SUPER-EXPONENTIAL DECAY OF DIFFRACTION MANAGED SOLITONS DIRK HUNDERTMARK AND YOUNG-RAN LEE Abstract. This is the second part of a series of papers where we develop rigorous decay estimates for breather solutions of an averaged version of the non-linear Schrödinger equation. In this part we study the diffraction managed discrete nonlinear Schrödinger equation, an equation which describes coupled waveguide arrays with periodic diffraction management geometries. We show that, for vanishing average diffraction, all solutions of the non-linear and non-local diffraction management equation decay super-exponentially. As a byproduct of our method, we also have a simple proof of existence of diffraction managed solitons in the case of vanishing average diffraction. 1. Introduction Solitons, localized coherent structures resulting from a balance of non-linear and dispersive effects, have been the focus of an intense research activity over the last decades, see [35, 37]. Besides solitons in the continuum, discrete solitons have emerged in such diverse areas as solid states physics, some biological systems, Bose-Einstein condensation, and in discrete non-linear optics, e.g., optical waveguide arrays, [5, 9, 31, 32, 38]. The model describing this range of phenomena is given by the discrete non–linear Schrödinger equation i ∂ u(x) + d(ξ)(∆u)(x) + |u(x)|2 u(x) = 0 ∂ξ (1.1) where for waveguide arrays ξ is the distance along the waveguide, x ∈ Z the location of the array element, ∆ the discrete Laplacian given by (∆f )(x) = f (x + 1) + f (x − 1) − 2f (x) for all x ∈ Z, and d(ξ) the total diffraction along the waveguide. Nearly a decade after their theoretical prediction in [7], discrete solitons in an optical waveguide array were studied experimentally and, as in the continuous case localized stable non-linear waves where found [10]. Similar to the continuous case, i.e, non-linear fiber-optics, where the dispersion management technique introduced by [23] in 1980 turned out to be enormously successful in creating stable low power pulses by periodically varying the dispersion along the glass–fiber cable, see [1, 14, 15, 18, 21, 22, 28, 26, 29, 40] and the survey article [39], the diffraction management technique was proposed much more recently in [11] in order to create low power stable Date: 16 April 2008, version 7-3, file diffms-7-3.tex. c 2008 by the authors. Faithful reproduction of this article, in its entirety, by any means is permitted for non-commercial purposes. 1 2 D. HUNDERTMARK AND Y.-R. LEE discrete pulses by periodically varying the diffraction in discrete optical waveguide arrays. In this case, the total diffraction d(ξ) along the waveguide is given by e d(ξ) = ε−1 d(ξ/ε) + dav . (1.2) Here dav ≥ 0 is the average component of the diffraction and de its mean zero part. Note that unlike in the continuum case, the diffraction management technique uses the geometry of the waveguide to achieve a periodically varying diffraction, see [11]. In the region of strong diffraction management ε is a small positive parameter. Rescaling t = ξ/ε, (1.1) is equivalent to ∂ e u + d(t)∆u + ε dav ∆u + |u|2 u = 0 . (1.3) ∂t For small ε an average equation which describes the slow evolution of solutions of (1.3) was derived and numerical studies showed that this average equation possesses stable solutions which evolve nearly periodically when used as initial data in the diffraction managed non-linear discrete Schrödinger equation, [2, 3, 4]. Normalizing the period in the fast variable t to one, the average equation for the slow part v of solutions of (1.3) is given by i i ∂ v + εdav ∆v + εQ(v, v, v) = 0 ∂t where Q(v1 , v2 , v3 ) := Z 0 1 Ts−1 Ts v1 Ts v2 Ts v3 ds (1.4) (1.5) Rs e dξ the solution operator for the free discrete with Ts := eiD(s)∆ and D(s) = 0 d(ξ) Schrödinger equation with periodically varying diffraction ∂ e v = −d(t)∆v. (1.6) ∂t One should keep in mind that the variable t denotes the distance along the waveguide. Physically it makes sense to assume that the diffraction profile de is bounded, or even piecewise constant along the waveguide. This assumption was made in [27, 30, 34]. For our results we need only to assume that its integral D is bounded over one period in the fast variable t, Z t e dξ < ∞, τ := sup |D(t)| = sup d(ξ) (1.7) i t∈[0,1] t∈[0,1] 0 where we normalized, without loss of generality, the period in t to one. Using the same general method as in the continuum case, see, e.g., [43], the averaged equation (1.4) was derived in [2, 3, 4], where it was expressed in the Fourier space. The above formulation is from [27, 30]. Note that the non-linear and non-local equation (1.4) has an associated (averaged) Hamiltonian given by H(v) := ε 1 dav hv, −∆vi − Q(v, v, v, v) 2 4 (1.8) SUPER-EXPONENTIAL DECAY OF DIFFRACTION MANAGED SOLITONS 3 P with hg, f i := x∈Z g(x)f (x) the usual scalar product on l2 (Z), which, in our convention, is linear in the second component and anti-linear in the first and Z 1X Q(v1 , v2 , v3 , v4 ) := (Ts v1 )(x)(Ts v2 )(x)(Ts v3 )(x)(Ts v4 )(x) ds. (1.9) 0 x∈Z Following the procedure for the continuous case in [43], it was shown in [27] that over long scales 0 ≤ t ≤ Cε−1 solutions of the non-autonomous equation (1.3) stay ε-close to solutions of the autonomous average equation (1.4) with the same initial condition. Thus it is interesting to find stationary solutions of (1.4), which are precisely the right initial conditions leading to breather-like nearly periodic solutions of (1.3) on long scales 0 ≤ t ≤ Cε−1 . Making the ansatz v(t, x) = eiεωt f (x) in (1.4) one arrives at the non-linear and non-local eigenvalue problem −ωf = −dav ∆f − Q(f, f, f ). (1.10) ωf = Q(f, f, f ) (1.11) Solutions of this equation can be found by minimizing the Hamiltonian H in (1.8) over functions f ∈ l2 (Z) with a fixed l2 -norm. The problem of constructing such minimizers for positive average diffraction dav > 0 has been studied in [27, 30] using a discrete version of Lions’ concentration compactness method [24]. Moreover, using by now classical arguments, see, [41, 42] or [6], it was noticed in [27, 30] that these minimizers are so-called orbitally stable, explaining at least in part the strong stability properties of diffraction management. Similar as in the continuous case, see [19], proving existence of minimizers for vanishing average dispersion, dav = 0, i.e., existence of weak solutions f ∈ l2 (Z) of is much harder and has only recently been established in [34] using Ekeland’s variational principle, [12, 13]. Moreover, it was shown in [34], that the corresponding minimizer is decaying faster than polynomial, which again yields the orbital stability of solutions of (1.4) for dav = 0 and initial