Average Height Find the average height of a point on a unit semicircle. y=√1-x² area = π/2 Figure 1: The unit semicircle and an interval dx. Here f (x) = value of f (x) is: √ 1 − x2 for −1 ≤ x ≤ 1, so a = −1 and b = 1. The average Avg(f ) = = = = = � b 1 f (x) dx b−a a � 1 1� 1 − x2 dx 2 −1 1 (Area of a unit semicircle) 2 1 �π� 2 2 π . 4 (We will eventually learn how to find the antiderivative of on techniques of integration.) 1 √ 1 − x2 in the unit MIT OpenCourseWare http://ocw.mit.edu 18.01SC Single Variable Calculus�� Fall 2010 �� For information about citing these materials or our Terms of Use, visit: http://ocw.mit.edu/terms.