Problems: Regions of Integration 1. Find the mass of the region R bounded by y = x + 1; y = x2 ; x = 0 and x = 1, if density = δ(x, y) = xy. y = x + 1 Answer: Inner limits: y from x2 to x + 1. Outer limits: x from 0 to 1. x+1 1 ⇒ M = δ(x, y) dA = xy dy dx R x=0 R y=x2 y = x2 1 [ x+1 y2 [ x(x + 1)2 x5 x3 x x5 xy dy = x [[ = − = + x2 + − . 2 x2 2 2 2 2 2 [1 3 5 4 3 2 6 x x x x x x x [ 1 1 1 1 5 + x 2 + − dx = + + − [[ = + + − = . 2 2 2 8 3 4 12 0 8 3 4 12 8 x+1 Inner: x2 1 Outer: 0 Note: The syntax y = x2 in limits is redundant but useful. We know it must be y because of the dy matching the integral sign. 2. Find the volume of the tetrahedron shown below. 1 z = f (x, y) � 1 1 Tetrahedron Answer: The surface has height: z = 1 − x − y. y 1 y =1−x R 1 x Region R 1 1−x 1 − x − y dy dx. Limits: inner: 0 < y < 1 − x, outer: 0 < x < 1. ⇒ V = x=0 1−x Inner: y=0 1 Outer: 0 y=0 [1−x y 2 [[ 1 x2 1 − x − y dy = y − xy − [ = 1 − x − x + x2 − + x − . 2 0 2 2 1 x2 1 1 1 1 −x+ dx = − + = . 2 2 2 2 6 6 1 MIT OpenCourseWare http://ocw.mit.edu 18.02SC Multivariable Calculus Fall 2010 For information about citing these materials or our Terms of Use, visit: http://ocw.mit.edu/terms.