ie575 exam 2.docx

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IE575 EXAM-II FALL 2013
MAX SCORE = 100 POINTS
One side of an 8.5”x11” formula sheet permitted; Calculator permitted
1. Discrete RV X is known to have the following transform:
2
8
6
1 1
1 1
1
1
1
๐‘€๐‘‹ (๐‘ ) = ๐พ ( + ๐‘’ 11๐‘  ) ( + e2๐‘  + ๐‘’ 4๐‘  ) ( e๐‘  + ๐‘’ 5๐‘  )
8 8
4 2
4
2
2
(a) Determine the numerical values of
(i)
K
(ii)
E[X]
(iii)
(iv)
(v)
δ๐‘‹2
๐‘ƒ๐‘‹ (0)
๐‘ƒ๐‘‹ (1)
For the remaining parts of this problem, you may use K, E[X], δ๐‘‹2 , ๐‘ƒ๐‘‹ (0), ๐‘ƒ๐‘‹ (1) as known
quantities. Do not substitute their numerical values.
(b) Discrete RV Y has the transform:
1
1 1 1
1
๐‘€๐‘Œ (๐‘ ) = ๐‘€๐‘‹ (๐‘ ) + ( + e๐‘  + ๐‘’ 2๐‘  )
2
2 3 3
3
Evaluate E[Y], δ2๐‘Œ , ๐‘ƒ๐‘Œ (1).
(c) Discrete RV V has the transform:
1
1
1
1
1
๐‘€๐‘‰ (๐‘ ) = ๐‘€๐‘‹ (๐‘ ) with e๐‘  replaced by (5 + 5 e๐‘  + 5 ๐‘’ 2๐‘  + 5 ๐‘’ 3๐‘  + 5 ๐‘’ 4๐‘  )
Evaluate E[V], δ2๐‘‰ .
2. RVs X and Y have the following joint PDF:
1
๐‘“๐‘‹,๐‘Œ (๐‘ฅ, ๐‘ฆ) = {2 ๐‘ฆ
0
๐‘“๐‘œ๐‘Ÿ 0 ≤ x < 1 and 0 ≤ y < 2
๐‘œ๐‘กโ„Ž๐‘’๐‘Ÿ๐‘ค๐‘–๐‘ ๐‘’
Event C is the event X>Y. It has probability P(C)=1/12.
(a) Determine and sketch the conditional PDF for X given C.
(b) Find the conditional expected value for X given both that C occurred and the
experimental value of Y is 0.5.
(c) Let T=max{X,Y} and find the PDF for T.
(d) Are X and Y independent? You need to substantiate your answer with appropriate
calculations.
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