PHYS 3313 – Section 001 Lecture #16 Wednesday, April 1, 2015 Dr. Jaehoon Yu • • • Probability of Particle Schrodinger Wave Equation and Solutions Normalization and Probability Wednesday, April 1, 2015 PHYS 3313-001, Spring 2015 Dr. Jaehoon Yu 1 Special Project #4 • Prove that the wave function =A[sin(kx t)+icos(kx- t)] is a good solution for the timedependent Schrödinger wave equation. Do NOT use the exponential expression of the wave function. (10 points) • Determine whether or not the wave function =Ae- |x| satisfy the time-dependent Schrödinger wave equation. (10 points) • Due for this special project is Wednesday, Apr. 8. • You MUST have your own answers! Wednesday, April 1, 2015 PHYS 3313-001, Spring 2015 Dr. Jaehoon Yu 2 The Schrödinger Wave Equation • Erwin Schrödinger and Werner Heinsenberg proposed quantum theory in 1920 • The two proposed very different forms of equations • Heinserberg: Matrix based framework • Schrödinger: Wave mechanics, similar to the classical wave equation • Paul Dirac and Schrödinger later on proved that the two give identical results • The probabilistic nature of quantum theory is contradictory to the direct cause and effect seen in classical physics and makes it difficult to grasp! Wednesday, April 1, 2015 PHYS 3313-001, Spring 2015 Dr. Jaehoon Yu 3 The Time-dependent Schrödinger Wave Equation • The Schrödinger wave equation in its time-dependent form for a particle of energy E moving in a potential V in one dimension is 2 ¶Y ( x,t ) ¶2 Y ( x,t ) i =+ VY ( x,t ) 2 ¶t 2m ¶x • The extension into three dimensions is 2 æ ¶2 Y ¶2 Y ¶2 Y ö ¶Y i =+ 2 + 2 ÷ + VY ( x, y, z,t ) 2 ç ¶t 2m è ¶x ¶y ¶z ø • where i = -1 is an imaginary number Wednesday, April 1, 2015 PHYS 3313-001, Spring 2015 Dr. Jaehoon Yu 4 Ex 6.1: Wave equation and Superposition The wave equation must be linear so that we can use the superposition principle. Prove that the wave function in Schrodinger equation is linear by showing that it is satisfied for the wave equation (x,t1 (x,t2 (x,t where a and b are constants and 1 (x,t and 2 (x,t describe two waves each satisfying the Schrodinger Eq. 2 ¶Y1 ¶ 2 Y1 Y = aY1 + bY2 i =+ VY1 2 ¶t 2m ¶x ¶Y ¶ ¶Y ¶Y 2 = ( aY1 + bY 2 ) = a 1 + b ¶t ¶t ¶t ¶t ¶Y ¶ ¶Y ¶Y 2 = ( aY1 + bY 2 ) = a 1 + b ¶x ¶x ¶x ¶x 2 ¶Y ¶2 Y i =+ VY 2 ¶t 2m ¶x Rearrange terms 2 ¶Y 2 ¶2 Y 2 i =+ VY 2 2 ¶t 2m ¶x ¶2 Y ¶ æ ¶Y1 ¶Y 2 ö ¶2 Y1 ¶2 Y 2 = ça +b +b ÷ =a ¶x 2 ¶x è ¶x ¶x ø ¶x 2 ¶x 2 2 2 æ ¶ ö ¶Y ¶2 Y ¶2 i + VY = i + V çè ¶t 2m ¶x 2 ÷ø Y = 0 ¶t 2m ¶x 2 2 æ ¶ 2 Y1 ¶Y ¶Y 2 ö ¶2 Y 2 ö æ ¶Y1 i = i ça +b a +b + V ( aY1 + bY 2 ) ÷ =è ¶t ¶t ¶t ø 2m çè ¶x 2 ¶x 2 ÷ø 2 2 æ ¶Y1 ö æ ¶Y 2 ö ¶ 2 Y1 ¶2 Y 2 aç i + VY = -b i + VY 1÷ 2÷ = 0 çè ¶t 2m ¶x 2 è ¶t 2m ¶x 2 ø ø Wednesday, April 1, 2015 PHYS 3313-001, Spring 2015 Dr. Jaehoon Yu 5 General Solution of the Schrödinger Wave Equation • The general form of the solution of the Schrödinger wave equation is given by: Y ( x,t ) = Ae i( kx-w t ) = A éë cos ( kx - w t ) + isin ( kx - w t ) ùû • which also describes a wave propagating in the x direction. In general the amplitude may also be complex. This is called the wave function of the particle. • The wave function is also not restricted to being real. Only the physically measurable quantities (or observables) must be real. These include the probability, momentum and energy. Wednesday, April 1, 2015 PHYS 3313-001, Spring 2015 Dr. Jaehoon Yu 6 Ex 6.2: Solution for Wave Equation Show that Aei(kx- t) satisfies the time-dependent Schrodinger wave Eq. i( kx-w t ) ¶Y ¶ = Aei( kx-w t ) = -iAw ei( kx-w t ) = -iwY ¶t ¶t ( Y = Ae ) ¶Y ¶ = Aei( kx-w t ) = iAkei( kx-w t ) = ikY ¶x ¶x ( ) ¶2 Y ¶ ¶ i( kx-w t ) 2 i( kx-w t ) 2 = ikY = ik Y = ik iAke = -Ak e = -k Y ( ) ( ) 2 ¶x ¶x ¶x 2 2 æ ö k 2 ¶Y w V Y=0 2 ç ÷ i = i ( -iwY ) = wY = -k Y + VY ( ) 2m è ø ¶t 2m æ ö p2 æw ö = E V =0 The Energy: E = hf = h ç ÷ = w ç ÷ 2m è ø è 2p ø 2p 2p 2p p p The momentum: p = k The wave number: k = = = = l h p h 2 2 ( ) p From the energy conservation: E = K + V = +V 2m p E-V = 0 2m So Aei(kx- t) is a good solution and satisfies Schrodinger Eq. Wednesday, April 1, 2015 PHYS 3313-001, Spring 2015 Dr. Jaehoon Yu 7 Ex 6.3: Bad Solution for Wave Equation Determine (x,tAsin(kx- t) is an acceptable solution for the timedependent Schrodinger wave Eq. Y = Asin ( kx - w t ) ¶Y ¶ = ( Asin ( kx - w t )) = -Aw cos ( kx - w t ) ¶t ¶t ¶Y ¶ = ( Asin ( kx - w t )) = kAcos ( kx - w t ) ¶x ¶x ¶2 Y ¶ 2 2 = kAcos kx w t = -k Asin kx w t = -k Y ( ) ( ) ( ) 2 ¶x ¶x 2 i ( -w cos ( kx - w t )) = -k 2 sin ( kx - w t )) + V sin ( kx - w t ) ( 2m æ 2k2 ö -i w cos ( kx - w t ) = ç + V ÷ sin ( kx - w t ) è 2m ø æ p2 ö -iE cos ( kx - w t ) = ç + V ÷ sin ( kx - w t ) è 2m ø This is not true in all x and t. So (x,t)=Asin(kx- t) is not an acceptable solution for Schrodinger Eq. Wednesday, April 1, 2015 PHYS 3313-001, Spring 2015 Dr. Jaehoon Yu 8