizontal x2 y2 2 1 2 a b y 2 x2 Vertical 1 2 2 a b y=+/- (b/a)x (+/-a,o) y=+/- (a/b)x (0,+/-a) Foci lie on transverse axis, c units from the center c2 = a2+b2 Ex. 1)Graph 2 2 9 y 16 x 144 • Write in standard form (divide through by 144) • a=4 b=3 • transverse axis is vertical & vertices are (0,4) & (0, -4) Plot other pts from b value (3,0) , (-3,0) to make rectangle • Draw a rectangle centered at the origin. • Draw asymptotes. • Draw hyperbola with foci. • Graph Ex. 2 Graph x 4y 9 2 2 9.5B Write Equations of Hyperbolas Algebra II Ex. 1)Write the equation of a hyperbola with foci (0,-3) & (0,3) and vertices (0,-2) & (0,2). • Vertical because foci & vertices lie on the y-axis • Center @ origin because f & v are equidistant from the origin • Since c=3 & a=2, c2 = b2 + a2 2 2 • 9 = b2 + 4 y x 1 • 5 = b2 4 5 • +/-√5 = b Standard Form of Hyperbola w/ center @ origin Transverse Equation Asymptotes Vertices Axis Horizontal x2 y2 2 1 2 a b y 2 x2 Vertical 1 2 2 a b y=+/- (b/a)x (+/-a,o) y=+/- (a/b)x (0,+/-a) Foci lie on transverse axis, c units from the center c2 = a2+b2 Ex. 2 Write an equation of the hyperbola with the given foci & vertices • Foci: 3 6 , 0, 3 6 , 0 • Vertices: (-2,0), (2,0) Assignment