PHYS 3446 – Lecture #4 Monday, Sept. 11, 2006 Dr. Jae Yu 1. 2. 3. 4. Lab Frame and Center of Mass Frame Relativistic Treatment Feynman Diagram Invariant kinematic variables Monday, Sept. 11, 2006 PHYS 3446, Fall 2006 Jae Yu 1 Announcements • I now have 9 on the distribution list. – Only three more to go!! Whoopie!! – Please come and check to see if your request has been successful • I will send a test message this week • No lecture this Wednesday but • The class time should be devoted for your project group meetings in preparation for the workshop Monday, Sept. 11, 2006 PHYS 3446, Fall 2006 Jae Yu 2 Scattering Cross Section • For a central potential, measuring the yield as a function of q, or differential cross section, is equivalent to measuring the entire effect of the scattering • So what is the physical meaning of the differential cross section? Measurement of yield as a function of specific experimental variable This is equivalent to measuring the probability of certain process in a specific kinematic phase space • Cross sections are measured in the unit of barns: -24 1 barn = 10 cm Monday, Sept. 11, 2006 PHYS 3446, Fall 2006 Jae Yu 2 3 Lab Frame and Center of Mass Frame • We assumed that the target nuclei do not move through the collision in Rutherford Scattering • In reality, they recoil as a result of scattering • Sometimes we use two beams of particles for scattering experiments (target is moving) • This situation could be complicated but.. • If the motion can be described in the Center of Mass frame under a central potential, it can be simplified Monday, Sept. 11, 2006 PHYS 3446, Fall 2006 Jae Yu 4 Lab Frame and CM Frame • The equations of motion can be written m1r1 1V r1 r2 m2 r2 2V r1 r2 where ˆi qˆi i rˆi ri ri qi ri sin q i i i 1,2 Since the potential depends only on relative separation of the particles, we redefine new variables, relative coordinates & coordinate of CM r r1 r2 Monday, Sept. 11, 2006 and RCM PHYS 3446, Fall 2006 Jae Yu m1r1 m2 r2 m1 m2 5 Lab Frame and CM Frame • From the equations in previous slides V r m1m2 r r V r rˆ m1 m2 r and m1 m2 RCM Thus MRCM 0 Reduced Mass RCM constant Rˆ • What do we learn from this exercise? • For a central potential, the motion of the two particles can be decoupled when re-written in terms of – a relative coordinate – The coordinate of center of mass Monday, Sept. 11, 2006 PHYS 3446, Fall 2006 Jae Yu 6 Now with some simple arithmatics • From the equations of motion, we obtain m1r1 m2r2 m1r1 m2 r1 r m1 m2 r1 m2 r ˆ rˆ1 rˆ2 V r r Vr r2 r r1 • Since the momentum of the system is conserved: m1r1 m2 r2 RCM 0 m1r1 m2 r2 m2 r1 r m1 m2 • Rearranging the terms, we obtain m2 m1 m2 r1 m2r r1 r m1 m2 m2 m1m2 r m2 r r r̂ V r m1 m2 r m1 m2 m1 m2 Monday, Sept. 11, 2006 PHYS 3446, Fall 2006 Jae Yu 7 Lab Frame and CM Frame • The CM is moving at a constant velocity in the lab frame independent of the form of the central potential • The motion is as if that of a fictitious particle with mass (the reduced mass) and coordinate r. • In the frame where CM is stationary, the dynamics becomes equivalent to that of a single particle of mass scattering off of a fixed scattering center. • Frequently we define the Center of Mass frame as the frame where the sum of the momenta of all the interacting particles is 0. Monday, Sept. 11, 2006 PHYS 3446, Fall 2006 Jae Yu 8 Relationship of variables in Lab and CMS CMS v1 q Lab VCM • The speed of CM is vCM RCM • Speeds of the particles in CMS are v1 v1 vCM q CM v1 m1v1 m1 m2 m2v1 m1v1 and v2 vCM m1 m2 m1 m2 • The momenta of the two particles are equal and opposite!! Monday, Sept. 11, 2006 PHYS 3446, Fall 2006 Jae Yu 9 Scattering angles in Lab and CMS • qCM represents the changes in the direction of the relative position vector r as a result of the collision in CMS • Thus, it must be identical to the scattering angle for the particle with the reduced mass, . • Z components of the velocities of particle with m1 in lab and CMS are: v cosq Lab vCM v1 cosqCM • The perpendicular components of the velocities are: v sin q Lab v1 sin qCM • Thus, the angles are related, for elastic scattering only, as: sin qCM sin qCM sin qCM tan q Lab cosqCM vCM v1 cosqCM m1 m2 cosqCM Monday, Sept. 11, 2006 PHYS 3446, Fall 2006 Jae Yu 10 Differential cross sections in Lab and CMS • The particles that scatter in lab at an angle qLab into solid angle dWLab scatter at qCM into solid angle dWCM in CM. • Since is invariant, dLab = dCM. – Why? – is perpendicular to the direction of boost, thus is invariant. • Thus, the differential cross section