Old Lecture 23 sect ..

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ME 221 Statics
Lecture #23
Section 5.5
ME 221
Lecture 23
1
Homework #8
• Chapter 9 problems:
– 42, 43, 50 & 55
• Chapter 5 problems:
– 11, 13, 16, 20, 24 & 25
– See Blackboard for additional information
• Due Wednesday, October 30
ME 221
Lecture 23
2
Quiz #5
Wednesday, October 30
ME 221
Lecture 23
3
Last Lecture
• Equilibrium equations
• Free body diagrams
• Modeling supports
ME 221
Lecture 23
4
Equilibrium Equations
When the force system is replaced by a resultant force and
moment that are zero, the rigid body is in equilibrium.
F  0
~
and
M  0
~
The equilibrium conditions may be expressed as:
F
F
F
ME 221
x
0
y
0
z
0
M
M
M
Lecture 23
x
0
y
0
z
0
5
Supports for Rigid Bodies
If a rigid object is subjected to some set of forces
but does not move, then its motion could be
restrained by a normal force exerted by the ground,
a wall or from fixing the object with some support.
If the support prevents translation in a given
direction, then a force is developed on the member
in that direction. Likewise, if a rotation is
prevented, then a couple moment is exerted on the
member.
ME 221
Lecture 23
6
Free Body Diagram
• Draw the body separate from all other bodies
(including ground).
• Draw the magnitudes and directions of all external
forces acting on the body.
– Include: applied loads, reactions due to supports, and
the weight of the object.
• Include necessary dimensions of the body
– Dimensions are needed for summing moments
• Draw the positive sense of the coordinate system
used to write out equilibrium equations
ME 221
Lecture 23
7
Special Cases
•Equilibrium of Rigid Bodies
- 2D & 3D
Two- and Three-Force Members
Special Supports
ME 221
Lecture 23
8
Two- and Three-Force Members
F2
F1
Two-Force Members
F3
When the member is not subjected to
a couple and the forces are applied
only at two points, the member is
said to be two-force member.
A
B
F6
Let:

 


 

FA  F1  F2  F3 and FB  F4  F5  F6
F4
F5
FA
These forces will maintain equilibrium if:
A


FA   FB
B
(FA and FB must be collinear)
ME 221
FB
Lecture 23
9
Two- and Three-Force Members
Three-Force Members
If the member is subjected to three coplanar forces, then it is
necessary that the forces are either concurrent or parallel if the
member is to be in equilibrium.
F2
O

F3
F1
ME 221
Lecture 23
F3
F2
F1
10
Note:
• It should be noted that single bearing, single
pin and single hinge supports can support
both forces and couples. Most often,
however, these supports are used in
conjunction with other bearings, pins or
hinges to hold the body in equilibrium. In
this case, the force reaction at the support
may be adequate.
ME 221
Lecture 23
11
Chapter 5 Equilibrium Examples
ME 221
Lecture 23
12
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