Summary of Series Convergence Tests

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Summary of Series Convergence Tests
1. Harmonic Series
1. The harmonic series is the series
∞
∑
1
𝑛
𝑛=1
=
1 1 1
+ + + β‹―.
1 2 3
2. The harmonic series is divergent.
2. Geometric Series
1. A geometric series is any series of the form
∞
∑
π‘Žπ‘Ÿπ‘›−1 = π‘Ž + π‘Žπ‘Ÿ + π‘Žπ‘Ÿ2 + β‹― ,
𝑛=1
where π‘Ž, π‘Ÿ ∈ ℝ.
2. A geometric series converges to
π‘Ž
if |π‘Ÿ| < 1, and is divergent if |π‘Ÿ| ≥ 1.
1−π‘Ÿ
3. Divergence Test
∑∞
Let 𝑛=1 π‘Žπ‘› be a series.
1. If lim π‘Žπ‘› ≠ 0, then the series
𝑛→∞
∞
∑
π‘Žπ‘› is divergent.
𝑛=1
2. Caution: If lim π‘Žπ‘› = 0, you CANNOT conclude that the series
∞
∑
𝑛→∞
π‘Žπ‘› is convergent.
𝑛=1
4. Integral Test
∑∞
Let 𝑛=1 π‘Žπ‘› be a series, and let 𝑓 ∢ [1, ∞) → ℝ be function that satisfies the following four properties:
(1) 𝑓 (𝑛) = π‘Žπ‘› for all 𝑛.
(2) 𝑓 (π‘₯) is continuous on [1, ∞).
(3) 𝑓 (π‘₯) > 0 on [1, ∞).
(4) 𝑓 (π‘₯) is decreasing on [1, ∞).
Then
∑∞
𝑛=1
∞
π‘Žπ‘› is convergent if and only if
∫1
1
𝑓 (π‘₯) 𝑑π‘₯ is convergent.
5. Remainder Estimate for the Integral Test
∑∞
Let 𝑛=1 π‘Žπ‘› be a series.
∑∞
1. Suppose that 𝑛=1 π‘Žπ‘› is convergent by the Integral Test. Let π‘š ∈ β„•.
π‘š
∑
∞
π‘Žπ‘– +
𝑖=1
∫π‘š+1
𝑓 (π‘₯) 𝑑π‘₯ ≤
∞
∑
𝑛=1
π‘Žπ‘› ≤
π‘š
∑
∞
π‘Žπ‘– +
𝑖=1
∫π‘š
𝑓 (π‘₯) 𝑑π‘₯.
2. An approximate value for the sum of the series is the average of the upper bound and the lower
bound in the above inequalities. The difference between this approximate value and the actual
sum of the series is at most half the distance between the upper bound and the lower bound.
6. 𝑝-Series
1. A 𝑝-series is any series of the form
∞
∑
1
1
1
1
= 𝑝 + 𝑝 + 𝑝 + β‹―,
𝑝
𝑛
1
2
3
𝑛=1
where 𝑝 ∈ ℝ.
2. A 𝑝-series is convergent if 𝑝 > 1, and is divergent if 𝑝 ≤ 1.
7. Comparison Test
∑∞
∑∞
Let 𝑛=1 π‘Žπ‘› and 𝑛=1 𝑏𝑛 be series. Suppose that π‘Žπ‘› ≥ 0 and 𝑏𝑛 ≥ 0 for all 𝑛 ∈ β„•. Suppose that
π‘Žπ‘› ≤ 𝑏𝑛 for all 𝑛 ∈ β„•.
1. If
∞
∑
𝑏𝑛 is convergent, then
2. If
π‘Žπ‘› is convergent.
𝑛=1
𝑛=1
∞
∑
∞
∑
π‘Žπ‘› is divergent, then
𝑛=1
3. Caution: If
∞
∑
𝑏𝑛 is divergent.
𝑛=1
∞
∑
𝑛=1
π‘Žπ‘› is convergent or if
∞
∑
𝑏𝑛 is divergent, you CANNOT conclude anything about
𝑛=1
the other series by the Comparison Test.
2
8. Limit Comparison Test
∑∞
∑∞
Let 𝑛=1 π‘Žπ‘› and 𝑛=1 𝑏𝑛 be series. Suppose that π‘Žπ‘› ≥ 0 and 𝑏𝑛 ≥ 0 for all 𝑛 ∈ β„•. Suppose that
𝑏𝑛
= 𝐿,
𝑛→∞ π‘Ž
𝑛
lim
for some 𝐿 ∈ ℝ or 𝐿 = ∞.
1. Suppose that 0 < 𝐿 < ∞. Then either both
∑∞
and 𝑛=1 𝑏𝑛 are divergent.
2. Suppose that 𝐿 = 0. If
∞
∑
∑∞
𝑛=1
π‘Žπ‘› is convergent, then
𝑛=1
3. Suppose that 𝐿 = ∞. If
∞
∑
π‘Žπ‘› and
∞
∑
∑∞
𝑛=1
𝑏𝑛 are convergent, or both
∑∞
𝑛=1
π‘Žπ‘›
𝑏𝑛 is convergent.
𝑛=1
π‘Žπ‘› is divergent, then
𝑛=1
∞
∑
𝑏𝑛 is divergent.
𝑛=1
9. Alternating Series Test
∑∞
Let 𝑛=1 (−1)𝑛−1 π‘Žπ‘› be an alternating series, where π‘Žπ‘› > 0 for all 𝑛 ∈ β„•.
1. Suppose that the alternating series satisfies the following two properties:
{ }∞
(a) the sequence π‘Žπ‘› 𝑛=1 is decreasing.
(b) lim π‘Žπ‘› = 0.
𝑛→∞
Then the alternating series is convergent.
1. The same result holds for alternating series of the form
∑∞
𝑛=1
(−1)𝑛 π‘Žπ‘› .
10. Remainder Estimate for the Alternating Series Test
∑∞
Let 𝑛=1 (−1)𝑛−1 π‘Žπ‘› be an alternating series, where π‘Žπ‘› > 0 for all 𝑛 ∈ β„•. Let π‘š ∈ β„•.
1. The π‘šth remainder of the alternating series, denoted π‘…π‘š , is defined by
π‘…π‘š =
∞
∞
∑
∑
(−1)𝑛−1 π‘Žπ‘› − π‘ π‘š =
(−1)𝑛 π‘Žπ‘› .
𝑛=1
𝑛=π‘š+1
2. Suppose that the alternating series satisfies the hypotheses of the Alternating Series Test, and
hence is convergent. Then |π‘…π‘š | ≤ π‘Žπ‘š+1 .
∑∞
3. The same result holds for alternating series of the form 𝑛=1 (−1)𝑛 π‘Žπ‘› .
3
11. Ratio Test
∑∞
Let 𝑛=1 π‘Žπ‘› be a series. Suppose that π‘Žπ‘› ≠ 0 for all 𝑛 ∈ β„•. Suppose that
| π‘Žπ‘›+1 |
| = 𝐿,
lim ||
𝑛→∞ | π‘Ž ||
𝑛
for some 𝐿 ∈ ℝ or 𝐿 = ∞.
∑∞
1. If 𝐿 < 1, then 𝑛=1 π‘Žπ‘› is absolutely convergent.
∑∞
2. If 𝐿 > 1, then 𝑛=1 π‘Žπ‘› is divergent.
3. Caution: If 𝐿 = 1, you CANNOT conclude conclude that
divergent by the Ratio Test.
4
∑∞
𝑛=1
π‘Žπ‘› is either convergent or
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