TRANSMISSION MEDIA MAXWELL’S EQUATIONS AND TRANSMISSION MEDIA CHARACTERISTICS ENEE 482 Spring 2002 DR. KAWTHAR ZAKI MICROWAVE CIRCUIT ELEMENTS AND ANALYSIS Dielectric Two conductor wire Coaxial line Shielded Strip line ENEE482 2 Common Hollow-pipe waveguides Rectangular guide Circular guide ENEE482 Ridge guide 3 STRIP LINE CONFIGURATIONS W SINGLE STRIP LINE COUPLED LINES COUPLED STRIPS TOP & BOTTOM COUPLED ROUND BARS ENEE482 4 MICROSTRIP LINE CONFIGURATIONS TWO COUPLED MICROSTRIPS TWO SUSPENDED SUBSTRATE LINES SINGLE MICROSTRIP SUSPENDED SUBSTRATE LINE ENEE482 5 TRANSMISSION MEDIA • TRANSVERSE ELECTROMAGNETIC (TEM): – COAXIAL LINES – MICROSTRIP LINES (Quasi TEM) – STRIP LINES AND SUSPENDED SUBSTRATE • METALLIC WAVEGUIDES: – RECTANGULAR WAVEGUIDES –CIRCULAR WAVEGUIDES • DIELECTRIC LOADED WAVEGUIDES ANALYSIS OF WAVE PROPAGATION ON THESE TRANSMISSION MEDIA THROUGH MAXWELL’S EQUATIONS ENEE482 6 Electromagnetic Theory Maxwell’s Equations B E -M t D D ; H J t ; B 0 Continuity Equation : J t E Electric Filed Intensity V/m D Electric Flux Density C/m 2 B Magnetic Flux Density T (Telsa or V - Sec./m 2 ) H Magnetic Field Intensity A/m J Electric current density A/m 2 M Magnetic (fictitiou s) current density V/m 2 ENEE482 7 Auxiliary Relations: 1. F qE v B Newton q Charge ; v Velocity 2. J E (Ohm' s Law) Conductivi ty ; J Conduction Current 3. J v ; J Convection Current 4. D E r o E ; o 8.854 10 12 F/m r Relative Dielectric Constant 5. B H r o H ; o 4 10 12 H/m r Relative Permeabili ty ENEE482 8 Maxwell’s Equations in Large Scale Form D d S dv S V B dS 0 S l E d l t SB d S S M dS l H d l SJ d S t SD d S ENEE482 9 Maxwell’s Equations for the Time - Harmonic Case Assume e jt variations , then : E ( x, y, z , t ) Re[ E ( x, y, z )e jt ] E ( x, y, z ) a x ( E xr jExi ) a y ( E yr jE yi ) a z ( E zr jEzi ) E x Re[( E xr jExi )e jt ] Re[ E xr2 E xi2 e jt j ] E 2 xr E 2 xi cos(t ) , tan 1 ( E xi / E xr ) D , B 0 E j B M , H J j D ENEE482 10 Boundary Conditions at a General Material Interface 1,1 Et1 Et2 M s h Dn1 Dn2 s s Surface Charge Density Bn1 Bn2 E1t ; 2,2 E2t H t1 H t2 J s nˆ ( D1 D2 ) s Ds nˆ ( B1 B2 ) 0 D1n h nˆ ( E1 E2 ) M s D2n nˆ ( H1 H 2 ) J s ENEE482 11 Fields at a Dielectric Interface Et1 Et2 0 Dn1 Dn2 0 Bn1 Bn2 ; H t1 H t2 0 nˆ ( D1 ) nˆ ( D2 ) nˆ ( B1 ) nˆ ( B2 ) nˆ ( E1 ) nˆ ( E2 ) nˆ ( H1 ) nˆ ( H 2 ) ENEE482 12 Boundary Conditions at a Perfect Conductor : Et o n̂ E 0 D n ρ s nˆ D Bn 0 n̂ B 0 J s H t nˆ H Js s +++ n ENEE482 Ht 13 The magnetic wall boundary condition nˆ ( D ) 0 nˆ ( B ) 0 nˆ ( E ) M s nˆ ( H ) 0 ENEE482 14 Wave Equation E E ( E ) j H 2 j ( J jE ) For a Source free medium : 2 E k 2 E 0 H k H 0 2 2 ; ; k 2 2 k /v ENEE482 2 15 Plane Waves 2 2 2 E E E 2 2 E k 0 E 0 2 2 2 k 02 E x y z 2 Ei 2 E i 2 Ei 2 k 0 Ei 0 , i x, y , z 2 2 2 x y z Solve for E x ( x, y , z ), Using separation of variables k 2x k y2 k z2 k 02 jks x jk y y jkz z E x Ae r ax x a y y az z , Let k a x k x a y k y a z k z ENEE482 16 E x Ae jk r , E E 0 e jk r Similarly E y Be jk r , E z Ce jk r Since E 0 k E 0 0 The vector E 0 is perpendicu lar to the direction of propagatio n k. The solution is called plane wave E j 0 H H 1 j 0 E 0 e jk r 1 j 0 E 0 e jk r 1 0 k E 0 e jk r 0 1 nE n E Y0 n E nE 0 0 0 k0 0 is the interensic impedance of free space 377 Y0 is the intrinsic admittance of free space. ENEE482 17 z E H n y x H is perpendicular to E and to n. (TEM waves) E Re( E0 e jk r jt ) E0 cos( k r t ), if E0 is real k 0 0 2 , * 1 1 1 * * P Re E H n Re Y0 E ( n E ) n Y0 E0 E0 2 2 2 The time average energy densities in the electric and magnetic fields of a TEM wave are : * 1 1 * U e 0 E0 E0 , U m 0 H 0 H 0 U e 2 2 ENEE482 18 Plane Wave in a Good Conductor j j s 1 j (1 j) 2 j 2 1 (1 j ) (1 j) s 2 ENEE482 19 Boundary Conditions at the Surface of a Good Conductor The field amplitude decays exponentially from its surface According to e-u/s where u is the normal distance into the Conductor, s is the skin depth s 2 , J E The surface Impedance : 1 j Zm , Et Z m J s Z m n̂ H s ENEE482 20 Reflection From A Dielectric Interface Parallel Polarization Er 0 x n2 q2 n3 q3 q1 Et z n1 E ijk n r Ei E1e 0 1 1 , H i Y0n1 Ei Er E2e jk0n2 r1 , H r Y0n2 Er k0 0 0 , Y0 0 ENEE482 21 E t E 3e jk n3 r1 Y nY0 , H t Y n3 Et , k k0 , n k0n1 x k0n2 x kn3 x nk0n3 x n1 a x sin q1 a z cos q1 n2 a x sin q 2 a z cosq 2 n3 a x sin q 3 a z cos q 3 q1 q 2 sin q1 n sin q 3 E1 x E1 cos q1 , E1z E1 sin q1 E2 x E2 cos q 2 , E1z E2 sin q 2 E3 x E3 cos q 3 , E1z E3 sin q 3 ENEE482 22 Energy and Power Under steady-state sinusoidal time-varying Conditions, the time-average energy stored in the Electric field is 1 1 * We Re E D dV E E * dV 4V 4V If is constant and real, then We E E 4 * dV V ENEE482 23 Time average energy stored in the magnetic field is : 1 * Wm Re H B dV 4V 4 * H H dV if is real and constant V The time average power tran smitted across a closed surface S is given by : 1 P Re E H * dS 2 S ENEE482 24 Poynting Theorem E H * ( E ) H * ( H * ) E ( jB M ) H * jD * E E J * J J s E 1 1 * * E H d V E H dS 2V 2S 1 j ( B H * E D * )dV ( E J * H * M s )dV 2V 2V B H * E D* 1 * * 2 j dV ( E J H M s )dV 4 4 2V V ENEE482 25 If the medium is characteri zed by : - j and conductivi ty j , 1 1 * - ( E J Ss H M S )dV E H * dS 2S 2V 1 * * * E E dV ( H H E E )dV 2V 2V j * * )dV E E H H ( 2V 1 P0 E H * dS ENEE482 2S 26 P * * ( H H E E )dV 2V 1 * E E dV 2V Time average power loss 1 * Ps ( E J s H s M s )dV 2V * * 1 H H E E * dV Im E H dS 2 2S 4 4 V 2 (Wm We ) Ps P0 P 2 j (Wm We ) The power delivered by the sources (Ps ) is equal to the sum of the power tran smitted through t he surface P0 , the power lost to heat in the volume ( P ) and 2 times the reactive energy stored in the volume. ENEE482 27 Circuit Analogy I L R C V 1 * 1 1 j VI ZII * II * ( R jL ) 2 2 2 C * 1 1 1 II RII * 2 j ( LII * ) 2 2 4 4 C P 2 j (Wm We ) P 2 j (Wm We ) Z 1 * II 2 General Definitio n of the impedance of a network ENEE482 28 Potential Theory Let B A , E jA 0 , E jB j A E jA E jA 1 H A jE J 2A j J A A 2 A k 2 A j J , k 2 2 , Let A j or A j (Lorentz condition) 2 A k 2 A J Inhomogene ous Helmholtz equation. D 0 k 2 2 ENEE482 29 Solution For Vector Potential J (x’,y’, z’) R (x,y,z) r’ r e jkR A ( x, y , z ) A ( r ) J ( r ) dV for an infinitism al current 4 R R ( x x ) 2 ( y y ) 2 ( z z ) 2 r r A(r ) 4 V e jkR J ( r ) dV R ENEE482 30 Waves on An Ideal Transmission Line Rg z Lumped element circuit model for a transmission line I(z,t) V(z,t) Ldz I(z,t)+I/z dz Cdz V(z,t)+v/z dz ENEE482 31 2V ( z, t ) 2V ( z, t ) LC 0 2 2 z t 2 I ( z, t ) 2 I ( z, t ) LC 0 2 2 z t 1 v LC z z V ( z, t ) V f (t ) V f (t ) v v z z I ( z , t ) I f (t ) I f (t ) v v V V L I , I , Zc Zc Zc C Z c : Characteri stic Impedance ENEE482 32 Steady State Sinusoidal Waves V g (t ) V g cos t V ( z ) jLI ( z ) z I ( z ) jCV ( z ) z d 2V ( z ) 2 2 V ( z) 0 , 2 v dz v V ( z ) V e jz V e jz I ( z ) I e jz I e jz , I YcV , I YcV 1 L Zc Yc C , LC