QUADRATIC RELATIONS (the x–intercepts) VERTEX FORM y = a(x – h)2 + k STANDARD FORM y = ax2 + bx + c NOTE: V(h,k) NOTE: y–intercept is c INTERCEPT FORM y = a(x – r)(x – s) NOTE: r & s are the x–intercepts the intercept form is used to determine the x–intercepts the x–intercepts are also called the zeros the x-intercepts (or zeros) are the points where the parabola crosses the x–axis _____________________________________________________________________________________ Example State the x and y–intercepts of the relation. x–intercepts: ______________ y–intercepts: ______________ ___________________________________________________________ To determine the x–intercepts from an equation in intercept form, set each factor to zero and solve for x. y = 5(x – 3)(x + 5) Unit 3 Lesson6 Page 1 of 3 Example Determine the zeros of each of the following relations: a) y = (x + 6)(x – 4) b) y = –2(x + 2)(x – 2) c) y = x(x + 5) d) y = x2 – 12x + 32 e) y = 2x2 + 14x + 24 f) y = –3x2 + 48 Example Given the quadratic relation in vertex form, express the relation in standard form and intercept form. y = (x – 3)2 – 36 vertex: __________ Example a) y–intercept: __________ x–intercepts: __________ Factor each quadratic relation. Use the factors to determine the zeros. Then, sketch the graph using the a value to decide if the parabola opens upward or downward. y = 4x2 + 4x – 168 y x Unit 3 Lesson6 Page 2 of 3 b) y = –3x2 + 24x – 48 y x c) y = x2 + 3x + 20 y x Example Unit 3 Lesson6 A ball was tossed from the roof of a 5m tall building. The path of the ball can be modelled by the relation, y = –x2 + 4x + 5, where x is the horizontal distance travelled and y is the height, both in metres. a) Express the relation in intercept form. b) Determine the zeros of the relation. c) State the y–intercept and explain its meaning in this context. d) State the horizontal distance at which the ball hit the ground. Page 3 of 3