conditions close to a minimizer. In this paper we continue our study of regularity properties of the dispersion management technique initiated in [16] and study the decay properties of diffraction management solitons for vanishing average dispersion, i.e., weak solutions of (1.11). Our main result is a significant strengthening of the super-polynomial decay result for diffraction managed solitons in [34]. Theorem 1.1 (Super-exponential decay). Assume that the diffraction profile obeys (1.7). Then any weak solution f ∈ l2 (Z) of (1.11) decays faster than any exponential. More precisely, with c = 1 + ln(8τ ), 1 |f (x)| . e− 4 (|x|+1)(ln((|x|+1)/2)−c) for all x ∈ Z. Remarks 1.2. (i) In particular, for any 0 < µ < 1/4 Theorem 1.1 yields the bound |f (x)| . (|x| + 1)−µ(|x|+1) for all x ∈ Z. (ii) The bound given in Theorem 1.1 rigorously justifies the theoretical and experimental conclusion of [11], that the diffraction management technique leads to optical soliton like pulses along a waveguide array which are extremely well-localized along 4 D. HUNDERTMARK AND Y.-R. LEE the array elements. (iii) The super-exponential decay given in Theorem 1.1 is in stark contrast to the continuous case where one has, so far, only super-polynomial bounds on the decay of dispersion management solitons, see [16]. It is believed that the decay in the continuous case is exponential, see [25] for convincing but non-rigorous arguments. (iv) Weak solutions of (1.11) are defined as l2 (Z). ωhg, f i = hg, Q(f, f, f )i (1.12) hf1 , Q(f2 , f3 , f4 )i = Q(f1 , f2 , f3 , f4 ) (1.13) ωhg, f i = Q(g, f, f, f ) (1.14) for any g ∈ Recalling the definition (1.9) for the four-linear functional Q, a short calculation gives for any fj ∈ l2 (Z), j = 1, 2, 3, 4. Thus f is a weak solutions of (1.11) if and only if for all g ∈ l2 (Z). (v) One easily sees that Q(f, f, f, f ) > 0 as soon as f is not the zero function. Thus ω = Q(f, f, f, f )/hf, f i > 0 for any non-zero solution of (1.11). Our second result is a simple proof of existence of weak solutions of (1.11) under the weak condition (1.7) on the diffraction profile. Theorem 1.3. Assume that the diffraction profile obeys (1.7). Let λ > 0. There is an f ∈ l2 (Z) with kf k22 = λ such that Q(f, f, f, f ) = Pλ := sup Q(g, g, g, g)| g ∈ l2 (Z), kgk22 = λ . This maximizer f is also a weak solution of the diffraction management equation (1.11) where ω > 0 is a suitable Lagrange-multiplier. Remark 1.4. The existence of a maximizer is non-trivial, even for the corresponding problem with dav > 0, since the equation (1.11), respectively (1.10), is invariant under translations and so is the corresponding energy functional H given by (1.8). Thus maximizing sequences for Q, respectively minimizing sequences for H, can very easily converge to zero weakly. This was overcome using Lions’ concentration compactness principle in [27, 30] for positive average diffraction and, for vanishing average dispersion, in [34] using Ekeland’s variational principle [12, 13, 17], assuming that the diffraction profile is piecewise constant. Besides holding under much more general conditions, our proof is rather direct and, we believe, simple. We show that modulo translations any maximizing sequence has a strongly convergent subsequence, i.e., there is a sequence of shifts such that the shifted sequence, which by the translation invariance of the problem is also a maximizing sequence, has a strongly convergent subsequence. Our proof avoids the use of the concentration compactness principle but relies instead on a discrete version of multi-linear Strichartz estimates, see Corollary 2.9 and Lemma 4.4. Our paper is organized as follows: In the next section we fix our notation and develop our basic technical estimates, the discrete versions of bilinear and multi– linear Strichartz estimates from Lemmata 2.7 and 2.8 and Corollary 2.9. All results SUPER-EXPONENTIAL DECAY OF DIFFRACTION MANAGED SOLITONS 5 in Section 2 are valid in arbitrary dimension d ≥ 1. The proof of Theorem 1.1 is given in Section 3, see Theorem 3.2 and Corollary 3.3. Similar to our study of decay properties of dispersion managed solitons in [16], the main tool in the proof of our super-exponential decay Theorem 1.1 is the self-consistency bound from Proposition 3.1 on the tail distribution of weak solutions of the diffraction management equation (1.11). Our existence proof for diffraction management solitons is given in Section 4. It relies heavily on Lemma 4.4, which follows from the enhanced multi–linear estimates of Corollary 2.9, and a simple characterization of strong convergence in l2 (Z), or more generally, strong convergence in lp (Zd ) for 1 ≤ p < ∞, given in Lemma 4.1. 2. Basic estimates In this section we consider Zd for arbitrary dimension d ≥ 1. First we introduce some notation. By N we denote the natural numbers and N0 = N ∪ {0}. Given n ∈ N0 , we denote n! the factorial, 0! = 1 and (n + 1)! = (n + 1)n!. The integers are denoted by Z and Zd is the d-fold Euclidian product of Z. lp (Zd ) is the usual sequence space with norm 1/p X kf kp = |f (x)|p for 1 ≤ p < ∞ (2.1) x∈Zd and kf k∞ = sup |f (x)|. (2.2) x∈Zd Of course, for p = 2 we get the Hilbert space of square summable sequences indexed by Zd . In this case we use X f (x)g(x) (2.3) hf, gi := x∈Zd for the scalar product on l2 (Zd ). Here z is the complex conjugate of a complex number z. The real and imaginary parts of a complex number are given by Re(z) = 12 (z + z) 1 and Im(z) = 2i (z − z). Note that in our convention the scalar product given by (2.3) is linear in the second argument and anti-linear in the first. The discrete Laplacian on Zd is given by X f (x + ν) − 2df (x) (2.4) ∆f (x) = Pd |ν|=1 where we take |x| = j=1 |xj | for the norm on Zd . Since ∆ is a bounded symmetric operator, eit∆ is the unitary solution operator of the free discrete Schrödinger equation i∂t u = −∆u (2.5) e i∂t u = −d(t)∆u (2.6) on l2 (Zd ); for any f ∈ l2 (Zd ) the function u(t, x) = (eit∆ f )(x) solves (2.5) and u(0, ·) = f . Note that eit∆ is unitary, in particular, keit∆ f k2 = kf k2 for all f ∈ l2 (Zd ). Rt e dξ and Tt := eiD(t)∆ . Thus for any For a diffraction profile de we set D(t) = 0 d(ξ) initial condition f ∈ l2 (Zd ) the function u(t, ·) = Tt f solves 6 D. HUNDERTMARK AND Y.