ENEE482 33 Transmission Line Parameters Let the voltage between th e conductors be : V0 e jz and the current be I 0 e jz . The time - average stored magnetic energy for 1 m section of line : L Wm H H dS I 0 4S 4 * C We E E dS V0 4S 4 * 2 C1 2 C2 S Power loss per unit length due to finite conductivi ty of the conductor is Rs Pc 2 C1 C 2 H H d R I 0 / 2, Pd * 2 ENEE482 2 E E S * dS G V0 34 2 2 Terminated Transmission Line To generator Zc ZL Z V V V VL VL 1 I I I IL (V V ) ZL Z c V L Reflecti on coefficien t V 1 L Z L Z L / Zc 1 , L 1 L Z c Z L / Zc 1 ENEE482 35 1 1 * 2 P Re(VL I L ) Re Yc V (1 L )(1 L )* 2 2 1 2 2 Yc V (1 L ) 2 V V e jz LV e jz V e jz e jq V e jz , L e jq q 2 V V 1 4 sin 2 ( l ) 2 1 S 1 Z Z jZ c tan Z in in L Z c Z c jZ L tan ENEE482 1/ 2 36 Transmission Lines & Waveguides Wave Propagation in the Positive z-Direction is Represented By:e-jz E x, y , z E t x, y , z E z x, y , z et x, y e jz ez x, y e jz H x, y , z H t x, y , z H z x, y , z ht x, y e jz hz x, y e jz E ( t ja z ) ( et ez )e jz j ( ht hz )e jz t e ja z e t ez ja z ez j ( ht hz )e jz t et jhz , t ht jez t ht jhz , t et jez ENEE482 37 Modes Classification: 1. Transverse Electromagnetic (TEM) Waves Ez H z 0 2. Transverse Electric (TE), or H Modes Ez 0 but H z 0 , 3. Transverse Magnetic (TM), or E Modes Hz 0 , But Ez 0 , Ez 0 4. Hybrid Modes Hz 0 ENEE482 38 TEM WAVES t ht 0 t et 0 , , t ht 0 , t et 0 â z e t 0 h t â z h t 0 e t e x, y t x, y 0 Scalar Pot ential t x, y 0 2 Et et e jz t ( x, y )e jz H t ht e jz Y0 aˆ z e e jz ENEE482 39 1 Y0 Z0 0 Wave Impedance , Ey Ex 0 Hy Hx for wave propagatio n in the or - z direction The field must satisfy Helmholtz equation : 2 Et k 02 Et 0 , but t j a z t2 Et (k 02 ) Et 0 , , 2 t2 2 t [ t2 (k 02 ) ] 0 k 0 for TEM waves ENEE482 40 TE WAVES 2 H k 2 H 0 ( t 2 )hz ( x, y ) k 2 hz 0 2 t ( k 2 2 )hz 0 , let k c2 k 2 2 2 t h z k c2 hz 0 2 t et j hz , a z et ht t ht 0 , a z t hz ja z ht je t ht jhz , t et 0 ENEE482 41 j ht 2 t hz kc 0 k et aˆ z ht Z 0 aˆ z ht ; Zh k 0 0 Wave Impedance ey ex Zh hy hx ENEE482 42 TM WAVES 2 E k 2 E 0 ( t 2 )e z ( x, y ) k 2 e z 0 2 t e z ( k 2 2 )e z 0 , 2 let k c2 k 2 2 t e z k c2 ez 0 2 j et 2 t ez kc ht Ye aˆ z e Ye k Y0 Wave Admittance ENEE482 43 TEM TRANSMISSION LINES Parallel -plate Two-wire ENEE482 Coaxial 44 COAXIAL LINES a b 1 1 2 (r ) 2 0 for 0 2 r r r r C1 ln r C2 V0 at r a, 0 at r 0 ln( r / b) V0 ln( a / b) V0 E a r e - jkz r ln( b / a ) Y0 and ENEE482 V0 H Y0 a e - jkz r ln( b / a ) 45 V0 J s nˆ H aˆ r H Y0 aˆ z e - jkz a ln( b / a ) 2 V0 2V0 - jkz - jkz I Y0 ade Y0 e a ln( b / a ) 0 ln( b / a ) b 2 2 Y V 1 0 0 P Re E H * aˆ z rdrd 2 ln( b / a ) a 0 • THE CHARACTERISTIC IMPEDANCE OF A COAXIAL IS Z0 V0 1 b Zc ln Ohms I 0 2Y0 a ENEE482 46 Zc OF COAXIAL LINE AS A FUNCTION OF b/a 10 X ENEE482 = 260 240 220 200 180 160 140 120 100 80 60 40 20 1 0 b/a 100 r Zo 47 Transmission line with small losses k k 0 ( r j r)1 / 2 r ( r j r) 0 and Y Y0 ( r j r)1 / 2 For small losses rk 0 r 1 / 2 jk j j r k 0 (1 j ) j r k 0 r 2 r rk 0 2 r , E t e jkz Y r Y0 r k 0 , H Yaˆ z E , k k 0 r r is equivalent to the conductivi ty J E ENEE482 48 The power loss per unit length is : * 1 * P J J dS E E dS 2 S 2 S P P0 e z P , P 2P z * Y P E E dS , 2S r d k0 2Y 2Y0 r 2 r The power loss due to the conductor loss : Zm 1 j s Rm 1 * , P Re Z m J s J s d 2 2 S1 S2 1 Re E H * dS 2 RmY b a c 2 ln( b / a ) ab H H s d * s S1 S2 P , Y Y0 0 ENEE482 49 Qc OF COAXIAL LINE AS A FUNCTION OF Zo 3000 