1.5 Solution Sets of Linear Systems A solution of a linear system is a vector or a collection of vectors. We begin by looking at a special type of equation to see what solution sets are like. Definition: A homogeneous system of linear equations is a system of the form Ax = 0. A is and m x n matrix, and 0 is the zero vector in Rm. Every homogeneous system has at least one solution: x = 0. We call this the trivial solution. Example: x1 3 x2 0 2 x1 6 x2 0 The corresponding matrix equation is: 1 3 x1 0 2 6 x 0 2 1 The trivial solution is x1 0 x x2 0 ►Non-zero solutions are called non-trivial solutions. “Do non-trivial solutions for this system exist?” Put the associated augmented matrix into reduced row echelon form: 1 3 0 1 3 0 2 6 0 ~ 0 0 0 Yes, there are infinitely many solutions. Why? 2 Fact: The homogeneous equation Ax = 0 has a non-trivial solution if and only if the equation has at least one free variable. To see this: Recall: Theorem 1.2 part 2: If a linear system is consistent, then the solution contains either a) a unique solution (when there are no free variables) b) infinitely many solutions (when there is at least one free variable). If the homogeneous equation Ax = 0 has a non-trivial solution, it has more than one solution, hence infinitely many solutions, hence at least one free variable. If the equation has at least one free variable, infinitely many solutions, hence more than just the trivial one. 3 Example: Determine whether the homogeneous system has non-trivial solutions and describe the solution set. 2 x1 4 x2 6 x3 0 4 x1 8 x2 10 x3 0 “Is there a free variable?” Write the matrix associated to Ax = 0. 2 4 - 6 4 6 - 10 0 1 2 0 0 ~ 0 0 0 1 0 x1 2 x2 x2 is free x3 0 We can write this as a vector: x1 2 x2 x x2 x2 x3 0 4 Factor out x2 to get 2 x x2 1 or x x2 v 0 Note 1: a non-trivial solution can have zero entries. Note 2: since x2 can be any number, the solution set is Span{v}. ►Geometrically, this is a line through 0 and v. Example: A non-homogeneous system: 2 x1 4 x2 6 x3 0 4 x1 8 x2 10 x3 4 The only difference is b in Ax = b. 2 4 - 6 4 6 - 10 0 1 2 0 6 ~ 4 0 0 1 2 5 Solution: x1 6 2 x2 x3 2 x2 is free We can write this as a vector: x1 6 2 x2 x x2 x2 x3 2 We can separate this vector into two vectors and factor out x2 to get 6 2 x 0 x2 1 or x p x2 v . 2 0 Note: This solution set is the line parallel to v through p. It is a translation of x2 v by p. 6 ►You can think of solution sets of matrix equations as lines (if you have one free variable) or planes (if you have two). ►We call x x2 v and x p x2 v parametric vector equations. Sometimes we write x p tv to emphasize that t can be any real number. Theorem 6: Suppose the equation Ax = b is consistent for some given b, and let p be a solution. Then the solution set is the set of all vectors of the form w = p + vh , where vh is any solution of the homogeneous equation Ax = 0. Example: Describe the solution set of 2 x1 4 x2 4 x3 0 and compare it to the solution set of 2 x1 4 x2 4 x3 6 . “Are there free variables?” 7 Answer: These are systems of one equation each in three variables. For the homogeneous system: [2 –4 –4 0]~[1 –2 –2 0] The vector form of the solution is x1 2 x2 2 x3 x x2 x2 x3 x3 We can separate this vector into two vectors 2 2 x x2 1 x3 0 or x x2u x3 v 0 1 u v The non-homogenous situation is: [2 –4 –4 6]~[1 –2 –2 3] The vector form of the solution is x1 3 2 x2 2 x3 x x2 x2 x3 x3 8 Separate this vector into three vectors 3 2 2 x 0 x2 1 x3 0 0 0 1 or x p x2u x3 v Geometrically, the solution set of the homogeneous equation is a plane in R3 through 0, u, and v: Span{u,v}. The solution of the non-homogeneous equation is a plane parallel to Span{u,v} and shifted three units in the x1 direction. 9