P780.02 Spring 2003 L10 Richard Kass Weak Interactions Some Weak Interaction basics Weak force is responsible for b decay e.g. n → pev (1930’s) interaction involves both quarks and leptons not all quantum numbers are conserved in weak interaction: parity, charge conjugation, CP isospin flavor (strangeness, bottomness, charm) Weak (+EM) are “completely” described by the Standard Model Chapter 8 M&S Weak interactions has a very rich history 1930’s: Fermi’s theory described b decay. 1950’s: V-A (vector-axial vector) Theory: Yang & Lee describe parity violation Feynman and Gell-Mann describe muon decay and decay of strange mesons 1960’s: Cabibbo Theory N. Cabibbo proposes “quark mixing” (1963) "explains" why rates for decays with DS =0 > DS =1 BR( K ) 63.5% Chapter 8.2.3 M&S BR( ) 99.9% Quarks in strong interaction are not the same as the ones in the weak interaction: weak interaction basis different than strong interaction basis previous example: ( K o , K o ) ( K s , K L ) P780.02 Spring 2003 L10 Weak Interactions Richard Kass Weinberg-Salam-Glashow (Standard Model 1970’s-today) unify Weak and EM forces predict neutral current (Z) reactions gives relationship between mass of W and Z predict/explain lots of other stuff!..e.g. no flavor changing neutral currents existence of Higgs (“generates”mass in Standard Model) Renormalizable Gauge Theory But the picture is still incomplete: must input lots of parameters into the Standard Model (e.g. masses) where’s the Higgs and how many are there ? how many generations of quarks and leptons are there ? mass pattern of quarks and leptons ? neutrinos have mass! CP violation observed with quarks! is there CP violation with leptons? P780.02 Spring 2003 L10 Weak Interactions Classification of Weak Interactions Type Comment Leptonic involves only leptons Semileptonic leptons and quarks Non-Leptonic involves only quarks Richard Kass Examples muon decay ( evv) ee- eeneutron decay (Ds=0) NOT K+ + (Ds=1) Allowed B Do (Db=1) Allowed e , L -p & K+ +o WW- Some details of Weak Interactions quarks and leptons are grouped into doublets (SU(2)) (sometimes called families or generations) For every quark doublet there is a lepton doublet Q 2 / 3|e| u c t d s b Q 1/ 3|e| Q |e| e e Q 0 Charged Current Interactions (exchange of a W boson) W’s couple to leptons in the same doublet The W coupling to leptons/quarks is a combination of vector and axial vector terms: Ju ugu(1- g5 )u (parity violating charged e ee, W- W- e, W- - W- Cabibbo Model P780.02 Spring 2003 L10 Richard Kass Cabibbo’s conjecture was that the quarks that participate in the weak interaction are a mixture of the quarks that participate in the strong interaction. This mixing was originally postulated by Cabibbo (1963) to explain certain decay patterns in the weak interactions and originally had only to do with the d and s quarks. d’ = d cosq + s sinq Thus the form of the interaction (charged current) has an extra factor for d and s quarks d quark: Ju a gu(1- g5 )cosqc s quark: Ju a gu(1- g5 )sinqc d u u d d cos q c s sin qc cosqc s W- sinqc WPurely leptonic decays (e.g. muon decay) do not contain the Cabibbo factor: u u The Cabibbo angle is important for determining the rate of many reactions: 2 The+ Cabibbo angle can measured 2using data from the following + 2 + reactions: BR(K v) mk = sin q c BR(+ + v) cos 2 q c m 1- (m / m k ) 1- (m / m ) 2 cosqcor sinqc From the above branching ratio’s we find: qc= 0.27 radians We can check the above by measuring the rates u for:K oe e o e e Find: qc= 0.25 radians W+ d, s P780.02 Spring 2003 L10 Cabibbo’s Model Extensions to the Cabibbo Model: Cabibbo’s model could easily be extended to 4 quarks: c u u c d d cos q c s sin qc s s cosq c d sin q c d cosq s sin q c Richard Kass sin q c d cosq c s Adding a fourth quark actually solved a long standing puzzle in weak interactions, the “absence” (i.e. very small BR) of decays involving a “flavor” (e.g. strangeness) changing neutral current: 0 9 BR( K ) 7 10 8 10 0.64 BR( K ) However, Cabibbo’s model could NOT incorporate CP violation and by 1977 there was evidence for 5 quarks! M&S section 8.3.1 The CKM model: Cabibbo’s name In 1972 (2 years before discovery of charm!) Kobayashi and Maskawa was added to extended Cabibbo’s idea to six quarks: make “CKM” 6 quarks (3 generations or families) 3x3 matrix that mixes the weak quarks and the strong quarks (instead of 2x2) The matrix is unitary 3 angles (generalized Cabibbo angles), 1 phase (instead of 1 parameter) The phase allows for CP violation Just like qc had to be determined from experiment, the matrix elements of the CKM matrix must also be obtained from experiment. P780.02 Spring 2003 L10 The GIM Mechanism Richard Kass In 1969-70 Glashow, Iliopoulos, and Maiani (GIM) proposed a solution to the BR( K 0 ) 7 10 9 to the K0 + - rate puzzle. 108 BR( K ) 0.64 The branching fraction for K0 + - was expected to be small as the first order diagram is forbidden (no allowed W coupling). + + K+ allowed W+ ??0 K0 forbidden u d s s nd The 2 order diagram (“box”) was calculated & was found to give a rate higher than the experimental measurement! amplitude sinqccosqc GIM proposed that a 4th quark existed and its coupling to the s and d quark was: s’ = scosq - dsinq The new quark would produce a second “box” diagram with amplitude sinqccosqc These two diagrams almost cancel each other out. The amount of cancellation depends on the mass of the new quark A quark mass of 1.5GeV is necessary to get good agreement with the exp. data. First “evidence” for Charm quark! P780.02 Spring 2003 L10 Richard Kass CKM Matrix The CKM matrix can be written in many forms: 1) In terms of three angles and phase: c12c13 d i 13 s s12c23 c12 s23s13e b s s c c s ei13 12 23 12 23 13 s12c13 c12c23 s12 s23s13ei13 c12 s23 s12c23s13ei13 s13e i13 d s23c13 s c23c13 b This matrix is not unique, many other 3X3 forms in the literature. This one is from PDG2000. The four real parameters are , q12, q23, and q13. Here s=sin, c=cos, and the numbers refer to the quark generations, e.g. s12=sinq12. 2) In terms of coupling to charge 2/3 quarks (best for illustrating physics!) d' V ud V us V ub d s' = V cd V cs V cb s b' V td V ts V tb b 3) In terms of the sine of the Cabibbo angle (q12). This representation uses the fact that s12>>s23>>s13. 2 d 1 / 2 1 2 / 2 s b A3 (1 i ) A2 “Wolfenstein” representaton A3 ( i ) d 2 A s 1 b Here =sinq12, and A, , are all real and approximately one. This representation is very good for relating CP violation to specific decay rates. P780.02 Spring 2003 L10 CKM Matrix Richard Kass The magnitudes of the CKM elements, from experiment are (PDG2000): Vud Vcd V td Vus Vub 0.9742 0.9757 Vcs Vcb 0.219 0.225 Vts Vtb (0.4 1.4) 10 2 0.219 0.226 0.9734 0.9749 (3.5 4.3) 10 2 (2 5) 103 2 (3.7 4.3) 10 0.9990 0.9993 There are several interesting patterns here: 1) The CKM matrix is almost diagonal (off diagonal elements are small). 2) The further away from a family, the smaller the matrix element (e.g. Vub<<Vud). 3) Using 1) and 2), we see that certain decay chains are preferred: c s over c d D0 K-+ over D0 -+ (exp. find 3.8% vs 0.15%) b c over b u B0 D-+ over B0 -+ (exp. find 3x10-3 vs 1x10-5) 4) Since the matrix is supposed to be unitary there are lots of constraints among the matrix elements: Vud* Vud Vcd* Vcd Vtd* Vtd 1 Vub* Vud Vcb* Vcd Vtb*Vtd 0 So far experimental results are consistent with expectations from a Unitary matrix. But as precision of experiments increases, we might see deviations from Unitarity. P780.02 Spring 2003 L10 Measuring the CKM Matrix Richard Kass No one knows how to calculate the values of the CKM matrix. Experimentally, the cleanest way to measure the CKM elements is by using interactions or decays involving leptons. CKM factors are only present at one vertex in decays with leptons. Vud: neutron decay: npev duev Vus: kaon decay: K0 +e-ve suev Vbu: B-meson decay: B- ( or +)e-ve buev Vbc: B-meson decay: B- D0e-ve bcev Vcs: charm decay: D0 K-e+ve csev Vcd: neutrino interactions: d -c dc “Spectator” Model decay of D0 K-e+ve e, W c D0 Vcs For massless neutrinos the lepton “CKM” matrixis diagonal e, s K- Amplitude Vcs Decay rate Vcs2 u u Called a “spectator” diagram because only one quark participates in the decay, the other “stands around and watches”.