2800 2600 2400 2200 180 170 160 150 140 130 120 110 100 90 80 70 60 50 40 30 20 2000 10 Qc b f GHz 3200 0 Q-Coppe r of Coa xia l Line 3400 r Z c ENEE482 50 TEM Modes t2 ( x, y ) 0 Parallel Plate Waveguide 0 x w, y 0yd (x, y) A By d (x,0) 0, (x, d) V0 x w V0 y V0 ( x, y ) , e ( x, y ) t yˆ d d V0 jkz jkz E ( x, y ) e ( x, y ) e yˆ e d d V0 jkz H ( x, y ) zˆ E xˆ e , V E y dy V0 e jkz 0 d w w wV0 jkz I J s zˆdx ( yˆ H ) zˆdx e 0 0 d ENEE482 51 TM modes 2 2 k c e z ( x, y ) 0 y e z ( x, y ) A sin k c y B cos k c y 2 e z ( x, y ) 0 at y 0, d , k c d n , n 0,1,2,3,.... B0 n 2 K ( ) d n e z ( x, y ) An sin y d n E z ( x, y, z ) An sin y e - jz d j n H x ( x, y , z ) An cos y e - jz kc d 2 ENEE482 52 j n E y ( x, y , z ) An cos y e - jz , E x H y 0 kc d fc kc 2 2d The wave impedance of the TM modes is : Z TM H x k 2 vp , g Ey 1 w d 1 w d * P0 E H zˆdydx E y H x* dydx 2 x 0 y 0 2 x 0 y 0 2 Re( )d An for n 0 2 4k c Re( )d 2 A for n 0 n 2 2k c ENEE482 53 Attenuatio n due to conductor loss P c 2 P0 2 2 2 Rs w Rs w P 2 J s dx An 2 x 0 kc 2 2Rs 2kRs c Np/m for n 0 d d ENEE482 2 54 TE Modes 2 2 k c hz ( x, y ) 0 y hz ( x, y ) A sin k c y B cos k c y 2 e x ( x, y ) 0 at y 0, d , k c d n , n 1,2,3,.... A0 n 2 k ( ) d n hz ( x, y ) Bn cos y d n H z ( x, y, z ) Bn cos y e - jz d j n E x ( x, y , z ) Bn sin y e - jz kc d 2 ENEE482 55 j n H y ( x, y , z ) Bn sin y e - jz , E y H x 0 kc d fc kc 2 2d The wave impedance of the TM modes is : E x k Z TE Hy vp , g 2 1 w d 1 w d * P0 E H zˆdydx E x H *y dydx 2 x 0 y 0 2 x 0 y 0 dw 2 B Re( ) For n 0 n 2 4k c 2k c2 Rs c kd Np/m ENEE482 56 COUPLED LINES EVEN & ODD MODES OF EXCITATIONS AXIS OF EVEN SYMMETRY AXIS OF ODD SYMMETRY P.M.C. P.E.C. ODD MODE ELECTRIC FIELD DISTRIBUTION EVEN MODE ELECTRIC FIELD DISTRUBUTION Z 0o =ODD MODE CHAR. Z 0e =EVEN MODE CHAR. IMPEDANCE IMPEDANCE Equal &opposite currents are flowing in the two lines Equal currents are flowing in the two lines ENEE482 57 WAVEGUIDES • HOLLOW CONDUCTORS RECTANGULAR OR CIRCULAR. • PROPAGATE ELECTROMAGNETIC ENERGY ABOVE A CERTAIN FREQUENCY (CUT OFF) • INFINITE NUMBER OF MODES CAN PROPAGATE, EITHER TE OR TM MODES • WHEN OPERATING IN A SINGLE MODE, WAVEGUIDE CAN BE DESCRIBED AS A TRANSMISSION LINE WITH C/C IMPEDANCE Zc & PROPAGATION CONSTANT ENEE482 58 WAVEGUIDE PROPERTIES • FOR A W/G FILLED WITH DIELECTRIC r : r 1 1 2 2 2 2 1 g c 1 WHER E 1 IS WAVELENG TH IN DIELECTRIC IS WAVELENGT H IN FREE SPACE g IS GUIDE WAVELENG TH C IS CUT OFF WAVELENGT H WAVE IMPEDANCE Z w IS : ZW 377 g 1 r FOR TE MODES FOR TM MODES 377 r 1 g ENEE482 59 • PROPAGATION PHASE CONSTANT: 2 RADIANS/UN IT LENGTH g • FOR RECTANGULAR GUIDE a X b, CUTOFF WAVELENGTH OF TE10 MODES ARE: 11.8 C 2a , fc r c fc : CUT OFF FREQUENCY IN GHz (c INCHES): • FOR CIRCULAR WAVEGUIDE OF DIAMETER D CUTOFF WAVE LENGTH OF TE11 MODE IS: c 1.706 D • DOMINANT MODES ARE TE10 AND TE11 MODE FOR RECTANGULAR & CIRCULAR WAVEGUIDES ENEE482 60 RECTANGULAR WAVEGUIDE MODE FIELDS y b z x a CONFIGURATION ENEE482 61 TE modes 2 2 2 2 2 k c hz ( x, y ) 0 y x k c2 k 2 2 hz ( x, y ) X ( x)Y ( y ) 1 d 2 X 1 d 2Y 2 k c 0 2 2 X dx Y dy 1 d2X 2 k x 2 X dx 1 d 2Y 2 , k y 2 Y dy k x2 k y2 k c2 hz ( x, y ) ( A cos k x x B sin k x x)(C cos k y y D sin k y y ) mx ny jz H z ( x, y, z ) Amn cos cos e a b ENEE482 62 TEmn MODES mx ny H z cos( ) cos( ) e jz , E z 0 a b Ex Zh H y , E y Z h H x m Hx j ak c2 Hy j Zh n bk c2 mx ny sin( ) cos( ) e jz a b m ny cos( ) sin( ) e jz a b k Z0 m 2 n 2 ) ( ) a b 2ab c ( m 