Houston Community College System Chemistry 1411, Fall 2010 EXAM # 3 1 CHEM 1411 EXAM # 3 (Chapters 7, 8, 9, 10) Name:______________________________ Score: Directions- please answer the following multiple-choice questions next to each number. Please show all your work for bonus question and part(2) questions in the space provided. Part (1) - Multiple Choice - (3 points each) _____ 1. How many unpaired valence electrons are in phosphorus atom? A.7 B. 3 C. 5 D. 1 E.8 _____ 2. Which of the following molecules/ions is nonpolar? A. HCN B. HCl C. CO2 D. NH3 E. SO2 _____ 3. Determine the total number of sigma and pi bonds in the following molecular structure. H H O C C C H C H C C C C C A. 11 , 6 H B. 11 , 11 C. 16 , 6 H D. 16 , 11 E. none of these D. SO4- E. None of them _____ 4. Which of the molecule has 3 resonance structures ? A. SO2 C. PO3- B. NH3 _____ 5. Which of the following molecules has the bond order 1 ? A. O2 B. H2 C. H2- D. He2 _____ 6. According Molecular orbital theory what is the correct statement about Oxygen A. 2 unpaired electrons and diamagnetic B. 1 Unpaired electron and paramagnetic C. 2 unpaired electrons and paramagnetic D. 0 Unpaired electrons, diamagnetic E. None of them _____ 7. What kind or hybridization you can see in H2C=CH2 and CCl4 A. sp and sp3 C. sp and sp2 B. SP2 and SP2 D. sp2 and sp3 E. Cannot guess 2 E. B2- _____ 8. The configuration (σ1s)2(σ*1s)2 (σ2s)2(σ*2s)2 (π2p)2(π2p)2(σ2p)2 is the molecular orbital description for the ground state of A. Li2 B. B2 C. Be2 D. B22+ E. C22- D. 9 E. 0 _____ 9. How many electrons are present in π2p* of N2 molecule A. 1 B. 2 C. 3 _____ 10. Hydrogen bonding is predominant in the following molecules A) H2S B) CH2-CH2-O-H C) CH3-CH2-NH2 D) H3C-O-CH3 E) B and C _____11. Which of the molecule has more than octet electrons in central atom? A. NO2 B. SO2 C. CO2 D. PCl5 E. All of them ____ 12. Which one of the following ions has an octet of valence electrons? i. Cl+ ii. Al+2 iii. Cs+ iv. I- A. all of them B. none of them C. i & ii D. iii & iv E. ii alone _____ 13. Choose the correct order of ionization energy of the atoms, Ba, Br, Bi? A. Ba< Br < Bi B. Br < Bi < Ba C. Ba < Bi < Br D. Br < Ba<Bi E. Bi < Ba < Br _____ 14. What are the hybridization and the approximate bond angle of CH4? A. sp2, 104o B. sp3, 109.5o C. sp, 180o D. sp3d, 900 E. sp3d2, 180o _____ 15. The electron-pair geometry and molecular geometry of BH4- are respectively A. Tetrahedral, tetrahedral C. tetrahedral, trigonal pyramid E. octahedral, square planar B. tetrahedral, trigonal planar D. trigonal bipyramidal, see-saw _____ 16. Which of the following has bond order of 2? I. F2-2 A. I & III B. I & IV II. NO- III) O2 IV) N2 C. I only D. III Only E. II & III _____ 17. Which of the following can be expected to have relatively high boiling point? A. H-I B. H-Br C. H-Cl D. H-F 3 E. O2 _____ 18. Which of the following atoms cannot accommodate an excess of 8 electrons in Lewis structures where it is the central atom? A. C B. N C. O D. F E. all of them _____ 19. How many atoms/ions/molecules are assigned to Face centered cube A. 4 B. 2 C. 3 D. 1 E. 6 _____20. Choose from the molecules listed below, the one with the weakest intermolecular force A. H2O B. F2 C. H-Cl D. Cl2 E. NH3 Part (2) - Show all your work. ( 8 points each) 21. Draw Lewis dot (electron) structure for SF6 and determine a) Electron geometry F F b) molecular geometry c) polar or nonpolar F S F F Octahedral Non polar F Indicate 6 e- for each F 22. Use Molecular orbital theory to predict the following for NO- : a) Its molecular orbital configuration b) Its bond order c) Is it paramagnetic or diamagnetic? MO configuration (Same as N2 Model) (Total valence electrons = 12) ----- σ*2p ------ ------ π*2p ----- σ2p ------ Bond order 8 Bonding e4 Anti bonding e8-4/2 = 2 ------ π2p ----- σ*2s ----- σ2s 4 Magnetism Paramagnetic 23. The crystal of gold is Body centered cub. The edge length is 762 pm. Calculate the density of gold. Mass: Number of gold atoms in BCC are 2, 1 Mole Au = 197.0 g = 6.02 x 1023 Au atoms 2 Au atoms x 197.0g Au/6.02 x 1023Au atoms = 6.544 x 10-22 grams Au Volume: Length = 762 pm 1pm = 10-10 cm 762 pm x 10-10 cm/ 1pm = 7.62 x 10-8 cm Volume = length3 (7.62 x 10-8 cm)3 = 4.42 x 10-22 cm3 Density = m/v 6.543 x 10-22g/4.42 x 10-22 cm3 = 1.48g/cm3 24. Draw all the resonance structures of the nitrate ion, NO3- Follow the class notes to draw the dot structure: The resonance structures: 3 25. Consider the following three resonance structures of the thiosulfate ion, S2O3-2. a. Assign formal charges to all atoms in all three structures b. Pick the major structure based on the formal charges. S is less electronegative than O. .. .. :O: :O: :O-S-S: .. .. :O: .. Structure I :O: :O=S=S: :O=S-S: .. :O: :O: .. .. Structure II Structure III 5 6