-R. LEE with initial condition u(0, ·) = f . Again, Tt is a unitary operator on l2 (Zd ). For a function f : Zd → C, its support is given by the set supp (f ) := {x ∈ Zd : f (x) 6= 0}. For arbitrary A ⊂ Zd and x ∈ Zd the distance from x to A is given by and for subsets A, B ⊂ Zd dist(x, A) := inf(|x − y| : y ∈ A) their distance is given by dist(A, B) := inf(dist(x, B) : x ∈ A) = inf(|x − y| : x ∈ A, y ∈ B). For any operator T : l2 (Zd ) → l2 (Zd ) we denote its kernel by hx|T |yi := hδx , T δy i where δy is the Kronecker δ-function δy (x) := 1 0 if x = y . if x = 6 y T f (x) = X hx|T |yif (y) . In particular, y∈Zd (2.7) We use the . notation in inequalities, if it is convenient not to specify any constants in the bounds: for two real-valued functions g, h defined on the same domain, g . h means that there exists a non-negative constant C such that g(x) ≤ Ch(x) for all x. The extension of the non-linear and non-local functional Q to l2 (Zd ) is again denoted by Q, Z 1 X Q(f1 , f2 , f3 , f4 ) = (Tt f1 )(x)(Tt f2 )(x)(Tt f3 )(x)(Tt f4 )(x) dt. (2.8) 0 x∈Zd The first problem is to show that Q is well-defined on l2 (Zd ). Due to the next lemma this turns out to be easier than in the continuous case. Lemma 2.1. Let 1 ≤ p ≤ q ≤ ∞. Then, lp (Zd ) ⊂ lq (Zd ) and kf kq ≤ kf kp . Proof. Clearly kf k∞ ≤ kf kp for all f ∈ lp (Zd ) and all 1 ≤ p ≤ ∞. Let 0 ≤ s ≤ 1. Then for all non-negative sequences (an )n∈Zd , X s X an ≤ asn . n∈Zd This follows from (a1 + a2 )s = n∈Zd a1 a2 a1 a2 + ≤ 1−s + 1−s = as1 + as2 1−s 1−s (a1 + a2 ) (a1 + a2 ) a1 a2 and induction. Now let 1 ≤ p ≤ q < ∞ and f ∈ lp (Zd ). Then with s = p/q, X s X p kf kpp = |f (n)|qs ≥ |f (n)|q = kf kqs q = kf kq , n∈Zd n∈Zd (2.9) (2.10) SUPER-EXPONENTIAL DECAY OF DIFFRACTION MANAGED SOLITONS 7 where we used (2.10). This finishes the proof of (2.9). Corollary 2.2. For any fj ∈ l2 (Zd ), j = 1, . . . , 4, we have Z 1 X Y 4 4 Y |Q(f1 , f2 , f3 , f4 )| ≤ |Tt fj (x)| dt ≤ kfj k2 0 x∈Zd j=1 (2.11) j=1 Proof. Of course, the first inequality is just the triangle inequality. By Hölder’s inequality followed by Lemma 2.1 4 X Y x∈Zd j=1 |Tt fj (x)| ≤ 4 Y j=1 kTt fj k4 ≤ 4 Y j=1 kTt fj k2 = 4 Y j=1 kfj k2 where we also used that Tt is unitary on l2 (Zd ). Thus (2.11) follows by integrating this over t on [0, 1]. Remark 2.3. The bound from Corollary 2.2 justifies the ad-hoc formal calculation for all f, fj ∈ l2 (Zd ) with hf, Q(f1 , f2 , f3 )i = Q(f, f1 , f2 , f3 ) Q(f1 , f2 , f3 ) := Z 0 1 Tt−1 Tt f1 Tt f2 Tt f3 dt. (2.12) (2.13) In particular, this shows that Q(f1 , f2 , f3 ) ∈ l2 (Zd ) whenever fj ∈ l2 (Zd ), and Q defined in (2.13) is a bounded three linear map from (l2 (Zd ))3 to l2 (Zd ). This is in contrast to the continuous case, where it is bounded only for d = 1, 2, [16, 33, 43]. Lemma 2.4. For the kernel of the free time evolution eit∆ the bound sup |hx|eit∆ |yi| ≤ min(1, e4dτ t∈[−τ,τ ] (4dτ )|x−y| ) |x − y|! (2.14) holds for all x, y ∈ Zd and 0 ≤ τ < ∞. P Proof. The operator ∆ is given by ∆f (x) = |y−x|=1 f (y) − 2df (x) and, using, for example, the discrete Fourier transform, one sees that 0 ≤ −∆ ≤ 4d and k∆k = 4d. Now, by symmetry of ∆, eit∆ is unitary, hence one always has |hx|eit∆ |yi| ≤ 1 for any x, y ∈ Zd and all t. Since ∆ is bounded, the Taylor series for the exponential yields a strongly converging series for eit∆ . Thus hx|eit∆ |yi = ∞ X (it)n n=0 n! hx|∆n |yi = ∞ X n=|x−y| (it)n hx|∆n |yi n! since hx|∆n |yi = 6 0 if and only if x and y are connected by a path of length at most n, i.e., |x − y| ≤ n. In particular, using k∆k = 4d, it∆ |hx|e |yi| ≤ ∞ X n=|x−y| ∞ X (4d|t|)|x−y|+l |t|n k∆kn = n! (|x − y| + l)! l=0 8 D. HUNDERTMARK AND Y.-R. LEE ≤ ∞ (4d|t|)|x−y| X (4d|t|)l (4d|t|)|x−y| 4d|t| . = e |x − y|! l! |x − y|! l=0 Lemma 2.5. Let s ∈ N. For the free time-evolution eit∆ generated by ∆ the bound X (4dτ )2s max(s, 1)d−1 sup |hx|eit∆ |yi|2 . (2.15) (s!)2 t∈[−τ,τ ] y: |x−y|≥s holds, where the implicit constant depends only on the dimension d and τ . P Proof. The number of points y ∈ Zd with |y| = dj=1 |yj | = n can be estimated by 2d nd−1 and with Lemma 2.4 we have ∞ 2(n+s) X X (4dτ )2|y| X 8dτ d d−1 (4dτ ) sup |hx|eit∆ |yi|2 ≤ e8dτ ≤ e 2 (n + s) (|y|!)2 ((n + s)!)2 t∈[−τ,τ ] y: |x−y|≥s |y|≥s ≤ n=0 ∞ d−1 (4dτ )2n n (4dτ )2s max(s, 1)d−1 8dτ d X 1 + e 2 (s!)2 max(s, 1) (n!)2 n=0 ∞ ≤ 2n (4dτ )2s sd−1 8dτ d X d−1 (4dτ ) e 2 (1 + n) (s!)2 (n!)2 n=0 where we also used (n + s)! ≥ n!s!. Thus the inequality (2.15) holds with constant P 2n d−1 (4dτ ) < ∞. C = e8dτ 2d ∞ n=0 (1 + n) (n!)2 Remark 2.6. Estimating the number of points y ∈ Zd with |y| = n by 2d nd−1 is, of course, a gross over–counting. A tighter estimate can be given as follows: Counting P the number of different integers xj ≥ 0 with dj=1 xj = n is equal to distributing d − 1 separators on n + d − 1 places, i.e, d X n+d−1 d #{x ∈ N0 : xj = n} = d−1 j=1 Since we have 2 choices for the sign, except when some coordinates are zero, we get the better bound d d−1 X Y 2d d d n+d−1 #{y ∈ Z : |yj | = n} ≤ 2 = (n + j) d−1 (d − 1)! j=1 j=1 Qd−1 2d (1 + ε) d−1 j=1 (1 + j/n) d−1 d ≤ =2 n n (d − 1)! (d − 1)! for some small ε > 0 when n is large. For our purpose, the rough estimate 2d nd−1 is good enough. In the formulation of the next lemma we need some more notation. For any r ∈ R let ⌈r⌉ := min(z ∈ Z : r ≤ z) (2.16) SUPER-EXPONENTIAL DECAY OF DIFFRACTION MANAGED SOLITONS 9 the smallest integer greater than or equal to r. Lemma 2.7 (Strong Bilinear bound). There exists a constant C depending only on the dimension d and τ such that for f1 , f2 ∈ l2 (Zd ) and s = dist(supp (f1 ), supp (f2 )) sup k(eit∆ f1 )(eit∆ f2 )k2 ≤ min(1, C t∈[−τ,τ ] max(⌈s/2⌉, 1)d−1 (4dτ )⌈s/2⌉ )kf1 k2 kf2 k2 . ⌈s/2⌉! (2.17) Proof. First of all, note that X k(eit∆ f1 )(eit∆ f2 )k22 = |eit∆ f1 (x)|2 |eit∆ f2 (x)|2 ≤ keit∆ f1 k2∞ keit∆ f2 k22 . x∈Zd Hence, using Lemma 2.1 and the unicity of eit∆ on l2 (Zd ), we see k(eit∆ f1 )(eit∆ f2 )k22 ≤ keit∆ f1 k22 keit∆ f2 k22 = kf1 k22 kf2 k22 (2.18) uniformly in t. Now assume that |t| ≤ τ . Let Ij = supp (fj ), j = 1, 2 and assume, without loss of generality that s = dist(I1 , I2 ) ≥ 1. Moreover we need the slightly enlarged sets I1′ := {x : dist(x, I1 ) ≤ dist(x, I2 ) − 1}, I2′ := {x : dist(x, I1 ) ≥ dist(x, I2 )}. Note that Ij ⊂ Ij′ , j = 1, 2, and I2′ = Zd \ I1′ . The triangle inequality gives 2dist(x, I2 ) − 1 if x ∈ I1′ s = dist(I1 , I2 ) ≤ dist(x, I1 ) + dist(x, I2 ) ≤ 2dist(x, I1 ) if x ∈ I2′ so, since the distance is always an integer, we have min(dist(I1′ , I2 ), dist(I2′ , I1 )) ≥ ⌈s/2⌉. (2.19) Certainly, since I1′ ∪ I2′ = Zd , X X k(eit∆ f1 )(eit∆ f2 )k22 = |eit∆ f1 (x)|2 |eit∆ f2 (x)|2 + |eit∆ f1 (x)|2 |eit∆ f2 (x)|2 . x∈I1′ x∈I2′ (2.20) Because of eit∆ fj (x) = X y∈Ij hx|eit∆ |yifj (y), the Cauchy–Schwarz inequality implies |eit∆ fj (x)|2 ≤ kfj k22 X y∈Ij |hx|eit∆ |yi|2 . 10 D. HUNDERTMARK AND Y.