2 b 2 n 2 a 2 )1 / 2 k 2c ( ; 2 k 2 k c2 ; f cmn kc 2 1 2 ENEE482 m 2 n 2 ( ) ( ) a b 63 The dominant mode is TE10 x j z H z A10 cos e a j a x j z Ey A10 sin e a j a x j z Hx A10 sin e a Ex Ez H y 0 kc / a , k 2 ( / a) 2 a A10 b 1 * ˆ P10 Re E H zdydx Re( ) 2 x 0 y 0 2 4 2 Rs a 2 a3 2 P J s d Rs A10 (b ) 2 2 C 2 2 a b Rs c 3 (2b 2 a 3 k 2 ) Np/m a b k ENEE482 3 2 64 TMmn MODES mx ny E z sin( ) sin( ) e jz a b Hz 0 H x E y /Z e Ex j Ey j Ze 2 m ak c2 n bk c2 Z 0 k k 2 mx ny cos( ) sin( ) e jz a b m sin( ) a 2 c ny cos( ) e jz b m 2 n 2 k ( ) ( ) a b 2 c ; k H y E x / Ze , ; 2ab c ( m 2 b 2 n 2 a 2 )1 / 2 ENEE482 65 TE Modes of a Partially Loaded Waveguide y TE m0 have no y - variation and the structure is uniform in the y-direction 2 2 2 kd hz 0 for 0 x t x 2 2 x 2 ka hz 0 for t x a x kd , ka are the cutoff wavenumbers for dielectric and air regions r k02 kd2 k02 ka2 A cos kd x B sin kd x hz C cos ka (a x) D sin k a (a x) ENEE482 for 0 x t for t x a 66 j 0 k [ A sin k d x B cos k d x] ey d j 0 [C sin k a (a x) D cos k a (a x) k a for 0 x t for t x a To satisfy th e Boundary conditions that E y 0 at x 0 and x a B D 0 , (E y , H x ) are continuous at x t A C sin k d t sin k a (a t ) kd ka A cos k d t C cos k a (a t ) k a tan k d t k d tan k a (a t ) 0 This is the characteri stic equation t hat can yields to ENEE482 67 CIRCULAR WAVEGUIDE MODES y r a z ENEE482 x 68 TE Modes 2 H z k 2 H z 0 H z ( , , z ) hz ( , )e jz 2 1 1 2 2 2 2 k c hz ( , ) 0 2 hz ( , ) R ( ) ( ) 1 d 2R 1 dR 1 d 2 2 k c 0 2 2 2 R d R d d 1 d 2 2 k d 2 d 2 2 , k 0 2 d 2 d R dR 2 2 2 2 ( k k c )R 0 2 d d ENEE482 69 ( ) A sin n B cos n , k2 n 2 2 d R dR 2 2 2 2 ( k n )R 0 c 2 d d Bessel' s Different ial equation. The solution is : R( ) CJ n ( k c ) DY n ( k c ) J n ( k c ), Yn ( k c ) are the Bessel function of first and second kinds. Yn ( k c ) is infinite at 0 D 0 h z ( , ) ( A sin n B cos n ) J n ( k c ) The boundary condition E ( , ) 0 at a j E ( , , z ) ( A sin n B cos n ) J n ( k c )e jz kc ENEE482 70 J n ( kc a ) 0 )0 , J n ( pnm mth root of J n pnm 2 pnm pnm 2 2 2 kcnm , nm k kc k ( ) a a kc pnm f cnm 2 2a jn jz E ( A cos n B sin n ) J ( k ) e n c 2 kc E j ( A sin n B cos n ) J n ( kc )e jz kc j H ( A sin n B cos n ) J n ( kc )e jz kc H jn jz ( A cos n B sin n ) J ( k ) e n c kc2 ENEE482 71 E Z TE H E H k Dominant Mode is TE 11 H z A sin J1 (kc )e jz j E 2 A cos J1 (kc )e jz kc j E A sin J1(kc )e jz kc H j A sin J1(kc )e jz kc j H 2 A cos J1 (kc )e jz kc Ez 0 ENEE482 72 TEnm MODES pnm H z Jn a Ez 0 e jz cos( n ) sin( n ) H J n ( pnm / a ) jz jpnm e 2 ak c H / a ) jz jnJ n ( pnm e 2 rk c E Z h H cos( n ) sin( n ) sin( n ) cos( n ) E Z h H ; is the m' th zeros of Jn ( x ) pnm /a Z h kZ0 / ; k c pnm 2 k 2 k c2 ; c 2a / pnm ENEE482 73 TMnmMODES pnm Ez J n a Hz 0 e jz cos( n ) sin( n ) / a ) jz jpnm J n ( pnm E e 2 ak c cos( n ) sin( n ) sin( n ) cos( n ) H E / Z e jnJ n ( pnm / a ) jz E e 2 rk c H E /Z e ; pnm is the m' th zeros of J n ( x ) Z e Z 0 /k 2 k 2 k c2 k c pnm / a ; ; c 2a / pnm ENEE482 74 Cutoff frequencies of the first few TE And TM modes in circular waveguide TE11 0 TE21 TE01 TE31 1 fc/fcTE11 TM01 TM11 ENEE482 TM21 75 ATTENUATION IN WAVEGUIDES • ATTENUATION OF THE DOMINANT MODES (TEm0) IN A COPPER RECTANGULAR WAVEGUIDE DIM. a X b, AND (TE11) CIRCULAR WAVEGUIDE, DIA. D ARE: c (TE c (TE m0) 11 ) 1.9 x10 4 r b 2b f 2 c 1 a f f dB/unit length 2 fc 1 f 3.8 x10 4 r D f 2 c 0.42 f f dB/unit length 2 f 1 c f WHERE f IS THE