EXPERIMENT 10 REPORT Phasors, Matlab and PSPICE Name(s): Use Matlab to compute the following (enter your final answers in the space provided) I) Express these quantities in rectangular form: a+b a/b c c+d II) Express these quantities in polar form (magnitude and phase): a c/d ab a+c Phasor Drill Exercises First verify the solution to (a) in both problems above, then use Matlab to find answers to the other questions: 7.4 b) 7.4 c) 7.4 d) 7.5 b) 7.5 c) Example: We sometimes refer to the impedance of a capacitor or inductor as Zc or ZL. Find Zc and ZL for the circuit shown: Given: w = 60 Hz: Zc = ZL = phasor Vin = AC Solution by Phasor Analysis We are now ready to find phasor Vout in the circuit above. Clearly, this is an example of a voltage divider formula. Therefore, our solution in Matlab for Vout will be similar to the voltage divider formula we developed for DC circuits: Vout = Vin*Zc / (1000 + ZL + ZC) And that's it! Of course, we still need to convert back into the time domain. Enter your solution for Vout and vout below: phasor domain Vout = time domain vout = We now turn to PSPICE to see how we can get independent verification of our results in Matlab. PSPICE solution for the demo schematic and simulation results: Include your matlab history showing your calculations, plus your final results. Also insert pictures of your pspice schematics and your pspice simulation results. % I) a b c d = = = = 3 + 4i; -5 + 6i; polar2rect(8+45i); polar2rect(12+250i); a d = a + b c e = c + d % % % % % % % % a = 3 + 4i -2 + 10i 5.6569 + 5.6569i 3.6569 + 15.657i d = c = e = % II) % All variables are already in rectangular form. I can therefore easily use % them with the rect2polar() function. f h g i = = = = rect2polar(a) rect2polar(c / d) rect2polar(a*b) rect2polar(a + b) % % % % % % % % ' f = 5 + 53.13i 0.78446 - 56.31i 39.051 - 177.06i 10.198 + 101.31i h = g = i =