-R. LEE Together with (2.19) and the bound from Lemma 2.4, this yields X sup |eit∆ f1 (x)|2 |eit∆ f2 (x)|2 t∈[−τ,τ ] x∈I ′ 1 ≤ sup X t∈[−τ,τ ] x∈I ′ |eit∆ f1 (x)|2 kf2 k22 sup x∈I1′ y∈I 1 ≤ sup t∈[−τ,τ ] X x∈Zd . kf1 k22 kf2 k22 X 2 |hx|eit∆ |yi|2 X |eit∆ f1 (x)|2 kf2 k22 sup x∈Zd y: |x−y|≥⌈s/2⌉ |hx|eit∆ |yi|2 (2.21) max(⌈s/2⌉, 1)d−1 (4dτ )2⌈s/2⌉ . (⌈s/2⌉!)2 An identical argument gives sup X t∈[−τ,τ ] x∈I ′ |eit∆ f1 (x)|2 |eit∆ f2 (x)|2 . kf1 k22 kf2 k22 max(⌈s/2⌉, 1)d−1 (4dτ )2⌈s/2⌉ . (⌈s/2⌉!)2 2 (2.22) The bounds (2.21) and (2.22) together with (2.20) finish the proof of the Lemma. Lemma 2.8. For j ∈ {1, 2, 3, 4} let fj ∈ l2 (Zd ). For any choice j, k ∈ {1, 2, 3, 4} let s = dist(supp (fk ), supp (fl )). Then sup t∈[−τ,τ ] 4 4 d−1 ⌈s/2⌉ Y X Y it∆ (e fj )(x) . max(⌈s/2⌉, 1) (4dτ ) kfj k2 ⌈s/2⌉! d x∈Z j=1 (2.23) j=1 where the implicit constant depends only on the dimension d and τ . Proof. Follows using Cauchy-Schwarz together with Corollary 2.2 and Lemma 2.7. Corollary 2.9. Let the diffraction profile obey the bound (1.7). Then with c = 1 + ln(8dτ ) we have |Q(f1 , f2 , f3 , f4 )| . e−s(ln s−c)/2+(d−1) ln(max(s/2,1)) 4 Y j=1 kfj k2 (2.24) where s = dist(supp (fk ), supp (fl )) for any choice j, k ∈ {1, 2, 3, 4} and the implicit constant depends only on the dimension d and τ from (1.7). Remark 2.10. Since for any 0 < δ < 1/2, e−s(ln s−c)/2+(d−1) ln(max(s/2,1)) . e−δs ln s = s−δs , the bound (2.24) implies |Q(f1 , f2 , f3 , f4 )| . s−δs 4 Y j=1 kfj k2 for all 0 < δ < 1/2, where the implicit constant depends only on d, δ, and τ . (2.25) SUPER-EXPONENTIAL DECAY OF DIFFRACTION MANAGED SOLITONS 11 Proof. Since (1.7) holds, there exists 0 < τ < ∞ such that |D(t)| ≤ τ for all 0 ≤ t ≤ 1. Thus, since Tt = eiD(t)∆ , Z 1 X Y 4 4 X Y (Tt fj )(x) sup |Q(f1 , f2 , f3 , f4 )| ≤ (Tt fj )(x) dt ≤ 0 ≤ x∈Zd j=1 X x∈Zd x∈Zd 0≤t≤1 j=1 4 Y it∆ (e fj )(x) sup t∈[−τ,τ ] j=1 and the bound from Lemma 2.8 implies |Q(f1 , f2 , f3 , f4 )| . 4 max(⌈s/2⌉, 1)d−1 (4dτ )⌈s/2⌉ Y kfj k2 ⌈s/2⌉! . (2.26) j=1 An easy proof by induction shows n! ≥ en ln n−n . Hence, using ⌈s/2⌉ ≥ s/2, max(⌈s/2⌉, 1)d−1 (4dτ )⌈s/2⌉ . e−s/2 ln(s/2)+s/2 ln(4dτ )+s/2+(d−1) ln(max(s/2,1)) ⌈s/2⌉! = e−s ln(s)/2+cs/2+(d−1) ln(max(s/2,1)) where c = 1 + ln(8dτ ). This proves the bound (2.24). 3. Self-consistency bound and super-exponential decay As in the continuous case, see [16], the key idea is not to focus on the solution f directly, but to study its tail distribution defined, for n ∈ N0 , by X 1/2 |f (x)|2 . (3.1) α(n) := |x|≥n The fundamental a-priori estimate for the tail distribution of weak solutions f of (1.11) is given by the following Proposition 3.1 (Self-consistency bound). Let f be a weak solution of ωf = Q(f, f, f ). Then with c = 1 + ln(8τ ), where τ is from the bound (1.7) on the diffraction profile, α(2n) . α(n)3 + e−(n+1)(ln(n+1)−c)/2 . (3.2) In particular, for any 0 < δ < 1/2 the bound α(2n) . α(n)3 + (n + 1)−δ(n+1) (3.3) holds. In (3.2) and (3.3) the implicit constants depend only on ω, δ, kf k2 , and τ . Proof. Since f is a weak solution of ωf = Q(f, f, f ), we have, by definition, ωhg, f i = Q(g, f, f, f ) for all g ∈ l2 (Z). Since α(2n) = sup g∈l2 (Z), kgk2 =1, supp (g)⊂(−∞,−2n]∪[2n,∞) |hg, f i| 12 D. HUNDERTMARK AND Y.-R. LEE we need to estimate Q(g, f, f, f ) for g ∈ l2 (Z) with kgk2 = 1 and supp (g) ⊂ (−∞, −2n] ∪ [2n, ∞). Let In = {−n + 1, . . . n − 1}, Inc its complement and split f into its low and high parts, f = f< + f> with f< = f χIn and f> = f χInc . Using the multi-linearity of Q, Q(g, f, f, f ) = Q(g, f< , f, f ) + Q(g, f> , f, f ) = Q(g, f< , f, f ) + Q(g, f> , f< , f ) + Q(g, f> , f> , f< ) + Q(g, f> , f> , f> ). (3.4) The last term is estimated by |Q(g, f> , f> , f> )| . kgk2 kf> k32 = α(n)3 . For the first three terms in (3.4) we note that each of them contains one f< . Since s := dist(supp (g), supp (f< )) is at least n + 1, the enhanced multi-linear estimate (2.24) from Corollary 2.9 applies and gives, since d = 1, for the first term |Q(g, f< , f, f )| . e−s(ln s−c)/2 kgk2 kf< k2 kf k22 . Similar bounds hold for the second and third terms. Collecting terms and using s ≥ n + 1, we see α(2n) . ω −1 α(n)3 + e−(n+1)(ln(n+1)−c)/2 α(0)3 + α(0)2 α(n) + α(0)α(n)2 . α(n)3 + e−(n+1)(ln(n+1)−c)/2 since α is a bounded decreasing function. This proves (3.2). Note that the implicit constant depends only on ω, τ , and α(0) = kf k2 . To prove (3.3) one either argues as above, but uses (2.25) instead of (2.24), or simply notes that e−(n+1)(ln(n+1)−c)/2 . (n + 1)−δ(n+1) for any 0 < δ < 1/2. Theorem 3.2 (Super-exponential decay). Let α be a decreasing non-negative function which obeys the self-consistency bound (3.2) of Proposition 3.1 and decays to zero at infinity. Then the bound α(n) . e− n+1 4 −c) (ln( n+1 2 ) holds for all n ∈ N0 . Here one can choose c = 1 + ln(8τ ), with τ from the bound (1.7) on the diffraction profile. Corollary 3.3 (= Theorem 1.1). For any weak solution of ωf = Q(f, f, f ) and any 0 < µ < 14 the bound − holds for all x ∈ Z. |f (x)| . e |x|+1 4 |x|+1 ln 2 −c (3.5) Proof. Given Theorem 3.2, this follows immediately from |f (x)| ≤ α(|x|). It remains to prove Theorem 3.2. This is done in two steps. The first is a reduction of the full super-exponential decay to a slower but still super-exponential decay. SUPER-EXPONENTIAL DECAY OF DIFFRACTION MANAGED SOLITONS 13 Lemma 3.4. Let α be a non-negative decreasing function which obeys the selfconsistency bound (3.2). Then the bounds α(n) . e− n+1 4 −c) (ln( n+1 2 ) (3.6) and α(n) . (n + 1)−µ0 (n+1) for some µ0 > 0 are equivalent. (3.7) Proof. Of course, the bound (3.6) implies (3.7) for all 0 < µ0 < 1/4. To prove the converse we will show that if α(n) . (n + 1)−µ(n+1) for some µ > 0 and if 3µ < 1/2 one can boost the decay to 5 α(n) . (n + 1)− 4 µ(n+1) . (3.8) Assume this for the moment and assume that (3.7) holds for some µ0 > 0. Let l0 ∈ N0 such that 3(5/4)l0 −1 µ0 < 1/2 ≤ 3(5/4)l0 µ0 . We can iterate (3.8) exactly l0 times to see l0 α(n) . (n + 1)−(5/4) µ0 (n+1) . (3.9) Plugging the estimate (3.9) into the self–consistency bound (3.2) yields l0 µ (n+1) 0 α(2n) . (n + 1)−3(5/4) + e−(n+1)(ln(n+1)−c)/2 . e−(n+1)(ln(n+1)−c)/2 since 3(5/4)l0 µ0 ≥ 1/2, by assumption. Thus for even n we have the bound n n α(n) . e−( 2 +1)(ln( 2 +1)−c)/2 = e− n+2 (ln( n+2 )−c) 4 2 (3.10) and, by monotonicity of α, for odd n the bound (3.10) yields α(n) ≤ α(n − 1) . e− n+1 (ln( n+1 )−c) 4 2 . (3.11) The bounds (3.10) and (3.11) together show that (3.6) holds. It remains to prove the boost in decay given in (3.9). If α(n) . (n + 1)−µ(n+1) and 3µ < 1/2, the self-consistency bound (3.2) gives α(2n) . (n + 1)−3µ(n+1) + e−(n+1)(ln(n+1)−c)/2 . (n + 1)−3µ(n+1) as long as 3µ < 1/2. Thus, as before, for even n one gets 3 3 n + 2 − 32 µ(n+2) α(n) . . (n + 2)−( 2 −ε)(n+2) ≤ (n + 1)−( 2 −ε)(n+1) 2 for any ε > 0. For odd n the monotonicity of α and (3.12) give 3 α(n) ≤ α(n − 1) . (n + 1)−( 2 −ε)(n+1) (3.12) (3.13) for any ε > 0. The bounds (3.12) and (3.13) together show 3 α(n) . (n + 1)−( 2 −ε)(n+1) (3.14) for all n ∈ N0 and all ε > 0. Choosing ε = 1/4 yields (3.8). Given Lemma 3.4, in order to prove the super–exponential decay of α given in Theorem 3.2, it is enough to show that α(n) . (n + 1)−µ0 (n+1) for some arbitrarily small µ0 > 0. This is the content of the next proposition 14 D. HUNDERTMARK AND Y.