FREQUENCY IN GHz ENEE482 76 ATTENUATION IN COPPER WAVEGUIDES DUE TO CONDUCTOR LOSS Alfa*a/Sqrt(epsr*f(GHz)) dB (GHz)^(-1/2) 0.0020 Alfa TE0m;b/a=.45 Alfa TEm0;b/a=.5 0.0018 Alfa Circ. TE11 0.0016 a a 0.0014 b 0.0012 E E Rectangular Guide 0.0010 Circular Guide 0.0008 0.0006 0.0004 0.0002 0.0000 1 1.2 1.4 1.6 1.8 2 2.2 (f/fc) ENEE482 77 Higher Order Modes in Coaxial Line TE Modes: hz ( , ) ( A sin n B cos n )( CJ n (kc ) DYn ( kc )) Boundary conditions E ( kc ) 0 at a, b CJ n (kc a ) DYn(kc a ) 0 CJ n (kcb) DYn(kcb) 0 J n (kc a )Yn( kcb) J n ( kcb)Yn(kc a ) This is the characteri stic equation to solve for kc ENEE482 78 Grounded Dielectric Slab x d z Dielectric Ground plane TM Modes Assume e -jz variation 2 2 2 2 r k 0 ez ( x, y ) 0 for 0 x d x 2 2 2 2 k 0 ez ( x, y ) 0 for d x x E z ( x, y, z ) ez ( x, y )e - jz Let kc2 r k02 2 , h 2 2 k02 ENEE482 79 ez ( x, y ) A sin kc x B cos kc x for 0 x d ez ( x, y ) Ce hx De hx for d x Boundary conditions are : E z(x,y,z) 0 at x 0 E z(x,y,z) at x E z(x,y,z) continuous at x d H y(x,y,z) continuous at x d H x Ey H z 0 B0 , C 0 A sin kc d De hd kc tan kc d r h , r A D hd cos kc d e kc h kc2 h 2 ( r 1)k02 Solving the two equations kc , h. ENEE482 80 Stripline y w b x z Approximate Electrostatic Solution: y b/2 t ( x, y ) 0 2 ( x, y ) 0 -a/2 0 a/2 at x a / 2 & y 0, b ENEE482 81 nx ny An cos a sinh a for 0 y b/2 ( x, y ) n 1 Bn cos nx sinh n (b y ) for b/2 y b n 1 a a Potential must be continuous at y b/2 An Bn Ey y nx ny n A cos cosh for 0 y b/2 n a a a E y n 1 An n cos nx cosh n (b y ) for b/2 y b n 1 a a a ENEE482 82 1 for x w / 2 Let s ( x) for x w / 2 0 s ( x ) D y ( x, y b / 2 ) D y ( x, y b / 2 ) n n nb 2 0 r An ( ) cos cosh a a 2a n 1 odd 2a sin( nw / 2a ) (n ) 2 0 r cosh( nb / 2a ) An V b/2 0 nb E y ( x 0, y )dy An sinh 2a n 1 odd Q w/ 2 w / 2 s dx w ENEE482 83 Q C V w nb 2a 2 ( n ) 0 r cosh( nb / 2a) n 1 2a sin( nw / 2a ) sinh odd r L 1 Z0 C v p C cC Z 0 is the characteri stic impedance ENEE482 84 Microstrip y w d vp -a/2 , k0 e c e a/2 x e is the effective dielectric constant. 1 e r An Approximat e Electrosta tic solution t ( x, y ) 0 2 ( x, y ) 0 at x a / 2 , ( x, y ) 0 at y 0, ENEE482 85 nx ny A cos sinh for 0 y d n a a n 1 ( x, y ) ny n x Bn cos e a for d y n 1 a nx Potential must be continuous at y d An sin Bn e a Ey y nd a nx ny n An cosh for 0 y d cos a a a n 1 Ey An n cos nx sinh n (d e- n (y - d)/a for d y n 1 a a a ENEE482 86 1 for x w / 2 Let s ( x) for x w / 2 0 s ( x ) D y ( x, y d ) D y ( x, y d ) n n 2 0 An ( ) cos a a n 1 nd nd sinh a r cosh a odd 4a sin( nw / 2a ) An (n ) 2 0 [sinh( nd / a ) r cosh( nd / a ) V d 0 nd E y ( x 0, y )dy An sinh a n 1 odd Q w/ 2 w / 2 s dx w ENEE482 87 Q C V 1 nd 2a sin( nw / 2a ) sinh a 2 ( n ) w 0 r [sinh( nd / a ) r cosh( nd / a ) n 1 odd C Capacitanc e per unit length of the microstrip line with a dielectric constant r C 0 Capacitanc e per unit length of the microstrip line with an air dielectric ( r 1) C e C0 e 1 Z0 v pC cC Z 0 is the characteri stic impedance ENEE482 88 The Transverse Resonance Technique For a resonant line, at anypoint on the line, The input impedances seen looking to either side must be zero Zinr ( y ) Zin ( y ) 0 for all y TM Modes for the parallel plate waveguide y y d d 0 w Zinr ( y) Zin ( y) x ENEE482 89 Z0 ZTM k y / k k Z inr ( y ) jZTM tan k y (d y ) Z in ( y ) jZTM tan k y y Condition for transv erse resonance jZTM [tan k y (d y ) tan k y y ] 0 jZTM sin k y y cos k y (d y ) cos k y y