Unit 2 Section 10 Absolute Value Equations.notebook Nov 5­9:54 AM Nov 5­9:54 AM November 05, 2015 Unit 2 Section 10 Absolute Value Equations.notebook Nov 5­9:54 AM Absolute Value Equations Unit 2 Oct 13­8:49 AM November 05, 2015 Unit 2 Section 10 Absolute Value Equations.notebook November 05, 2015 Absolute Value Equations Example 1: |x| = 2 x = 2 or x = ­2 x is a number whose distance is 2 units away from the origin. Example 2: |x| + 3 = 8 Oct 13­8:50 AM The equation |z ­ 5| = 6 means that the distance on a number line from z ­ 5 to 0 is 6 units. There are two points that are 6 units from 0: 6 and ­6. So to find the values of x, solve the equations z ­ 5 = 6 and z ­ 5 = ­6. Example 3: |z ­ 5| = 6 Oct 13­8:52 AM Unit 2 Section 10 Absolute Value Equations.notebook November 05, 2015 The absolute value of an expression cannot be negative, so there is no solution. 1.) | t + 6| = ­4 2.) |2y + 1| = ­6 Oct 13­8:53 AM Always isolate the absolute value before splitting into two equations. Try these: 3.) 3 = |w| ­ 4 4.) |x| + 5 = 4 ­ 6 Oct 13­8:53 AM Unit 2 Section 10 Absolute Value Equations.notebook November 05, 2015 6.) 3|3x ­ 7| + 6 = 9 5.) 4|n| = 32 Oct 13­8:52 AM 7.) 7|3x ­ 5| = ­14 Oct 13­8:56 AM Unit 2 Section 10 Absolute Value Equations.notebook 8.) |x + 6 | = 0 November 05, 2015 9.) |2x ­ 1| = 3x Nov 8­11:00 AM 10.) |3y ­ 2| = 2y ­ 1 Nov 8­11:02 AM Unit 2 Section 10 Absolute Value Equations.notebook November 05, 2015 Bell Ringer 1.) |2z ­ 1| + 2 = 3z + 4 Nov 4­8:57 AM 2.) Bonnie estimates her stride to be 16 in. However, any given stride is likely to vary from her estimate up to 2 in. Write and solve an equation to find Bonnie's maximum and minimum stride. Oct 13­8:57 AM Unit 2 Section 10 Absolute Value Equations.notebook November 05, 2015 3.) The ideal circumference of a woman's basketball is 28.75 in. The actual circumference may vary from the ideal by at most 0.25 in. What are the acceptable circumferences for a women's basketball? Nov 5­10:57 AM 4.) The absolute value of twice a number added to 5 is 33. 5.) Five times the absolute value of the difference of four times a number and 4 is 20. 6.) If 4 is subtracted from twice the absolute value of the difference of twice a number and 2, the result is 24. Nov 8­11:03 AM Unit 2 Section 10 Absolute Value Equations.notebook Homework: Homework Packet page 29 and 30 Nov 4­9:05 AM Oct 9­8:46 AM November 05, 2015