-R. LEE Proposition 3.5. Assume that α is a non-negative decreasing function which obeys the self-consistency bound (3.2) and goes to zero at infinity. Then there exists µ0 > 0 such that α(n) . (n + 1)−µ0 (n+1) For the proof of Proposition 3.5 we need some more notation. Given n ∈ N0 let (n + 2)n+2 if n is even F (n) := (3.15) (n + 1)n+1 if n is odd and, for ε ≥ 0, its regularized version Fε (n) := Finally, for µ ≥ 0 let F (n) 1 = . −1 1 + εF (n) F (n) + ε (3.16) Fµ,ε (n) := Fε (n)µ = (F (n)−1 + ε)−µ . (3.17) kαkµ,ε,b := sup Fµ,ε (n)|α(n)|. (3.18) Furthermore let n≥b Of course, the super-exponential decay given in Proposition 3.5 is equivalent to showing for some µ0 > 0 and some b ∈ N0 . kαkµ0 ,0,b < ∞ Since kαkµ,0,b = sup0<ε≤1 kαkµ,ε,b , see Lemma 3.6.vi below, it is enough to find an ε-independent bound on kαkµ,ε,b , which is where the second self-consistency bound of Proposition 3.1 enters. First we gather some basic properties of Fµ,ε needed in the proof of Proposition 3.5. Lemma 3.6. (i) For any ε ≥ 0 the function n 7→ Fε (n) is increasing in n and, for fixed n, decreasing in ε ≥ 0. Moreover, Fε (n) ≤ ε−1 for all n. (ii) For any µ, ε ≥ 0 the function n 7→ Fµ,ε (n) is increasing and bounded by ε−µ . Moreover, Fµ,ε (n) is decreasing in ε ≥ 0 and depends continuously on the parameters µ and ε for fixed n ∈ N0 . (iii) For any 0 ≤ µ ≤ δ/3, the function N0 ∋ n → Fµ,0 (2n)(n+1)−δ(n+1) is decreasing. (iv) The bound Fµ,ε (2n) ≤ 4Fµ,ε (n)3 (3.19) holds for all 0 ≤ µ, ε ≤ 1 and n ∈ N0 . (v) For fixed b ∈ N0 and an arbitrary bounded function α the map (µ, ε) 7→ kαkµ,ε,b is continuous on [0, 1] × (0, 1]. (vi) For fixed 0 < µ, b ∈ N0 , and an arbitrary bounded function α, kαkµ,0,b = lim kαkµ,ε,b = sup kαkµ,ε,b . ε→0 0<ε≤1 Remark 3.7. The last part of the lemma shows that for fixed 0 < µ ≤ 1 and b ∈ N0 the map ε 7→ kαkµ,ε,b is continuous on [0, 1]. Here we interpret continuity in a generalized sense: One certainly has kαkµ,ε,b ≤ kαk∞ /ε < ∞ for all ε > 0. If kαkµ,0,b < ∞, then limε→0 kαkµ,ε,b = kαkµ,0,b , and if kαkµ,0,b = ∞, then limε→0 kαkµ,ε,b = ∞. SUPER-EXPONENTIAL DECAY OF DIFFRACTION MANAGED SOLITONS 15 We postpone the proof of Lemma 3.6 after the proof of Proposition 3.5. Proof of Proposition 3.5. We assume that α decays monotonically to zero and obeys the second self-consistency bound given in Proposition 3.1. That is, for fixed 0 < δ < 1/2 there exists a constant C0 such that α(2n) ≤ C0 α(n)3 + C0 (n + 1)−δ(n+1) . (3.20) Multiply this by χ[b,∞), the characteristic function of the set [b, ∞), using χ[b,∞)(n) = χ[b,∞)(2n) − χ[b,2b) (2n), (3.21) putting αb = χ[b,∞)α, and rearranging terms yields αb (2n) ≤ C0 αb (n)3 + C0 (n + 1)−δ(n+1) χ[b,∞) (n) + χ[b,2b) (2n)α(2n). (3.22) Now let µ ≤ δ/3. Multiplying (3.22) by Fµ,ε (2n), using the bound (3.19) from Lemma 3.6 on the first term on the right hand side of (3.22) and Fµ,ε (2n) ≤ Fµ,0 (2n) from Lemma 3.6.ii on the other two, assuming b ≥ 0, we get 3 Fµ,0 (2n) χ[b,∞) (n) Fµ,ε (2n)αb (2n) ≤ C1 Fµ,ε (n)αb (n) + C0 (n + 1)δ(n+1) + Fµ,0 (2n)χ[b,2b) (2n)α(2n) 3 (3.23) Fµ,0 (2b) ≤ C1 Fµ,ε (n)αb (n) + C0 + F (2b)α(b) µ,0 (b + 1)δ(b+1) C0 3 ≤ C1 kαkµ,ε,b + Fµ,0 (2b) + α(b) . (b + 1)δ(b+1) For the second inequality we used that α and, by Lemma 3.6.iii, Fµ,0 (2n)(n+1)−δ(n+1) are decreasing and that Fµ,0 (2n) is increasing in n. In the third inequality, we used the obvious bound Fµ,ε (n)αb (n) ≤ kαkµ,ε,b for all n ∈ N0 . by the definition (3.18) for kαkµ,ε,b . The punchline is that, since Fµ,ε (2n) = Fµ,ε (2n + 1) by construction of Fµ,ε , the monotonicity of α gives sup Fµ,ε (n)α(n) = sup Fµ,ε (2n)αb (2n) n≥b (3.24) n∈N0 whenever b is an even natural number. So, since (3.23) holds for any n ∈ N0 , taking the supremum over n in (3.23) yields 3 C 0 kαkµ,ε,b ≤ C1 kαµ,ε,b + Fµ,0 (2b) + α(b) (3.25) (b + 1)δ(b+1) which is a closed inequality for kαkµ,ε,b and holds as long as b is even and 0 < µ ≤ δ/3 and 0 < ε ≤ 1 or µ = 0 and 0 ≤ ε ≤ 1. Equivalently, with G(ν) := ν − C1 ν 3 defined for ν ≥ 0, we arrived at the a-priori bound G(kαkµ,ε,b ) ≤ Fµ,0 (2b) C0 (b + 1)−δ(b+1) + α(b) . (3.26) 16 D. HUNDERTMARK AND Y.-R. LEE A simple exercise shows that the maximum of G is attained at νmax = (3C1 )−1/2 and is √ given by Gmax = G(νmax ) = 2/(3 3C1 ). Let 0 < G0 < Gmax and 0 < ν0 < νmax < ν1 with G(ν0 ) = G(ν1 ) = G0 . Since G(ν) < ν for ν > 0, we have G(ν0 ) < ν0 . Moreover, G−1 ((−∞, G0 ]) = [0, ν0 ] ∪ [ν1 , ∞). (3.27) This situation is visualized in Figure 1. Now we finish the proof of the decay estimate: Gmax G0 0 ν0 νmax ν1 [0, ν0 ] ∪ [ν1 , ∞) = G−1 (−∞, G0 ] Figure 1. Graph of G(ν) = ν − C1 ν 3 and the trapping region G−1 (−∞, G0 ] . we need to show that kαkµ,0,b is finite for some µ > 0 and b ∈ N0 . Note that by Lemma 3.6.v the map (µ, ε) 7→ kαkµ,ε,b is continuous in (µ, ε) ∈ [0, 1] × (0, 1], and, by Lemma 3.6.vi, for fixed 0 < µ ≤ 1 kαkµ,0,b = limε→0 kαkµ,ε,b . So it will be enough to find, for some µ > 0 and b ∈ N0 , a uniform in 0 < ε ≤ 1 estimate for kαkµ,ε,b . This is where the bound (3.26) will enter. Step 1: Choose an even b such that C0 (b + 1)−δ(b+1) + α(b) < G0 < Gmax . This is possible since α goes to zero at infinity. Since α is monotone decreasing, it also guarantees kαk0,1,b = supn∈N0 αb (n) = α(b) < G0 ≤ ν0 . Step 2: For the b fixed in Step 1, let 0 < µ0 ≤ δ/3 such that Fµ0 ,0 (2b)(C0 (b + 1)−δ(b+1) + α(b)) ≤ G0 < Gmax and kαkµ0 ,1,b < ν0 . This is possible since F0,0 (2b) = 1 and Fµ,0 (2b) and kαkµ,1,b are continuous in 0 ≤ µ ≤ δ/3. Putting things together, (3.26) gives G(kαkµ0 ,ε,b ) ≤ G0 for all 0 < ε ≤ 1. (3.28) Since G is continuous and kαkµ0 ,ε,b depends continuously on ε > 0, the bound (3.28) shows that kαkµ0 ,ε,b is trapped in the same connected component of G−1 ((−∞, G0 ]) as kαkµ0 ,1,b for all 0 < ε ≤ 1. Thus, using 0 ≤ kαkµ0 ,1,b < ν0 and (3.27), we must have kαkµ0 ,ε,b ≤ ν0 for all 0 < ε ≤ 1. (3.29) Together with kαkµ0 ,0,b = limε→0 kαkµ0 ,ε,b , the bound (3.29) shows kαkµ0 ,0,b ≤ ν0 < ∞ which proves the estimate α(n) ≤ ν0 F (n)−µ0 SUPER-EXPONENTIAL DECAY OF DIFFRACTION MANAGED SOLITONS 17 for all large n. This finished our proof of Proposition 3.5. It remains to prove the properties of Fµ,ε given in Lemma 3.6. Proof of Lemma 3.6. The function F is clearly increasing in n and since s 7→ s/(1+εs) is increasing in s ≥ 0 for fixed ε ≥ 0, we see that Fε and hence also Fµ,ε is increasing in n. The other claims in part (i) and (ii) of Lemma 3.6 are obvious. δ − 1 ≥ 1/2, we have (iii): With λ = 2µ h i2µ Fµ,0 (2n)(n + 1)−δ(n+1) = (2(n + 1))2µ(n+1) (n + 1)−δ(n+1) = 2n+1 (n + 1)−λ(n+1) . Hence " #2µ Fµ,0 (2(n + 1))(n + 2)−δ(n+2) 2 1 (n+1) −λ = 1+ . (n + 2)λ n+1 Fµ,0 (2n)(n + 1)−δ(n+1) 1 n+1 is increasing, one has (1 + n+1 ) ≥ 2 and 2µ Fµ,0 (2(n + 1))(n + 2)−δ(n+2) 2 −λ ≤ 2 ≤ 2(1−2λ)2µ ≤ 1 (n + 2)λ Fµ,0 (2n)(n + 1)−δ(n+1) Since the sequence (1 + 1 n+1 n+1 ) so the function Fµ,0 (2n)(n + 1)−δ(n+1) is decreasing on N0 . (iv): Put Fε (2n) (F (n)−1 + ε)3 . f (n, ε) := = Fε (n)3 F (2n)−1 + ε We claim that sup f (n, ε) = 4, which obviously yields Fε (2n) n∈N0 , 0≤ε≤1 ≤ 4Fε (n)3 and Fµ,ε (2n) ≤ 4µ Fµ,ε (n)3 ≤ 4Fµ,ε (n)3 (3.30) (3.31) for all 0 ≤ µ ≤ 1. So in order to prove (3.19) it is enough to show that (3.31) holds. The partial derivative of f with respect to ε is given by ∂f (F (n)−1 + ε)2 = 3F (2n)−1 − F (n)−1 + 2ε . −1 2 ∂ε (F (2n) + ε) In the case 3F (2n)−1 − F (n)−1 ≥ 0 one has ∂f ∂ε ≥ 0 for all ε ≥ 0 and the case ∂f −1 −1 3F (2n) − F (n) < 0 one has ∂ε < 0 as long as 0 < ε < (F (n)−1 − 3F (2n)−1 )/2 −1 − 3F (2n)−1 )/2. Altogether, as a function of ε, f (n, ε) and ∂f ∂ε > 0 for ε > (F (n) is either increasing on [0, ∞) or it has a single minimum and no maximum in (0, ∞). Hence, for fixed n ∈ N0 , its maximum in ε ∈ [0, 1] is attained at the boundary, sup n∈N0 , 0≤ε≤1 f (n, ε) = max( sup f (n, 0), sup f (n, 1)). n∈N0 (3.32) n∈N0 Since F1 (n) = F (n)/(1 + F (n)) = (1 + F (n)−1 )−1 and F (n) ≥ 4 for all n ∈ N0 , 5 3 F1 (2n) F (2n) −1 3 f (n, 1) = = 1 + F (n) ≤ <2 (3.33) F1 (n)3 1 + F (2n) 4 18 D. HUNDERTMARK AND Y.-R. LEE and using (n + 1)n+1 ≤ F (n) ≤ (n + 2)n+2 one sees 2(n+1) n+1 2(n + 1) 4 F (2n) f (n, 0) = ≤ = ≤4 F (n)3 n+1 (n + 1)3(n+1) (3.34) for all n ∈ N0 . Putting (3.32), (3.33), and (3.34) together and noticing f (1, 0) = 4 yields (3.31). (v): Continuity of kαkµ,ε,b in (µ, ε) ∈ [0, 1] × (0, 1]: First note that the triangle inequality implies kαkµ ,ε ,b − kαkµ ,ε ,b ≤ sup (Fµ ,ε (n) − Fµ ,ε (n))α(n) 1 1 2 2 n≥b 1 1 2 2 −µ1 −µ2 ≤ kαk∞ sup F (n)−1 + ε1 − F (n)−1 + ε2 n∈N0 −µ1 −µ2 ≤ kαk∞ sup x + ε1 − x + ε2 (3.35) 0≤x≤1/4 since 4 ≤ F (n) for all n ∈ N0 . Let h(x, µ, ε) := (x + ε)−µ . For any 0 < ε′ < 1, h is continuous on the compact set [0, 1/4]× [0, 1]× [ε′ , 1] and hence uniformly continuous. Thus for any η > 0 there exists δ > such that for (xj , µj , εj ) ∈ [0, 1] × [0, 1] × [ε′ , 1], j = 1, 2 with |x1 − x2 |, |µ1 − µ2 |, |ε1 − ε2 | < δ we have |h(x1 , µ1 , ε1 )− h(x2 , µ2 , ε2 )| < η. In particular, sup |h(x, µ1 , ε1 ) − h(x, µ2 , ε2 )| < η 0≤x≤1/4 which, together with (3.35), shows that (µ, ε) 7→ kαkµ,ε,b is uniformly continuous on any compact subset of [0, 1] × (0, 1], hence continuous on [0, 1] × (0, 1]. (vi): Fix µ > 0. Recall that kαkµ,ε,b is decreasing in ε. Thus lim kαkµ,ε,b = sup kαkµ,ε,b = sup sup Fµ,ε (n)|α(n)| ε→0 0<ε≤1 0<ε≤1 n≥b = sup sup Fµ,ε (n)|α(n)| = sup Fµ,0 (n)|α(n)| = kαkµ,0,b n≥b 0<ε≤1 n≥b which finishes the proof of Lemma 3.6. 4. Existence of Diffraction managed solitons for zero average diffraction Here we want to give a simple proof of existence of diffraction managed solitons, i.e., weak solutions of (1.11), via the direct method from the calculus of variations. This hinges on the fact that the diffraction management equation is the Euler–Lagrange equation for the functional ϕ(f ) := Q(f, f, f, f ) (4.1) 2 on l (Z). The corresponding constraint maximization problem is given by Pλ = sup ϕ(f ) : f ∈ l2 (Z), kf k22 = λ (4.2) where λ > 0. Up to some minor technical details it is clear that any maximizer f of the variational problem (4.2), that is, any f ∈ l2 (Z) with kf k22 = λ and Q(f, f, f, f ) = Pλ (4.3) SUPER-EXPONENTIAL DECAY OF DIFFRACTION MANAGED SOLITONS 19 is by the Lagrange multiplier theorem a weak solution of the diffraction management equation (1.11). The usual way to show existence of a maximizer is to identify it as the limit of a suitable maximizing sequence, i.e., a sequence (fn )n with kfn k22 = λ and limn→∞ ϕ(fn ) = Pλ . Such a sequence always exists, the problem, due to the translation invariance of the time evolution Tt = eiD(t)∆ , is that the functional ϕ is invariant under translation; if fn is a maximizing sequence for (4.2) and ξn any sequence in Z, then the shifted sequence fn,ξn (x) := fn (x − ξn ) is also a maximizing sequence. That is, the problem (4.2) is invariant under shifts, yielding a loss of compactness since maximizing sequences can very easily converge weakly to zero. The usual way to overcome this is the use of Lions’ concentration compactness method [24] which, for positive average dispersion has been used in [27, 30]. For vanishing average diffraction, and under much more restrictive conditions on the diffraction profile than (1.7), the existence of a maximizer of (4.2) has been shown in [34] with the help of Ekeland’s variational principle, [12, 13], see also [17]. We will give a different approach, which avoids the use of Lions’ concentration compactness method or Ekeland’s variational principle by using the translation invariance of the problem to show that for any maximizing sequence fn there exists a sequence of shifts ξn such that the shifted sequence fn,ξn is tight in the sense of (4.4) below. Then, since fn,ξn is bounded in l2 (Z), it has a weakly convergent and hence, by the compactness Lemma 4.1 below, also a strongly convergent subsequence. The limit of this subsequence is then a natural candidate for the maximizer of (4.2), see Theorem 4.7. In the following, we will always assume that the diffraction profile obeys the bound (1.7). Our main tools are the multi-linear bound from Corollary 2.9 and the following simple compactness result. Lemma 4.1. Let 1 ≤ p < ∞. A sequence (fn )n∈N ⊂ lp (Zd ) is strongly converging to f in lp (Zd ) if and only if it is weakly convergent to f and the sequence is tight, i.e., X |fn (x)|p = 0. (4.4) lim lim sup L→∞ n→∞ |x|>L Proof. For L ≥ 1, let KL be the operator of multiplication with the characteristic function of [−L, L]d ∩ Zd , that is, f (x) for |x| ≤ L KL f (x) = 0 for |x| > L and K L := 1 − KL . Note that both KL is an operator with finite dimensional range. In particular, for any 1 ≤ L < ∞, KL : lp (Zd ) → lp (Zd ) is a compact operator. Furthermore, both KL and K L are bounded operators with operator norm one since p kf kpp = kKL f kpp + kK L f kpp ≥ max kKL f kp , kK L f kp 20 D. HUNDERTMARK AND Y.