n kc k y d 0 for n 0,1,2,.. ENEE482 90 MODES IN DIELTECTRIC LOADED WAVEGUIDE b er1 a er 2 CATEGORIES OF FIELD SOLUTIONS: • TE0m MODES • TM0m MODES • HYBRID HEnm MODES ENEE482 91 BOUNDARY CONDITIONS FIELDS SATISFY THE WAVE EQUATION, SUBJECT TO THE BOUNDARY CONDITIONS Ez , E , Hz , H ARE CONTINUOUS AT r=b Ez , E VANISH AT r=a E z AJ n (1r ) cos n for 0 r a j H z AJ n (1r ) sin n Er 1 J n (1r ) / 1r jH A cos n n n k 2 / 2 J ( r ) n 1 1 1 E J n (1r ) / 1r jH A sin n n r nk 2 / 2 J ( r ) n 1 1 1 ENEE482 92 for a r b E z An Rn ( 2 r ) cos n j H z APn ( 2 r ) sin n Er P ( r ) / r n 1 A cos n n 2 1 jH 2 2 2 n k 2 / Rn ( 2 r ) E Rn ( 2 r ) / 1r jH A sin n n r 2 2 P ( r ) nk / 2 2 n 2 WHERE A IS AN ARBITRARY CONSTANT ENEE482 93 Characteristic equation Gn U n2 k02 a 2VnWn 0 Where z=1a is the radial wave number in 12 k12 2 ; k12 r1k 02 ; 22 ( k 22 2 ) k 22 r 2 k 02 ; k 02 0 0 1 1 U n nJ n (1a ) 2 2 2 2 2a 1 a J ( a ) P ( a ) Vn n 1 n 2 ( 2 a ) (1a ) ENEE482 94 J n (1a ) Rn ( 2 a ) r2 Wn r1 a a 2 1 K n ( 2 r ) I n ( 2 b) I n ( 2 r ) K n ( 2 b) Pn( 2 r ) J n (1a ) K n ( 2 a ) I n ( 2 b) I n ( 2 a ) K n ( 2 b) K n ( 2 r ) I n ( 2 b) I n ( 2 r ) K n ( 2 b) Rn ( 2 r ) J n (1a ) K n ( 2 a ) I n ( 2 b) I n ( 2 a ) K n ( 2 b) ENEE482 95 For n = 0, the Characteristic Equation Degenerates in two Separate Independent Equations for TE and TM Modes: J ( a ) P ( a ) Vn n 1 n 2 0 ( 2 a ) (1a ) For TE Modes And: J n (1a ) Rn ( 2 a ) Wn r1 r2 0 1 a 2a For TM Modes ENEE482 96 COMPLEX MODES • COMPLEX PROPAGATION CONSTANT : j • ONLY HE MODE CAN SUPPORT COMPLEX WAVES • PROPAGATION CONSTANT OF COMPLEX MODES ARE CONJUGATE : j • COMPLEX MODES DON’T CARRY REAL POWER • COMPLEX MODES CONSTITUTE PART OF THE COMPLETE SET OF ELECTROMAGNETIC FIELD SPACE • COMPLEX MODES HAVE TO BE INCLUDED IN THE FIELD EXPANSIONS FOR CONVERGENCE TO CORRECT SOLUTIONS IN MODE MATCHING TECHNIQUES. ENEE482 97 OPTICAL FIBER 2a IN CIRCULAR CYLINDRICAL COORDINATES: 1 Step-index fiber 2 E z 1 E z 1 2 E z 2 2 ( k ) E z 0 ; i 1 for r a, i 2 2 2 r r r r i 0 for r a ra ra cos n E z1 AJ n ( k c1r ) sin n cos n AK n ( k c 2 r ) sin n ; E z2 sin n H z1 BJ n ( k c1r ) cos n ; H z2 k c1 ( k 12 2 )1 / 2 ; k c 2 ( k 02 2 )1 / 2 ENEE482 sin n BK n ( k c 2 r ) cos n 98 For the symmetric case n=0, the solution break into Separate TE and TM sets. The continuity condition for Ez1= Ez2 and H1= H2 at r=a gives for the TM set: J 1 ( k c1 a ) 0 k c1 a K 1 ( k c 2 a ) J 0 ( k c1 a ) 1k c 2 a K 0 k c 2 a The continuity condition for Hz1= Hz2 and E1= E2 at r=a gives for the TE set: J 1 ( k c1a ) k c1 K1 ( k c 2 a ) J 0 ( k c1a ) k c 2 K 0 k c 2 a If n is different from 0, the fields do not separate into TM and TE types, but all the fields become coupled through continuity conditions. ENEE482 99 Parallel Plate Transmission Line y c a Assume e jz b x Partially loaded parallel Plate waveguide variation , no variation with x 2 2 k in the air region 0 2 2 2 TM modes : t ez k c ez 0 , k c 2 2 k in the dielectric region for air region p Let k c for the dielectric region ENEE482 100 2 p 2 ( r 1)k 02 d 2 ez 2 ez 0 2 dy for 0 y a d 2 ez 2 p ez 0 for a y b 2 dy ez ( y ) 0 at y 0, b , e z ( y ) is continuous at y a H x is continuous at y a ey ( y) j 2 j p2 ez y e z y r ez 2 y y a 1 ez 2 p y y a For dielectric region for air region ENEE482 101 j r k 0Y0 e z 2 y hx ( y ) jk Y ez 02 p y e z ( y ) C1 sin y e z ( y ) C 2 sin p (b y ) For dielectric region for air region 0 ya a yb C1 sin a C 2 sin pc r 1 