becomes: d d q Lab sin q Lab dq Lab qCM sin qCM dqCM d WLab d WCM d d cosqCM d qCM q Lab reorganize d WLab d WCM d cosq Lab Using Eq. 1.53 Monday, Sept. 11, 2006 1 2 cosqCM d d qCM q Lab d WCM 1 cosqCM d WLab PHYS 3446, Fall 2006 Jae Yu 2 3/ 2 11 Some Quantities in Special Relativity • Fractional velocity v c 1 • Lorentz g factor g 1 2 • Relative momentum and the total energy of the particle moving at a velocity v c is P M g v M g c E T 2 E 2 P 2c 2 M 2c 4 M g c 2 Re st • Square of four momentum P=(E,pc), rest mass E P Mc E p c 2 Monday, Sept. 11, 2006 2 2 PHYS 3446, Fall 2006 Jae Yu 2 2 12 Relativistic Variables • Velocity of CM in the scattering of two particles with rest mass m1 and m2 is: P1 P2 c vCM CM E1 E2 c • If m1 is the mass of the projectile and m2 is that of the target, for a fixed target we obtain CM Pc Pc 1 1 2 2 2 4 2 E1 E2 P1 c m1 c m2 c Monday, Sept. 11, 2006 PHYS 3446, Fall 2006 Jae Yu 13 Relativistic Variables • At very low energies where m1c2>>P1c, the velocity reduces to: m1v1 m1v1c CM 2 2 m1c m2c m1 m2 c • At very high energies where m1c2<<P1c and m2c2<<P1c , the velocity can be written as: CM CM 1 2 m1c m2 c 2 1 Pc 1 1 Pc 2 Monday, Sept. 11, 2006 PHYS 3446, Fall 2006 Jae Yu m2 c 1 m1c 1 P1 2 P1 Expansion 14 2 Relativistic Variables • For high energies, if m1~m2, • CM gCM becomes: 2 g CM 1 CM • And 1/ 2 1 1 CM 1 CM 2 CM E m c 2 • Thus gCM becomes 2 g CM 1 CM Monday, Sept. 11, 2006 m2c 2 P 1 1 2 P1 2m2c m12c 4 2 E1m2c 2 m22c 4 1 1/ 2 m2 c 1 P1 2 1/ 2 2 2 E1 m2 c 2 m12 c 4 2 E1m2 c 2 m22 c 4 PHYS 3446, Fall 2006 Jae Yu Invariant 15 s Scalar: Relativistic Variables • The invariant scalar, s, is defined as: 2 2 s P1 P2 E1 E2 P1 P2 E c 2 2E1m2c • So what is this the CMS frame? 0 s m12c 4 m22c 4 2E1m2c 2 2 2 2 E1CM E2CM P1CM P2CM c 2 4 m1 c 2 4 m2 c 2 E1CM E2CM 2 2 CM ToT 2 • Thus, s represents the total available energy in the CMS Monday, Sept. 11, 2006 PHYS 3446, Fall 2006 Jae Yu 16 Useful Invariant Scalar Variables • Another invariant scalar, t, the momentum transfer (differences in four momenta), is useful for scattering: t P1 f P1i 2 E1f E1i 2 P1 f P1i 2 c2 • Since momentum and total energy are conserved in all collisions, t can be expressed in terms of target variables t E2f E2i 2 P2 f P2i 2 c2 • In CMS frame for an elastic scattering, where PiCM=PfCM=PCM and EiCM=EfCM: f2 i2 f i 2 t PCM PCM 2 PCM PCM c 2 2 PCM c 2 1 cos qCM . Monday, Sept. 11, 2006 PHYS 3446, Fall 2006 Jae Yu 17 Feynman Diagram • The variable t is always negative for an elastic scattering • The variable t could be viewed as the square of the invariant mass of a particle with E2f E2i and P2f P2i exchanged in the scattering t-channel diagram Time Momentum of the carrier is the difference between the two particles. • While the virtual particle cannot be detected in the scattering, the consequence of its exchange can be calculated and observed!!! – A virtual particle is a particle whose mass is different than the rest mass Monday, Sept. 11, 2006 PHYS 3446, Fall 2006 18 Jae Yu Useful Invariant Scalar Variables • For convenience we define a variable q2, q 2c 2 t • In the lab frame, P2iLab 0 , thus we obtain: 2 2 f 2 f q c E2 Lab m2c P2 Labc 2m2 c 2 E2fLab m2 c 2 2m2 c 2T2fLab 2 2 • In the non-relativistic limit: f T2 Lab 1 2 m2v2 2 • q2 represents “hardness of the collision”. Small qCM corresponds to small q2. Monday, Sept. 11, 2006 PHYS 3446, Fall 2006 Jae Yu 19 Relativistic Scattering Angles in Lab and CMS • For a relativistic scattering, the relationship between the scattering angles in Lab and CMS is: tan q Lab g CM sin qCM sin qCM CM • For Rutherford scattering (m=m1<<m2, v~v0<<c): dq 2 P 2 d cos q 2 Resulting in a cross section d 2 dq P 2d W 4 kZZ ' e 2 v2 2 1 q4 • Divergence at q2~0, a characteristics of a Coulomb field Monday, Sept. 11, 2006 PHYS 3446, Fall 2006 Jae Yu 20 Assignments 1. Extension of previous w/ the following (due 9/18): • 2. 3. • • 4. 5. • Plot the differential cross section of the Rutherford scattering as a function of the scattering angle q with some sensible lower limit of the angle + express your opinion on the sensibility of the cross section, along with good physical reasons Derive Eq. 1.55 starting from 1.48 and 1.49 Derive the formulae for the available CMS energy ( s ) for Fixed target experiment with masses m1 and m2 with incoming energy E1. Collider experiment with masses m1 and m2 with incoming energies E1 and E2. Reading assignment: Section 1.7 End of chapter problem 1.7 These assignments are due next Wednesday, Sept. 20. Monday, Sept. 11, 2006 PHYS 3446, Fall 2006 Jae Yu 21