STA 4321/5325 – Exam 3 – Spring 2007 0 y 1 e y / dy ( ) 1 0 y 1 (1 y) 1 dy ( )( ) ( ) The moment generating function for the gamma distribution with parameters and is M(t) = (1-t)-. Use this to demonstrate that the mean is in fact . M’(t) = -(1-t)-) E(Y) = M’(0) = People are dispersed on a linear beach with a density function f(y)=4y3 0 < y < 1, 0 elsewhere. An ice cream vendor wishes to locate her cart at the median of the locations (where half of the people will be on each side of her). Where will she locate her cart? m 0.5 4 y dy y 3 0 4 m 0 m4 m 0.51/ 4 .8409 Scores on a standardized exam are normally distributed with mean 1000 and standard deviation 160. What proportion of students score under 850 on the exam? P(Y<850) = P(Z<(850-1000)/160 = -0.94) = .5-.3264 = .1736 They wish to calibrate the exam so that 1400 represents the 98th percentile. What should they set the mean to (without changing the standard deviation). P(Z<2.055) .98 P(Y < 1000+2.055(160) = 1328.8) .98 Derive E(Yk) for the Uniform(0,1) distribution. EY k 1 y k 1 1 y (1)dy 0 k 1 0 k 1 1 k The amount of time between arrivals at a car wash is exponentially distributed with a mean of 30 minutes. What is the probability over 15 minutes passes between arrivals? 1 y / 30 e dy e y / 30 0 (e 1 / 2 ) .6065 15 15 30 P(Y 15) Derive the moment generating function for the exponential distribution with mean . 1 1 1 M (t ) e ty e y / dy exp y 0 0 1 t dy 1 1 exp y t 1 0 t 1 e e 0 (1 t ) 1 1 t A computer program generates pseudo-random numbers from a Uniform(0,1) distribution. If it is working properly, what is the probability it will return 4 consecutive numbers greater than 0.75? (.25)4 = .0039 The amount of impurity in batches of a chemical follow a Beta distribution with =1, and =2. Give the density function, as well as the mean amount of impurity. f(y) = 2(1-y) 0≤ y ≤ 1 E(Y) = 1/(1+2) = 1/3 If the amount of impurity exceeds 0.7, the batch cannot be sold. What proportion of batches can be sold? 0.7 0 2(1 y)dy 2 y y 2 0.7 0 1.4 0.49 0.91 Lifetimes of electrical components follow a Gamma distribution with =3, and =6 Give the density function(be very specific to any numbers), as well as the mean and standard deviation of the lifetimes. f(y) = (1/432)y2e-y/6 y>0 E(Y) = 18 Y = (3(6)2) = 10.39 The monetary value to the firm of a component with a lifetime of Y is V = 3Y2 + Y – 1. Give the expected monetary value of a component. E(Y2) = 108+(18)2 = 432 E(V) = 3(432) + 18 -1 = 1313