C1 cos a C 2 cos pc p tan a r p tan pc Transceden tal equation must be solved simultaneo usly with 2 p 2 ( r 1) k 02 ENEE482 , p 102 k 02 p 2 k 2 l 2 Most of the modes will be nonpropaga ting if is imaginary The variation is e z and the field decays exponentia lly. The value of between k 0 and k can occur if p jp0 Let 0 to be the correspond ing value of then : 0 tan 0 a r p0 tan p0 c 20 p02 ( r 1)k 02 ENEE482 103 Low Frequency Solution When the frequency is low, k 02 is very small number , 0 and p0 are very small 0 a r p02 c 2 ( r 1) k 02 p02 r p02 c a 2 ( 1 ) k 2 r 0a or p0 The solution for is a rc k p0 2 0 2 rb k0 e k0 a rc e is the effective dielectric constant ENEE482 104 y c b a x -W e LC W L, C are the static inductance and capacitanc e per meter. The time average stored magnetic energy is Wm 0 0 1 2 Wm H dxdy WbJ LI z 0 w 4 2 4 b I z 2WJ z L 0 2W b w 2 x 2 z ENEE482 105 C2 C1 sin 0 a / j sinh p0 c jC1 0 a / p0 c 0 ya ez C1 0 y j b ey C1 jC1 0 ( r 1)c j r k 0Y0 ( r c a ) r hx C1 jY0C1 0 ( r 1)c Ca Cd 0 2W 0 r 2W The capacitanc e C , Ca , Cd Ca Cd c a 0 r 2W C rc a 0 r 0 b LC rc a LC ENEE482 106 The capacitanc e C 0 r 2W C rc a 0 r 0 b LC rc a Ca Cd Ca Cd , Ca 0 2W c , Cd 0 r 2W a LC Field expression s : C2 C1 sin 0 a / j sinh p0 c jC1 0 a / p0 c 0 ya ez C1 0 y ey j b C1 jC1 0 ( r 1)c ENEE482 107 j r k 0Y0 ( r c a ) r hx C1 jY0C1 0 ( r 1)c In the air region : (b y ) e z C1 0 a c j 0 a b e y 2 C1 jC1 r ( r 1)c p0 c hx j k 0Y0 0 C1 jY0C1 b V e y dy jC1 0 ( r c a ) r ( r 1)c b (a r c) ( r 1)c I z 2WJ z 2WH x ENEE482 108 The characteri stic impedance is : Z0 V Zc I 2W ( a r c )b r L C In the low frequency limit, the dominant mode of propagatio n becomed a TEM mode (quasi - TEM mode) At hight frequency the mode of propagatio n is an E mod ENEE482 109 High Frequency Solution: At high frequency k 0 and 0 , p0 are large. tanh p0 c 1 0 tanh 0 a r p0 r ( r 1)k 02 20 20 p02 ( r 1)k 02 The solution is independen t of b e z ( y ) C1 sin 0 y for 0 y a sinh p0 (b y ) e z ( y ) C 2 j sinh p0 (b y ) C1 sin 0 a sinh p0 (b a ) e p0 ( b y ) C1 sin 0 a p0 ( ba ) C1 sin 0 ae p0 ( y a ) for a y b e The field decays exponentia lly away from the air - dielectric surface and does not depend on b as long as p0 c p0 (b a ) is large. The field is guided by the dielectric sheet. This type of mode is called surface ENEE482 110 wave mode. Microstrip Transmission Line w y H x ( x, y , z ) s ( x, z ) ( y H ) J ( x, y , z ) J s ( x, z ) ( y H ) B A, E jB j A E jA H jD J For anisotropi c dielectric : D 0 r ( E x aˆ x E z aˆ z ) 0 y E y aˆ y ENEE482 111 A A 2 A j 0 D 0 J D 0 r [ j ( Ax aˆ x Az aˆ z ) aˆ x aˆ z ] x z 0 y ( jAy aˆ y aˆ y ) y let A j 0 r 0 (Lorentz condition) - 2 A j 0 [ j 0 r A 0 r 0 ( y r ) jaˆ y Ay aˆ y ] 0 J y J does not have a y component 2 Ax r ( y )k 02 Ax 0 J x 2 Az r ( y )k 02 Az 0 J z ENEE482 112 r Ay y ( y )k Ay j 0 0 ( y r ) r y 2 2 0 j 0 0 ( y r ) ( H ) r 1) ( y H ) y D 2 2 r 2 2 y r2 k 02 y y y x Ay j ( y 1) Ay ( H ) ( y H ) j ( y r ) 0 y ENEE482 113 Boundary conditions: lim 0 H H Ax Ax dy 2 y y 2 H H lim 0 H H 0 J sx ( x, z ) ( y H )dy 0 J sx Ax y H 0 J sx Ay y y Az y , H Ax 0 H z y H , 0 J sz H Az 0 H x y H j 0 0 ( r 1) ( H ) H H y y H s j ( y 1) Ay ( H ) 0 ENEE482 114 In the substrate region away from the interface we have : ( 2 r k 02 ) Ax 0 ( 2 r k 02 ) Az 0 ( 2 y k 02 ) Ay j 0 0 ( y r ) y Ay 2 2 y 2 2 2 r k 0 j ( y r ) 2 2 x z r y y In the air region r y 1 For an isotropic substrate r y ENEE482 115