PHYSICS: MIDTERM MATHEMATICAL MODELS NAME: CHAPTER I – INTRODUCTION TO PHYSICS PHYSICAL QUANTITY SYMBOL UNITS MATH MODEL Distance d m - How far an object is located from the origin. Scalar Distance + direction Vector Change between two positions Vector m/s Change between two positions over change in time. Scalar m/s Speed + direction Slope of position vs. clock reading graph. Vector Change between two velocities over change in time. Slope of velocity vs. clock reading graph. Vector Position dx or dy m - Displacement dx or dy m dx = dxf - dxi TYPE OF PHYSICAL QUANTITY DEFINITION CHAPTER II – MOTION WITH CONSTANT VELOCITY Speed Velocity v vx or vy CHAPTER III – Motion with constant acceleration Acceleration ax or ay m/s2 vxf - vxi a t CHAPTER II & CHAPTER III – MOTION WITH CONSTANT VELOCITY & MOTION WITH CONSTANT ACCELERATION Position MWCV MWCA dxf dxi vx t 1 dxf dxi vx t ax t 2 2 vxf vxi ax t Velocity (constant) acceleration ax 0 m s2 Displacement (Area under the graph) dx vx t Velocity after any displacement (constant) vxf - vxi a t (constant) dx 1 vf vi t 2 vxf 2 vxi2 2 ax dx CHAPTER IV – VECTORS Vertical component (y-component) By B sin Vectors: Physical quantities that require of a magnitude (number) and a direction. Examples: Position, displacement, velocity, acceleration, Force, Impulse, Momentum, Electric current, magnetic field, Electric Field. Bx = B · cos ( ) Scalars: Physical quantities that require only of a magnitude (number) Resultant Examples: Mass, volume, density, temperature, speed, distance, energy, work, power, Voltage, Resistance. By = B · sin ( ) Horizontal component (x-component) Pythagorean Theorem B2 = ( Bx)2 + (By)2 CHAPTER V – FORCES Force of Earth FEonO N Force that Earth exerts on an object. Vector Mass m kg Amount of matter in an object. scalar Gravitational constant g m/s2 Acceleration of an object due to the force exerted by Earth Slope of FEonO vs. mass. Vector Force of the Spring FSonO N Force that a spring exerts on an object. Vector Elongation L m Change between two lengths of a stretched/compressed spring. Vector Spring constant k N/m Ratio between the force exerted by the spring on an object and the elongation caused on the spring. Slope of FSonO vs. Elongation. scalar Force of kinetic Friction Fk N Force exerted by a surface, parallel to the surface. Vector Normal Force FN N Force exerted by a surface, perpendicular to the surface. Vector Coefficient of kinetic Friction k - Ratio between two force Fk & FN Slope of Fk vs. FN. scalar Tension Force FT N Force exerted by a cable, rope, thread, string, etc. vector FSonO k L Fk k FN - CHAPTER VI – PROJECTILE MOTION FREE FALL VERTICAL LAUNCH HORIZONTAL LAUNCH ANGLED LAUNCH Position HOW FAR (at any given t) dy = ( ½ · g · t2) dy = ( ½ · g · t2) + ( vyi · t ) + (dyi) dy = ( ½ · g · t2) dy = ( ½ · g · t2) + ( vyi · t ) + (dyi) Velocity HOW FAST (at any given t) Vy = ( g · t) + vyi Vy = ( g · t) + vyi Vy = ( g · t) + vyi Vy = ( g · t) + vyi Acceleration g = -9.8 (at any given t) Time to reach maximum height g = -9.8 t TOP = N/A GOING UP Time in Flight COMING DOWN m s2 t = 2 · dy vyi 0 Initial velocity m s Initial velocity Maximum height 2 · dy g vyi = vyTOP - (g · tTOP) ( vyi )2 = ( vyTOP )2 - (2 · g · dyTOP) N/A (NO t) g = -9.8 vy TOP - vyi g t = g m s2 dy TOP = N/A (vy TOP )2 - (vy i )2 (NO t) 2·g m s2 t TOP = N/A t = 2 · dy g vyi 0 N/A N/A g = -9.8 m s t = m s2 vy TOP - vyi g 2 · dy g vyi = vyTOP - (g · tTOP) ( vyi )2 = ( vyTOP )2 - (2 · g · dyTOP) dy TOP = (vy TOP )2 - (vy i )2 2·g CHAPTER VII – CIRCULAR MOTION Circumference c m Tangential velocity vT m/s Centripetal acceleration aC m/s2 Centripetal Force FC N c 2r r T v2 ac = r v2 Fc m r vT = 2 Perimeter of a circle Scalar Velocity of an object moving in circular motion. Tangential to the circle and perpendicular to the Centripetal Force. Vector Acceleration of an object moving in circular motion. Towards the center of the circle. Vector Any type Force that keeps an object moving in circular motion. Towards the center of the circle. Vector PHYSICS: FINAL EXAM MATHEMATICAL MODELS NAME: CHAPTER VIII – UNIVERSAL GRAVITATION Gravitational Force FG N Gravitational constant g m2 / s2 Universal gravitational constant G N · m2 / kg2 Velocity of an orbiting object ving m/s FG = G m1 m2 2 r m g = G 2P rP G = 6.673 x 10-11 G · morbited rcircle Ving = Force of attraction between two objects of masses m1 and m2. Vector Gravitational constant of any planet. Vector Constant of proportionality Velocity of an object orbiting another object. Vector CHAPTER IX – IMPULSE & MOMENTUM Momentum p kgm/s Impulse I Ns p m v I F t p CONSERVATION OF MOMENTUM i p Vector Product of Force times change in clock reading. Force exerted over a period of time that changes the momentum of an object. Vector The initial momentum of system can change only if an impulse is delivered on the system. The final momentum of the system will equal the initial momentum of the system plus the delivered impulse on the system. Pi + I = pF IMPULSE