-R. LEE for all f ∈ lp (Zd ) and KL , respectively K L , acts as the identity on its range. Moreover, the tightness-condition (4.4) is equivalent to lim lim sup kK L fn kp = 0. L→∞ n→∞ (4.5) Now assume that fn converges strongly to f in lp (Zd ). Then it clearly converges also weakly to f and kK L fn kp ≤ kK L f kp + kK L (fn − f )kp ≤ kK L f kp + kfn − f kp . Thus, by strong convergence of fn to f , lim sup kK L fn kp ≤ kK L f kp . n→∞ Since f ∈ tight. lp (Zd ) and p < ∞, we have limL→∞ kK L f kp = 0, so the sequence fn is For the converse assume that fn converges to f weakly in lp (Zd ) and is tight, that is, (4.5) holds. Then kf − fn kp ≤ kKL (f − fn )kp + kK L (f − fn )kp ≤ kKL (f − fn )kp + kK L f kp + kK L fn kp . Since KL is a compact operator on Lp , it maps weakly convergent sequences into strongly converging sequences. Hence lim sup kf − fn kp ≤ kK L f kp + lim sup kK L fn kp n→∞ Now using f ∈ to get lp (Zd ) n→∞ and the condition (4.5), take the limit L → ∞ in this inequality lim sup kf − fn kp ≤ 0. n→∞ Thus fn converges to f strongly in lp (Zd ). Remark 4.2. The proof above breaks down for p = ∞, since for an arbitrary f ∈ l∞ (Zd ), one does not, in general, have lim kK L f k∞ = 0. L→∞ However, for the closed subspace l0∞ (Zd ) ⊂ l∞ (Z d ) consisting of bounded sequences indexed by Zd vanishing at infinity, limx→∞ f (x) = 0 for any f ∈ l∞ (Zd ), the above proof immediately generalizes and yields the analogous compactness statement: (fn )n∈N converges strongly in l0∞ (Zd ) if and only if it converges weakly and lim lim sup sup |fn (x)| = 0. L→∞ n→∞ |x|>L In the next Lemma we gather some simple bounds for the non-linear functional ϕ and the associated constraint maximization problem (4.2). Lemma 4.3. For any λ > 0 one has 0 < Pλ ≤ 1 and the scaling property Pλ = P1 λ2 holds. In particular, for any f ∈ l2 (Z) the bound holds. ϕ(f ) ≤ P1 kf k42 SUPER-EXPONENTIAL DECAY OF DIFFRACTION MANAGED SOLITONS 21 R1 Proof. Since ϕ(f ) = Q(f, f, f, f ) = 0 kTt f k44 dt we obviously have Pλ ≥ ϕ(f ) ≥ 0. √ With Corollary 2.2, we see Pλ ≤ 1. By scaling, replacing f with fe = f / λ, one gets Q(f, f, f, f ) = λ2 Q(fe, fe, fe, fe) and taking the supremum over f with kf k22 = λ we see Pλ = P1 λ2 . If P1 = 0 then R1 0 = Q(f, f, f, f ) = 0 kTt f k44 dt for all f ∈ l2 (Z) with kf k2 = 1. Thus, for almost every t ∈ [0, 1] one would have Tt f (x) = 0 for all x ∈ Z. Hence f = 0 in contradiction to kf k2 = 1. Thus P1 > 0. The next lemma is key in our proof that maximizing sequences have strongly convergent subsequences modulo translations. Its proof is inspired by the proof of Lemma 2.3 in [20]. Lemma 4.4. Assume that the diffraction profile obeys the bound (1.7). Then there is a constant C such that if f ∈ l2 (Z), ε2 < kf k22 and a, b ∈ Z, a ≤ b with X x<a |f (x)|2 ≥ X ε2 ε2 and |f (x)|2 ≥ , 2 2 (4.6) x>b then ϕ(f ) ≤ P1 (kf k42 − ε4 /2) + Ckf k42 1/2 (b − a + 1)1/2 − 1 (4.7) Proof. The number of points in [a, b] ∩ Z is given by b − a + 1. Choose l ∈ N such that l ≤ (b − a + 1)1/2 < l + 1 (4.8) and let I be a subinterval of {a, a + 1, . . . , b} consisting of l2 consecutive points. By pigeonholing, there must be a subset I0 = {a′ , . . . , b′ } ⊂ I consisting of l consecutive points with X x∈I0 |f (x)|2 ≤ kf k22 . l (4.9) We split f into three parts, f−1 := f |(−∞,a′ ) , f1 := f |(b′ ,∞) , and f0 := f |I0 . Then f = f−1 + f0 + f1 , kf k22 = kf−1 k22 + kf0 k22 + kf1 k22 , and (4.6) and (4.9) give kf−1 k22 ≥ ε2 , 2 kf1 k22 ≥ ε2 , 2 kf k2 and kf0 k2 ≤ √ . l (4.10) 22 D. HUNDERTMARK AND Y.-R. LEE Using the multi-linearity of Q, X Q(f, f, f, f ) = Q(fj1 , fj2 , fj3 , fj4 ) jl ∈{−1,0,1} l=1,...,4 X = jl ∈{−1,1} l=1,...,4 Q(fj1 , fj2 , fj3 , fj4 ) + X jl ∈{−1,0,1} l=1,...,4 some jl =0 Q(fj1 , fj2 , fj3 , fj4 ) = Q(f−1 , f−1 , f−1 , f−1 ) + Q(f1 , f1 , f1 , f1 ) X X + Q(fj1 , fj2 , fj3 , fj4 ) + jl ∈{−1,1} ∃k,l:jk =−1,jl =1 jl ∈{−1,0,1} l=1,...,4 some jl =0 Q(fj1 , fj2 , fj3 , fj4 ). (4.11) Lemma 4.3 shows Q(f−1 , f−1 , f−1 , f−1 ) + Q(f1 , f1 , f1 , f1 ) = ϕ(f−1 ) + ϕ(f1 ) ≤ P1 kf−1 k42 + kf1 k42 (4.12) and, utilizing that the supports of f−1 and f1 have distance at least l + 1 ≥ 2, the enhanced multi-linear bound (2.25) with the choice δ = 1/4 gives X 1 kf k42 4 Q(fj , fj , fj , fj ) . √ . kf k ≤ 2 1 2 3 4 (4.13) (l + 1)δ(l+1) l jl ∈{−1,1} ∃k,l:jk =−1,jl =1 Also, X jl ∈{−1,0,1} l=1,...,4 some jl =0 Q(fj , fj , fj , fj ) ≤ 1 2 3 4 X 4 Y kf k4 kfjl k2 ≤ √ 2 l j ∈{−1,0,1} l=1 l l=1,...,4 some jl =0 (4.14) by the a-priori-bound on Q given in Corollary 2.2 and (4.10) since each term in the above sum contains at least one factor kf0 k2 . Thus (4.11) together with (4.12), (4.13), and (4.14) gives C ϕ(f ) = Q(f, f, f, f ) ≤ P1 kf−1 k42 + kf1 k42 + √ kf k42 (4.15) l for some constant C. Since kf−1 k22 , kf1 k22 ≥ ε2 /2 and kf−1 k22 + kf1 k22 ≤ kf k22 , we have kf−1 k42 + kf1 k42 ≤ kf k42 − 2kf−1 k22 kf1 k22 ≤ kf k42 − ε4 /2. Together with (4.8) the bound (4.15) yields (4.7). Lemma 4.5. Assume that the diffraction profile obeys the bound (1.7) and let (fn )n∈N be a maximizing sequence for the constraint maximization problem (4.2). Then there √ exists a sequence (ξn )n∈N and, for each 0 < ε < λ, there exists Rε , which is independent of n, such that X lim sup |fn (x)|2 ≤ ε2 . (4.16) n→∞ |x−ξn |>Rε SUPER-EXPONENTIAL DECAY OF DIFFRACTION MANAGED SOLITONS 23 √ Proof. Given 0 < ε < λ as in the Lemma, we will show that there are corresponding intervals In,ε = {cn,ε , . . . , dn,ε } which are nested, In,ε ⊂ In,ε′ for all 0 < ε′ ≤ ε, (4.17) have bounded length, sup(dn,ε − cn,ε ) < ∞, (4.18) n∈N and contain most of the l2 norm of fn , X lim sup |fn (x)|2 ≤ ε2 . n→∞ (4.19) x6∈In,ε Given (4.17), √ (4.18), and (4.19), ξn and Rε can be constructed as follows: Fix some 0 < ε0 < λ. For each n ∈ N define ξn by simply choosing some point from the set In,ε0 and define Rε by Rε := sup(dn,ε − cn,ε ) n∈N √ for ε ≤ ε0 and Rε =√Rε0 for ε0 < ε < λ. The bound (4.18) guarantees that Rε is finite for all 0 < ε < λ. Since the intervals In,ε are nested in ε, the point ξn ∈ In,ε for any 0 < ε ≤ ε0 . In particular, In,ε ⊂ {x : |x−ξn | ≤ Rε } for all 0 < ε ≤ ε0 by definition of Rε . Moreover,√again since the sets In,ε are nested, In,ε ⊂ In,ε0 ⊂ {x : |x−ξn | ≤ Rε } for all ε0 < ε < λ, too. Putting everything together, (4.19) shows that with this choice of ξn and Rε the bound (4.16) holds. Thus it is enough to prove (4.17), (4.18), and (4.19): Let an,ε := min z ∈ Z : bn,ε X x<z |fn (x)|2 ≥ X ε2 2 ε2 := max z ∈ Z : |fn (x)| ≥ . 2 x>z (4.20) 2 Both exist and are finite, since fn ∈ l2 (Z). Put cn,ε = min(an,ε , bn,ε ) − 1 and dn,ε = max(an,ε , bn,ε ) + 1. With this choice (4.17) and (4.19) certainly hold and we only have to check (4.18), which is where Lemma 4.4 enters. Either an,ε > bn,ε , in which case dn,ε − cnε ≤ 2, or Lemma 4.4 applies and gives the bound ε2 Ckfn k42 P1 − Pλ − ϕ(fn ) ≤ (4.21) 1/2 2 1/2 (dn,ε − cn,ε − 1) − 1 where we rearranged (4.7) a bit and used the scaling P1 kfn k42 = P1 λ2 = Pλ . Since fn is a maximizing sequence for (4.2) we have limn→∞ ϕ(fn ) = Pλ . Thus taking the limit n → ∞ in (4.21) gives P1 ε2 Cλ2 ≤ lim inf 1/2 n→∞ 2 (dn,ε − cn,ε − 1)1/2 − 1 24 D. HUNDERTMARK AND Y.