CHANGES MOMENTUM Amount of motion of an object. f p1i p 2i I p1F p 2F The total momenta of the system are conserved after a collision. The total momenta before the collision equal the total momenta after the collision. CHAPTER X – WORK – POWER - ENERGY Work W J W = F · d Force parallel to d Gravitational Potential Energy UG J Kinetic Energy KE Elastic Potential Energy Power Potential to do something Scalar UG = g · m · dy Potential to do something due to a change in a vertical position (dy) Scalar J KE = ½ · m · v2 Potential to do something due to a change in a velocity (v) Scalar US J US = ½ · k · L2 Potenti Potential to do something due to a change in the elongation (L) of an elastic object. Scalar P W P = W / t Rate at which work is done scalar UGi + W = UGF KEi + W = KEF USi + W = USF WORK CHANGES ENERGY CONSERVATION OF MECHANICAL ENERGY The initial energy of the system can change only if work is done on the system. The final energy of the system will equal the initial energy of the system plus the work done on the system. The total mechanical energy of the system is neither created nor destroyed. UGi + KEi + USi + W = UGF + KEF + USF The total mechanical energy is conserved. v= 2KE m CHAPTER XI – TORQUE Torque Property of a force to make an object rotate. N·m When the force causing the torque: FEonO = g · m F r ROTATIONAL EQUILIBRIUM Force perpendicular to r CW Vector CCW The sum of the Torques in the counter clockwise direction (ccw) equal the sum of the Torques in the clockwise direction (cw) CHAPTER XII – ELECTRICITY Electrostatics constant Electric force Coulomb’s law K N · m2 / C2 Fq1onq2 N Electric field (at any point) Electric field (felt by a charged particle) K = 9 x 109 Fq1onq2 = K E=K E N/m E= Electric Potential Energy Uq J Uq = K Electric potential V v V= v v Uq J Change in electric potential Constant of proportionality q1 q2 2 d q d2 Attractive or repulsive force between two charges of charge q1 and q2 Vector Space around an electric Charge. Electric field felt at any point around that electric charge. Vector Fq Space around an electric Charge. Electric field felt by a charge place around that electric charge. q q1 q2 Potential to change the velocity of charged particle. scalar Potential to change the energy of an electric charge placed between two electric plates with a constant Electric field (E) and a distance (d). scalar V = E · d Difference between two different electric potentials. scalar Uq = V · q Energy that changes when a charge moves from one place to another place. scalar d (K · qA ) d (Voltage) Change in Electric Potential Energy CHAPTER XIII – ELECTRIC CIRCUITS Electric current Ohm’s law I A I A V V R q I Flow of electric charge (q) per unit of time (t). t V I R Vector Charges in motion Electric current (I) is directly proportional to the change in electric potential (V). Vector Electric current (I) is inversely proportional to the resistance (R). P I V Power (Electric) P P I2 R W Rate at which electric work is done. 2 V P Scalar R PHYSICAL QUANTITY CIRCUITS IN SERIES CIRCUITS IN PARALLEL Stays the same IT = I1 + I2 + I3 +. . . VT = V1 + V2 + V3 +. . . Stays the same RT = R 1 + R 2 + R 3 + . . . 1 1 1 1 = + + + ... RT R1 R 2 R3 PT = P1 + P2 + P3 +. . . PT = P1 + P2 + P3 +. . . ELECTRIC CURRENT VOLTAGE RESISTANCE POWER CHAPTER XIV – MAGNETISM Magnetic force on a charged particle Magnetic force on a current carrying wire FB FB N N FB = B FB = L v B q I sin Force (FB) felt by a charged particle (q) that travels with velocity (v) perpendicular to a magnetic field (B). The direction of this force is perpendicular to both the direction of the magnetic field and the direction of the velocity of the particle. Vector sin Force (FB) felt by a wire of length (L) carrying an electric current (I) placed perpendicular to a magnetic field (B). The direction of this magnetic force is perpendicular to both the direction of the magnetic field and the direction of the electric current. Vector CHAPTER XIV – WAVES Period of a simple pendulum: T =2· · T= L = G= L g Period Length of the string gravitational constant (seconds) (meters) (m/s2) Period of a mass-spring system: T =2· · T= m = k= m k Period mass Spring constant Period T s Frequency f Hz Wavelength m Speed (wave) v m/s (seconds) (kilograms) (N/m) 1 T f v f v T Time for one cycle. Distance peak to peak measured in the “time graph”. Scalar Number of cycles in one second. Scalar Length of one cycle. Distance peak to peak measured in the “position graph”. Vector Change in position over the change in time of a disturbance. Fundamental Frequency of a standing wave on a string or in an open pipe f1 = v ( 2·L ) f1 = v = L= Fundamental frequency wave speed Length of spring or open pipe (Hertz) (kilograms) (meters) Frequency of a any harmonic of a standing wave on a string or in an open pipe fn = n · v ( 2·L ) (n = 1, 2, 3, 4, . . . ) fn = v = L= n= Frequency of the harmonic wave speed Length of spring or open pipe number of the harmonic (Hertz) (kilograms) (meters) Vector