-R. LEE or lim sup(dn,ε − cn,ε ) ≤ h 2Cλ2 2 P1 ε2 which proves (4.18) and hence the Lemma. n→∞ i2 + 1 + 1 < ∞. A simple reformulation of Lemma 4.5 is Corollary 4.6. Assume that the diffraction profile obeys the bound (1.7) and let λ > 0. Then, given any maximizing sequence (fn )n of the variational problem (4.2), there exists a sequence of translations ξn such that the translated sequence fn,ξn with fn,ξn (x) := fn (x − ξn ) is tight, that is, X lim lim sup |fn,ξn (x)|2 = 0. (4.22) L→∞ n→∞ |x|>L Moreover, this shifted sequence is still a maximizing sequence for the variational problem (4.2). Proof. By Lemma 4.5, the sequence fn,ξn is certainly tight. On the other hand it is also a maximizing sequence for 4.2, since the time evolution Tt = eiD(t)∆ commutes with translation, Tt fn,ξn (x) = Tt fn (x − ξn ) for all x, and hence ϕ(fn,ξn ) = Q(fn,ξn , fn,ξn , fn,ξn , fn,ξn ) = Q(fn , fn , fn , fn ) = ϕ(fn ) for all n ∈ N. Theorem 4.7 (= Theorem 1.3). Let λ > 0 and assume that the diffraction profile obeys the bound (1.7). Then there is an f ∈ l2 (Z) with kf k22 = λ such that ϕ(f ) = Pλ := sup ϕ(g). g:kgk22 =λ This maximizer f is also a weak solution of the dispersion management equation ωf = Q(f, f, f ). where ω = Pλ /λ > 0 is the Lagrange-multiplier. Proof. Let λ > 0 and (fn )n be a maximizing sequence for (4.2) with kfn k2 = λ. By Corollary 4.6, we can, without loss of generality, assume that this maximizing sequence is already tight in the sense of equation (4.22). Since the unit ball in l2 (Z) is weakly compact, there is a subsequence (fnj )j∈N of (fn )n∈N which converges weakly to some f ∈ l2 (Z). From Lemma 4.1 we know that fnj converges even strongly to f in l2 (Z). Thus kf k22 = λ and hence f is a good candidate for the maximizer. To conclude that f is a maximizer for the variational problem, we need to show that ϕ(f ) = Pλ . Since kf k22 = λ one certainly has ϕ(f ) ≤ Pλ = lim ϕ(fn ), n→∞ so one only needs upper semi-continuity of ϕ at f , i.e., lim sup ϕ(fnj ) ≤ ϕ(f ). n→∞ (4.23) SUPER-EXPONENTIAL DECAY OF DIFFRACTION MANAGED SOLITONS 25 By Lemma 4.8 below, the map f 7→ ϕ(f ) is even continuous on l2 (Z), in particular, (4.23) is true which finished the proof that the variational problem (4.2) has a maximizer. The proof that the above maximizer is a weak solution of the associated Euler– Lagrange equation (1.11) is standard in the calculous of variations, we sketch it for the convenience of the reader: Lemma 4.9 below shows that the derivative of the functional ϕ at any f ∈ l2 (Z) is given by the linear map Dϕ(f )[h] = 4ReQ(h, f, f, f ). Similarly, one can check that the derivative of ψ(f ) = kf k22 = hf, f i is given by Dψ(f )[h] = 2Rehh, f i. Note that although, in our convention for the inner product, the map h 7→ hh, f i is anti-linear, the map h 7→ Rehh, f i is linear. Similarly, one easily checks that for fixed f the map h 7→ ReQ(h, f, f, f ) is linear. Now let f be any maximizer of the constraint variational problem (4.2) and h ∈ l2 (Z) arbitrary. Define, for any (s, t) ∈ R2 , F (s, t) := ϕ(f + sf + th), G(s, t) := ψ(f + sf + th). Note that Dϕ(f + sf + th)[f ] ∇F (s, t) = Dϕ(f + sf + th)[h] ReQ(f, f + sf + th, f + sf + th, f + sf + th) =4 ReQ(h, f + sf + th, f + sf + th, f + sf + th) and ∇G(s, t) = Since hf, f i = λ 6= 0, Dψ(f + sf + th)[f ] Dψ(f + sf + th)[h] ∇G(0, 0) = 2 =2 hf, f i Rehh, f i Rehf, f + sf + thi Rehh, f + sf + thi . is not the zero vector in R2 and since ∇G(s, t) depends multi-linearly, in particular continuously, on (s, t), the implicit function theorem [36] shows that there exists an open interval I ⊂ R containing 0 and a differentiable function φ on I with φ(0) = 0 such that λ = kf k22 = G(0, 0) = G(φ(t), t) for all t ∈ I. Consider the function I ∋ t 7→ F (φ(t), t). Since f is a maximizer for the constraint variational problem (4.2), F (φ(t), t) has a local maximum at t = 0. Hence, using the chain rule, ′ dF (φ(t), t) φ (0) = ∇F (0, 0) · = 4Q(f, f, f, f )φ′ (0) + 4ReQ(h, f, f, f ) 0= 1 dt t=0 Since λ = G(φ(t), t), the chain rule also yields ′ dG(φ(t), t) φ (0) 0= = ∇G(0, 0) · = 2hf, f iφ′ (0) + 2Rehh, f i. 1 dt t=0 26 D. HUNDERTMARK AND Y.-R. LEE Solving this for φ′ (0) and plugging it back into the expression for the derivative of F , we see that Q(f, f, f, f ) Rehh, f i = ReQ(h, f, f, f ). hf, f i In other words, with ω := Q(f, f, f, f )/hf, f i = Pλ /λ > 0 and f any maximizer of (4.2), we have Re(ωhh, f i) = ReQ(h, f, f, f ) (4.24) 2 for any h ∈ l (Z). Replacing h by ih in (4.24), one gets for all h ∈ l2 (Z). for any h ∈ (1.11). l2 (Z), Im(ωhh, f i) = ImQ(h, f, f, f ) (4.25) (4.24) and (4.25) together show ωhh, f i = Q(h, f, f, f ) that is, f is a weak solution of the diffraction management equation In the proof of Theorem 4.7, we needed the following two Lemmata. Lemma 4.8. The map f 7→ ϕ(f ) = Q(f, f, f, f ) is locally Lipshitz continuous on l2 (Z). Proof. Given f, g, one has Q(f, f, f, f ) − Q(g, g, g, g) = = Z 1 0 Z kTt f k44 − kTt gk44 dt 3 1X 0 j=0 kTt f k3−j 4 kTt f k4 − kTt gk4 kTt gkj4 (4.26) dt . The above together with the triangle inequality, the bound khk4 ≤ khk2 for all h ∈ l2 (Z), see Lemma 2.1, and the unicity of Tt on l2 (Z) gives Z 1X 3 Q(f, f, f, f ) − Q(g, g, g, g) ≤ kTt f k2 − kTt gk2 kTt gkj dt kTt f k3−j 2 2 0 j=0 ≤ Z ≤ 3 X 3 1X 0 j=0 j=0 j kTt f k3−j 2 kTt (f − g)k2 kTt gk2 dt (4.27) j kf k3−j 2 kf − gk2 kgk2 ≤ 4 max(1, kf k32 , kgk32 )kf − gk2 . We need one more technical result, about the differentiability of the non-linear functional ϕ. Lemma 4.9. The functional ϕ is continuously differentiable with derivative Dϕ(f )[h] = 4ReQ(h, f, f, f ) SUPER-EXPONENTIAL DECAY OF DIFFRACTION MANAGED SOLITONS 27 Proof. Using the multi-linearity of Q, one can check that for any f, h ∈ l2 (Z) ϕ(f + h) = ϕ(f ) + Q(f, f, f, h) + Q(f, f, h, f ) + Q(f, h, f, f ) + Q(h, f, f, f ) + O(khk22 ) = ϕ(f ) + 4ReQ(h, f, f, f ) + O(khk22 ) (4.28) where in the term O(khk22 ) we gathered expressions of the form Q(h, f, f, h), and Q(h, f, f, f + h), and similar, which by Corollary 2.2 are bounded by Ckhk22 . This shows that ϕ is differentiable with derivative Dϕ(f )[h] = 4ReQ(h, f, f, f ). Moreover, Dϕ(f )[h] − Dϕ(g)[h] = 4Re Q(h, f, f, f ) − Q(h, g, g, g) = 4Re Q(h, f − g, f, f ) + Q(h, g, f − g, f ) + Q(h, g, g, f − g) . Hence using the bound from Corollary 2.2 again, we see sup Dϕ(f )[h] − Dϕ(g)[h] ≤ 4(kf k22 + kf k2 kgk2 + kgk22 )kf − gk2 (4.29) khk2 ≤1 which shows that the derivative Dϕ is even locally Lipshitz continuous. Acknowledgment: It is a pleasure to thank Vadim Zharnitsky for introducing us to the dispersion management technique. 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